ijͬѧÉè¼ÆÁËÒ»¸ö¼òµ¥µÄʵÑ飨ÈçͼËùʾ£©£¬ÒԲⶨþÂÁºÏ½ðÖÐÂÁµÄÖÊÁ¿·ÖÊý¡£¿É¹©Ñ¡ÓõÄÊÔ¼ÁÓУºÅ¨H2SO4¡¢Å¨ÏõËá¡¢6 mol?l-1 NaOHÈÜÒº¡£

ÇëÌîдÏÂÁпհףº

£¨1£©ÓйØÊµÑé²Ù×÷£ºa¡¢ÍùÊÔ¹ÜÖзÅÈëÊÊÁ¿µÄÂÁºÏ½ðÑùÆ·£»b¡¢´Ó·ÖҺ©¶·ÍùÊÔ¹ÜÖмÓÈë¹ýÁ¿µÄAÈÜÒº£»c¡¢¼ì²é×°ÖÃµÄÆøÃÜÐÔ£»d¡¢²â¶¨ÊÕ¼¯µ½µÄË®µÄÌå»ý¡£

ÕýÈ·µÄ²Ù×÷˳ÐòΪ_________________________________________¡£

£¨2£©AÈÜÒº¿ÉÑ¡ÓÃ___________________________________________

£¨3£©Ð´³öʵÑéÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ:____________________¡£

£¨4£©ÈôʵÑéÖвâµÃÑùÆ·µÄÖÊÁ¿ÎªW g  £¬ÇâÆøµÄÌå»ýΪa  L £¨±ê×¼×´¿ö£©£¬ÔòÑùÆ·ÖÐALµÄÖÊÁ¿·ÖÊýΪ_______________________________________¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijͬѧÉè¼ÆÁËÒ»¸ö¼òµ¥µÄʵÑ飨ÈçͼËùʾ£©£¬ÒԲⶨþÂÁºÏ½ðÖÐÂÁµÄÖÊÁ¿·ÖÊý£®¿É¹©Ñ¡ÓõÄÊÔ¼ÁÓУºÅ¨H2SO4¡¢Å¨ÏõËá¡¢6mol?L-1 NaOHÈÜÒº£®ÇëÌîдÏÂÁпհףº
ÓйØÊµÑé²Ù×÷£º¢ÙÍùÊÔ¹ÜÖзÅÈëÊÊÁ¿µÄÂÁºÏ½ðÑùÆ·£»¢Ú´Ó·ÖҺ©¶·ÍùÊÔ¹ÜÖмÓÈë¹ýÁ¿µÄAÈÜÒº£»¢Û¼ì²é×°ÖÃµÄÆøÃÜÐÔ£»¢Ü²â¶¨ÊÕ¼¯µ½µÄË®µÄÌå»ý£®
£¨1£©ÕýÈ·µÄ²Ù×÷˳ÐòΪ
¢Û¡ú¢Ù¡ú¢Ú¡ú¢Ü
¢Û¡ú¢Ù¡ú¢Ú¡ú¢Ü
£»
£¨2£©AÈÜÒº¿ÉÑ¡ÓÃ
NaOHÈÜÒº
NaOHÈÜÒº
£»Ð´³öʵÑéÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
2Al+2NaOH+2H2O¨T2NaAlO2+3H2¡ü
2Al+2NaOH+2H2O¨T2NaAlO2+3H2¡ü
£»
£¨3£©ÈôʵÑéÖвâµÃÑùÆ·µÄÖÊÁ¿ÎªWg£¬ÇâÆøµÄÌå»ýΪaL £¨±ê×¼×´¿ö£©£¬ÔòÑùÆ·ÖÐAlµÄÖÊÁ¿·ÖÊýΪ
18a
22.4w
¡Á100%
18a
22.4w
¡Á100%
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨7·Ö£©Ä³Í¬Ñ§Éè¼ÆÁËÒ»¸ö¼òµ¥µÄʵÑ飨ÈçͼËùʾ£©£¬ÒԲⶨþÂÁºÏ½ðÖÐÂÁµÄÖÊÁ¿·ÖÊý¡£¿É¹©Ñ¡ÓõÄÊÔ¼ÁÓУºÅ¨H2SO4¡¢Å¨ÏõËá¡¢6 mol¡¤L-1 NaOHÈÜÒº¡£

ÇëÌîдÏÂÁпհףº

£¨1£©ÓйØÊµÑé²Ù×÷£ºa¡¢ÍùÊÔ¹ÜÖзÅÈëÊÊÁ¿µÄÂÁºÏ½ðÑùÆ·£»b¡¢´Ó·ÖҺ©¶·ÍùÊÔ¹ÜÖмÓÈë¹ýÁ¿µÄAÈÜÒº£»c¡¢¼ì²é×°ÖÃµÄÆøÃÜÐÔ£»d¡¢²â¶¨ÊÕ¼¯µ½µÄË®µÄÌå»ý¡£

ÕýÈ·µÄ²Ù×÷˳ÐòΪ_______________________________£¨Ìî×Öĸ£©¡£

£¨2£©AÈÜÒº¿ÉÑ¡ÓÃ___________________________________________

£¨3£©Ð´³öʵÑéÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ:_________________________________________¡£

