ʵÑéÊÒÖÆÈ¡ÒÒÏ©£¬³£Òòζȹý¸ß¶øʹÒÒ´¼ºÍŨÁòËá·´Ó¦Éú³ÉÉÙÁ¿µÄ¶þÑõ»¯Áò¡£ÓÐÈËÉè¼ÆÈçͼËùʾʵÑéÒÔÈ·ÈÏÉÏÊö»ìºÏÆøÌåÖÐÓÐÒÒÏ©ºÍ¶þÑõ»¯Áò¡£ÊԻشðÏÂÁÐÎÊÌâ

£¨1£©ÊµÑéÊÒÖƱ¸ÒÒÏ©µÄ»¯Ñ§·½³Ìʽ                          ¡£Éýε½140¡æʱµÄ¸±·´Ó¦²úÎïµÄ½á¹¹¼òʽ                          

£¨2£©Í¼ÖТ١¢¢Ú¡¢¢Û¡¢¢Ü×°ÖÿÉÊ¢·ÅµÄÊÔ¼ÁÊÇ£º¢Ù      £»¢Ú     £»¢Û     £»¢Ü      ¡£(½«ÏÂÁÐÓйØÊÔ¼ÁµÄÐòºÅÌîÈë¿Õ¸ñÄÚ)

      A£®Æ·ºìÈÜÒº    B£®NaOHÈÜÒº         C£®Å¨ÁòËá    D£®ËáÐÔKMn04ÈÜÒº

£¨3£©ÄÜ˵Ã÷¶þÑõ»¯ÁòÆøÌå´æÔÚµÄÏÖÏóÊÇ                            

£¨4£©Ê¹ÓÃ×°ÖâڵÄÄ¿µÄÊÇ                                

£¨5£©Ê¹ÓÃ×°Öâ۵ÄÄ¿µÄÊÇ                              ¡£

£¨6£©È·¶¨º¬ÓÐÒÒÏ©µÄÏÖÏóÊÇ                              

(11·Ö) ·½³Ìʽ2·Ö ÆäÓà1·Ö

   (1)CH3CH2OHCH2£½CH2¡ü£«H2O     CH3CH2£­O£­CH2CH3

£¨2£©¢Ù   A   £»¢Ú  B   £»¢Û A    £»¢Ü  D    ¡£

£¨3£©×°ÖâÙÖÐÆ·ºìÈÜÒºÍÊÉ«£¨4£©³ýµô¶þÑõ»¯ÁòÒÔÃâ¸ÉÈÅÒÒÏ©µÄÐÔÖÊʵÑé

£¨5£©¼ìÑé¶þÑõ»¯ÁòÊÇ·ñ³ý¾¡    £¨6£©¢Û ÖеÄÈÜÒºÍÊÉ«£¬¢ÜÖеÄÈÜÒº²»ÍÊÉ«

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ʵÑéÊÒÖÆÈ¡ÒÒÏ©£¬³£Òòζȹý¸ß¶øʹÒÒ´¼ºÍŨH2SO4·´Ó¦Éú³ÉÉÙÁ¿µÄ¶þÑõ»¯Áò£¬ÓÐÈËÉè¼ÆÏÂÁÐʵÑéÒÔÈ·¶¨ÉÏÊö»ìºÏÆøÌåÖÐÓÐÒÒÏ©ºÍ¶þÑõ»¯Áò£®
£¨1£©ÊµÑéÊÒÖÆÈ¡ÒÒÏ©µÄ»¯Ñ§·½³Ìʽ
CH3CH2OH
ŨÁòËá
170¡æ
CH2=CH2¡ü+H2O
CH3CH2OH
ŨÁòËá
170¡æ
CH2=CH2¡ü+H2O
£¬·´Ó¦ÀàÐÍΪ
ÏûÈ¥·´Ó¦
ÏûÈ¥·´Ó¦
£®
£¨2£©¢ñ¡¢¢ò¡¢¢ó¡¢¢ô×°ÖÿÉÊ¢·ÅµÄÊÔ¼ÁÊÇ¢ñ
