ʵÑ飺²âÁ¿Ä³ÖÖʳÓÃÓ͵ÄÃܶȣ®
£¨1£©°ÑÌìƽ·ÅÔÚˮƽ×ÀÃæÉÏ£¬½«ÓÎÂëÒÆÖÁÁã¿Ì¶È´¦£¬È»ºóµ÷½Ú________£¬Ê¹ÌìƽºáÁºÆ½ºâ£®
£¨2£©½øÐÐÏÂÁÐʵÑé²Ù×÷£º
A£®ÓÃÌìƽ²â³ö¿ÕС±­µÄÖÊÁ¿m0£»
B£®ÓÃÌìƽ²âÁ¿ÉÕ±­ºÍÊ£ÓàʳÓÃÓ͵Ä×ÜÖÊÁ¿m1£»
C£®½«´ý²âʳÓÃÓ͵¹ÈëÉÕ±­ÖУ¬ÓÃÌìƽ²â³öÉÕ±­ºÍʳÓÃÓ͵Ä×ÜÖÊÁ¿m2£»
D£®½«ÉÕ±­ÖÐʳÓÃÓ͵ÄÒ»²¿·Öµ¹ÈëÁ¿Í²£¬²â³öÕⲿ·ÖʳÓÃÓ͵ÄÌå»ýV£»
ÒÔÉϲÙ×÷ÖгýÈ¥¶àÓಽÖ裬Õýȷ˳ÐòÊÇ£º________£¨Ìî×Öĸ´úºÅ£©£®
£¨3£©¸ù¾ÝͼÖеÄʾÊý£¬Ôòm2=________ g£¬Ñ¡ÔñºÏÊÊÊý¾ÝËã³öÕâÖÖʳÓÃÓ͵ÄÃܶÈÊÇ________g/cm3£®

