È¥Ä궬ÌìºÍ½ñ´ºÎÒ¹úÎ÷±±¡¢»ª±±¡¢Î÷ÄϺܶàÊ¡ÇøÔâÊÜ°ÙÄê²»ÓöµÄÌØ´ó¸Éºµ¡£Ò»Ð©ÔÖÇøȺÖÚÓÃË®¼«ÆäÀ§ÄÑ£¬ËûÃÇÔÚÕþ¸®µÄ°ïÖúÏ£¬¶à·½Ñ°ÕÒˮԴ¡£

(1)½«»ë×ǵÄË®±ä³ÎÇåµÄ¼òµ¥·½·¨ÊÇ                   ¡£½«³ÎÇåºóµÄË®Öó·Ð£¬ÈôË®ÖгöÏֽ϶àË®¹¸£¬¸ÃˮΪ             (Ñ¡ÌӲˮ¡±»ò¡°ÈíË®¡±)¡£

(2)½ñÄêÎÒÊмӴó¶Ô±¾µØÇøË®ÖʵÄÕûÖÎÁ¦¶È£¬ÇëÄã˵³öÔì³ÉË®ÖÊÎÛȾµÄÔ­ÒòÖ®Ò»ÊÇ       

                        ¡£

(3)È«ÇòÆøºò±äů»áµ¼Ö¸ɺµ¡¢ºéÀÔµÈÔÖº¦µÄƵ·¢¡£Ãæ¶ÔÈ«ÇòÆøºò±äůµÄÑϾþÌôÕ½£¬¸÷¹ú¶¼Ó¦²ÉÈ¡µÄ´ëÊ©ÓР                               (дһÌõ¼´¿É)¡£

(1) ¹ýÂË»ò¾²Öã¨ÆäËûºÏÀí´ð°¸¾ù¿É£©£¨1·Ö£©  Ӳˮ£¨1·Ö£©

(2) ¹¤Òµ¡°Èý·Ï¡±µÄÈÎÒâÅÅ·Å£¨ÆäËûºÏÀí´ð°¸¾ù¿É£©£¨1·Ö£©

(3) ´óÁ¦¿ª·¢ºÍʹÓÃÐÂÄÜÔ´£¨ÆäËûºÏÀí´ð°¸¾ù¿É£©£¨1·Ö£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

È¥Ä궬ÌìÖÁ½ñÄê´ºÌ죬ÎÒ¹úÎ÷ÄϵØÇøÔâÓö´ó·¶Î§³ÖÐø¸Éºµ£®È«¹úÈËÃñÍŽáÒ»Ö£¬¹²Í¬¿¹ºµ£®
£¨1£©Éú»îÖÐÇø·ÖӲˮºÍÈíË®µÄ³£Ó÷½·¨ÊÇ
¼ÓÈë·ÊÔíË®¿´²úÉúÅÝÄ­¶àÉÙ£¬²úÉúÅÝÄ­¶àÊÇÈíË®£¬²úÉúÅÝÄ­ÉÙÊÇӲˮ
¼ÓÈë·ÊÔíË®¿´²úÉúÅÝÄ­¶àÉÙ£¬²úÉúÅÝÄ­¶àÊÇÈíË®£¬²úÉúÅÝÄ­ÉÙÊÇӲˮ
£»
£¨2£©Èç¹ûÔÖÇøµØÏÂˮӲ¶È´ó£¬»òÕß¿ÓË®Öв¡Ô­Î¢ÉúÎï¹ý¶à²»ÄÜÖ±½ÓÒûÓ㬶¼¿ÉÒÔ²ÉÈ¡
Öó·Ð
Öó·Ð
µÄ·½·¨£¬À´½µµÍÓ²¶ÈºÍɱÃð²¡Ô­Î¢ÉúÎ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ë®ÊÇÈËÀàÉú»îÖв»¿ÉȱÉÙµÄÎïÖÊ£®
£¨1£©È¥Ä궬ÌìÖÁ½ñÄê´ºÌ죬ÎÒ¹úÎ÷ÄϵØÇøÔâÓö´ó·¶Î§³ÖÐø¸Éºµ£®ÓÐЩ´åׯ´òÉȡÓõØÏÂË®£®¼ìÑéµØÏÂË®ÊÇӲˮ»¹ÊÇÈíË®£¬¿ÉÓõÄÎïÖÊÊÇ
·ÊÔíË®
·ÊÔíË®
£¬²â¶¨µØÏÂË®µÄËá¼î¶È¿ÉÓÃ
pHÊÔÖ½
pHÊÔÖ½
£®
£¨2£©ÓÐЩ´åÃñÈ¡»ë×ǵĿÓË®×÷Éú»îÓÃË®£®ÓÐͬѧÀûÓÃËùѧµÄ֪ʶÓÃÈçͼ1ËùʾµÄ¼òÒ×¾»Ë®Æ÷½øÐо»»¯£¬ÆäÖÐСÂÑʯ¡¢Ê¯Ó¢É³µÄ×÷ÓÃÊÇ
¹ýÂË
¹ýÂË
£»»îÐÔÌ¿µÄ×÷ÓÃÊÇ
Îü¸½
Îü¸½
£®
£¨3£©Èç¹ûµØÏÂˮӲ¶È´ó£¬»òÕß¿ÓË®Öв¡Ô­Î¢ÉúÎï¹ý¶à£¬¶¼¿ÉÒÔ²ÉÈ¡
Öó·Ð
Öó·Ð
·½·¨£¬À´½µµÍÓ²¶ÈºÍɱÃð²¡Ô­Î¢ÉúÎ
£¨4£©ÏÂÁÐÎïÖʶ¼¿ÉÓÃÓÚË®Öʵľ»»¯»òɱ¾úÏû¶¾£®
¢Ù³ôÑõ£¨»¯Ñ§Ê½O3£©£ºÓÐÇ¿Ñõ»¯ÐÔ£¬¿ÉÓÃÓÚÓÎÓ¾³Ø¡¢Éú»îÓÃË®¡¢ÎÛË®µÄɱ¾úºÍÏû¶¾£®³ôÑõºÍÑõÆø×é³ÉÔªËØÏàͬ¶ø»¯Ñ§ÐÔÖʲ»Í¬µÄÔ­ÒòÊÇ
·Ö×Ó¹¹³É²»Í¬
·Ö×Ó¹¹³É²»Í¬
£®
¢ÚClO2£º×ÔÀ´Ë®³§³£ÓÃClO2Ïû¶¾£®ÖÆÈ¡ClO2µÄ·´Ó¦Æä΢¹Û¹ý³ÌÈçͼ2Ëùʾ£¨ÆäÖР±íʾÂÈÔ­×Ó£¬ ±íʾÄÆÔ­×Ó£¬±íʾÑõÔ­×Ó£©£®Çëд³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ
Cl2+2NaClO2¨T2ClO2+2NaCl
Cl2+2NaClO2¨T2ClO2+2NaCl
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

