¡¾ÌâÄ¿¡¿Ä³ÖÆÌdz§ÒÔ¸ÊÕáΪԭÁÏÖÆÌÇ£¬Í¬Ê±µÃµ½´óÁ¿µÄ¸ÊÕáÔü£¬¶Ô¸ÊÕá½øÐÐ×ÛºÏÀûÓ㬲»½ö¿ÉÒÔÌá¸ß¾­¼ÃЧÒ棬¶øÇÒ»¹ÄÜ·ÀÖ¹»·¾³ÎÛȾ£¬ÏÖ°´ÒÔÏ·½Ê½½øÐУº

ÒÑÖªF¡¢H¾ùÊǾßÓÐÏãζµÄÒºÌ壬FΪEµÄÈý¾ÛºÏÎ²¢¾ßÌØÊâµÄÁùÔª»·×´¶Ô³Æ½á¹¹£¬ÊÔÌî¿Õ£º

£¨1£©AµÄÃû³Æ________£»DµÄͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽΪ________________¡£

£¨2£©E¡úGµÄ»¯Ñ§·½³Ìʽ_________________________¡£

£¨3£©G¡úHµÄ»¯Ñ§·½³Ìʽ_________________________¡£

£¨4£©FµÄ½á¹¹¼òʽ£º_____________________¡£

¡¾´ð°¸¡¿ ÏËάËØ CH3¡ªO¡ªCH3 CH3CH2OH+CH3COOHCH3COOCH2CH3+H2O

¡¾½âÎö¡¿Ê×ÏÈÓÉAµÄ·Ö×Óʽ£¨C6H10O5£©n¿ÉÖªA²»Êǵí·Û¾ÍÊÇÏËάËØ£¬ÁªÏµÉú»îʵ¼ÊÈ·¶¨AΪÏËάËØ£¬BΪÆÏÌÑÌÇ£¬DΪ¾Æ¾«£¬EΪÒÒÈ©¡£FΪEµÄÈý¾ÛÎÇÒ¾ßÓÐÌØÊâµÄÁùÔª»·×´¶Ô³Æ½á¹¹£¬ËùÒÔÒÀ¾Ý³É¼üÔ­ÀíÖ»ÄÜÊÇC=O·½Ê½¼Ó³ÉÉú³É¡£ÈçͼËùʾ£º¡££¨1£©AµÄÃû³ÆÏËάËØ£»DΪ¾Æ¾«£¬Æäͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽΪCH3¡ªO¡ªCH3£»£¨2£©E¡úGÊÇÒÒÈ©Ñõ»¯Éú³ÉÒÒËᣬ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º£»

£¨3£©G¡úHÒÒËáºÍÒÒ´¼ÔÚŨÁòËáµÄ´ß»¯Ï·´Ó¦Éú³ÉÒÒËáÒÒõ¥ºÍË®£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCH3CH2OH+CH3COOHCH3COOCH2CH3+H2O£»£¨4£©FµÄ½á¹¹¼òʽΪ£º¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Ä³ôÈËáõ¥µÄ·Ö×ÓʽΪC18H26O5£¬1mol¸Ãõ¥ÍêÈ«Ë®½â¿ÉµÃµ½1molôÈËáºÍ2molÒÒ´¼£¬¸ÃôÈËáµÄ·Ö×ÓʽΪ

A.C14H18O5B.C14H16O4C.C14H22O5D.C14H10O5

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿µªµÄÑõ»¯ÎïÊÇÖ÷ÒªµÄ¿ÕÆøÎÛȾÎĿǰÏû³ýÂÈÑõ»¯ÎïÎÛȾµÄ·½·¨ÓжàÖÖ¡£

