Ϊ̽¾¿CO2Óë¹ýÁ¿µÄNaOHÈÜҺȷʵ·¢ÉúÁË»¯Ñ§·´Ó¦£¬¼×¡¢ÒÒ¡¢±ûÈýλͬѧÉè¼ÆÁËÏÂÁÐÈýÖÖʵÑé×°Öã¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)Çëд³öCO2Óë¹ýÁ¿µÄNaOH·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º________£®

(2)Ñ¡ÔñÈÎÒâÒ»ÖÖʵÑé×°Ö㬼òÊöÔ¤¼Æ³öÏÖµÄʵÑéÏÖÏ󣬽âÊͲúÉú¸ÃʵÑéÏÖÏóµÄÔ­Òò£®

ÄãÑ¡ÔñµÄʵÑé×°ÖÃÊÇ________£¬ÊµÑéÏÖÏóÊÇ________£¬½âÊͲúÉú¸ÃʵÑéÏÖÏóµÄÔ­Òò________£®

(3)¼×¡¢ÒÒ¡¢±ûͬѧÉè¼ÆµÄÈý¸ö·½°¸ÖУ¬ÓÐÒ»¸ö·½°¸ÔÚʵ¼Ê²Ù×÷ÖпÉÐÐÐԺͰ²È«ÐÔ´æÔÚÎÊÌ⣬¸Ã·½°¸ÊÇ________£®(Ìî¼×¡¢ÒÒ»ò±û)

(4)ÇëÉè¼ÆÒ»¸öʵÑé¼ìÑéÉú³ÉµÄ²úÎïÖк¬ÓÐNa2CO3£®(¼òÊöËùÓÃÊÔ¼Á¡¢ÊµÑéÏÖÏóºÍ½áÂÛ£®)

___________________£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ij¿ÎÍâ»î¶¯Ð¡×éΪ̽¾¿CO2Óë¹ýÁ¿µÄNaOHÈÜҺȷʵ·¢ÉúÁË»¯Ñ§·´Ó¦£¬¼×¡¢ÒÒ¡¢±ûÈýλͬѧÉè¼ÆÁËÏÂÁÐÈýÖÖʵÑé×°Öã¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©¼××°ÖÃÖÐCO2Óë¹ýÁ¿µÄNaOH·´Ó¦µÄÀë×Ó·½³Ìʽ
CO2+2OH-=CO32-+H2O
CO2+2OH-=CO32-+H2O
£®
£¨2£©±û×°ÖÃʵÑéÏÖÏóÊÇ
µ±NaOHÈÜÒºµÎÈë׶ÐÎÆ¿Ö®ºó£¬ÉÕ±­ÖеÄË®µ¹ÎüÈë׶ÐÎÆ¿
µ±NaOHÈÜÒºµÎÈë׶ÐÎÆ¿Ö®ºó£¬ÉÕ±­ÖеÄË®µ¹ÎüÈë׶ÐÎÆ¿
£¬½âÊͲúÉú¸ÃʵÑéÏÖÏóµÄÔ­Òò
NaOHÓëCO2·´Ó¦£¬µ¼ÖÂ׶ÐÎÆ¿ÄÚѹǿ½µµÍ£¬ÔÚ´óÆøѹµÄ×÷ÓÃÏ£¬ÉÕ±­ÖеÄË®µ¹ÎüÈë׶ÐÎÆ¿
NaOHÓëCO2·´Ó¦£¬µ¼ÖÂ׶ÐÎÆ¿ÄÚѹǿ½µµÍ£¬ÔÚ´óÆøѹµÄ×÷ÓÃÏ£¬ÉÕ±­ÖеÄË®µ¹ÎüÈë׶ÐÎÆ¿
£®
£¨3£©¼×¡¢ÒÒ¡¢±ûͬѧÉè¼ÆµÄÈý¸ö·½°¸ÖУ¬ÓÐÒ»¸ö·½°¸ÔÚʵ¼Ê²Ù×÷Öа²È«ÐÔ´æÔÚÎÊÌ⣬¸Ã·½°¸ÊÇ
ÒÒ
ÒÒ
 £¨Ìî¼×¡¢ÒÒ»ò±û£©£¬Ô­ÒòÊÇ
NaOHÓëCO2·´Ó¦£¬×¶ÐÎÆ¿ÄÚѹǿ½µµÍ£¬ÔÚ´óÆøѹµÄ×÷ÓÃÏ£¬ÆøÇòÕʹ󣬿ÉÄܻᷢÉú±¬Õ¨
NaOHÓëCO2·´Ó¦£¬×¶ÐÎÆ¿ÄÚѹǿ½µµÍ£¬ÔÚ´óÆøѹµÄ×÷ÓÃÏ£¬ÆøÇòÕʹ󣬿ÉÄܻᷢÉú±¬Õ¨
£®
£¨4£©ÇëÉè¼ÆÒ»¸öʵÑé¼ìÑéÉú³ÉµÄ²úÎïNa2CO3ÖеÄÒõÀë×Ó£®£¨¼òÊö²Ù×÷²½Öè¡¢ËùÓÃÊÔ¼Á¡¢ÊµÑéÏÖÏóºÍ½áÂÛ£®£©
£¨5£©ÊµÑéÊÒÖÐÈôÐèÓÃ44.8L£¨±ê׼״̬£©CO2£¬ÏÖÓú¬CaCO390%ʯ»ÒʯÓë×ãÁ¿µÄÑÎËá·´Ó¦£¬ÖÁÉÙÐèÒªÕâÖÖʯ»Òʯ
222.2
222.2
g£¨½á¹û±£ÁôһλСÊý£©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ϊ̽¾¿CO2Óë¹ýÁ¿µÄNaOHÈÜҺȷʵ·¢ÉúÁË»¯Ñ§·´Ó¦£¬¼×¡¢ÒÒ¡¢±ûÈýλͬѧÉè¼ÆÁËÏÂÁÐÈýÖÖʵÑé×°Öã¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¾«Ó¢¼Ò½ÌÍø
£¨1£©Çëд³öCO2Óë¹ýÁ¿µÄNaOHÈÜÒº·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
 