Ë®ÊÇÈËÀàÉú»îÖв»¿ÉȱÉÙµÄÎïÖÊ£®

£¨1£©È¥Ä궬ÌìÖÁ½ñÄê´ºÌ죬ÎÒ¹úÎ÷ÄϵØÇøÔâÓö´ó·¶Î§³ÖÐø¸Éºµ£®ÓÐЩ´åׯ´òÉȡÓõØÏÂË®£®¼ìÑéµØÏÂË®ÊÇӲˮ»¹ÊÇÈíË®£¬¿ÉÓõÄÎïÖÊÊÇ
·ÊÔíË®
·ÊÔíË®
£¬²â¶¨µØÏÂË®µÄËá¼î¶È¿ÉÓÃ
pHÊÔÖ½»òpH¼Æ
pHÊÔÖ½»òpH¼Æ
£®
£¨2£©ÓÐЩ´åÃñÈ¡»ë×ǵĿÓË®×÷Éú»îÓÃË®£®ÓÐͬѧÀûÓÃËùѧµÄ֪ʶ»ë×ǵĿÓË®ÓÃͼËùʾµÄ¼òÒ×¾»Ë®Æ÷½øÐо»»¯£¬ÆäÖÐСÂÑʯ¡¢Ê¯Ó¢É³µÄ×÷ÓÃÊÇ
¹ýÂË
¹ýÂË
£»»îÐÔÌ¿µÄ×÷ÓÃÊÇ
Îü¸½
Îü¸½
£®
£¨3£©Èç¹ûµØÏÂˮӲ¶È´ó£¬»òÕß¿ÓË®Öв¡Ô­Î¢ÉúÎï¹ý¶à£¬¶¼¿ÉÒÔ²ÉÈ¡
Öó·Ð
Öó·Ð
·½·¨£¬À´½µµÍÓ²¶ÈºÍɱÃð²¡Ô­Î¢ÉúÎ
£¨4£©ÏÂÁÐÎïÖʶ¼¿ÉÓÃÓÚË®Öʵľ»»¯»òɱ¾úÏû¶¾£®
¢Ù³ôÑõ£¨»¯Ñ§Ê½O3£©£ºÓÐÇ¿Ñõ»¯ÐÔ£¬¿ÉÓÃÓÚÓÎÓ¾³Ø¡¢Éú»îÓÃË®¡¢ÎÛË®µÄɱ¾úºÍÏû¶¾£®³ôÑõºÍÑõÆø×é³ÉÔªËØÏàͬ¶ø»¯Ñ§ÐÔÖʲ»Í¬µÄÔ­ÒòÊÇ
·Ö×Ó²»Í¬
·Ö×Ó²»Í¬
£®
¢ÚƯ°×·Û£º¿ÉÓÃÓÚË®µÄɱ¾úÏû¶¾£¬ÆäÓÐЧ³É·ÖÊÇ´ÎÂÈËá¸Æ[»¯Ñ§Ê½ÎªCa£¨ClO£©2]£®´ÎÂÈËá¸Æ¿É·¢ÉúÈçÏ·´Ó¦£ºCa£¨ClO£©2+X+H2O=CaCO3+2HClO£¬ÔòXµÄ»¯Ñ§Ê½Îª
CO2
CO2
£®
¢ÛClO2£º×ÔÀ´Ë®³§³£ÓÃClO2Ïû¶¾£®ÖÆÈ¡ClO2µÄ·´Ó¦Æä΢¹Û¹ý³ÌÈçͼËùʾ£¨ÆäÖР±íʾÂÈÔ­×Ó£¬ ±íʾÄÆÔ­×Ó£¬ ±íʾÑõÔ­×Ó£©£®Çëд³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ
Cl2+2NaClO2¨T2ClO2+2NaCl
Cl2+2NaClO2¨T2ClO2+2NaCl
£®
£¨5£©²úÎïÖÐÓÐË®Éú³ÉµÄ·´Ó¦ºÜ¶à£¨ÈçͼËùʾ£©£¬Çë°´ÒªÇóд³öÒ»¸ö»¯Ñ§·½³Ìʽ£®
¢Ù²úÎïÖÐÓÐË®Éú³ÉµÄ»¯ºÏ·´Ó¦£º
2H2+O2
 µãȼ 
.
 
