·ÖÎö £¨1£©¶ÁÈ¡Á¿Í²ÖÐÒºÌåµÄÌå»ýʱ£¬Ê×ÏÈÒªÃ÷È·Á¿Í²µÄ·Ö¶ÈÖµ£¬¶ÁÊýʱÊÓÏßÓëÒºÃæ×î°¼´¦ÏàÆ½£»
ÒÑÖªÉÕ±ºÍ½´Ó͵ÄÖÊÁ¿£¬ÉÕ±µÄÖÊÁ¿£¬¿ÉÒԵõ½ÉÕ±Öн´Ó͵ÄÖÊÁ¿£»ÒÑÖª½´Ó͵ÄÖÊÁ¿ºÍÌå»ý£¬ÀûÓù«Ê½¦Ñ=$\frac{m}{V}$µÃµ½½´Ó͵ÄÃܶȣ®
£¨2£©Ð¡Ã÷µÄ·½°¸ÖС°°ÑÉÕ±ÄڵĽ´ÓÍÈ«²¿µ¹ÈëÁ¿Í²ÄÚ¡±»áʹµÃ½´ÓͲ»ÄÜÈ«²¿µ¹ÈëÁ¿Í²ÄÚ£¬´Ó¶øÊ¹ÃܶȳöÏֺܴóµÄÎó²î£®
£¨3£©Ö»ÓÐÌìÆ½£¬Ã»ÓÐÁ¿Í²£¬¿ÉÒÔÀûÓõÈÌå»ýµÄË®ºÍ½´ÓÍ£¬³ÆÁ¿Ë®ºÍ½´Ó͵ÄÖÊÁ¿£¬¸ù¾ÝÌå»ýÏàµÈÁгöµÈʽÇó³ö½´Ó͵ÄÃܶȣ®
£¨4£©Òª¿¼ÂÇÕû¸ö¹ý³ÌÖжԽ´Ó͵ÄÖÊÁ¿ºÍÌå»ýÓÐÓ°ÏìµÄµØ·½£®
½â´ð ½â£º£¨1£©Á¿Í²µÄ·Ö¶ÈֵΪ2cm3£¬Á¿Í²Öн´Ó͵ÄÌå»ýΪV=40cm3£»
ÔÚÌìÆ½µÄ±ê³ßÉÏ£¬1gÖ®¼äÓÐ5¸öС¸ñ£¬Ò»¸öС¸ñ´ú±íµÄÖÊÁ¿ÊÇ0.2g£¬¼´ÌìÆ½µÄ·Ö¶ÈֵΪ0.2g£»
ÉÕ±ºÍ½´Ó͵Ä×ÜÖÊÁ¿ÊÇm1=50g+10g+2g=62g£»
¿ÕÉÕ±µÄÖÊÁ¿Îªm2=17g£¬
ÉÕ±Öн´Ó͵ÄÖÊÁ¿Îªm=m1-m2=62g-17g=45g£¬
½´Ó͵ÄÃܶÈΪ¦Ñ=$\frac{m}{V}$=$\frac{45g}{40c{m}^{3}}$=1.125g/cm3=1.125¡Á103kg/m3£®
£¨2£©Ð¡Ã÷²»¿ÉÄܰÑÉÕ±ÄڵĽ´ÓÍÈ«²¿µ¹ÈëÁ¿Í²ÄÚ£¬µ¼Ö²âÁ¿µÄ½´Ó͵ÄÌå»ýƫС£¬Óɹ«Ê½¦Ñ=$\frac{m}{V}$Öª£ºÃܶȲâÁ¿½á¹ûÆ«´ó£»
Ϊ¼õСÎó²î£¬¿ÉÏȲâÉÕ±ºÍ½´Ó͵ÄÖÊÁ¿£¬½«½´Ó͵¹ÈëÁ¿Í²£¬¶Á³öÌå»ý£¬ÔÙ²â³öÉÕ±µÄÖÊÁ¿£¬²½ÖèΪbca£®
£¨3£©Ð¡»ª²»Ð¡ÐĽ«Á¿Í²´òËéÁË£¬ÓÃÌìÆ½Ò²ÄܲâÁ¿³ö½´Ó͵ÄÃܶȣº
¢Ùµ÷ºÃÌìÆ½£¬ÓÃÌìÆ½²â³ö¿ÕÉÕ±ÖÊÁ¿Îªm0£®
¢Ú½«Ò»¸öÉÕ±×°ÂúË®£¬ÓÃÌìÆ½²â³öÉÕ±ºÍË®µÄ×ÜÖÊÁ¿Îªm1£®
ÔòË®µÄÖÊÁ¿mË®=m1-m0£¬
ÓɦÑ=$\frac{m}{V}$¿ÉÇóµÃ£¬Ë®µÄÌå»ýV=$\frac{{m}_{1}-{m}_{0}}{{¦Ñ}_{Ë®}}$£¬
¢ÛÓÃÁíÒ»¸öÉÕ±×°Âú½´ÓÍ£¬ÓÃÌìÆ½²â³öÉÕ±ºÍ½´Ó͵Ä×ÜÖÊÁ¿Îªm2£®
Ôò½´Ó͵ÄÖÊÁ¿m½´ÓÍ=m2-m0£¬
ÉÕ±ÄÚË®µÄÌå»ýµÈÓÚ½´Ó͵ÄÌå»ý
