Question

£¨1£©ÂÁÊǵؿÇÖк¬Á¿×î´óµÄ½ðÊô£¬ÂÁÖÊÇᣬȼÉÕʱ·ÅÈÈÁ¿¸ß£¬ÔÚ³£Î³£Ñ¹Ï£¬9gµÄÂÁ·ÛÍêȫȼÉÕÉú³É¹Ì̬µÄA₂O₃ʱ·Å³ö235kJµÄÈÈ£¬ÔòÕâ¸ö·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ______£»
£¨2£©ÖйúÊÇÊÀ½çÉÏ×î´óµÄµçÒ±ÂÁ¹ú¼ÒÖ®Ò»£¬µçÒ±ÂÁµÄÔ­ÁÏÊÇÑõ»¯ÂÁ£¬ÔÚÈÛÈÚϽøÐеç½â£¬ÊÔд³öµç½â·¨Ò±Á¶ÂÁµÄ·½³ÌʽΪ______£»
£¨3£©ÂÁÓÃ;ºÜ¹ã£¬Ôڵ绯ѧÖг£ÓÃÓڳ䵱µç¼«²ÄÁÏ£®°ÑÂÁºÍþÓõ¼ÏßÁ¬½Óºó£¬Èô²åÈ뵽ϡÁòËáÖУ¬ÔòÕý¼«ÊÇ______£¬²åÈëÇâÑõ»¯ÄÆÈÜÒºÖУ¬¸º¼«µÄµç¼«·´Ó¦Ê½ÊÇ______
£¨4£©ÖйúÊ×´´µÄº£ÑóÂÁ¿óµÆ£¬ÊÇÒÔÂÁ¡¢¿ÕÆøºÍº£Ë®ÎªÔ­ÁÏËùÉè¼ÆµÄÔ­µç³Ø£¬µ±°Ñµç³ØÖÃÓÚº£Ë®µç³Ø¾ÍÓнϴóµÄµçѹ£¬´Ëµç³ØµÄÕý¼«·´Ó¦Ê½Îª______£®
£¨5£©²ÉÓöèÐԵ缫´ÓNO₃^-¡¢SO₄^2-¡¢Cl^-¡¢Cu²⁺¡¢Mg²⁺¡¢H⁺ÖÐÑ¡³öÊʵ±µÄÀë×Ó×é³Éµç½âÖÊ£¬²¢¶ÔÆäÈÜÒº½øÐеç½â
¢ÙÈôÁ½¼«·Ö±ð·Å³öH₂ºÍO₂£¬Ôòµç½âÖʵĻ¯Ñ§Ê½Îª______£»
¢ÚÈôÒõ¼«Îö³ö½ðÊô£¬Ñô¼«·Å³öO₂£¬Ôòµç½âÖʵĻ¯Ñ§Ê½Îª______£®

Answer 1

£¨1£©9gÂÁµÄÎïÖʵÄÁ¿=

9g

27g/mol

=

1

3

mol£¬9gµÄÂÁ·ÛÍêȫȼÉÕÉú³É¹Ì̬µÄA₂O₃ʱ·Å³ö235kJµÄÈÈ£¬Ôò4molÂÁÍêȫȼÉշųö2820KJÈÈÁ¿£¬ËùÒÔÆäÈÈ»¯Ñ§·´Ó¦·½³ÌʽΪ£º
4Al£¨s£©+3O₂£¨g£©=2Al₂O₃£¨s£©£¬¡÷H=2820kJ/mol£»
¹Ê´ð°¸Îª£º4Al£¨s£©+3O₂£¨g£©=2Al₂O₃£¨s£©£¬¡÷H=2820kJ/mol£»
£¨2£©µç½âÈÛÈÚ̬Ñõ»¯ÂÁÉú³ÉÂÁºÍÑõÆø£¬µç½â·½³ÌʽΪ2Al₂O₃

µç½â  .

4Al+3O₂¡ü£»
¹Ê´ð°¸Îª£º2Al₂O₃

µç½â  .

4Al+3O₂¡ü£»
£¨3£©ÂÁ¡¢Ã¾¡¢Ï¡ÁòËá¹¹³ÉµÄÔ­µç³ØÖУ¬Õý¼«ÉÏÇâÀë×ӵõç×ÓÉú³ÉÇâÆø£¬µç¼«·´Ó¦Ê½Îª2H⁺+2e^-=H₂¡ü£¬ÂÁ¡¢Ã¾¡¢ÇâÑõ»¯ÄÆÈÜÒº¹¹³ÉµÄÔ­µç³ØÖУ¬ÂÁ×÷¸º¼«£¬Ã¾×÷Õý¼«£¬¸º¼«ÉÏÂÁʧµç×ÓºÍÇâÑõ¸ùÀë×Ó·´Ó¦Éú³ÉÆ«ÂÁËá¸ùÀë×ÓºÍË®£¬
µç¼«·´Ó¦Ê½ÎªAl-3e^-+4HO^-=AlO₂^-+2H₂O£»
¹Ê´ð°¸Îª£º2H⁺+2e^-=H₂¡ü£»Al-3e^-+4HO^-=AlO₂^-+2H₂O£»
£¨4£©ÂÁ¡¢¿ÕÆøºÍº£Ë®¹¹³ÉµÄÔ­µç³ØÖУ¬¸º¼«ÉÏÂÁʧµç×ÓÉú³ÉÂÁÀë×Ó£¬µç¼«·´Ó¦Ê½ÎªAl-3e^-=Al³⁺£»
¹Ê´ð°¸Îª£ºAl-3e^-=Al³⁺£»
£¨5£©¢ÙÈôÁ½¼«·Ö±ð·Å³öH₂ºÍO₂£¬ÔòÒõ¼«ÉÏÇâÀë×ӷŵ磬Ñô¼«ÉÏÇâÑõ¸ùÀë×ӷŵ磬¸ù¾ÝÒõÑôÀë×ӷŵç˳ÐòÖª£¬ÈÜÒºÖдæÔÚµÄÒõÀë×ÓΪº¬ÑõËá¸ùÀë×Ó£¬ÑôÀë×ÓΪÇâÀë×Ó»ò»îÆýðÊôÀë×Ó£¬ËùÒÔµç½âÖʵĻ¯Ñ§Ê½ÎªHNO₃¡¢H₂SO₄¡¢Mg£¨NO₃£©₂¡¢MgSO₄£»
¹Ê´ð°¸Îª£ºHNO₃¡¢H₂SO₄¡¢Mg£¨NO₃£©₂¡¢MgSO₄£»
¢ÚÈôÒõ¼«Îö³ö½ðÊô£¬¸ù¾ÝÀë×ӵķŵç˳ÐòÖª£¬ÈÜÒºÖк¬ÓÐHÖ®ºóµÄ²»»îÆýðÊôÑôÀë×Ó£¬Ñô¼«·Å³öO₂£¬ÔòÈÜÒºÖк¬Óк¬ÑõËá¸ùÀë×Ó£¬ËùÒÔµç½âÖʵĻ¯Ñ§Ê½ÎªCu£¨NO₃£©₂¡¢CuSO₄£»
¹Ê´ð°¸Îª£ºCu£¨NO₃£©₂¡¢CuSO₄£®