ÏÖÓÐÊÒÎÂÏÂŨ¶È¾ùΪ1¡Á10£­3mol/LµÄ¼¸ÖÖÈÜÒº¢ÙÑÎËá¡¢¢ÚÁòËá¡¢¢Û´×Ëá¡¢¢ÜÂÈ»¯ï§¡¢¢Ý°±Ë®¡¢¢ÞNaOHÈÜÒº£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©PH¾ùµÈÓÚ3µÄÈÜÒº¢Ù¡¢¢Ú¡¢¢Û¡¢¢ÜÖÐË®µçÀë²úÉúµÄc(H+)µÄ±ÈÖµÊÇ         
£¨2£©½«¢Û¡¢¢Þ»ìºÏºó£¬ÈôÈÜÒº³ÊÖÐÐÔ£¬ÔòÏûºÄÁ½ÈÜÒºµÄÌå»ýΪ¢Û   ¢Þ£¨Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±£©£¬ÈÜÒºÖеÄÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ                                         
(3) ½«µÈÌå»ýµÄ¢Ù¡¢¢Ý»ìºÏ£¬ÔòÈÜÒºµÄPH     7£¨Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±£©£¬ÓÃÀë×Ó·½³Ìʽ˵Ã÷ÆäÔ­Òò                                                  
(4)ÏòÏàͬÌå»ýµÄ¢Ù¡¢¢Ú¡¢¢ÛÈÜÒºÖзֱð¼ÓÈëÏàͬµÄÇÒ×ãÁ¿µÄпÁ££¬·´Ó¦µÄ³õʼËÙÂÊÓÉ¿ìµ½ÂýµÄ˳ÐòΪ            £¬×îÖÕ²úÉúH2×ÜÁ¿µÄ¹ØϵΪ                 
£¨5£©ÏòÏàͬÌå»ýµÄ¢Ù¡¢¢ÛÈÜÒºÖзֱð¼ÓÈëÏàͬŨ¶È¡¢ÏàͬÌå»ýµÄCH3COONaÈÜÒº£¬³ä·Ö»ìºÏºó£¬»ìºÏÒºµÄPH´óС¹ØϵΪ¢Ù      ¢Û£¨Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±£©
£¨6£©Èô½«µÈÌå»ýµÄ¢Ý¡¢¢ÞÈÜÒº¼ÓÈÈÖÁÏàͬζȺó£¬ÈÜÒºµÄPH¢Ý    ¢Þ£¨Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±£©

£¨1£©1£º1£º1£º108   
£¨2£©>    c(NH4+)=c(C1-)>c(H+)=c(OH-)
(3)<    NH4++H2ONH3¡¤H2O+H+
(4) ¢Ú¢Ù¢Û       ¢Ú£¾¢Ù=¢Û
£¨5£©<                
£¨6£©<

