Question

¡¾ÌâÄ¿¡¿ÈçͼװÖÃËùʾ£¬C¡¢D¡¢E¡¢F¡¢X¡¢Y¾ùΪ¶èÐԵ缫£¬¼×¡¢ÒÒÖÐÈÜÒºÌå»ý¾ùΪ500mLÇÒÈÜҺŨ¶È¾ùÏàͬ(¼ÙÉèͨµçÇ°ºóÈÜÒºÌå»ý²»±ä)£¬A¡¢BΪÍâ½ÓÖ±Á÷µçÔ´µÄÁ½¼«£®½«Ö±Á÷µçÔ´½Óͨºó£¬F¼«¸½½ü³ÊºìÉ«£®Çë»Ø´ð£º

£¨1£©B¼«ÊǵçÔ´µÄ_____¼«£¬Ò»¶Îʱ¼äºó£¬¼×ÖÐÈÜÒºÑÕÉ«Öð½¥±ä____£¬¶¡ÖÐX¼«¸½½üµÄÑÕÉ«Öð½¥±ädz£¬Y¼«¸½½üµÄÑÕÉ«Öð½¥±äÉÕâ±íÃ÷Fe(OH)3½ºÌå΢Á£´ø____ºÉ¡£

£¨2£©µç½âÒ»¶Îʱ¼äºó¼×¡¢ÒÒ×°ÖÃÖеÄC¡¢D¡¢E¡¢Fµç¼«¾ù·Ö±ðÖ»ÓÐÒ»ÖÖµ¥ÖÊÉú³Éʱ£¬¶ÔÓ¦µ¥ÖʵÄÎïÖʵÄÁ¿Ö®±ÈΪ______________£¬ÒÒÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ__________________________________£¬ÈôҪʹµç½âºóµÄ¼××°ÖÃÖеÄÈÜÒº»Ö¸´µ½Ô­Å¨¶ÈÔòÐè¼ÓÈëÒ»¶¨Á¿µÄ_________(Ìѧʽ)¡£

£¨3£©ÏÖÓñû×°ÖøøÍ­¼þ¶ÆÒø£¬ÔòHÓ¦¸ÃÊÇ______(Ìî¡°¶Æ²ã½ðÊô¡±»ò¡°¶Æ¼þ¡±)£¬µ±¶Æ¼þÉÏÎö³ö5.4gÒøʱ£¬ ¼×¡¢ÒÒÖÐÈÜÒºµÄpH·Ö±ðΪ_____ºÍ_____

Answer 1

¡¾´ð°¸¡¿ ¸º dz Õý 1:2:2:2 2NaCl£«2H2O2NaOH£«H2¡ü£«Cl2¡ü CuO ¶Æ¼þ 1 13

¡¾½âÎö¡¿ÊÔÌâ·ÖÎö£º±¾Ì⿼²é¶à³Ø´®Áª×°Öã¬Éæ¼°×°ÖõķÖÎö£¬½ºÌåµÄµçÓ¾£¬µç»¯Ñ§µÄ¼ÆË㣬µç¶Æ¡£½ÓͨµçÔ´£¬F¼«¸½½ü³ÊºìÉ«£¬FΪÒõ¼«£¬EΪÑô¼«£¬ÔòAΪµçÔ´µÄÕý¼«£¬BΪµçÔ´µÄ¸º¼«¡£

£¨1£©B¼«ÊǵçÔ´µÄ¸º¼«¡£C¡¢DΪ¶èÐԵ缫£¬¼×ÖÐΪCuSO4ÈÜÒº£¬¼×Öеç½â·´Ó¦·½³ÌʽΪ2CuSO4+2H2O2Cu+2H2SO4+O2¡ü£¬¼×ÖÐCu2+Ũ¶È¼õС£¬¼×ÖÐÈÜÒºµÄÑÕÉ«Öð½¥±ädz¡£¸ù¾ÝͼʾXΪÑô¼«£¬YΪÒõ¼«£¬Y¼«¸½½üµÄÑÕÉ«Öð½¥±äÉ±íÃ÷Fe£¨OH£©3½ºÌå΢Á£´øÕýµçºÉ¡£

£¨2£©CΪÑô¼«£¬C¼«µÄµç¼«·´Ó¦Ê½Îª4OH--4e-=O2¡ü+2H2O£¬DΪÒõ¼«£¬D¼«µÄµç¼«·´Ó¦Ê½ÎªCu2++2e-=Cu£¬EΪÑô¼«£¬E¼«µÄµç¼«·´Ó¦Ê½Îª2Cl--2e-=Cl2¡ü£¬FΪÒõ¼«£¬F¼«µÄµç¼«·´Ó¦Ê½Îª2H++2e-=H2¡ü£¬¸ù¾Ýµç·ÖÐͨ¹ýµç×ÓÎïÖʵÄÁ¿ÏàµÈ£¬C¡¢D¡¢E¡¢FÉú³ÉµÄµ¥ÖÊÎïÖʵÄÁ¿Ö®±ÈΪ1:2:2:2¡£ÒÒÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2NaCl+2H2O2NaOH+H2¡ü+Cl2¡ü¡£¼××°ÖÃÖз¢ÉúµÄ·´Ó¦Îª2CuSO4+2H2O2Cu+2H2SO4+O2¡ü£¬¸ù¾ÝÔ­×ÓÊغ㣬Ҫʹ¼××°ÖÃÖеÄÈÜÒº»Ö¸´µ½Ô­Å¨¶ÈÐè¼ÓÈëÒ»¶¨Á¿µÄCuO¡£

£¨3£©±û×°ÖÃÖÐGΪÑô¼«£¬HΪÒõ¼«£¬¸ù¾Ýµç¶ÆÔ­Àí£¬¸øÍ­¼þ¶ÆÒø£¬HΪ¶Æ¼þ£¬¶Æ¼þÉϵĵ缫·´Ó¦Ê½ÎªAg++e-=Ag£¬n£¨Ag£©==0.05mol£¬µç·ÖÐͨ¹ýµÄµç×ÓÎïÖʵÄÁ¿Îª0.05mol£»¼×Öз´Ó¦Îª2Cu2++2H2O2Cu+4H++O2¡ü~4e-£¬¼×ÖÐÉú³Én£¨H+£©=n£¨e-£©=0.05mol£¬c£¨H+£©==0.1mol/L£¬¼×ÖÐÈÜÒºµÄpH=1£»ÒÒÖз´Ó¦Îª2Cl-+2H2O2OH-+H2¡ü+Cl2¡ü~2e-£¬ÒÒÖÐÉú³Én£¨OH-£©=n£¨e-£©=0.05mol£¬c£¨OH-£©==0.1mol/L£¬c£¨H+£©=110-13mol/L£¬ÒÒÖÐÈÜÒºµÄpH=13¡£