̼Óë̼µÄ»¯ºÏÎïÔÚ¹¤Å©ÒµÉú²ú¼°ÈÕ³£Éú»îÖÐÓй㷺µÄÓÃ;£®
£¨1£©Ì¼Ô×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇ
4
4
£¬Ì¼ÔªËØÔÚÔªËØÖÜÆÚ±íÖÐλÓÚµÚ
2
2
ÖÜÆÚ£®
£¨2£©¹Å´úÓÃÄ«Êéд»ò»æÖƵÄ×Ö»ËäÄê¾ÃÈÔ²»±äÉ«£¬ÔÒòÊÇÄ«ÖÐÖ÷Òª³É·Ö̼ÔÚ³£ÎÂϾßÓÐ
Îȶ¨
Îȶ¨
ÐÔ£®Í¼ÊÇľ̿»¹ÔÑõ»¯ÍµÄʵÑ飬´óÊÔ¹ÜÖеķ´Ó¦ÌåÏÖÁË̼µÄ»¹ÔÐÔ£¬µ¥ÖÊ̼µÄ»¹ÔÐÔ¿ÉÒÔÓÃÓÚÒ±½ð¹¤Òµ£®
¢Ù¾Æ¾«µÆ¼ÓµÆÕÖµÄÄ¿µÄ£º
Ìá¸ß»ðÑæµÄζÈ
Ìá¸ß»ðÑæµÄζÈ
£»
¢Ú¸Õ¿ªÊ¼Ô¤ÈÈ£¬ÊԹܢÚÖÐÁ¢¼´²úÉúÆøÅÝ£¬µ«Ê¯»ÒË®²»±ä»ë×Ç£¬ÔÒòÊÇ
¸Õ¿ªÊ¼ÅųöµÄÆøÌåÊÇ×°ÖÃÄڵĿÕÆø
¸Õ¿ªÊ¼ÅųöµÄÆøÌåÊÇ×°ÖÃÄڵĿÕÆø
£»
¢Û¼ÌÐø¼ÓÈÈ£¬¹Û²ìµ½Ê¯»ÒË®Öð½¥±ä»ë×Ç£¬ºÚÉ«·ÛÄ©ÖгöÏÖºìÉ«ÎïÖÊ£®ÇëÄãд³ö´øµã²¿·ÖµÄ»¯Ñ§·½³Ìʽ£º
C+2CuO
2Cu+CO
2¡ü£»CO
2+Ca£¨OH£©
2¨TCaCO
3¡ý+H
2O
C+2CuO
2Cu+CO
2¡ü£»CO
2+Ca£¨OH£©
2¨TCaCO
3¡ý+H
2O
£®
¢ÜÍ£Ö¹¼ÓÈÈʱ£¬Ó¦ÏȽ«µ¼¹Ü´ÓÊԹܢÚÖг·³ö£¬´ýÊԹܢÙÀäÈ´ºóÔÙ°ÑÊÔ¹ÜÀïµÄ·ÛÄ©µ¹³ö£®ÕâÑù²Ù×÷µÄÔÒòÊÇA
·ÀÖ¹µ¹ÎüÏÖÏó
·ÀÖ¹µ¹ÎüÏÖÏó
£»B
·ÀÖ¹×ÆÈȵÄͱ»Ñõ»¯
·ÀÖ¹×ÆÈȵÄͱ»Ñõ»¯
£®
£¨3£©¶þÑõ»¯Ì¼ÄܲÎÓë¹âºÏ×÷ÓÃÍê³É´óÆøÖеġ°Ì¼Ñ»·¡±£¬µ«ÊÇ´óÆøÖжþÑõ»¯Ì¼µÄº¬Á¿²»¶ÏÉÏÉý£¬»áʹȫÇò±äů£¬´Ó¶øµ¼ÖÂ
ÎÂÊÒЧӦ
ÎÂÊÒЧӦ
£®Ê߲˴óÅïÓÃ×÷Æø·ÊµÄ¶þÑõ»¯Ì¼£¬¿ÉÓöàÖÖ·½·¨ÖƵã¬ÀýÈç¿ÉÒÔÓÃÏ¡ÁòËáÓë̼ËáÇâ泥¨NH
4HCO
3£©·´Ó¦ÖƵ㬷´Ó¦ºóÉú³ÉÁòËá李¢Ë®ºÍ¶þÑõ»¯Ì¼£¬ÕâÒ»·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ
2NH4HCO3+H2SO4¨T£¨NH4£©2SO4+2H2O+2CO2¡ü
2NH4HCO3+H2SO4¨T£¨NH4£©2SO4+2H2O+2CO2¡ü
£®