计算:
(1)(-20)+(+3)-(-5)-(+7)+7.2-(-4.8)
(2)-12008×-2
(3)3x2-3x2-y2+5y+x2-5y+y2
(4)4(x2-5x)-5(2x2+3x)
解:(1)原式=-20+3+5-7+7.2+4.8
=-27+8+12
-7;
(2)原式=-1
2008×[(-2)
5-3
2-

÷(-

)]-2
=-1×(-3
2-9-

)-2
=36

;
(3)原式=(3-3+1)x
2+(-1+1)y
2+(5-5)y
=x
2;
(4)原式=4x
2-20x-10x
2-15x
=(4-10)x
2+(-20-15)x
=-6x
2-35x.
分析:(1)先去括号,然后合并同类项;
(2)先算乘方,在算括号里面的,将除法转化为乘法解答;
(3)合并同类项即可;
(4)去括号,合并同类项.
点评:本题考查了整式的加减和有理数的运算,熟悉运算法则是解题的关键.