£¨2011?ÑïÖÝ£©´Ö»¹ÔÌú·ÛÊÇÒ»ÖÖÖØÒªµÄ»¯¹¤ÔÁÏ£¬Ä³ÐËȤС×é¶ÔÆä½øÐÐÏÂÁÐÑо¿£º
[ÎïÖÊÖƱ¸]ÀûÓÃÂÌ·¯ÖƱ¸¾«»¹ÔÌú·ÛµÄ¹¤ÒÕÁ÷³ÌÈçÏ£º
´Ö»¹ÔÌú·ÛÖл¹º¬ÓÐÉÙÁ¿ÌúµÄÑõ»¯ÎïºÍFe
3C£¬¿ÉÓÃÇâÆøÔÚ¸ßÎÂϽøÒ»²½»¹Ô£¬Æä·´Ó¦·½³ÌʽΪ£ºFe
xO
Y+yH
2xFe+yH
2O Fe
3C+2H
23Fe+CH
4£¨1£©Ð´³ö±ºÉÕÖÐÑõ»¯ÌúÓëCO·´Ó¦µÄ»¯Ñ§·½³Ìʽ
£®
£¨2£©±ºÉÕÖмӽ¹Ì¿µÄ×÷ÓóýÁË¿ÉÒÔÉú³ÉCOÍ⣬»¹ÄÜ
ÌṩÈÈÁ¿
ÌṩÈÈÁ¿
£®
[º¬Á¿²â¶¨]ΪµÃµ½¾«»¹ÔÌú·Û²¢²â¶¨´Ö»¹ÔÌú·ÛÖÐÑõºÍ̼ԪËصÄÖÊÁ¿·ÖÊý£¬°´ÈçÏÂ×°ÖýøÐÐÊÔÑ飬ÒÑÖª 3CH
4+4Fe
2O
33CO
2+6H
2O+8Fe
£¨¼ÙÉèÿ²½·´Ó¦¶¼ÍêÈ«ÇÒ²»¿¼ÂÇ×°ÖÃÄÚÔÀ´ÓпÕÆø¶Ô²â¶¨½á¹ûµÄÓ°Ï죩£®
£¨3£©Ö÷ҪʵÑé²½ÖèÈçÏ£º
¢Ù°´Ë³Ðò×é×°ÒÇÆ÷£¬¼ì²é×°ÖõÄÆøÃÜÐÔ£¬³ÆÁ¿ÑùÆ·ºÍ±ØҪװÖõÄÖÊÁ¿£»¢ÚµãȼA´¦¾Æ¾«µÆ£»¢Û»º»ºÍ¨Èë´¿¾»¸ÉÔïµÄH
2£»¢ÜµãȼC´¦¾Æ¾«µÆ£»¢Ý·Ö±ðϨµÆA¡¢C´¦¾Æ¾«µÆ£»¢ÞÔÙ»º»ºÍ¨ÈëÉÙÁ¿H
2£»¢ßÔٴγÆÁ¿±ØҪװÖõÄÖÊÁ¿£®
²Ù×÷µÄÏȺó˳ÐòÊÇ¢Ù¢Û
¢Ü¢Ú
¢Ü¢Ú
¢Ý¢Þ¢ß£¨ÌîÐòºÅ£©£»
£¨4£©²½Öè¢ÛµÄÄ¿µÄÊÇ
³ýÈ¥×°ÖÃÄÚµÄÑõÆø£¬·ÀÖ¹·¢Éú±¬Õ¨
³ýÈ¥×°ÖÃÄÚµÄÑõÆø£¬·ÀÖ¹·¢Éú±¬Õ¨
£¬ÑéÖ¤¸Ã²½ÖèÄ¿µÄ´ïµ½µÄʵÑé·½·¨ÊÇ
ÊÕ¼¯Î²Æø¿¿½üȼ×ŵľƾ«µÆ£¬ÌýÉùÒô
ÊÕ¼¯Î²Æø¿¿½üȼ×ŵľƾ«µÆ£¬ÌýÉùÒô
£»²½Öè¢ÞµÄÄ¿µÄÊÇ
·ÀÖ¹Éú³ÉµÄ»¹ÔÌú·ÛÔٴα»Ñõ»¯£¬Æð±£»¤×÷ÓÃ
·ÀÖ¹Éú³ÉµÄ»¹ÔÌú·ÛÔٴα»Ñõ»¯£¬Æð±£»¤×÷ÓÃ
£¨5£©Èô×°ÖÃD¡¢E·Ö±ðÔöÖØmgºÍng£¬ÔòmÓënµÄ¹ØϵΪ
C
C
A.11m=9n B.11m£¼9n C.11m£¾9n
ÈôȱÉÙ×°ÖÃD£¬ÔòËù²âÑõÔªËصÄÖÊÁ¿·ÖÊý½«
µÈÓÚ
µÈÓÚ
£¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°µÈÓÚ¡±£®ÏÂͬ£©£®Ì¼ÔªËصÄÖÊÁ¿·ÖÊý½«
Æ«´ó
Æ«´ó
£®
£¨6£©´Ö»¹ÔÌú·ÛÑùÆ·µÄÖÊÁ¿Îª10.000g£¬×°ÖÃB£¬E·Ö±ðÔöÖØ0.180gºÍ0.220g£®¼ÆËãÑùÆ·ÖÐÑõºÍ̼ԪËصÄÖÊÁ¿·ÖÊý£¨ÒªÇó¼ÆËã¹ý³Ì£©£®