½â£º£¨1£©Ììƽ·ÅÔÚˮƽ×ÀÃæÉϺó£¬Ó¦ÏȽ«ÓÎÂëÒÆÖÁÁã¿Ì¶È´¦£¬ÔÙµ÷½ÚƽºâÂÝĸ£¬Ê¹ÌìƽºáÁºÆ½ºâ£»
£¨2£©ÔÚʹÓÃÌìƽÓëÁ¿Í²²âÒºÌåµÄÃܶÈʱ£¬×îºÏÀíµÄ²½Öè¾ÍÊÇÏȽ«´ý²âʳÓÃÓ͵¹ÈëÉÕ±­ÖУ¬ÓÃÌìƽ²â³öÉÕ±­ºÍʳÓÃÓ͵Ä×ÜÖÊÁ¿£¬ÔÙ½«ÉÕ±­ÖÐʳÓÃÓ͵ÄÒ»²¿·Öµ¹ÈëÁ¿Í²£¬²â³öÕⲿ·ÖʳÓÃÓ͵ÄÌå»ý£¬×îºóÓÃÌìƽ²âÁ¿ÉÕ±­ºÍÊ£ÓàʳÓÃÓ͵Ä×ÜÖÊÁ¿£¬Á½´ÎµÄÖÊÁ¿Ö®²î¾ÍÊÇÁ¿Í²Öе¹³öµÄʳÓÃÓ͵ÄÖÊÁ¿£¬Í¬Ê±£¬ÕâÒ»²½Öè°²ÅűÜÃâÁËʳÓÃÓÍÔÚÇãµ¹¹ý³ÌÖжԲâÁ¿½á¹ûµÄÓ°Ï죬×î´ó³Ì¶ÈµØ¼õСÁËÎó²îµÄ²úÉú£®Òò´Ë£¬²½ÖèÖС°A£®ÓÃÌìƽ²â³ö¿ÕС±­µÄÖÊÁ¿m0£»¡±ÊDz»±ØÒªµÄ£¬ÆäºÏÀíµÄ˳ÐòӦΪCDB£»
£¨3£©¶Áͼ¿ÉµÃ£¬m2=100g+50g+1.4g=151.4g£¬m1=100g+10g=110g£¬Á¿Í²µÄ·Ö¶ÈֵΪ2ml£¬Ê¾ÊýΪ46ml=46cm3£¬
ÔòʳÓÃÓ͵ÄÃܶÈΪ¦Ñ===0.9g/cm3£®
¹Ê´ð°¸Îª£º£¨1£©Æ½ºâÂÝĸ£»£¨2£©CDB£»£¨3£©151.4£»0.9£®
·ÖÎö£º£¨1£©ÌìƽÔÚʹÓÃÇ°ÒªÏȽøÐе÷½Ú£¬ÕâÒ»¹ý³ÌÊÇͨ¹ýµ÷½ÚƽºâÂÝĸÀ´Íê³ÉµÄ£»
£¨2£©ÔÚ²âÒºÌåµÄÖÊÁ¿ºÍÌå»ýʱ£¬×îÈÝÒ×Ôì³ÉÎó²îµÄ»·½Ú¾ÍÊÇ´ÓÒ»¸öÈÝÆ÷ÏòÁíÒ»¸öÈÝÆ÷Çãµ¹ÒºÌåʱ£¬ÈÝÆ÷±ÚÉÏ»áÓÐÕ´ÓÐÒ»²¿·ÖÒºÌ壬Òò´Ë£¬´ÓÕâÒ»½Ç¶È¿É¿¼ÂǺÏÀíµØ°²ÅÅʵÑé²½Öè˳Ðò£»
£¨3£©ÌìƽÔÚ¶ÁÊýʱӦ½«íÀÂëÖÊÁ¿ÓëÓÎÂëʾÊýÏà¼Ó£¬²¢×¢Òâ±ê³ßÉϵķֶÈÖµ£¬Í¬Ê±¶ÁÈ¡ÓÎÂëµÄ×ó±ßÔµ¶ÔÓ¦µÄ¿Ì¶È£®Á¿Í²ÔÚ¶ÁÊýʱҪÃ÷È··Ö¶ÈÖµ£¬ÊÓÏßÓëÒºÃæƽÆ룬×îºóÀûÓù«Ê½¦Ñ=¼ÆËãÒºÌåµÄÃܶȣ®
µãÆÀ£ºÍ¨¹ý±¾ÊµÑ鿼²éÁËÌìƽµÄµ÷½Ú¡¢Ê¹ÓÃÓë¶ÁÊý£¬Á¿Í²µÄ¶ÁÊý£¬²âÒºÌåÃܶȲ½ÖèµÄºÏÀí°²ÅÅ£¬Ãܶȹ«Ê½µÄ¼òµ¥¼ÆËãµÈ£¬¶¼ÊôÓÚÎÒÃDZØÐëÊìÁ·ÕÆÎյĻù±¾ÖªÊ¶£¬ÄѶÈËä²»´ó£¬µ«ÔÚ¶ÁÊýʱȴÓÈÆäÐèҪϸÐÄ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

