½â£º£¨1£©¸Ã·´Ó¦¿ÉÉú³É¶þÑõ»¯Ì¼ÆøÌ壬Ϊ¼ìÑé¶þÑõ»¯Ì¼ÆøÌåµÄ´æÔÚ£¬ËùÒÔBÖеÄÊÔ¼ÁÊdzÎÇåʯ»ÒË®£®¹Ê´ð°¸Îª£º³ÎÇåʯ»ÒË®£»
£¨2£©ÔÚ¸ßÎÂÌõ¼þÏ£¬Ì¿»áÓë¶þÑõ»¯Ì¼·´Ó¦£¬Éú³ÉÒ»Ñõ»¯Ì¼£®ËùÒÔÒ»¶¨ÓÐCO£»ÍøÕֿɼ¯ÖлðÑ棬¼¯ÖеĻðÑæ¿ÉÒÔʹζȸü¸ß£®¹Ê´ð°¸Îª£ºCO¡¢ÐγɸßÎÂÌõ¼þ£»
£¨3£©·´Ó¦ÎïÊÇÌ¿ºÍÑõ»¯Í£¬·´Ó¦Ìõ¼þÊǸßÎÂд³ö»¯Ñ§·´Ó¦Ê½£ºC+2CuO
2Cu+CO
2¡ü£®
¹Ê´ð°¸Îª£ºC+2CuO
2Cu+CO
2¡ü£»
£¨4£©Éú³ÉµÄ¶þÑõ»¯Ì¼µÄÁ¿£º42-37.6=4.4g
É裺²úÉú4.4g¶þÑõ»¯Ì¼ÐèÒªÑõ»¯ÍXg
C+2CuO
2Cu+CO
2¡ü
160 44
X 4.4
=
X=16g
´ð£ºÓÐ16¿ËÑõ»¯Í²Î¼ÓÁË·´Ó¦£®
·ÖÎö£º£¨1£©¸ù¾Ý¸Ã·´Ó¦¿ÉÉú³É¶þÑõ»¯Ì¼ÆøÌ忼ÂÇ£¬BÖÐÊÔ¼ÁµÄÃû³Æ£»
£¨2£©Ì¿»áÓë¶þÑõ»¯Ì¼·´Ó¦£¬Éú³ÉÒ»Ñõ»¯Ì¼£»´ÓÍøÕֿɼ¯ÖлðÑ濼ÂÇ£»
£¨3£©¸ù¾Ý·´Ó¦ÎïºÍ·´Ó¦Ìõ¼þд³ö»¯Ñ§·´Ó¦Ê½£»
£¨4£©¸ù¾ÝÌ¿»¹ÔÑõ»¯ÍµÄ»¯Ñ§·´Ó¦Ê½ºÍ±í¸ñÖеÄÏà¹ØÊý¾Ý¼ÆËã¼´¿É£®
µãÆÀ£º±¾Ì⿼²é»¯Ñ§·´Ó¦Ê½µÄÊéдºÍÏà¹Ø¼ÆË㣬ËäÊôÓÚ»ù´¡ÖªÊ¶£¬µ«Í¬Ñ§ÃÇÒª¶ÔÌ¿µÄ»¯Ñ§ÐÔÖÊÓнÏΪϵͳµÄÁ˽â²Å¿É×öºÃ´ËÌ⣮