ij°àͬѧÔÚʵÑéÊÒ½øÐÐÁË¡°ËáµÄÐÔÖÊ¡±ÊµÑ飬ʹÓùýµÄÊÔ¼ÁÓУº
¢ÙÌúм ¢ÚÑõ»¯Ìú ¢ÛÑÎËá ¢ÜÇâÑõ»¯ÄÆÈÜÒº ¢Ý̼ËáÄÆÈÜÒº
£¨1£© ʵÑé½áÊø£¬ËûÃǽ«·ÏҺȫ²¿·ÏÒºµ¹Èë·ÏÒº¸×¡£ÎªÁËʹ·ÏÒºÄÜÎÞº¦ÅÅ·Å£¬ÐèÒªÓÃ____________²â¶¨·ÏÒºµÄËá¼î¶È£¬²â¶¨·ÏÒºµÄpH=1£¬·ÏÒº³Ê______ÐÔ¡£
£¨2£© ÒÔÉÏÌṩµÄ5ÖÖÊÔ¼ÁÔÚ·ÏÒºÖв»¿ÉÄÜÓеÄÊÇ_______£¨ ÌîÐòºÅ£©£¬ÄãÑ¡ÔñµÄÀíÓÉÊÇ£¨ÈÎÑ¡Á½ÖÖ£¬Óû¯Ñ§·½³Ìʽ˵Ã÷£©_______________£¬______________________¡£·ÏÒºÖеÄÈÜÖÊ×î¶à¿ÉÄÜÓÐ______ÖÖ¡£
£¨1£©pHÊÔÖ½£»Ëá
£¨2£©¢Ù¢Ú¢Ü¢Ý£»Na2CO3+2HCl==2NaCl+H2O+CO2¡ü¡¢Fe2O3+6HCl==2FeCl3+3H2O¡¢HCl+NaOH==NaCl+H2O¡¢Fe+2HCl==FeCl2+H2¡ü£¨ÈÎÑ¡Á½¸ö£©£»4
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

34¡¢Ä³°àͬѧÔÚʵÑéÊÒ½øÐÐÁË¡°ËáµÄÐÔÖÊ¡±ÊµÑ飬ʹÓõÄÎïÖÊÓУº¢ÙÌúм¡¢¢ÚÑõ»¯Ìú¡¢¢ÛÑÎËá¡¢¢ÜÇâÑõ»¯ÄÆÈÜÒº¡¢¢Ý̼ËáÄÆÈÜÒº£®
£¨1£©ÊµÑé½áÊø£¬ËûÃǽ«·ÏҺȫ²¿µ¹Èë·ÏÒº¸×£®¼ì²â·ÏÒºµÄpH=1£¬Ôò·ÏÒº³Ê
Ëá
ÐÔ£®
£¨2£©ÒÔÉÏÌṩµÄ5ÖÖÎïÖÊÔÚ·ÏÒºÖв»¿ÉÄÜÓеÄÊÇ
¢Ù¢Ú¢Ü¢Ý
£¨ÌîÐòºÅ£©£¬ÄãÑ¡ÔñµÄÀíÓÉÊÇ£¨ÈÎÑ¡Á½ÖÖ£¬Óû¯Ñ§·½³Ìʽ˵Ã÷£©
Na2CO3+2HCl¨T2NaCl+H2O+CO2¡ü
£¬
Fe2O3+6HCl¨T2FeCl3+3H2O
£®·ÏÒºÖеÄÈÜÖÊ¿ÉÄÜÓÐ
FeCl2¡¢FeCl3¡¢NaCl¡¢HCl
£¨ÌîÎïÖʵĻ¯Ñ§Ê½£©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2007?Ì«Ô­£©Ä³°àͬѧÔÚʵÑéÊÒ½øÐÐÁË¡°ËáµÄÐÔÖÊ¡±ÊµÑ飬ʹÓùýµÄÊÔ¼ÁÓУº¢ÙÌúм¢ÚÑõ»¯Ìú¢ÛÑÎËá¢ÜÇâÑõ»¯ÄÆÈÜÒº¢Ý̼ËáÄÆÈÜÒº£®
£¨1£©ÊµÑé½áÊø£¬ËûÃǽ«·ÏҺȫ²¿·ÏÒºµ¹Èë·ÏÒº¸×£®ÎªÁËʹ·ÏÒºÄÜÎÞº¦ÅÅ·Å£¬ÐèÒªÓÃ
pHÊÔÖ½
pHÊÔÖ½
²â¶¨·ÏÒºµÄËá¼î¶È£¬²â¶¨·ÏÒºµÄpH=1£¬·ÏÒº³Ê
Ëá
Ëá
ÐÔ£®
£¨2£©ÒÔÉÏÌṩµÄ5ÖÖÊÔ¼ÁÔÚ·ÏÒºÖв»¿ÉÄÜÓеÄÊÇ
¢Ù¢Ú¢Ü¢Ý
¢Ù¢Ú¢Ü¢Ý
£¨ ÌîÐòºÅ£©£¬ÄãÑ¡ÔñµÄÀíÓÉÊÇ£¨ÈÎÑ¡Á½ÖÖ£¬Óû¯Ñ§·½³Ìʽ˵Ã÷£©
Na2CO3+2HCl¨T2NaCl+H2O+CO2¡ü
Na2CO3+2HCl¨T2NaCl+H2O+CO2¡ü
£¬
Fe2O3+6HCl¨T2FeCl3+3H2O
Fe2O3+6HCl¨T2FeCl3+3H2O
£®·ÏÒºÖеÄÈÜÖÊ×î¶à¿ÉÄÜÓÐ
4
4
ÖÖ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