£®
£¨2£©Ñ¡ÔñÈÎÒâÒ»ÖÖʵÑé×°Ö㬼òÊöÔ¤¼Æ³öÏÖµÄʵÑéÏÖÏ󣬽âÊͲúÉú¸ÃʵÑéÏÖÏóµÄÔ­Òò£®ÄãÑ¡ÔñµÄʵÑé×°ÖÃÊÇ
 
£¬ÊµÑéÏÖÏóÊÇ
 
£®
 
½âÊͲúÉú¸ÃʵÑéÏÖÏóµÄÔ­Òò
 
£®
£¨3£©¼×¡¢ÒÒ¡¢±ûͬѧÉè¼ÆµÄÈý¸ö·½°¸ÖУ¬ÓÐÒ»¸ö·½°¸ÔÚʵ¼Ê²Ù×÷ÖпÉÐÐÐԺͰ²È«ÐÔ´æÔÚÎÊÌ⣬¸Ã·½°¸ÊÇ
 
£®£¨Ìî¼×¡¢ÒÒ»ò±û£©
£¨4£©ÇëÉè¼ÆÒ»¸öʵÑé¼ìÑéÉú³ÉµÄ²úÎïÖк¬ÓÐNa2CO3£®£¨¼òÊöËùÓÃÊÔ¼Á¡¢ÊµÑéÏÖÏóºÍ½áÂÛ£®£©
 
£®
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ij¿ÎÍâ»î¶¯Ð¡×éΪ̽¾¿CO2Óë¹ýÁ¿µÄNaOHÈÜҺȷʵ·¢ÉúÁË»¯Ñ§·´Ó¦£¬¼×¡¢ÒÒ¡¢±ûÈýλͬѧÉè¼ÆÁËÏÂÁÐÈýÖÖʵÑé×°Öã¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺

 

(1)¼××°ÖÃÖÐCO2Óë¹ýÁ¿µÄNaOH·´Ó¦µÄÀë×Ó·½³Ìʽ                                       ¡£

(2)±û×°ÖÃʵÑéÏÖÏóÊÇ                                                      £¬½âÊͲúÉú¸ÃʵÑéÏÖÏóµÄÔ­Òò                                                              

                                                                     ¡£

(3)¼×¡¢ÒÒ¡¢±ûͬѧÉè¼ÆµÄÈý¸ö·½°¸ÖУ¬ÓÐÒ»¸ö·½°¸ÔÚʵ¼Ê²Ù×÷Öа²È«ÐÔ´æÔÚÎÊÌ⣬¸Ã·½°¸ÊÇ                     (Ìî¼×¡¢ÒÒ»ò±û)£¬Ô­ÒòÊÇ                                          

                                                                  ¡£

 (4)ÇëÉè¼ÆÒ»¸öʵÑé¼ìÑéÉú³ÉµÄ²úÎïNa2CO3ÖеÄÒõÀë×Ó¡£(¼òÊö²Ù×÷²½Öè¡¢ËùÓÃÊÔ¼Á¡¢ÊµÑéÏÖÏóºÍ½áÂÛ¡£)                                                                   

                                                                                             

