ijͬѧÔÚѧϰ·Ö×ÓÓйØÐÔÖʺ󣬽øÐÐÈçÏÂʵÑ飺
¢Ù°Ñ200mLµÄË®Óë100mLµÄÒÒ´¼»ìºÏ£»¢ÚÏò»ìºÏºóµÄÈÜÒºÖмÓÈ뼸µÎºìīˮ£»
ÇëÄã¸ù¾ÝËùѧ·Ö×ÓµÄÓйØÖªÊ¶£¬Ô¤²â¡¢Íƶϲ¢»Ø´ðÓйØÎÊÌ⣺
£¨1£©»ìºÏºóµÄÈÜÒºÖУ¬ÏÂÁйØÏµ³ÉÁ¢µÄÊÇ£¨m-ÒºÌåµÄÖÊÁ¿¡¢V-ÒºÌåµÄÌå»ý¡¢¦Ñ-ÒºÌåµÄÃܶȣ©£º______£¨ÌîÐòºÅ£©£®
¢Ù»ìºÏºóÈÜÒºµÄÖÊÁ¿£ºm»ì=mË®+mÒÒ´¼£»¡¡
¢Ú»ìºÏºóÈÜÒºµÄÌå»ý£ºV»ì=VË®+VÒÒ´¼£»
¢Û»ìºÏºóµÄÃܶȣº¦Ñ»ì=Êýѧ¹«Ê½£¨¦ÑË®+¦ÑÒÒ´¼£©£®
£¨2£©È¡ÓÃÒÒ´¼Ê±£¬Îŵ½ÒÒ´¼µÄÏãζ£¬ËµÃ÷·Ö×Ó______£®ÊµÑéÖÐ______µÄÏÖÏóÒ²¿ÉÖ¤Ã÷·Ö×ÓµÄÕâÖÖÐÔÖÊ£®

½â£º£¨1£©ÒÒ´¼ºÍË®¶¼ÊÇÓÉ·Ö×Ó¹¹³ÉµÄÎïÖÊ£¬¹¹³ÉËüÃǵÄ΢Á£Ö®¼ä¶¼´æÔÚÒ»¶¨µÄ¼ä¸ô£®°ÑËüÃÇ»ìºÏʱÁ½ÖÖ·Ö×Ó»áÏ໥´©²åÉøÍ¸£¬µ¼ÖÂ×ÜÌå»ýСÓÚ¶þÕßÌå»ýÖ®ºÍ£®µ«×ÜÖÊÁ¿²»±ä£¬Óɹ«Ê½m=¦Ñv¿ÉÖª£¬»ìºÏºóµÄÃܶÈÒª±ÈÈÎÒ»³É·ÖµÄÃܶȶ¼´ó£¬¶ø²»ÊǶþÕßµÄÃÜ¶ÈÆ½¾ùÖµ£®
¹Ê´ð°¸Îª£º¢Ù£®
£¨2£©ÒÒ´¼ÊÇÒ»ÖÖ¾ßÓÐÌØÊâÏãζµÄÒºÌ壬ÎÒÃÇÄÜÎŵ½ÕâÖÖÆøÎ¶£¬ËµÃ÷ÁË·Ö×ÓÔÚ²»¶ÏµØÔ˶¯£®ÊµÑéÖкìīˮ»áÏòË®ÖÐÀ©É¢µÄÏÖÏóÒ²ÄÜ˵Ã÷·Ö×ÓÔÚ²»¶ÏµØÔ˶¯£®
¹Ê´ð°¸Îª£ºÔÚ²»¶ÏµØÔ˶¯£»ºìīˮÏòË®ÖÐËÄ´¦À©É¢£®
·ÖÎö£º£¨1£©¹¹³ÉÎïÖʵÄ΢Á£Ö®¼ä¶¼ÓÐÒ»¶¨µÄ¿Õ϶£¬Òò´Ëµ±»ìºÏºó×ÜÌå»ý»á¼õС¡¢ÖÊÁ¿²»±ä¡¢ÃܶȻáÔö´ó£»
£¨2£©¹¹³ÉÎïÖʵÄ΢Á£ÊÇÔÚ²»Í£µØÔ˶¯µÄ£¬Éú»îÖеÄÐí¶àÏÖÏó¶¼ÄÜ˵Ã÷ÕâÒ»»ù±¾ÌØÕ÷£®
µãÆÀ£º±¾ÌâÖ÷Ҫͨ¹ýÑéÖ¤·Ö×ÓÖ®¼ä´æÔÚÒ»¶¨¼ä¸ôµÄʵÑé˵Ã÷ÁË΢Á£Ëù¾ßÓеĻù±¾ÌØÕ÷£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍøÄ³Í¬Ñ§ÔÚѧϰ·Ö×ÓÓйØÐÔÖʺ󣬽øÐÐÈçÏÂʵÑ飺
¢Ù°Ñ200mLµÄË®Óë100mLµÄÒÒ´¼»ìºÏ£»¢ÚÏò»ìºÏºóµÄÈÜÒºÖмÓÈ뼸µÎºìīˮ£»
ÇëÄã¸ù¾ÝËùѧ·Ö×ÓµÄÓйØÖªÊ¶£¬Ô¤²â¡¢Íƶϲ¢»Ø´ðÓйØÎÊÌ⣺
£¨1£©»ìºÏºóµÄÈÜÒºÖУ¬ÏÂÁйØÏµ³ÉÁ¢µÄÊÇ£¨m-ÒºÌåµÄÖÊÁ¿¡¢V-ÒºÌåµÄÌå»ý¡¢¦Ñ-ÒºÌåµÄÃܶȣ©£º
 