10¡¢Ä³°àͬѧÔÚʵÑéÊÒ½øÐÐÁË¡°ËáµÄÐÔÖÊ¡±ÊµÑ飬ʹÓùýµÄÊÔ¼ÁÓУº¢ÙÌúм£¬¢ÚÑõ»¯Ìú£¬¢ÛÏ¡ÁòËᣬ¢ÜÇâÑõ»¯ÄÆÈÜÒº£¬¢Ý̼ËáÄÆÈÜÒº£®ÊµÑé½áÊø£¬ËûÃǽ«·ÏҺȫ²¿µ¹Èë·ÏÒº¸×£¬²âµÃ·ÏÒºµÄpH=1£®Ôò·ÏÒºÖÐÈÜÖʵÄÖÖÀà×î¶à¿ÉÄÜÓУ¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ij°àͬѧÔÚʵÑéÊÒ½øÐÐÖÆÈ¡¶þÑõ»¯Ì¼ÆøÌåµÄʵÑ飮¿É¹©Ñ¡ÔñµÄʵÑé×°ÖÃÈçÏÂ
¢ÙÒÇÆ÷aºÍbµÄÃû³Æ£ºa
Ìú¼Ų̈
Ìú¼Ų̈
£¬b
³¤¾±Â©¶·
³¤¾±Â©¶·
£®
¢ÚÓÃÆôÆÕ·¢ÉúÆ÷ÖÆÈ¡¶þÑõ»¯Ì¼ÆøÌ壬·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ
CaCO3+2HCl¨TCaCl2+CO2¡ü+H2O
CaCO3+2HCl¨TCaCl2+CO2¡ü+H2O
£®
¢ÛB×°ÖþßÓÐÆôÆÕ·¢ÉúÆ÷Ë濪ËæÓá¢Ëæ¹ØËæÍ£µÄÓŵ㣬±¾ÊµÑéÖжà¿×ɸÍøµÄ²ÄÁÏÒ»¶¨²»ÄÜÊÇ
C
C
£¬ÀíÓÉÊÇ
ÌúÓëÑÎËá·´Ó¦Éú³ÉÇâÆø£¬Ê¹ÖƵõĶþÑõ»¯Ì¼ÆøÌå²»´¿
ÌúÓëÑÎËá·´Ó¦Éú³ÉÇâÆø£¬Ê¹ÖƵõĶþÑõ»¯Ì¼ÆøÌå²»´¿
£®
A¡¢ËÜÁÏ          B¡¢²£Á§         C¡¢Ìú         D¡¢Í­£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ij°àͬѧÔÚʵÑéÊÒ½øÐÐÁË¡°ËáµÄÐÔÖÊ¡±ÊµÑ飬ÓÃÑÎËá·Ö±ðÓëFe¡¢NaOHÈÜÒº·´Ó¦Ì½¾¿¡°ËáµÄÐÔÖÊ¡±£®
£¨1£©ÊµÑé½áÊø£¬ËûÃǽ«·ÏҺȫ²¿µ¹Èë·ÏÒº¸×£®ÎªÁËʹ·ÏÒºÄÜÎÞº¦ÅÅ·Å£¬ÐèÒªÓÃ
 
²â¶¨·ÏÒºµÄËá¼î¶È£¬²âµÃ·ÏÒºµÄpH=1£¬·ÏÒº³Ê
 
ÐÔ£¬ÔÚ·ÏÒºÖеÎÈë×ÏɫʯÈïÊÔÒº³Ê
 
É«£®
£¨2£©ÒÔÉÏÌṩµÄ3ÖÖÎïÖÊÔÚ·ÏÒºÖв»¿ÉÄÜÓеÄÊÇ
 
£¨Ìѧʽ£©ÀíÓÉÊÇ
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