ʵÑ飺²âÁ¿Ä³ÖÖʳÓÃÓ͵ÄÃܶȣ®
£¨1£©°ÑÌìƽ·ÅÔÚˮƽ×ÀÃæÉÏ£¬½«ÓÎÂëÒÆÖÁÁã¿Ì¶È´¦£¬È»ºóµ÷½Ú
ƽºâÂÝĸ
ƽºâÂÝĸ
£¬Ê¹ÌìƽºáÁºÆ½ºâ£®
£¨2£©½øÐÐÏÂÁÐʵÑé²Ù×÷£º
A£®ÓÃÌìƽ²âÁ¿ÉÕ±­ºÍÊ£ÓàʳÓÃÓ͵Ä×ÜÖÊÁ¿m1£»
B£®½«´ý²âʳÓÃÓ͵¹ÈëÉÕ±­ÖУ¬ÓÃÌìƽ²â³öÉÕ±­ºÍʳÓÃÓ͵Ä×ÜÖÊÁ¿m2£»
C£®½«ÉÕ±­ÖÐʳÓÃÓ͵ÄÒ»²¿·Öµ¹ÈëÁ¿Í²£¬²â³öÕⲿ·ÖʳÓÃÓ͵ÄÌå»ýV£»
ÒÔÉϲÙ×÷µÄÕýȷ˳ÐòÊÇ£º
BCA
BCA
£®
£¨3£©ÏÖÒѲâ³öm1ÊÇ110g£¬¸ù¾ÝÏÂͼÖеÄʾÊý£¬m2=
151.4g
151.4g
£»V=
46cm3
46cm3
£»Ëã³öÕâÖÖʳÓÃÓ͵ÄÃܶÈÊÇ
0.9g/cm3
0.9g/cm3
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

ʵÑ飺²âÁ¿Ä³ÖÖʳÓÃÓ͵ÄÃܶȣ®

£¨1£©°ÑÌìƽ·ÅÔÚˮƽ×ÀÃæÉÏ£¬½«ÓÎÂëÒÆÖÁÁã¿Ì¶È´¦£¬È»ºóµ÷½Ú
ƽºâÂÝĸ
ƽºâÂÝĸ
£¬Ê¹ÌìƽºáÁºÆ½ºâ£®
£¨2£©½øÐÐÏÂÁÐʵÑé²Ù×÷£ºÒÔϲÙ×÷µÄÕýȷ˳ÐòÊÇ£º
BAC
BAC
£¨Ìî×Öĸ´úºÅ£©£®
A£®½«ÉÕ±­ÖÐʳÓÃÓ͵ÄÒ»²¿·Öµ¹ÈëÁ¿Í²£¬²â³öÕⲿ·ÖʳÓÃÓ͵ÄÌå»ýV£»
B£®½«´ý²âʳÓÃÓ͵¹ÈëÉÕ±­ÖУ¬ÓÃÌìƽ²â³öÉÕ±­ºÍʳÓÃÓ͵Ä×ÜÖÊÁ¿m2£»
C£®ÓÃÌìƽ²âÁ¿ÉÕ±­ºÍÊ£ÓàʳÓÃÓ͵Ä×ÜÖÊÁ¿m1£»
£¨3£©ÏÖÒѲâ³öm1ÊÇ110g£¬¸ù¾ÝͼÖеÄʾÊý£¬Ëã³öÕâÖÖʳÓÃÓ͵ÄÃܶÈÊÇ
0.9g/cm3
0.9g/cm3
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

ʵÑ飺²âÁ¿Ä³ÖÖʳÓÃÓ͵ÄÃܶȣ®

£¨1£©°ÑÌìƽ·ÅÔÚ
ˮƽ
ˮƽ
×ÀÃæÉÏ£¬½«
ÓÎÂë
ÓÎÂë
ÒÆÖÁÁã¿Ì¶ÈÏß´¦£¬È»ºóµ÷½Ú
ƽºâÂÝĸ
ƽºâÂÝĸ
£¬Ê¹ÌìƽºáÁºÆ½ºâ£®³ÆÁ¿Ê±£¬ÎïÌå·ÅÔÚ
×ó
×ó
ÅÌ£¬íÀÂë·ÅÔÚ
ÓÒ
ÓÒ
ÅÌ£®
£¨2£©½øÐÐÏÂÁÐʵÑé²Ù×÷£º
A£®Èçͼ¼×½«´ý²âʳÓÃÓ͵¹ÈëÉÕ±­ÖУ¬ÓÃÌìƽ²â³öÉÕ±­ºÍʳÓÃÓ͵Ä×ÜÖÊÁ¿m2=
151.4
151.4
g£»
B£®½«ÉÕ±­ÖÐʳÓÃÓ͵ÄÒ»²¿·Öµ¹ÈëÁ¿Í²£¬ÈçͼÒÒ²â³öÕⲿ·ÖʳÓÃÓ͵ÄÌå»ýV=
46
46
cm3£»
C£®ÓÃÌìƽ²âÁ¿ÉÕ±­ºÍÊ£ÓàʳÓÃÓ͵Ä×ÜÖÊÁ¿m1Ϊ110g£»
D£®¸ù¾Ý¹«Ê½
¦Ñ=
m2-m1
V
¦Ñ=
m2-m1
V
Ëã³öÕâÖÖʳÓÃÓ͵ÄÃܶÈÊÇ
0.9
0.9
g/cm3£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