B
B
£»¢ò
C
C
£»¢ó£»
B
B
¢ô
A
A
£®£¨½«ÏÂÁÐÓйØÊÔ¼ÁµÄÐòºÅÌîÈë¿Õ¸ñÄÚ£©
A£®ËáÐÔKMnO4   B£®Æ·ºìÈÜÒº    C£®NaOHÈÜÒº    D£®Å¨H2SO4
£¨3£©ÄÜ˵Ã÷¶þÑõ»¯ÁòÆøÌå´æÔÚµÄÏÖÏóÊÇ
×°ÖâñÖеÄÆ·ºìÈÜÒºÍÊÉ«
×°ÖâñÖеÄÆ·ºìÈÜÒºÍÊÉ«
£®
£¨4£©×°ÖâòÖпªÊ¼·´Ó¦Ê±µÄÀë×Ó·½³ÌʽÊÇ
SO2+2OH-=SO32-+H2O
SO2+2OH-=SO32-+H2O
£®
£¨5£©Ê¹ÓÃ×°ÖâóµÄÄ¿µÄÊÇ
¼ìÑéSO2ÊÇ·ñ³ý¾¡
¼ìÑéSO2ÊÇ·ñ³ý¾¡
£®
£¨6£©È·Ö¤º¬ÓÐÒÒÏ©µÄÏÖÏó
¢óÖеÄÆ·ºì²»ÍÊÉ«£¬¢ôÖеĸßÃÌËá¼ØÈÜÒºÍÊÉ«
¢óÖеÄÆ·ºì²»ÍÊÉ«£¬¢ôÖеĸßÃÌËá¼ØÈÜÒºÍÊÉ«
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍøʵÑéÊÒÖÆÈ¡ÒÒÏ©£¬³£Òòζȹý¸ß¶øʹÒÒ´¼ºÍŨH2SO4·´Ó¦Éú³ÉÉÙÁ¿µÄ¶þÑõ»¯Áò£¬ÓÐÈËÉè¼ÆÏÂÁÐʵÑéÒÔÈ·ÈÏÉÏÊö»ìºÍÆøÌåÖÐÓÐÒÒÏ©ºÍ¶þÑõ»¯Áò£®I¡¢¢ò¡¢¢ó¡¢¢ô×°ÖÿÉÊ¢·ÅµÄÊÔ¼Á·Ö±ðÊÇ£ºI¡¢Æ·ºìÈÜÒº¢ò¡¢NaOHÈÜÒº¢ó¡¢Æ·ºìÈÜÒº¢ô¡¢ËáÐÔKMnO4
£¨1£©ÄÜ˵Ã÷¶þÑõ»¯ÁòÆøÌå´æÔÚµÄÏÖÏóÊÇ
 

£¨2£©Ê¹ÓÃ×°ÖâòÖеÄÄ¿µÄÊÇ
 
£¬
£¨3£©Ê¹ÓÃ×°ÖâóµÄÄ¿µÄÊÇ
 
£¬
£¨4£©È·Ö¤º¬ÓÐÒÒÏ©µÄÏÖÏóÊÇ
 
£®
£¨5£©Ð´³öʵÑéÊÒÖÆÈ¡ÒÒÏ©µÄ»¯Ñ§·½³Ìʽ£®
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ʵÑéÊÒÖÆÈ¡ÒÒÏ©£¬³£Òòζȹý¸ß¶øʹÒÒ´¼ºÍŨH2SO4·´Ó¦Éú³ÉÉÙÁ¿µÄ¶þÑõ»¯Áò£¬ÓÐÈËÉè¼ÆÏÂÁÐʵÑéÒÔÈ·ÈÏÉÏÊö»ìºÏÆøÌåÖÐÓÐÒÒÏ©ºÍ¶þÑõ»¯Áò¡£

£¨1£©Ð´³öʵÑéÊÒÖÆÒÒÏ©µÄ·´Ó¦·½³Ìʽ£º                                               

£¨2£©¢ñ¡¢¢ò¡¢¢ó¡¢¢ô×°ÖÿÉÊ¢·ÅµÄÊÔ¼ÁÊÇ£º¢ñ___________£»¢ò___________£»¢ó___________£»¢ô£ºÅ¨äåË®£¨½«ÏÂÁÐÓйØÊÔ¼ÁµÄÐòºÅÌîÈë¿Õ¸ñÄÚ£©¡£