¢ÜÔò½´Ó͵ÄÃܶȱí´ïʽ¦Ñ=$\frac{m}{V}$=$\frac{{m}_{½´ÓÍ}}{V}$=$\frac{{m}_{2}-{m}_{0}}{\frac{{m}_{1}-{m}_{0}}{{¦Ñ}_{Ë®}}}$=$\frac{{m}_{2}-{m}_{0}}{{m}_{1}-{m}_{0}}$•¦ÑË®£®
£¨4£©ÉÕ±×°ÂúË®£¬Ò×È÷³ö£¬²»·½±ã²Ù×÷£®
¹Ê´ð°¸Îª£º£¨1£©45£»1.125¡Á103£»£¨2£©Æ«´ó£»bca£»£¨3£©¢Ú×°ÂúË®£»¢Ü$\frac{{m}_{2}-{m}_{0}}{{m}_{1}-{m}_{0}}$•¦ÑË®£»
£¨4£©ÉÕ±×°ÂúË®£¬Ò×È÷³ö£¬²»·½±ã²Ù×÷£®
µãÆÀ ²âÁ¿ÒºÌåÃܶÈʱ£¬Ö»ÓÐÁ¿Í²Ã»ÓÐÌìÆ½£¬¿ÉÒÔ²ÉÓñ»²âÒºÌåºÍË®µÄÖÊÁ¿Ïàͬ½øÐвâÁ¿£»Ö»ÓÐÌìÆ½Ã»ÓÐÁ¿Í²£¬¿ÉÒÔ²ÉÓñ»²âÒºÌåºÍË®µÄÌå»ýÏàͬ½øÐвâÁ¿£®½´ÓÍÌå»ýµÄ²âÁ¿ÊDZ¾ÊµÑéµÄÄѵ㣬ÇÉÃîµØÀûÓõÈÐ§Ìæ´ú·¨£¬Êǽâ¾ö´ËÌâµÄ¹Ø¼ü£®
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ͨ¹ý¼×µÆµçÁ÷±ÈÒҵƴó | B£® | ¼×µÆµÄ¶î¶¨¹¦ÂʱÈÒÒµÆÐ¡ | ||
| C£® | ¼×µÆµÄµç×è±ÈÒÒµÆÐ¡ | D£® | ¼×µÆµÄʵ¼Ê¹¦ÂʱÈÒҵƴó |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | µçů¯ | B£® | °×³ãµÆ | C£® | µç·¹ìÒ | D£® | ·¢µç»ú |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ÈëÉä¹âÏßÏò·¨Ïß¿¿Â££¬·´Éä¹âÏßÒ²Ïò·¨Ïß¿¿Â£ | |
| B£® | ÈëÉä½ÇÔö´ó10¡ã£¬·´Éä½ÇÒ²Ôö´ó10¡ã | |
| C£® | ÈëÉä¹âÏßÓë·´ÉäÃæ¼Ð½ÇΪ30¡ã·´Éä¹âÏßÓë·¨Ï߼нÇΪ60¡ã | |
| D£® | ÈëÉä½ÇΪ0¡ãµÄÈëÉä¹âÏßûÓз´Éä¹âÏß |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
| A£® | ÎïÌåµÄÄÚÄÜÔö¼Ó£¬Î¶ÈÒ»¶¨Éý¸ß | B£® | ÎïÌåµÄÄÚÄÜÔö¼Ó£¬Ò»¶¨ÎüÊÕÁËÈÈÁ¿ | ||
| C£® | ζȸߵÄÎïÌ壬ÄÚÄܲ»Ò»¶¨´ó | D£® | ¸ßÎÂÎïÌå×ܰÑζȴ«µÝ¸øµÍÎÂÎïÌå |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com