ʵÑ飺²âÁ¿Ä³ÖÖʳÓÃÓ͵ÄÃܶȣ®ÊµÑéÖнøÐÐÁËÏÂÁÐʵÑé²Ù×÷£º
A£®ÓÃÌìƽ²âÁ¿ÉÕ±­ºÍÊ£ÓàʳÓÃÓ͵Ä×ÜÖÊÁ¿m1£»
B£®½«´ý²âʳÓÃÓ͵¹ÈëÉÕ±­ÖУ¬ÓÃÌìƽ²â³öÉÕ±­ºÍʳÓÃÓ͵Ä×ÜÖÊÁ¿m2£¨Èçͼ£¨2£©£©£»
C£®½«ÉÕ±­ÖÐʳÓÃÓ͵ÄÒ»²¿·Öµ¹ÈëÁ¿Í²£¬²â³öÕⲿ·ÖʳÓÃÓ͵ÄÌå»ýV£¨Èçͼ£¨1£©£©£»
£¨1£©ÒÔÉϲÙ×÷µÄÕýȷ˳ÐòÊÇ£º
BCA
BCA
£¨Ìî×Öĸ´úºÅ£©£®
£¨2£©ÏÖÒѲâ³öm1ÊÇ110g£¬Ôòµ¹ÈëÁ¿Í²µÄʳÓÃÓÍÖÊÁ¿Îª
41.4g
41.4g
£¬ÕâÖÖʳÓÃÓ͵ÄÃܶÈÊÇ
0.9g/cm3
0.9g/cm3
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍøʵÑ飺²âÁ¿Ä³ÖÖʳÓÃÓ͵ÄÃܶȣ®
£¨1£©°ÑÌìƽ·ÅÔÚ
 
×ÀÃæÉÏ£¬½«ÓÎÂëÒÆÖÁ
 
£¬È»ºóµ÷½Ú
 
£¬Ê¹ÌìƽºáÁºÆ½ºâ£®
£¨2£©½øÐÐÏÂÁÐʵÑé²Ù×÷£º
A£®ÓÃÌìƽ²âÁ¿ÉÕ±­ºÍÊ£ÓàʳÓÃÓ͵Ä×ÜÖÊÁ¿m1£»
B£®½«´ý²âʳÓÃÓ͵¹ÈëÉÕ±­ÖУ¬ÓÃÌìƽ²â³öÉÕ±­ ºÍʳÓÃÓ͵Ä×ÜÖÊÁ¿m2£»
C£®½«ÉÕ±­ÖÐʳÓÃÓ͵ÄÒ»²¿·Öµ¹ÈëÁ¿Í²£¬²â³öÕⲿ·ÖʳÓÃÓ͵ÄÌå»ýV£» 
ÒÔÉϲÙ×÷µÄÕýȷ˳ÐòÊÇ£º
 
£¨Ìî×Öĸ´úºÅ£©£®
£¨3£©ÏÖÒѲâ³öm1ÊÇ160g£¬ÓÉͼÖÐʾÊý¿ÉËã³öÕâÖÖʳÓÃÓ͵ÄÃܶÈÊÇ
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