Question

（8分）某手机专营店代理销售A、B两种型号手机．手机的进价、售价如下
表：

（1）第一季度：用36000元购进A、B两种型号的手机，全部售完后获利6300元，求
第一季度购进A、B两种型号手机的数量；
（2）第二季度：计划购进A、B两种型号手机共34部，且不超出第一季度的购机总费用，则A型号手机最多能购多少部？

Answer 1

（1）解：设该专营店第一季度购进A、B两种型号手机的数量分别为x部和y部． 1分
答：该专营店本次购进A、B两种型号手机的数分别为15部和18部．······························································ 4分
（2）解：设第二季度购进A型号手机a部．···················································· 5分
由题意可知：1200a+1000(34－a)≤36000，····················································· 6分
解得：a≤10··························································································· 7分
不等式的最大整数解为10
答：第二季度最多能购A型号手机10部．······················································ 8分

解析