| ÎÊÌâÓë²ÂÏë | ʵÑé²½Öè | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
| £¨1£©¸ÉÔï¼ÁÊÇ·ñʧЧ | È¡ÑùÆ··ÅÈëÊÔ¹ÜÖÐ ¼ÓÊÊÁ¿µÄË®£¬´¥ÃþÊÔ¹Ü±Ú | ûÓÐÈȸР| |
| £¨2£©Ê§Ð§µÄ¸ÉÔï¼ÁÖÐ º¬ÓÐÇâÑõ»¯¸Æ | ¼ÓË®³ä·Ö½Á°è£¬¹ýÂ˺ó£¬ÓÃPHÊÔÖ½²âÆäÈÜÒºµÄPHÖµ | ÓÐÇâÑõ»¯¸Æ |
| ÎÊÌâÓë²ÂÏë | ʵÑé²½Öè | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
| ûÓÐÑõ»¯¸Æ | |||
| pH´óÓÚ7 |
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
£¨2005?µÂÖÝ£©ÔÚÒ»¸öÃܱÕÈÝÆ÷ÄÚÓÐA¡¢B¡¢C¡¢DËÄÖÖÎïÖÊ£¬ÔÚÒ»¶¨Ìõ¼þϳä·Ö·´Ó¦£®²âµÃ·´Ó¦Ç°ºó¸÷ÎïÖʵÄÖÊÁ¿ÈçÏ£º
|
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
| ѧÉú | Ñ¡ÓÃÊÔ¼Á | ÆÀ¼Û£¨ÊÇ·ñ¿ÉÐУ¬²¢¼òÊöÀíÓÉ£© |
| ¼× | Ï¡ÑÎËá | ·ñ£» HCl+NaOH=NaCl+H2O£¬°ÑNaOH·´Ó¦ÁË ·ñ£» HCl+NaOH=NaCl+H2O£¬°ÑNaOH·´Ó¦ÁË |
| ÒÒ | ʯ»ÒË® | ¿ÉÒÔ£»Na2CO3+Ca£¨OH£©2=CaCO3¡ý+2NaOH¹ýÂ˳ýÈ¥ ¿ÉÒÔ£»Na2CO3+Ca£¨OH£©2=CaCO3¡ý+2NaOH¹ýÂ˳ýÈ¥ |
| ±û | ÂÈ»¯±µ | ·ñ£»ÒýÈëÁËÐÂÔÓÖÊNaCl ·ñ£»ÒýÈëÁËÐÂÔÓÖÊNaCl |
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com