(5)ʵÑéÊÒÖÐÈôÐèÓÃ44.8 L(±ê׼״̬)CO2 £¬ÏÖÓú¬CaCO3 90%ʯ»ÒʯÓë×ãÁ¿µÄÑÎËá·´Ó¦£¬ÖÁÉÙÐèÒªÕâÖÖʯ»Òʯ              g

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêËÄ´¨Ê¡³É¶¼ÆßÖиßÒ»ÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

ij¿ÎÍâ»î¶¯Ð¡×éΪ̽¾¿CO2Óë¹ýÁ¿µÄNaOHÈÜҺȷʵ·¢ÉúÁË»¯Ñ§·´Ó¦£¬¼×¡¢ÒÒ¡¢±ûÈýλͬѧÉè¼ÆÁËÏÂÁÐÈýÖÖʵÑé×°Öã¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)¼××°ÖÃÖÐCO2Óë¹ýÁ¿µÄNaOH·´Ó¦µÄÀë×Ó·½³Ìʽ                                     ¡£
(2)±û×°ÖÃʵÑéÏÖÏóÊÇ                                                     £¬½âÊͲúÉú¸ÃʵÑéÏÖÏóµÄÔ­Òò                                                              
                                                                    ¡£
(3)¼×¡¢ÒÒ¡¢±ûͬѧÉè¼ÆµÄÈý¸ö·½°¸ÖУ¬ÓÐÒ»¸ö·½°¸ÔÚʵ¼Ê²Ù×÷Öа²È«ÐÔ´æÔÚÎÊÌ⣬¸Ã·½°¸ÊÇ                   (Ìî¼×¡¢ÒÒ»ò±û)£¬Ô­ÒòÊÇ                                          
                                                                 ¡£
(4)ÇëÉè¼ÆÒ»¸öʵÑé¼ìÑéÉú³ÉµÄ²úÎïNa2CO3ÖеÄÒõÀë×Ó¡£(¼òÊö²Ù×÷²½Öè¡¢ËùÓÃÊÔ¼Á¡¢ÊµÑéÏÖÏóºÍ½áÂÛ¡£)                                                                  
                                                                                           
(5)ʵÑéÊÒÖÐÈôÐèÓÃ44.8 L(±ê׼״̬)CO2 £¬ÏÖÓú¬CaCO3 90%ʯ»ÒʯÓë×ãÁ¿µÄÑÎËá·´Ó¦£¬ÖÁÉÙÐèÒªÕâÖÖʯ»Òʯ              g

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêËÄ´¨Ê¡¸ßÒ»ÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

ij¿ÎÍâ»î¶¯Ð¡×éΪ̽¾¿CO2Óë¹ýÁ¿µÄNaOHÈÜҺȷʵ·¢ÉúÁË»¯Ñ§·´Ó¦£¬¼×¡¢ÒÒ¡¢±ûÈýλͬѧÉè¼ÆÁËÏÂÁÐÈýÖÖʵÑé×°Öã¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺

 

(1)¼××°ÖÃÖÐCO2Óë¹ýÁ¿µÄNaOH·´Ó¦µÄÀë×Ó·½³Ìʽ                                       ¡£

(2)±û×°ÖÃʵÑéÏÖÏóÊÇ                                                      £¬½âÊͲúÉú¸ÃʵÑéÏÖÏóµÄÔ­Òò                                                               

                                                                     ¡£

(3)¼×¡¢ÒÒ¡¢±ûͬѧÉè¼ÆµÄÈý¸ö·½°¸ÖУ¬ÓÐÒ»¸ö·½°¸ÔÚʵ¼Ê²Ù×÷Öа²È«ÐÔ´æÔÚÎÊÌ⣬¸Ã·½°¸ÊÇ                     (Ìî¼×¡¢ÒÒ»ò±û)£¬Ô­ÒòÊÇ                                          

                                                                  ¡£

 (4)ÇëÉè¼ÆÒ»¸öʵÑé¼ìÑéÉú³ÉµÄ²úÎïNa2CO3ÖеÄÒõÀë×Ó¡£(¼òÊö²Ù×÷²½Öè¡¢ËùÓÃÊÔ¼Á¡¢ÊµÑéÏÖÏóºÍ½áÂÛ¡£)                                                                  

                                                                                             

(5)ʵÑéÊÒÖÐÈôÐèÓÃ44.8 L(±ê׼״̬)CO2 £¬ÏÖÓú¬CaCO3 90%ʯ»ÒʯÓë×ãÁ¿µÄÑÎËá·´Ó¦£¬ÖÁÉÙÐèÒªÕâÖÖʯ»Òʯ              g

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