(1)ÓÃCH4´ß»¯»¹Ô­µªÑõ»¯Îï¿ÉÒÔÏû³ýµªÑõ»¯ÎïµÄÎÛȾ¡£

CH4(g)£«4NO(g)£½2N2(g)£«CO2(g)£«2H2O(g) ¦¤H£½£­1160 kJ¡¤mol£­1£¨¢ñ£©

CH4(g)£«4NO2(g)£½4NO(g)£«CO2(g)£«2H2O(g) ¦¤H£½£­574 kJ¡¤mol£­1£¨¢ò£©

H2O(g)£½H2O(l) ¦¤H£½£­44£®0 kJ¡¤mol£­1£¨¢ó£©

¢Ùд³öCH4 (g)ÓëNO2 (g)·´Ó¦Éú³ÉN2 (g) ,CO2(g)ºÍH2O(l)µÄÈÈ»¯Ñ§·½³Ìʽ£º________

¢ÚΪÑо¿²»Í¬Ìõ¼þ϶ÔÉÏÊö·´Ó¦( ¢ò )µÄÓ°Ï죬ÔÚºãÎÂÌõ¼þÏÂ,Ïò2 L µÄºãÈÝÃܱÕÈÝÆ÷ÖмÓÈë0.2mol CH4ºÍ0.4mol NO2,10min·´Ó¦£¨¢ò£©´ïµ½Æ½ºâ£¬²âµÃl0minÄÚv(NO)=5¡Á10-3mol/(L¡¤min),Ôòƽºâºón(CH4)=___mol,NO2µÄת»¯ÂÊa1=_________.ÆäËüÌõ¼þ²»±ä£¬·´Ó¦ÔÚºãѹÌõ¼þϽøÐУ¬Æ½ºâʱNO2µÄת»¯ÂÊa2____a1(Ìî¡°´óÓÚ¡± СÓÚ¡±»ò¡° µÈÓÚ¡± )¡£

£¨2£©ÓûîÐÔÌ¿»¹Ô­·¨´¦ÀíµªÑõ»¯Îï¡£Óйط´Ó¦Îª£ºC(s)£«2NO(g)N2(g)£«CO2(g)ijÑо¿Ð¡×éÏòºãÈÝÃܱÕÈÝÆ÷¼ÓÈëÒ»¶¨Á¿µÄ»îÐÔÌ¿ºÍNO£¬ºãΣ¨T¡æ)Ìõ¼þÏ·´Ó¦£¬·´Ó¦½øÐе½²»Í¬Ê±¼ä²âµÃ¸÷ÎïÖʵÄŨ¶ÈÈçÏÂ

ʱ¼ä

Ũ¶È(mol/L)

ÎïÖÊ

NO

N2

CO2

0

0.100

0

0

10

0.058

0.021

0.021

20

0.040

0.030

0.030

30

0.040

0.030

0.030

40

0.032

0.034

0.017

50

0.032

0.034

0.017

¢Ù²»ÄÜ×÷ΪÅжϷ´Ó¦´ïµ½»¯Ñ§Æ½ºâ״̬µÄÒÀ¾Ý ÊÇ_________

A£®ÈÝÆ÷ÄÚCO2µÄŨ¶È±£³Ö²»±ä

B£®vÕý£¨N2£©= vÕý£¨NO£©

C£®»ìºÏÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿±£³Ö²»±ä

D£®»ìºÏÆøÌåµÄÃܶȱ£³Ö²»±ä

E£®ÈÝÆ÷ÄÚѹǿ±£³Ö²»±ä

¢ÚÔÚT¡æʱ£®¸Ã·´Ó¦µÄƽºâ³£ÊýΪ_______ (±£ÁôÁ½Î»Ð¡Êý)£»