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÖÓÐÊÒÎÂÏÂŨ¶È¾ùΪ1¡Á10-3mol/LµÄ¼¸ÖÖÈÜÒº¢ÙÑÎËá¡¢¢ÚÁòËá¡¢¢Û´×Ëá¡¢¢ÜÂÈ»¯ï§¡¢¢Ý°±Ë®¡¢¢ÞNaOHÈÜÒº£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©pH¾ùµÈÓÚ3µÄÈÜÒº¢Ù¡¢¢Ú¡¢¢Û¡¢¢ÜÖÐË®µçÀë²úÉúµÄc£¨H+£©µÄ±ÈÖµÊÇ
1£º1£º1£º108
1£º1£º1£º108
£®
£¨2£©½«¢Û¡¢¢Þ»ìºÏºó£¬ÈôÈÜÒº³ÊÖÐÐÔ£¬ÔòÏûºÄÁ½ÈÜÒºµÄÌå»ýΪ¢Û
£¾
£¾
¢Þ£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£¬ÈÜÒºÖеÄÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ
c£¨NH4+£©=c£¨C1-£©£¾c£¨H+£©=c£¨OH-£©
c£¨NH4+£©=c£¨C1-£©£¾c£¨H+£©=c£¨OH-£©
£®
£¨3£©½«µÈÌå»ýµÄ¢Ù¡¢¢Ý»ìºÏ£¬ÔòÈÜÒºµÄPH
£¼
£¼
 7£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£¬ÓÃÀë×Ó·½³Ìʽ˵Ã÷ÆäÔ­Òò
NH4++H2ONH3?H2O+H+
NH4++H2ONH3?H2O+H+
£®
£¨4£©ÏòÏàͬÌå»ýµÄ¢Ù¡¢¢Ú¡¢¢ÛÈÜÒºÖзֱð¼ÓÈëÏàͬµÄÇÒ×ãÁ¿µÄпÁ££¬·´Ó¦µÄ³õʼËÙÂÊÓÉ¿ìµ½ÂýµÄ˳ÐòΪ
¢Ú¢Ù¢Û
¢Ú¢Ù¢Û
£¬×îÖÕ²úÉúH2×ÜÁ¿µÄ¹ØϵΪ
¢Ú£¾¢Ù=¢Û
¢Ú£¾¢Ù=¢Û
£®
£¨5£©ÏòÏàͬÌå»ýµÄ¢Ù¡¢¢ÛÈÜÒºÖзֱð¼ÓÈëÏàͬŨ¶È¡¢ÏàͬÌå»ýµÄCH3COONaÈÜÒº£¬³ä·Ö»ìºÏºó£¬»ìºÏÒºµÄpH´óС¹ØϵΪ¢Ù
£¼
£¼
¢Û£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£®
£¨6£©Èô½«µÈÌå»ýµÄ¢Ý¡¢¢ÞÈÜÒº¼ÓÈÈÖÁÏàͬζȺó£¬ÈÜÒºµÄpH¢Ý
£¼
£¼
¢Þ£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÖÓÐÊÒÎÂÏÂŨ¶È¾ùΪ1¡Á10-3mol/LµÄ¼¸ÖÖÈÜÒº£º¢ÙÑÎËá¡¢¢ÚÁòËá¡¢¢Û´×Ëá¡¢¢ÜÂÈ»¯ï§¡¢¢Ý°±Ë®¡¢¢ÞNaOHÈÜÒº£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©½«¢Û¡¢¢Þ»ìºÏºó£¬ÈôÈÜÒº³ÊÖÐÐÔ£¬ÔòÏûºÄÁ½ÈÜÒºµÄÌå»ýΪ¢Û
£¾
£¾
¢Þ£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£®ÈÜÒºÖеÄÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ
C£¨Na+£©=C£¨CH3COO-£©£¾C£¨OH-£©=C£¨H+£©
C£¨Na+£©=C£¨CH3COO-£©£¾C£¨OH-£©=C£¨H+£©
£®
£¨2£©½«µÈÌå»ýµÄ¢Ù¡¢¢Ý»ìºÏ£¬ÔòÈÜÒºµÄpH
£¼
£¼
7£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£¬ÓÃÀë×Ó·½³Ìʽ˵Ã÷ÆäÔ­Òò
NH4++H2O?NH3?H2O+H+
NH4++H2O?NH3?H2O+H+

£¨3£©ÏòÏàͬÌå»ýµÄ¢Ù¡¢¢Ú¡¢¢ÛÈÜÒºÖзֱð¼ÓÈëÏàͬµÄÇÒ×ãÁ¿µÄпÁ££¬·´Ó¦µÄ³õʼËÙÂÊÓÉ¿ìµ½ÂýµÄ˳ÐòΪ
¢Ú¢Ù¢Û
¢Ú¢Ù¢Û
£¬×îÖÕ²úÉúH2×ÜÁ¿µÄ¹ØϵΪ
¢Ú£¾¢Ù=¢Û
¢Ú£¾¢Ù=¢Û

£¨4£©ÏòÏàͬÌå»ýµÄ¢Ù¡¢¢ÛÈÜÒºÖзֱð¼ÓÈëÏàͬŨ¶È¡¢ÏàͬÌå»ýµÄCH3COONaÈÜÒº£¬³ä·Ö»ìºÏºó£¬»ìºÏÒºµÄpH ´óС¹ØϵΪ¢Ù
£¼
£¼
¢Û£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©
£¨5£©Èô½«µÈÌå»ýµÄ¢Ý¡¢¢ÞÈÜÒº¼ÓÈÈÖÁÏàͬζȺó£¬ÈÜÒºµÄpH¢Ý
£¼
£¼
¢Þ£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(14·Ö)ÏÖÓÐÊÒÎÂÏÂŨ¶È¾ùΪ1¡Á10£­3mol/LµÄ¼¸ÖÖÈÜÒº¢ÙÑÎËá¡¢¢ÚÁòËá¡¢¢Û´×Ëá¡¢¢ÜÂÈ»¯ï§¡¢¢Ý°±Ë®¡¢¢ÞNaOHÈÜÒº£¬»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©PH¾ùµÈÓÚ3µÄÈÜÒº¢Ù¡¢¢Ú¡¢¢Û¡¢¢ÜÖÐË®µçÀë²úÉúµÄc(H+)µÄ±ÈÖµÊÇ          