£¨ÌîÐòºÅ£©£®
¢Ù»ìºÏºóÈÜÒºµÄÖÊÁ¿£ºm»ì=mË®+mÒÒ´¼£»   
¢Ú»ìºÏºóÈÜÒºµÄÌå»ý£ºV»ì=VË®+VÒÒ´¼£»
¢Û»ìºÏºóµÄÃܶȣº¦Ñ»ì=
12
£¨¦ÑË®+¦ÑÒÒ´¼£©£®
£¨2£©È¡ÓÃÒÒ´¼Ê±£¬Îŵ½ÒÒ´¼µÄÏãζ£¬ËµÃ÷·Ö×Ó
 
£®ÊµÑéÖÐ
 
µÄÏÖÏóÒ²¿ÉÖ¤Ã÷·Ö×ÓµÄÕâÖÖÐÔÖÊ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

£¨2008?ÐûÎäÇø¶þÄ££©Ä³Ñо¿ÐÔѧϰС×éµÄͬѧÔÚѧϰÁ˶þÑõ»¯Ì¼µÄÓйØÖªÊ¶ºó£¬ÓÖ²éÔÄÏà¹Ø×ÊÁÏ£¬¶Ô¶þÑõ»¯Ì¼ÖªÊ¶½øÐÐÊáÀí£®
£¨1£©ÈçͼËùʾµÄÊÇÓйضþÑõ»¯Ì¼ÐÔÖʵÄʵÑ飮