2H2O
2H2+O2
 µãȼ 
.
 
2H2O
£»
¢Ú²úÎïÖÐÓÐË®Éú³ÉµÄ¸´·Ö½â·´Ó¦£º
NaOH+HCl¨TNaCl+H2O
NaOH+HCl¨TNaCl+H2O
£»
¢Û²úÎïÖÐÓÐË®Éú³ÉµÄÆäËû·´Ó¦£º
CO2+Ca£¨OH£©2¨TCaCO3¡ý+H2O
CO2+Ca£¨OH£©2¨TCaCO3¡ý+H2O
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

È¥Ä궬ÌìºÍ½ñ´ºÎÒ¹úÎ÷±±¡¢»ª±±¡¢Î÷ÄϺܶàÊ¡ÇøÔâÊÜ°ÙÄê²»ÓöµÄÌØ´ó¸Éºµ£®Ò»Ð©ÔÖÇøȺÖÚÓÃË®¼«ÆäÀ§ÄÑ£¬ËûÃÇÔÚÕþ¸®µÄ°ïÖúÏ£¬¶à·½Ñ°ÕÒˮԴ£®
£¨1£©½«»ë×ǵÄË®±ä³ÎÇåµÄ¼òµ¥·½·¨ÊÇ
¹ýÂË£¨ºÏÀí¾ù¿É£©
¹ýÂË£¨ºÏÀí¾ù¿É£©
£®½«³ÎÇåºóµÄË®Öó·Ð£¬ÈôË®ÖгöÏֽ϶àË®¹¸£¬¸ÃˮΪ
Ӳˮ
Ӳˮ
£¨Ñ¡ÌӲˮ¡±»ò¡°ÈíË®¡±£©£®
£¨2£©½ñÄêÎÒÊмӴó¶Ô±¾µØÇøË®ÖʵÄÕûÖÎÁ¦¶È£¬ÇëÄã˵³öÔì³ÉË®ÖÊÎÛȾµÄÔ­ÒòÖ®Ò»ÊÇ
¹¤Òµ¡°Èý·Ï¡±µÄÈÎÒâÅÅ·Å
¹¤Òµ¡°Èý·Ï¡±µÄÈÎÒâÅÅ·Å

Å©ÒµÉÏ»¯·Ê¡¢Å©Ò©µÄ¹ýÁ¿Ê¹Ó㨺ÏÀí¾ù¿É£©
Å©ÒµÉÏ»¯·Ê¡¢Å©Ò©µÄ¹ýÁ¿Ê¹Ó㨺ÏÀí¾ù¿É£©
£®
£¨3£©È«ÇòÆøºò±äů»áµ¼Ö¸ɺµ¡¢ºéÀÔµÈÔÖº¦µÄƵ·¢£®Ãæ¶ÔÈ«ÇòÆøºò±äůµÄÑϾþÌôÕ½£¬¸÷¹ú¶¼Ó¦²ÉÈ¡µÄ´ëÊ©ÓÐ
´óÁ¦¿ª·¢ºÍʹÓÃÐÂÄÜÔ´£¨ºÏÀí¾ù¿É£©£¨
´óÁ¦¿ª·¢ºÍʹÓÃÐÂÄÜÔ´£¨ºÏÀí¾ù¿É£©£¨
£¨Ð´Ò»Ìõ¼´¿É£©£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