¢ÛÔÚ30 min,¸Ä±äijһÌõ¼þ,·´Ó¦ÖØдﵽƽºâ,Ôò¸Ä±äµÄÌõ¼þÊÇ________¡£

£¨3£©¿Æѧ¼ÒÕýÔÚÑо¿ÀûÓô߻¯¼¼Êõ½«³¬ÒôËÙ·É»úβÆøÖеÄNOºÍCOת±ä³ÉCO2ºÍN2, Ñо¿±íÃ÷£ºÔÚʹÓõÈÖÊÁ¿´ß»¯¼Áʱ£¬Ôö´ó´ß»¯¼ÁµÄ±È±íÃæ»ý¿ÉÌá¸ß»¯Ñ§·´Ó¦ËÙÂÊ£®Èçͼ±íʾÔÚÆäËûÌõ¼þ²»±äʱ£¬·´Ó¦£º2CO(g)£«2NO(g)N2(g)£«2CO2(g) ÖÐNOµÄŨ¶Èc(NO)ËæζÈ(T)¡¢´ß»¯¼Á±íÃæ»ý(S)ºÍʱ¼ä(t)µÄ±ä»¯ÇúÏß¡£

¢Ù¸Ã·´Ó¦µÄ¦¤H____0£¨Ìî¡°>¡±»ò¡°<¡±£©¡£

¢ÚÈô´ß»¯¼ÁµÄ±íÃæ»ýS1 >S2£¬ÔÚͼÖл­³öc(NO)ÔÚT1¡¢S2Ìõ¼þÏ´ﵽƽºâ¹ý³ÌÖеı仯ÇúÏß¡£____

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿¿ÉÓÃÓÚ¼ìÑé¾ÃÖõÄFeSO4ÈÜÒºÊÇ·ñ±äÖʵÄÊÔ¼Á

A.¹ýÑõ»¯ÄÆB.Ìú·ÛC.ÑÎËáD.KSCNÈÜÒº

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂÁÐʵÑéÏÖÏóÖÐÓа×Ñ̳öÏÖµÄÊÇ£¨ £©
A.Í­Ë¿ÔÚCl2ÖÐȼÉÕ
B.ÌúË¿ÔÚÑõÆøÖÐȼÉÕ
C.ÇâÆøÔÚÂÈÆøÖÐȼÉÕ
D.NaÔÚCl2ÖÐȼÉÕ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿¹è¼°Æ仯ºÏÎïµÄÓ¦Ó÷¶Î§ºÜ¹ã¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ

A. ¹èÊÇÈËÀཫ̫ÑôÄÜת»»ÎªµçÄܵij£ÓòÄÁÏ

B. ´Ö¹èÖƱ¸µ¥¾§¹è²»Éæ¼°Ñõ»¯»¹Ô­·´Ó¦

C. ʯӢ²£Á§ºÍ²Í×ÀÉϵĴÉÅ̶¼ÊǹèËáÑÎÖÆÆ·

D. ÑÎËá¿ÉÒÔÓë¹è·´Ó¦£¬¹Ê²ÉÓÃÑÎËáΪÅ×¹âÒºÅ׹ⵥ¾§¹è

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿¢Ù2-äå±ûÍé ¢Ú±ûȲ ¢ÛÂÈÒÒÏ© ¢ÜÏõ»ù±½ ¢Ý¼×±½5ÖÖÓлúÎï·Ö×ÓÖУ¬ËùÓÐÔ­×Ó²»¿ÉÄÜ´¦ÓÚͬһƽÃæÄÚµÄÊÇ( )

A. ¢Ù¢Ú¢Û¢Ü B. ¢Ù¢Ú¢Ý C. ¢Û¢Ü¢Ý D. ¢Û¢Ü

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂͼÖÐA¡¢B¡¢C·Ö±ðÊÇÈýÖÖÓлúÎïµÄ½á¹¹Ä£ÐÍ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©A¡¢BÁ½ÖÖÄ£ÐÍ·Ö±ðÊÇÓлúÎïµÄ________Ä£ÐͺÍ________Ä£ÐÍ¡£

£¨2£©A¼°ÆäͬϵÎïµÄ·Ö×Óʽ·ûºÏͨʽ________(ÓÃn±íʾ)¡£µ±n£½________ʱ£¬ÍéÌþ¿ªÊ¼³öÏÖͬ·ÖÒì¹¹Ìå¡£

