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【题目】请你利用图中所提供的3个数据,自拟一道有关化学方程式的计算题,并写出解答过程.

【答案】自拟试题:要制得56kg含杂质3%的生铁需要含Fe2O3 80%的赤铁矿石多少千克?(或多少千克含Fe2O3 80%的赤铁矿石,可以炼出56kg含杂质3%的生铁?)

解:设需要含Fe2O3 80%的赤铁矿石的质量为x.

Fe2O3+3CO2Fe+3CO2

160 112

x×80% 56kg×(1-3%)

160︰112=(x×80%)︰[56kg×(1-3%)] x=97kg

答:要制得56kg含杂质3%的生铁需要含Fe2O3 80%的赤铁矿石97kg.

【解析】解:设需要含Fe2O3 80%的赤铁矿石的质量为x.

Fe2O3+3CO2Fe+3CO2

160 112

x×80% 56kg×(1-3%)

160︰112=(x×80%)︰[56kg×(1-3%)] x=97kg

答:要制得56kg含杂质3%的生铁需要含Fe2O3 80%的赤铁矿石97kg

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