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【题目】有一灯泡上标有“6 V 01 A”字样,现要测绘该灯泡的伏安特性曲线,有下列器材可供选用

A电压表0~5 V,内阻20

B电压表0~10 V,内阻30

C电流表0~100m A,内阻20 Ω

D电流表0~6 A,内阻15 Ω

E滑动变阻器30 Ω,2 A

F滑动变阻器100 Ω,05 A

G学生电源直流9 V及开关、导线等

1实验中所用的电压表应选________,电流表应选________,滑动变阻器应选________。

2画出实验电路图,要求电压从零开始测量。

3根据你的实验电路,将图中所示的器材连成实验电路。

4该同学描绘出的IU图像应是图中的________

【答案】1B;C;E 2如图3如图4B

【解析】1电压表的量程应大于小灯泡的额定电压6 V,故电压表应选B。小灯泡的额定电流是01 A,故电流表应选C。由题目要求可知滑动变阻器采用分压式,故应选电阻较小的E。

2小灯泡的电阻R=Ω=60 Ω,电压表的内阻与待测电阻的比为=50,待测电阻与电流表的内阻的比为=30,,故电流表应采用外接法,滑动变阻器接成分压式,电路图见答案。

3电路图如图所示

4小灯泡的电阻随着温度的升高而变大,所以B正确

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