Question

ijʵÑéС×éÑо¿ÑÎËá¡¢ÇâÑõ»¯¸ÆÁ½ÖÖÎïÖʵĻ¯Ñ§ÐÔÖÊ£¬×öÁËÈçͼËùʾ8¸öʵÑ飮
ÒÑÖª£ºNa₂CO₃+CaCl₂=CaCO₃¡ý+2NaCl
£¨1£©ÈôʵÑéºóijÊÔ¹ÜÖÐΪ»ÆÉ«ÈÜÒº£¬Ôò¸ÃÊÔ¹ÜÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º______£®
£¨2£©ÈôʵÑéºóijÊÔ¹ÜÖÐΪºìÉ«ÈÜÒº£¬ÔòÏòÆäÖмÓÈë×ãÁ¿µÄ______£¬ÈÜÒº±äΪÎÞÉ«£®ÓÉ´ËÍƶϣ¬¸ÃÊÔ¹ÜÖÐ×î³õÊ¢ÓеÄÎïÖÊÊÇ______£®
£¨3£©ÈôʵÑéºóijÊԹܵĵײ¿Óа×É«¹ÌÌ壬ÇÒ¹ýÂ˺óÏòÂËÒºÖеμÓÏ¡ÑÎËᣬһ¶Îʱ¼äºóÓÐÆøÅݳöÏÖ£¬Ôò¸ÃÊÔ¹ÜÖÐ×î³õ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌΪ______£®
£¨4£©ÊµÑéºóijÊÔ¹ÜÖеõ½ÎÞÉ«ÈÜÒºA£¬ÏòÆäÖмÓÈë×ãÁ¿µÄNa₂CO₃ÈÜÒº£¬ÎÞÃ÷ÏÔÏÖÏó£®ÓÉ´ËÍƶϣ¬¸ÃÊÔ¹ÜÖÐ×î³õ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______£»ÎÞÉ«ÈÜÒºAÖеÄÈÜÖÊ¿ÉÄÜÊÇ______£®
£¨5£©ÔÚʵÑéÖз¢ÉúÖкͷ´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______£®
£¨6£©Èô½«¶þÑõ»¯Ì¼Í¨Èë³ÎÇåʯ»ÒË®ÖУ¬Éú³É5g°×É«³Áµí£¬¹ýÂ˺óÓöàÉÙ¿Ë10%µÄÏ¡ÑÎËáÄܽ«°×É«³ÁµíÇ¡ºÃÈܽ⣮

Answer 1

¡¾´ð°¸¡¿·ÖÎö£º£¨1£©¸ù¾ÝÑõ»¯ÌúºÍÏ¡ÑÎËá·´Ó¦Éú³ÉÂÈ»¯ÌúºÍË®ÂÈ»¯ÌúÈÜÓÚË®³Ê»ÆÉ«·ÖÎö£®
£¨2£©¸ù¾Ý¼îÄÜʹ·Ó̪±äÉ«¡¢¼îºÍÏ¡ÑÎËá·´Ó¦Éú³ÉÑκÍË®¡¢ÑκÍËᶼ²»ÄÜʹ·Ó̪±äÉ«·ÖÎö£®
£¨3£©¸ù¾ÝÇâÑõ»¯¸ÆºÍ̼ËáÄÆ·´Ó¦Éú³É̼Ëá¸ÆºÍÇâÑõ»¯ÄÆ·ÖÎö£®
£¨4£©¸ù¾Ý̼ËáÄƺÍÏ¡ÑÎËá·´Ó¦Éú³ÉÆøÌå¡¢ÂÈ»¯ÄƺÍÏ¡ÑÎËá²»·´Ó¦·ÖÎö£®
£¨5£©¸ù¾ÝÇâÑõ»¯¸ÆºÍÏ¡ÑÎËá·´Ó¦Éú³ÉÂÈ»¯¸ÆºÍË®·ÖÎö£®
£¨6£©¸ù¾Ý̼Ëá¸ÆºÍÏ¡ÑÎËá·´Ó¦Éú³ÉÂÈ»¯¸Æ¡¢Ë®ºÍ¶þÑõ»¯Ì¼·´Ó¦µÄ»¯Ñ§·½³Ìʽ¼ÆËã·ÖÎö£®
½â´ð£º½â£ºÑõ»¯ÌúºÍÏ¡ÑÎËá·´Ó¦Éú³ÉÂÈ»¯ÌúºÍË®£¬ÂÈ»¯ÌúÈÜÓÚË®³Ê»ÆÉ«£¬¹Ê£¨1£©´ð°¸£ºFe₂O₃+6HCl=2FeCl₃+3H₂O
£¨2£©ÇâÑõ»¯¸ÆÄÜʹ·Ó̪±äºìÉ«£¬Ï¡ÑÎËáºÍÇâÑõ»¯¸Æ·´Ó¦Éú³ÉÂÈ»¯¸Æ¡¢Ë®ºÍ¶þÑõ»¯Ì¼£¬Ï¡ÑÎËáÓпÉÄܹýÁ¿µ«ÂÈ»¯¸ÆºÍÏ¡ÑÎËᶼ²»ÄÜʹ·Ó̪±äÉ«£¬¹Ê´ð°¸£ºÏ¡ÑÎË᣻ÎÞÉ«·Ó̪ÊÔÒº
£¨3£©ÇâÑõ»¯¸ÆºÍ̼ËáÄÆ·´Ó¦Éú³É̼Ëá¸Æ³ÁµíºÍÇâÑõ»¯ÄÆ£¬¹Ê´ð°¸£ºCa£¨OH£©₂+Na₂CO₃=CaCO₃¡ý+2NaOH
£¨4£©Ì¼ËáÄƺÍÏ¡ÑÎËá·´Ó¦Éú³ÉÆøÌå¶þÑõ»¯Ì¼£¬ÂÈ»¯ÄƺÍÏ¡ÑÎËá²»·´Ó¦£¬ËùÒÔ¹ÌÌåÖпÉÄܺ¬ÓÐ̼ËáÄÆ£¬Ò»¶¨º¬ÓÐÂÈ»¯ÄÆ£®¹Ê´ð°¸£ºNa₂CO₃+2HCl=2NaCl+H₂O+CO₂¡ü£»NaCl»òNaClºÍNa₂CO₃£®
£¨5£©ÇâÑõ»¯¸ÆºÍÏ¡ÑÎËá·´Ó¦Éú³ÉÂÈ»¯¸ÆºÍË®£¬¹Ê´ð°¸£ºCa£¨OH£©₂+2HCl=CaCl₂+2H₂O     
£¨6£©½â£ºÉèËùÐèÏ¡ÑÎËáµÄÖÊÁ¿Îªx£®
CaCO₃+2HCl=CaCl₂+H₂O+CO₂¡ü                            
100    73
5g     10%x                                          
=
x=36.5g
´ð£ºËùÐèÏ¡ÑÎËáµÄÖÊÁ¿Îª36.5g£®
µãÆÀ£º±¾Ìâ×ۺϿ¼²éÁËÇâÑõ»¯¸ÆµÄ»¯Ñ§ÐÔÖʵÄ̽¾¿£¬È«Ãæ×ۺϵĿ¼²é£¬½Ç¶ÈÐÂÓ±£¬½â´ðʱץסÇâÑõ»¯¸ÆµÄ»¯Ñ§ÐÔÖʲ»Äѽâ´ð£®