£¨2£©½«¢Û¡¢¢Þ»ìºÏºó£¬ÈôÈÜÒº³ÊÖÐÐÔ£¬ÔòÏûºÄÁ½ÈÜÒºµÄÌå»ýΪ¢Û    ¢Þ£¨Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±£©£¬ÈÜÒºÖеÄÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ                                         

(3) ½«µÈÌå»ýµÄ¢Ù¡¢¢Ý»ìºÏ£¬ÔòÈÜÒºµÄPH     7£¨Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±£©£¬ÓÃÀë×Ó·½³Ìʽ˵Ã÷ÆäÔ­Òò                                                  

(4)ÏòÏàͬÌå»ýµÄ¢Ù¡¢¢Ú¡¢¢ÛÈÜÒºÖзֱð¼ÓÈëÏàͬµÄÇÒ×ãÁ¿µÄпÁ££¬·´Ó¦µÄ³õʼËÙÂÊÓÉ¿ìµ½ÂýµÄ˳ÐòΪ            £¬×îÖÕ²úÉúH2×ÜÁ¿µÄ¹ØϵΪ                 

£¨5£©ÏòÏàͬÌå»ýµÄ¢Ù¡¢¢ÛÈÜÒºÖзֱð¼ÓÈëÏàͬŨ¶È¡¢ÏàͬÌå»ýµÄCH3COONaÈÜÒº£¬³ä·Ö»ìºÏºó£¬»ìºÏÒºµÄPH´óС¹ØϵΪ¢Ù       ¢Û£¨Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±£©

£¨6£©Èô½«¢Ý¡¢¢ÞÈÜÒº¼ÓÈÈÖÁÏàͬζȺó£¬ÈÜÒºµÄpH¢Ý     ¢Þ£¨Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±£©

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010-2011ѧÄêºÓ±±Ê¡¸ßÈý¸ß¿¼·ÂÕ棨Èý£©£¨Àí×Û£©»¯Ñ§²¿·Ö ÌâÐÍ£ºÌî¿ÕÌâ

(14·Ö)ÏÖÓÐÊÒÎÂÏÂŨ¶È¾ùΪ1¡Á10£­3mol/LµÄ¼¸ÖÖÈÜÒº¢ÙÑÎËá¡¢¢ÚÁòËá¡¢¢Û´×Ëá¡¢¢ÜÂÈ»¯ï§¡¢¢Ý°±Ë®¡¢¢ÞNaOHÈÜÒº£¬»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©PH¾ùµÈÓÚ3µÄÈÜÒº¢Ù¡¢¢Ú¡¢¢Û¡¢¢ÜÖÐË®µçÀë²úÉúµÄc(H+)µÄ±ÈÖµÊÇ          

£¨2£©½«¢Û¡¢¢Þ»ìºÏºó£¬ÈôÈÜÒº³ÊÖÐÐÔ£¬ÔòÏûºÄÁ½ÈÜÒºµÄÌå»ýΪ¢Û    ¢Þ£¨Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±£©£¬ÈÜÒºÖеÄÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ                                         

(3) ½«µÈÌå»ýµÄ¢Ù¡¢¢Ý»ìºÏ£¬ÔòÈÜÒºµÄPH      7£¨Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±£©£¬ÓÃÀë×Ó·½³Ìʽ˵Ã÷ÆäÔ­Òò                                                  

(4)ÏòÏàͬÌå»ýµÄ¢Ù¡¢¢Ú¡¢¢ÛÈÜÒºÖзֱð¼ÓÈëÏàͬµÄÇÒ×ãÁ¿µÄпÁ££¬·´Ó¦µÄ³õʼËÙÂÊÓÉ¿ìµ½ÂýµÄ˳ÐòΪ             £¬×îÖÕ²úÉúH2×ÜÁ¿µÄ¹ØϵΪ                 

£¨5£©ÏòÏàͬÌå»ýµÄ¢Ù¡¢¢ÛÈÜÒºÖзֱð¼ÓÈëÏàͬŨ¶È¡¢ÏàͬÌå»ýµÄCH3COONaÈÜÒº£¬³ä·Ö»ìºÏºó£¬»ìºÏÒºµÄPH´óС¹ØϵΪ¢Ù       ¢Û£¨Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±£©

£¨6£©Èô½«¢Ý¡¢¢ÞÈÜÒº¼ÓÈÈÖÁÏàͬζȺó£¬ÈÜÒºµÄpH¢Ý     ¢Þ£¨Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±£©

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