ÏÖÏó ½áÂÛ£¨½áºÏÎÄ×ֺͻ¯Ñ§·½³Ìʽ£©
A
Ã°ÆøÅÝ£¬À¯Öò´ÓÏÂÖÁÉÏϨÃð
Ã°ÆøÅÝ£¬À¯Öò´ÓÏÂÖÁÉÏϨÃð
Na2CO3+2HCl¨T2NaCl+CO2¡ü+H2O
CO2±È¿ÕÆøÃܶȴ󣬲»Ö§³ÖȼÉÕ£¬Ò²²»È¼ÉÕ
Na2CO3+2HCl¨T2NaCl+CO2¡ü+H2O
CO2±È¿ÕÆøÃܶȴ󣬲»Ö§³ÖȼÉÕ£¬Ò²²»È¼ÉÕ
B
ÈÜÒº±ä»ë×Ç£¬Æ¿×Ó±ä±ñ
ÈÜÒº±ä»ë×Ç£¬Æ¿×Ó±ä±ñ
Ca£¨OH£©2+CO2¨TCaCO3¡ý+H2O
CO2¼õÉÙ£¬Æ¿ÄÚѹǿСÓÚÍâ½ç´óÆøÑ¹
Ca£¨OH£©2+CO2¨TCaCO3¡ý+H2O
CO2¼õÉÙ£¬Æ¿ÄÚѹǿСÓÚÍâ½ç´óÆøÑ¹
C
ÈÜÒº±äºì£¬Ã°ÆøÅÝ
ÈÜÒº±äºì£¬Ã°ÆøÅÝ
CO2+H2O¨TH2CO3
H2CO3ÊÇËᣬ¿Éʹָʾ¼Á±äÉ«
CO2+H2O¨TH2CO3
H2CO3ÊÇËᣬ¿Éʹָʾ¼Á±äÉ«
£¨2£©ÓÉÓÚÈËÀàÏûºÄµÄÄÜÔ´¼±¾çÔö¼Ó£¬É­ÁÖÔâµ½ÆÆ»µ£¬´óÆøÖÐCO2µÄº¬Á¿ÉÏÉý£¬Ôì³ÉÎÂÊÒЧӦ£¬ÓÐÈ˽¨Òé¶àÖ²Ê÷ÔìÁÖÒÔ¼õÉÙCO2µÄº¬Á¿£¬ÆäÔ­ÀíÊÇ£º6CO2+6H2O
¹â
Ò¶ÂÌËØ
C6H12O6+6O2£¬ÔòC6H12O6ÖÐÌ¼ÔªËØµÄÖÊÁ¿·ÖÊýÊÇ
40%
40%
£®
»¯Ñ§¼ÒÒ²ÖÂÁ¦ÓÚCO2µÄ¡°×éºÏת»¯¡±¼¼ÊõÑо¿£¬°Ñ¹ý¶àµÄCO2ת»¯ÎªÓÐÒæÓÚÈËÀàµÄÎïÖÊ£®È罫CO2ÓëH2»ìºÏ£¬ÔÚÒ»¶¨Ìõ¼þϰ´·Ö×Ó¸öÊý±ÈΪ1£º4µÄ±ÈÀý·¢Éú·´Ó¦£¬Éú³ÉijÖÖÖØÒªµÄ»¯¹¤Ô­ÁϺÍË®£®¸Ã»¯¹¤Ô­ÁÏÊÇ
CH4
CH4
£®Ð´³ö¸Ã»¯¹¤Ô­ÁϵÄÓÃ;£¨Óû¯Ñ§·½³Ìʽ±íʾ£©
CH4+2O2
 µãȼ 
.
 
CO2+2H2O
CH4+2O2
 µãȼ 
.
 
CO2+2H2O
£®
£¨3£©½«¶þÑõ»¯Ì¼Í¨Èë³ÎÇåʯ»ÒË®ÖУ¬Óа×É«³ÁµíÉú³É£¬Èô¼ÌÐøÍ¨Èë¶þÑõ»¯Ì¼£¬°×É«³Áµí½«ÍêÈ«Èܽ⣮Æä·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
¢ÙCa£¨OH£©2+CO2¨TCaCO3¡ý+H2O¡¢¢ÚCaCO3+CO2+H2O¨TCa£¨HCO3£©2£¬µ±¶þÑõ»¯Ì¼³ÖÐø²»¶ÏµØÍ¨Èë³ÎÇåʯ»ÒË®ÖÐʱ£¬³ÁµíÖÊÁ¿µÄ±ä»¯·ûºÏÏÂÁÐͼÖеÄ
B
B
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£ºÉ½¶«Ê¡Öп¼ÕæÌâ ÌâÐÍ£ºÌî¿ÕÌâ

ijͬѧÔÚѧϰ·Ö×ÓÓйØÐÔÖʺ󣬽øÐÐÈçÏÂʵÑ飺
¢Ù°Ñ200mLµÄË®Óë100mLµÄÒÒ´¼»ìºÏ£»
¢ÚÏò»ìºÏºóµÄÈÜÒºÖмÓÈ뼸µÎºìīˮ£»