A£®Æ·ºìÈÜÒº    B£®NaOHÈÜÒº    C£®Å¨H2SO4      D£®ËáÐÔKMnO4ÈÜÒº

£¨3£©ÄÜ˵Ã÷¶þÑõ»¯ÁòÆøÌå´æÔÚµÄÏÖÏóÊÇ_______________________________¡£

£¨4£©È·Ö¤º¬ÓÐÒÒÏ©µÄÏÖÏóÊÇ_________________________________________¡£

£¨5£©Ð´³ö¢ôÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º                                 ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(13·Ö)ʵÑéÊÒÖÆÈ¡ÒÒÏ©£¬³£Òòζȹý¸ß¶øʹÒÒ´¼ºÍŨH2SO4·´Ó¦Éú³ÉÉÙÁ¿µÄ¶þÑõ»¯Áò£¬ÓÐÈËÉè¼ÆÏÂÁÐʵÑéÒÔÈ·¶¨ÉÏÊö»ìºÏÆøÌåÖÐÓÐÒÒÏ©ºÍ¶þÑõ»¯Áò¡£

(1)ʵÑéÊÒÖÆÈ¡ÒÒÏ©µÄ»¯Ñ§·½³Ìʽ_____________________£¬·´Ó¦ÀàÐÍΪ_______¡£

(2)¢ñ¡¢¢ò¡¢¢ó¡¢¢ô×°ÖÿÉÊ¢·ÅµÄÊÔ¼ÁÊÇ¢ñ______;¢ò_____;¢ó; _____¢ô_______¡£(½«ÏÂÁÐÓйØÊÔ¼ÁµÄÐòºÅÌîÈë¿Õ¸ñÄÚ)

A.ËáÐÔKMnO4   B. Æ·ºìÈÜÒº    C. NaOHÈÜÒº    D. ŨH2SO4

(3)ÄÜ˵Ã÷¶þÑõ»¯ÁòÆøÌå´æÔÚµÄÏÖÏóÊÇ__________________________________¡£

(4)×°ÖâòÖпªÊ¼·´Ó¦Ê±µÄÀë×Ó·½³ÌʽÊÇ______________________________¡£

(5)ʹÓÃ×°ÖâóµÄÄ¿µÄÊÇ______________________________________________¡£

(6)È·Ö¤º¬ÓÐÒÒÏ©µÄÏÖÏó_______________________________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ìºÓ±±Ê¡¸ß¶þÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

ʵÑéÊÒÖÆÈ¡ÒÒÏ©£¬³£Òòζȹý¸ß¶øʹÒÒ´¼ºÍŨÁòËá·´Ó¦Éú³ÉÉÙÁ¿µÄSO2¡£Ä³Í¬Ñ§Éè¼ÆÏÂÁÐʵÑéÒÔÈ·¶¨ÉÏÊö»ìºÏÆøÌåÖк¬ÓÐÒÒÏ©ºÍSO2¡£

£¨1£©I¡¢II¡¢III¡¢IV×°ÖÿÉÊ¢·ÅµÄÊÔ¼ÁÊÇ£ºI£º   II£º III£º   IV£º   £¨Ç뽫ÏÂÁÐÓйØÊÔ¼ÁµÄÐòºÅÌîÈë¿Õ¸ñÄÚ£©¡£

A£®Æ·ºìÈÜÒº         B£®NaOHÈÜÒº        C£®Å¨ÁòËá           D£®äåË®

£¨2£©ÄÜ˵Ã÷SO2ÆøÌå´æÔÚµÄÏÖÏóÊÇ                         £»

ʹÓÃ×°ÖÃIIµÄÄ¿µÄÊÇ                                 £»

ʹÓÃ×°ÖÃIIIµÄÄ¿µÄÊÇ                                £»

È·¶¨º¬ÓÐÒÒÏ©µÄÏÖÏóÊÇ                               ¡£

£¨3£©¢ôÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ             £»²úÎïµÄÃû³ÆÊÇ         ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