Question

3£®ÉÕ±­ÖÐ×°ÓÐÒ»¶¨Á¿ÁòËáºÍÁòËáÍ­µÄ»ìºÏÈÜÒº£¬ÒÑÖª¸ÃÈÜÒºÖк¬H₂SO₄µÄÖÊÁ¿Îª9.8g£®Ä³Í¬Ñ§Îª²â¶¨¸Ã»ìºÏÈÜÒºÖÐÁòËáÍ­µÄÖÊÁ¿£¬ÏòÉÕ±­ÖÐÖð½¥¼ÓÈë10%µÄNaOHÈÜÒº£¬µÃµ½³ÁµíµÄÖÊÁ¿¼Ç¼ÈçÏ£º

¼ÓÈëNaOHÈÜÒºµÄÖÊÁ¿/g	50.0	100.0	150.0	200.0	250.0
Éú³É³ÁµíµÄÖÊÁ¿/g	0.0	2.5	8.6	9.8	9.8

£¨1£©µÃµ½³ÁµíµÄ×ÜÖÊÁ¿Îª9.8g£»
£¨2£©¸Ã»ìºÏÈÜÒºÖÐÁòËáÍ­µÄ×ÜÖÊÁ¿ÊǶàÉÙ£¿
£¨3£©²Î¼Ó·´Ó¦µÄNaOHÈÜÒºµÄ×ÜÖÊÁ¿ÊǶàÉÙ£¿
£¨4£©»­³öÔڸûìºÏÈÜÒºÖмÓÈëNaOHÈÜÒºÖÊÁ¿ÓëÉú³É³ÁµíÖÊÁ¿±ä»¯¹ØϵµÄÇúÏߣ®£¨ÒªÇó±ê³ö¾ßÌåÊýÖµ£©

Answer 1

·ÖÎö ¸ù¾ÝÇâÑõ»¯ÄƺÍÁòËá·´Ó¦Éú³ÉÁòËáÄƺÍË®£¬ÇâÑõ»¯ÄƺÍÁòËáÍ­·´Ó¦Éú³ÉÇâÑõ»¯Í­³ÁµíºÍÁòËáÄÆ£¬½áºÏ·´Ó¦µÄ»¯Ñ§·½³Ìʽ¼°ÆäÌṩµÄÊý¾Ý¿ÉÒÔ½øÐÐÏà¹Ø·½ÃæµÄ¼ÆËãºÍÅжϣ®

½â´ð ½â£º£¨1£©Í¨¹ý±íÖÐÊý¾Ý¿ÉÖª£¬µÃµ½³ÁµíµÄ×ÜÖÊÁ¿Îª9.8g£»
£¨2£©Éè²Î¼Ó·´Ó¦µÄÁòËáÍ­ÖÊÁ¿Îªx£¬·´Ó¦µÄÇâÑõ»¯ÄÆÖÊÁ¿Îªy£¬
CuSO₄+2NaOH=Na₂SO₄+Cu£¨OH£©₂¡ý£¬
160         80                        98
 x            y                         9.8g
         $\frac{160}{x}$=$\frac{80}{y}$=$\frac{98}{9.8g}$
x=16g
y=8g
ËùÒÔ»ìºÏÈÜÒºÖÐÁòËáÍ­ÖÊÁ¿ÊÇ16g£»
£¨3£©ÉèÓëÁòËá·´Ó¦µÄÇâÑõ»¯ÄÆÖÊÁ¿Îªz£¬
2NaOH+H₂SO₄¨TNa₂SO₄+2H₂O£¬
   80        98
   z         9.8g
     $\frac{80}{z}$=$\frac{98}{9.8g}$
       z=8g£¬
²Î¼Ó·´Ó¦µÄNaOHÈÜÒºµÄ×ÜÖÊÁ¿ÊÇ£º$\frac{8g+8g}{10%}$=160g£¬
ËùÒԲμӷ´Ó¦µÄNaOHÈÜÒºµÄ×ÜÖÊÁ¿ÊÇ160g£»
£¨4£©ÔڸûìºÏÈÜÒºÖмÓÈëNaOHÈÜÒºÖÊÁ¿ÓëÉú³É³ÁµíÖÊÁ¿±ä»¯¹ØϵµÄÇúÏßÈçÏÂͼËùʾ£º

¹Ê´ð°¸Îª£º£¨1£©9.8g£»
£¨2£©16g£»
£¨3£©160g£»
£¨4£©

µãÆÀ ÔÚ½â´ðÉæ¼°·´Ó¦ÇúÏßÀàÎÊÌâʱ£¬Òª×¢ÒâÇúÏßÆðµã¡¢ÕÛµãµÄÌØÊâÒâÒ壬ÆðµãΪ·´Ó¦¿ªÊ¼·¢Éú¡¢ÕÛµãÔòÊǸ÷´Ó¦Ç¡ºÃÍêÈ«·´Ó¦£®