£¨4£©ÈôʵÑéÖвâµÃÑùÆ·µÄÖÊÁ¿ÎªWg £¬ÇâÆøµÄÌå»ýΪa L£¨±ê×¼×´¿ö£©£¬ÔòÑùÆ·ÖÐAlµÄÖÊÁ¿·ÖÊýΪ_       __¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijͬѧÉè¼ÆÁËÒ»¸ö¼òµ¥µÄʵÑ飨ÈçͼËùʾ£©£¬ÒԲⶨþÂÁºÏ½ðÖÐÂÁµÄÖÊÁ¿·ÖÊý¡£¿É¹©Ñ¡ÓõÄÊÔ¼ÁÓУºÅ¨H2SO4¡¢Å¨ÏõËá¡¢6 mol¡¤l-1 NaOHÈÜÒº¡£

            

ÇëÌîдÏÂÁпհ×

£¨1£©ÓйØÊµÑé²Ù×÷£ºa¡¢ÍùÊÔ¹ÜÖзÅÈëÊÊÁ¿µÄÂÁºÏ½ðÑùÆ·£»b¡¢´Ó·ÖҺ©¶·ÍùÊÔ¹ÜÖмÓÈë¹ýÁ¿µÄAÈÜÒº£»c¡¢¼ì²é×°ÖÃµÄÆøÃÜÐÔ£»d¡¢²â¶¨ÊÕ¼¯µ½µÄË®µÄÌå»ý¡£ÕýÈ·µÄ²Ù×÷˳ÐòÊÇ                  

£¨2£©AÖпÉÑ¡ÓõÄÈÜÒºÊÇ          

£¨3£©ÊµÑéÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                            

£¨4£©ÈôʵÑéÖвâµÃÑùÆ·µÄÖÊÁ¿ÎªW g £¬ÇâÆøµÄÌå»ýΪaL £¨±ê×¼×´¿ö£©£¬ÔòÑùÆ·ÖÐAlµÄÖÊÁ¿·ÖÊýΪ              

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ì¹ã¶«Ê¡¸ßÒ»11ÔÂÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

£¨7·Ö£©Ä³Í¬Ñ§Éè¼ÆÁËÒ»¸ö¼òµ¥µÄʵÑ飨ÈçͼËùʾ£©£¬ÒԲⶨþÂÁºÏ½ðÖÐÂÁµÄÖÊÁ¿·ÖÊý¡£¿É¹©Ñ¡ÓõÄÊÔ¼ÁÓУºÅ¨H2SO4¡¢Å¨ÏõËá¡¢6 mol¡¤L-1 NaOHÈÜÒº¡£

ÇëÌîдÏÂÁпհףº

£¨1£©ÓйØÊµÑé²Ù×÷£ºa¡¢ÍùÊÔ¹ÜÖзÅÈëÊÊÁ¿µÄÂÁºÏ½ðÑùÆ·£»b¡¢´Ó·ÖҺ©¶·ÍùÊÔ¹ÜÖмÓÈë¹ýÁ¿µÄAÈÜÒº£»c¡¢¼ì²é×°ÖÃµÄÆøÃÜÐÔ£»d¡¢²â¶¨ÊÕ¼¯µ½µÄË®µÄÌå»ý¡£

ÕýÈ·µÄ²Ù×÷˳ÐòΪ_______________________________£¨Ìî×Öĸ£©¡£

£¨2£©AÈÜÒº¿ÉÑ¡ÓÃ___________________________________________

£¨3£©Ð´³öʵÑéÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ:_________________________________________¡£

£¨4£©ÈôʵÑéÖвâµÃÑùÆ·µÄÖÊÁ¿ÎªWg £¬ÇâÆøµÄÌå»ýΪa L£¨±ê×¼×´¿ö£©£¬ÔòÑùÆ·ÖÐAlµÄÖÊÁ¿·ÖÊýΪ_       __¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ì¼ªÁÖÊ¡¸ßÒ»ÉÏѧÆÚÆÚÄ©¿¼ÊÔÀí¿Æ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

ijͬѧÉè¼ÆÁËÒ»¸ö¼òµ¥µÄʵÑ飨ÈçͼËùʾ£©£¬ÒԲⶨþÂÁºÏ½ðÖÐÂÁµÄÖÊÁ¿·ÖÊý¡£¿É¹©Ñ¡ÓõÄÊÔ¼ÁÓУºÅ¨H2SO4¡¢Å¨ÏõËá¡¢6 mol¡¤l-1 NaOHÈÜÒº¡£

            

ÇëÌîдÏÂÁпհ×

£¨1£©ÓйØÊµÑé²Ù×÷£ºa¡¢ÍùÊÔ¹ÜÖзÅÈëÊÊÁ¿µÄÂÁºÏ½ðÑùÆ·£»b¡¢´Ó·ÖҺ©¶·ÍùÊÔ¹ÜÖмÓÈë¹ýÁ¿µÄAÈÜÒº£»c¡¢¼ì²é×°ÖÃµÄÆøÃÜÐÔ£»d¡¢²â¶¨ÊÕ¼¯µ½µÄË®µÄÌå»ý¡£ÕýÈ·µÄ²Ù×÷˳ÐòÊÇ                  

£¨2£©AÖпÉÑ¡ÓõÄÈÜÒºÊÇ          

£¨3£©ÊµÑéÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                            

£¨4£©ÈôʵÑéÖвâµÃÑùÆ·µÄÖÊÁ¿ÎªW g £¬ÇâÆøµÄÌå»ýΪaL £¨±ê×¼×´¿ö£©£¬ÔòÑùÆ·ÖÐAlµÄÖÊÁ¿·ÖÊýΪ              

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