Question

£¨1£©ÊÒÎÂÏ£¬½«2¿ËҺ̬±½£¨C₆H₆£©ÍêȫȼÉÕÉú³ÉҺ̬ˮºÍCO₂£¬·Å³ö83.6KJµÄÈÈÁ¿£¬Ð´³öC₆H₆ȼÉÕµÄÈÈ»¯Ñ§·½³Ìʽ£º    £®
£¨2£©Óɽðºìʯ£¨TiO₂£©ÖÆÈ¡µ¥ÖÊTi£¬Éæ¼°µ½µÄ²½ÖèΪ£ºTiO₂ ¡úTiCl₄Ti 
ÒÑÖª£º¢ÙC£¨s£©+O₂£¨g£©=CO₂£¨g£©£»¡÷H=-393.5kJ?mol^-1
¢Ú2CO£¨g£©+O₂£¨g£©=2CO₂£¨g£©£»¡÷H=-566kJ?mol^-1
¢ÛTiO₂£¨s£©+2Cl₂£¨g£©=TiCl₄£¨s£©+O₂£¨g£©£»¡÷H=+141kJ?mol^-1
ÔòTiO₂£¨s£©+2Cl₂£¨g£©+2C£¨s£©=TiCl₄£¨s£©+2CO£¨g£©µÄ¡÷H=    £®

Answer 1

¡¾´ð°¸¡¿·ÖÎö£º£¨1£©ÒÀ¾ÝÌâ¸ÉÌõ¼þ¼ÆËã·ûºÏÈÈ»¯Ñ§·½³Ìʽ¶ÔÓ¦Á¿µÄìʱ䣬¸ù¾ÝÈÈ»¯Ñ§·½³ÌʽµÄÊéд·½·¨Ð´³ö£¬×¢ÒâÎïÖʾۼ¯×´Ì¬±ê×¢£¬ìʱäµÄÕý¸º£»
£¨2£©ÒÀ¾Ý¸Ç˹¶¨ÂÉ·ÖÎö¼ÆËãµÃµ½·´Ó¦µÄìʱ䣮
½â´ð£º½â£º£¨1£©½«2¿ËҺ̬±½£¨C₆H₆£©ÎïÖʵÄÁ¿==mol£»ÍêȫȼÉÕÉú³ÉҺ̬ˮºÍCO₂£¬·Å³ö83.6KJµÄÈÈÁ¿£¬1mol±½È¼ÉÕ·ÅÈÈ=83.6KJ×39mol=3260.4KJ£»
·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£ºC₆H₆£¨l£©+O₂£¨g£©¡ú6CO₂£¨g£©+6H₂O£¨l£©¡÷H=-3260.4KJ/mol£¬
¹Ê´ð°¸Îª£ºC₆H₆£¨l£©+O₂£¨g£©¡ú6CO₂£¨g£©+6H₂O£¨l£©¡÷H=-3260.4KJ/mol£»
£¨2£©£º¢ÙC£¨s£©+O₂£¨g£©=CO₂£¨g£©£»¡÷H=-393.5kJ?mol^-1
¢Ú2CO£¨g£©+O₂£¨g£©=2CO₂£¨g£©£»¡÷H=-566kJ?mol^-1
¢ÛTiO₂£¨s£©+2Cl₂£¨g£©=TiCl₄£¨s£©+O₂£¨g£©£»¡÷H=+141kJ?mol^-1
ÒÀ¾Ý¸Ç˹¶¨ÂÉ£¬¢Ù×2-¢Ú+¢ÛµÃµ½£ºTiO₂£¨s£©+2Cl₂£¨g£©+2C£¨s£©=TiCl₄£¨s£©+2CO£¨g£©¡÷H=-80KJ/mol£¬
¹Ê´ð°¸Îª£ºTiO₂£¨s£©+2Cl₂£¨g£©+2C£¨s£©=TiCl₄£¨s£©+2CO£¨g£©¡÷H=-80KJ/mol£®
µãÆÀ£º±¾Ì⿼²éÁËìʱä¼ÆË㣬ÈÈ»¯Ñ§·½³ÌʽµÄÊéд·½·¨×¢ÒâÎÊÌ⣬¸Ç˹¶¨ÂɵļÆËãÓ¦Ó㬹ؼüÊÇìʱäµÄ¼ÆË㣮