»·¾³ÎÊÌâÊÇ2011Äê¡°Á½»áÉÏ¡±µÄÈÈÃÅ»°ÌâÖ®Ò»£®
£¨1£©È¼Æø°²È«ÊǼÒÍ¥Éú»îÖеÄÍ·µÈ´óÊ£®ÎªÁË·ÀֹȼÆøй©£¬³£ÔÚȼÆøÖмÓÈëÉÙÁ¿ÓÐÌØÊâÆøζµÄÒÒÁò´¼£¨C
2H
5SH£©£®Ò»µ©È¼Æøй©¼´¿ÉÎŵ½Æø棬´Ó΢¹ÛµÄ½Ç¶È·ÖÎöÆäÔÒòÊÇ
·Ö×ÓÔÚ²»¶ÏÔ˶¯
·Ö×ÓÔÚ²»¶ÏÔ˶¯
£»ÒÒÁò´¼³ä·ÖȼÉÕʱÉú³É¶þÑõ»¯Ì¼¡¢¶þÑõ»¯ÁòºÍË®£¬ÒÒÁò´¼È¼ÉյĻ¯Ñ§·½³ÌʽΪ
2C
2H
5SH+9O
22SO
2+4CO
2+6H
2O
2C
2H
5SH+9O
22SO
2+4CO
2+6H
2O
£»
£¨2£©º¬ÁòúȼÉÕºó£¬Åŷŵ½¿ÕÆøÖеÄÓж¾ÆøÌåÖ÷ÒªÊÇSO
2£¬ËüÓöµ½ÓêË®ºó¿ÉÐÎ
³É
ËáÓê
ËáÓê
½µÂäµ½µØÃæÉÏ»á´øÀ´¼«´óΣº¦£®ÎªÁ˼õÉÙ´ËÎÛȾ£¬Ó¦²ÉÈ¡µÄ´ëÊ©ÓÐ
ʹÓÃÇå½àÄÜÔ´£»Ê¹ÓÃÍÑÁòú¡¢¹¤³§·ÏÆø´¦ÀíºóÔÙÅŷŵÈ
ʹÓÃÇå½àÄÜÔ´£»Ê¹ÓÃÍÑÁòú¡¢¹¤³§·ÏÆø´¦ÀíºóÔÙÅŷŵÈ
£¨ÌîÁ½µã£©£®
£¨3£©Ð¹Â©µÄÌìÈ»ÆøÓö»ð¿ÉÄܱ¬Õ¨£¬Òò´Ë¼ÒÍ¥Ó¦¸Ã°²×°ÌìÈ»Æø±¨¾¯Æ÷£®°²×°ÌìÈ»Æø±¨¾¯Æ÷ʱӦ½«±¨¾¯Æ÷°²ÔÚÔį̂µÄÉÏ·½»¹ÊÇÏ·½£¿ÀíÓÉÊÇ£º
ÉÏ·½
ÉÏ·½
¡¢
ÌìÈ»ÆøµÄÖ÷Òª³É·ÖÊǼ×Í飬ÃܶȱȿÕÆøС
ÌìÈ»ÆøµÄÖ÷Òª³É·ÖÊǼ×Í飬ÃܶȱȿÕÆøС
£»
£¨4£©ÎªÁ˼ìÑéÌìÈ»ÆøµÄ´¿¶È£¬µ±ÄãÊÕ¼¯Ò»ÊÔ¹ÜÆøÌåºó£¬½ÓÏÂÀ´ÄãµÄ×ö·¨ÊÇ£º
¹Ü¿ÚÏòÏ£¬¿¿½ü»ðÑæµã»ð
¹Ü¿ÚÏòÏ£¬¿¿½ü»ðÑæµã»ð
£»
£¨5£©µ±»®»ð²ñµã»ðʱ£¬ÈËÃÇ·¢ÏÖ»ðÑæÔÚÉÏÖ±Á¢»ð²ñ£¬»ðÑæ»áÂýÂýϨÃð£¬ÈôÂýÂýÇãбµ¹Á¢»ð²ñ£¬ÔòȼÉÕ¸üÍú£¬ÇëÎÊ»ðÑæÔÚÉÏÖ±Á¢»ð²ñ£¬»ðÑæ»áÂýÂýϨÃðµÄÔÒòÊÇ£º
»ðÑæÔÚÉÏÈÈÁ¿ÍùÉÏ´«µÝ£¬Î¶ȴﲻµ½µ×Ï»ð²ñµÄ×Å»ðµã¶øϨÃð
»ðÑæÔÚÉÏÈÈÁ¿ÍùÉÏ´«µÝ£¬Î¶ȴﲻµ½µ×Ï»ð²ñµÄ×Å»ðµã¶øϨÃð
£»
£¨6£©µ±³´²ËÇ°·¢ÏÖ¹øÄÚµÄÓÍ×Å»ð£¬Èç¹û²»ÓøÇ×ÓÈ¥¸Ç²¢ÇÒÔÚ²»µ¹µôÓ͵ÄÇ°ÌáÏ£¬ÒªÏ뽫»ðϨÃð£¬ÄãµÄ×ö·¨×îºÃÊÇ
µ¹ÈëÇà²Ë
µ¹ÈëÇà²Ë
£¬
ÕâÖÖÃð»ðµÄÔÀíÊÇ£º
ʹζȽµµ½×Å»ðµãÒÔÏÂ
ʹζȽµµ½×Å»ðµãÒÔÏÂ
£®