ʵÑé²Ù×÷ | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
È¡ÉÙÁ¿¸ÃÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏòÈÜÒºÖеμÓÏ¡ÑÎËᣬ²¢²»¶ÏÕñµ´£® | ÓÐÆøÅÝð³ö£® | ÇâÑõ»¯ÄÆÈÜÒºÒ»¶¨±äÖÊÁË£® |
ʵÑé²½Öè | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
£¨1£©È¡ÉÙÁ¿¸ÃÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏòÈÜÒºÖеμӹýÁ¿µÄÂÈ»¯¸ÆÈÜÒº£¬²¢²»¶ÏÕñµ´£® | ÓÐ °×É«³Áµí °×É«³Áµí Éú³É£® |
˵Ã÷ÔÈÜÒºÖÐÒ»¶¨ÓÐ̼ËáÄÆ£® |
£¨2£©È¡²½Ö裨1£©ÊÔ¹ÜÖеÄÉÙÁ¿ÉϲãÇåÒº£¬µÎ¼Ó·Ó̪ÈÜÒº£® | ÈÜÒº±äºìÉ«£® | ˵Ã÷ÔÈÜÒºÖÐÒ»¶¨ÓÐ ÇâÑõ»¯ÄÆ ÇâÑõ»¯ÄÆ £® |
106 |
x |
44 |
4.4g |
10.6g |
50g |
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â
ʵÑé²Ù×÷ | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
È¡ÉÙÁ¿¸ÃÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏòÈÜÒºÖеμÓÏ¡ÑÎËᣬ²¢²»¶ÏÕñµ´£® | ÓÐÆøÅÝð³ö£® | ÇâÑõ»¯ÄÆÈÜÒºÒ»¶¨±äÖÊÁË£® |
ʵÑé²½Öè | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
£¨1£©È¡ÉÙÁ¿¸ÃÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏòÈÜÒºÖеμӹýÁ¿µÄÂÈ»¯¸ÆÈÜÒº£¬²¢²»¶ÏÕñµ´£® | ÓÐ £¨°×É«£©³Áµí £¨°×É«£©³Áµí Éú³É£® | ˵Ã÷ÔÈÜÒºÖÐÒ»¶¨ÓÐ̼ËáÄÆ£® |
£¨2£©È¡²½Ö裨1£©ÊÔ¹ÜÖеÄÉÙÁ¿ÉϲãÇåÒº£¬µÎ¼Ó·Ó̪ÈÜÒº£® | ÈÜÒº±äºìÉ«£® | ˵Ã÷ÔÈÜÒºÖÐÒ»¶¨ÓÐ ÇâÑõ»¯ÄÆ£¨»òNaOH£© ÇâÑõ»¯ÄÆ£¨»òNaOH£© £® |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â
ʵÑé²Ù×÷ | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
È¡ÉÙÁ¿¸ÃÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏòÈÜÒºÖеμÓÏ¡ÑÎËᣬ²¢²»¶ÏÕñµ´£® | ³öÏÖÆøÅÝ ³öÏÖÆøÅÝ |
ÇâÑõ»¯ÄÆÈÜÒºÒ»¶¨±äÖÊÁË£® |
ʵÑé²½Öè | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
£¨1£©È¡ÉÙÁ¿¸ÃÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏòÈÜÒºÖеμӹýÁ¿µÄÂÈ»¯±µÈÜÒº£¬²¢²»¶ÏÕñµ´£® | ÓÐ °×É«³Áµí °×É«³Áµí Éú³É£® |
˵Ã÷ÔÈÜÒºÖÐÒ»¶¨ÓÐ̼ËáÄÆ£® ·´Ó¦·½³Ìʽ Na2CO3+BaCl2¨T2NaCl+BaCO3¡ý Na2CO3+BaCl2¨T2NaCl+BaCO3¡ý |
£¨2£©È¡²½Ö裨1£©ÊÔ¹ÜÖеÄÉÙÁ¿ÉϲãÇåÒº£¬µÎ¼Ó·Ó̪ÈÜÒº£® | ÈÜÒº±äºìÉ«£® | ˵Ã÷ÔÈÜÒºÖÐÒ»¶¨ÓÐ ÇâÑõ»¯ÄÆ ÇâÑõ»¯ÄÆ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ʵÑé²Ù×÷ | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
È¡ÉÙÁ¿¸ÃÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏòÈÜÒºÖÐµÎ¼Ó Ï¡ÑÎËá Ï¡ÑÎËá £¬²¢²»¶ÏÕñµ´£® |
ÓÐ ÆøÅÝ ÆøÅÝ ²úÉú£® |
ÇâÑõ»¯ÄÆÈÜÒºÒ»¶¨±äÖÊÁË£® |
ʵÑé²½Öè | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
£¨1£©È¡ÉÙÁ¿¸ÃÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏòÈÜÒºÖеμӹýÁ¿µÄ ÂÈ»¯¸Æ ÂÈ»¯¸Æ ÈÜÒº£¬²¢²»¶ÏÕñµ´£® |
ÓÐ °×É«³Áµí °×É«³Áµí Éú³É£® |
˵Ã÷ÔÈÜÒºÖÐÒ»¶¨ÓÐ̼ËáÄÆ£® |
£¨2£©È¡²½Ö裨1£©ÊÔ¹ÜÖеÄÉÙÁ¿ÉϲãÇåÒº£¬µÎ¼Ó·Ó̪ÈÜÒº£® | ÈÜÒº±äºìÉ«£® | ˵Ã÷ÔÈÜÒºÖÐÒ»¶¨ÓÐ ÇâÑõ»¯ÄÆ ÇâÑõ»¯ÄÆ £® |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â
ʵÑé²Ù×÷ | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
È¡ÉÙÁ¿¸ÃÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏòÈÜÒºÖеμÓÏ¡ÑÎËᣬ²¢²»¶ÏÕñµ´£® | ³öÏÖÆøÅÝ ³öÏÖÆøÅÝ |
ÇâÑõ»¯ÄÆÈÜÒºÒ»¶¨±äÖÊÁË£® |
ʵÑé²½Öè | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
£¨1£©È¡ÉÙÁ¿¸ÃÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏòÈÜÒºÖеμӹýÁ¿µÄÂÈ»¯±µÈÜÒº£¬²¢²»¶ÏÕñµ´£® | ÓÐ °×É«³Áµí °×É«³Áµí Éú³É£® |
˵Ã÷ÔÈÜÒºÖÐÒ»¶¨ÓÐ̼ËáÄÆ£® |
£¨2£©È¡²½Ö裨1£©ÊÔ¹ÜÖеÄÉÙÁ¿ÉϲãÇåÒº£¬µÎ¼Ó·Ó̪ÈÜÒº£® | ÈÜÒº±äºìÉ«£® | ˵Ã÷ÔÈÜÒºÖÐÒ»¶¨ÓÐ ÇâÑõ»¯ÄÆ ÇâÑõ»¯ÄÆ £® |
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com