£¨3£©A¡¢B¡¢CÈýÖÖÓлúÎïÖУ¬ËùÓÐÔ­×Ó¾ù¹²ÃæµÄÊÇ________(ÌîÃû³Æ)¡£½á¹¹¼òʽΪCH2=CH(CH2)5CH3µÄÓлúÎïÖУ¬´¦ÓÚͬһƽÃæÄÚµÄ̼ԭ×ÓÊý×î¶àΪ________¡£

£¨4£©ÓлúÎïC¾ßÓеĽṹ»òÐÔÖÊÊÇ________(Ìî×Öĸ)¡£

a£®ÊÇ̼̼˫¼üºÍ̼̼µ¥¼ü½»ÌæµÄ½á¹¹

b£®Óж¾¡¢²»ÈÜÓÚË®¡¢ÃܶȱÈˮС

c£®²»ÄÜʹËáÐÔKMnO4ÈÜÒººÍäåË®ÍÊÉ«

d£®Ò»¶¨Ìõ¼þÏÂÄÜÓëÇâÆø»òÑõÆø·´Ó¦

£¨5£©µÈÖÊÁ¿µÄÈýÖÖÓлúÎïÍêȫȼÉÕÉú³ÉH2OºÍCO2£¬ÏûºÄÑõÆøµÄÌå»ý(Ïàͬ״¿öÏÂ)×î´óµÄÊÇ________(Ìî·Ö×Óʽ)¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿A¡¢B¡¢C¡¢DΪԭ×ÓÐòÊýÒÀ´ÎÔö´óµÄÇ°ËÄÖÜÆÚÔªËØ¡£BA3ÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶£¬A¡¢B¡¢CÈýÖÖÔ­×ӵĵç×ÓÊýÖ®ºÍµÈÓÚ25£¬DC¾§ÌåÖÐD+µÄ3dÄܼ¶Éϵç×ÓÈ«³äÂú¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÒÔÉÏËÄÖÖÔªËØÖУ¬µÚÒ»µçÀëÄÜ×î´óµÄÊÇ________£¨ÌîÔªËØ·ûºÅ)£» DµÄ»ù̬ԭ×ӵĺËÍâµç×ÓÅŲ¼Ê½Îª__________¡£

£¨2£©ÔÚBA3¡¢ACÖУ¬·Ðµã½Ï¸ßµÄÊÇ________¡££¨Ìѧʽ)£¬ÆäÔ­ÒòÊÇ____________¡£DAµÄ¾§ÌåÀàÐÍÊÇ____________________¡£

£¨3£©BA4C¾§ÌåÖк¬ÓеĻ¯Ñ§¼üΪ_____________¡£

a£®·¶µÂ»ªÁ¦ b£®Çâ¼ü c£®Àë×Ó¼ü d£®Åäλ¼ü e£®¹²¼Û¼ü

£¨4£©»¯ºÏÎïBC3µÄÁ¢Ìå¹¹ÐÍΪ_____________£¬ÆäÖÐÐÄÔ­×ÓµÄÔÓ»¯¹ìµÀÀàÐÍΪ______________¡£

£¨5£©ÓÉB¡¢DÐγɵľ§ÌåµÄ¾§°ûͼËùʾ£¬¼ºÖª½ôÁÚµÄBÔ­×ÓÓëDÔ­×Ó¾àÀëΪacm¡£

¢Ù¸Ã¾§°û»¯Ñ§Ê½Îª___________¡£

¢ÚBÔªËØÔ­×ÓµÄÅäλÊýΪ____________¡£

¢Û¸Ã¾§ÌåµÄÃܶÈΪ____________£¨Óú¬a¡¢NAµÄ´úÊýʽ±íʾ£¬ÉèNAΪ°¢·ü¼ÓµÂÂÞ³£ÊýÖµ£©g¡¤cm-3¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