ÇëÄã¸ù¾ÝËùѧ·Ö×ÓµÄÓйØÖªÊ¶£¬Ô¤²â¡¢Íƶϲ¢»Ø´ðÓйØÎÊÌ⣺
£¨1£©»ìºÏºóµÄÈÜÒºÖУ¬ÏÂÁйØÏµ³ÉÁ¢µÄÊÇ£¨m-ÒºÌåµÄÖÊÁ¿¡¢V-ÒºÌåµÄÌå»ý¡¢¦Ñ-ÒºÌåµÄÃܶȣ©£º________£¨ÌîÐòºÅ£©¡£
¢Ù»ìºÏºóÈÜÒºµÄÖÊÁ¿£ºm»ì£½mË®+mÒÒ´¼£»
¢Ú»ìºÏºóÈÜÒºµÄÌå»ý£ºV»ì£½VË®+VÒÒ´¼£»
¢Û»ìºÏºóµÄÃܶȣº¦Ñ»ì£½£¨¦ÑË® +¦ÑÒÒ´¼£©/2¡£
£¨2£©È¡ÓÃÒÒ´¼Ê±£¬Îŵ½ÒÒ´¼µÄÏãζ£¬ËµÃ÷·Ö×Ó_______________¡£ÊµÑéÖÐ_____________µÄÏÖÏóÒ²¿ÉÖ¤Ã÷·Ö×ÓµÄÕâÖÖÐÔÖÊ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2010Äêɽ¶«Ê¡µÂÖÝÊÐÖп¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

£¨2010?µÂÖÝ£©Ä³Í¬Ñ§ÔÚѧϰ·Ö×ÓÓйØÐÔÖʺ󣬽øÐÐÈçÏÂʵÑ飺
¢Ù°Ñ200mLµÄË®Óë100mLµÄÒÒ´¼»ìºÏ£»¢ÚÏò»ìºÏºóµÄÈÜÒºÖмÓÈ뼸µÎºìīˮ£»
ÇëÄã¸ù¾ÝËùѧ·Ö×ÓµÄÓйØÖªÊ¶£¬Ô¤²â¡¢Íƶϲ¢»Ø´ðÓйØÎÊÌ⣺
£¨1£©»ìºÏºóµÄÈÜÒºÖУ¬ÏÂÁйØÏµ³ÉÁ¢µÄÊÇ£¨m-ÒºÌåµÄÖÊÁ¿¡¢V-ÒºÌåµÄÌå»ý¡¢¦Ñ-ÒºÌåµÄÃܶȣ©£º______£¨ÌîÐòºÅ£©£®
¢Ù»ìºÏºóÈÜÒºµÄÖÊÁ¿£ºm»ì=mË®+mÒÒ´¼£»   
¢Ú»ìºÏºóÈÜÒºµÄÌå»ý£ºV»ì=VË®+VÒÒ´¼£»
¢Û»ìºÏºóµÄÃܶȣº¦Ñ»ì=£¨¦ÑË®+¦ÑÒÒ´¼£©£®
£¨2£©È¡ÓÃÒÒ´¼Ê±£¬Îŵ½ÒÒ´¼µÄÏãζ£¬ËµÃ÷·Ö×Ó______£®ÊµÑéÖÐ______µÄÏÖÏóÒ²¿ÉÖ¤Ã÷·Ö×ÓµÄÕâÖÖÐÔÖÊ£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