Question

£¨18·Ö£©ÔËÓÃÎïÖʽṹµÄ֪ʶÍê³ÉÏÂÁÐÎÊÌâ¡£
£¨1£©µÚÒ»µçÀëÄܽéÓÚB¡¢NÖ®¼äµÄµÚ¶þÖÜÆÚÔªËØÓР         (ÌîÔªËØ·ûºÅ)¡£
£¨2£©ÅäÀë×Ó[TiCl(H₂O)₅]^2£«µÄÖÐÐÄÀë×Ó»¯ºÏ¼ÛΪ¡¡¡¡ ¡¡£¬ÅäÌåµÄ»¯Ñ§Ê½Îª       ¡£
£¨3£©BF₃ÓëÒ»¶¨Á¿Ë®ÐγÉ(H₂O)₂¡¤BF₃¾§ÌåQ£¬QÔÚÒ»¶¨Ìõ¼þÏ¿Éת»¯ÎªR£º

Q                                R
¢Ù¾§ÌåQÖв»´æÔÚµÄ×÷ÓÃÁ¦Îª          £¨Ìî×Öĸ£©¡£
A£®¹²¼Û¼ü   B£®Àë×Ó¼ü   C£®Åäλ¼ü    D£®·¶µÂ»ªÁ¦    E£®Çâ¼ü
¢ÚRÖÐÑôÀë×ӵĿռ乹ÐÍΪ                ¡£
£¨4£©ÅðÉ°ÊǺ¬½á¾§Ë®µÄËÄÅðËáÄÆ£¬ÆäÒõÀë×ÓX^m¡ª£¨º¬B¡¢O¡¢HÈýÖÖÔªËØ£©µÄÇò¹÷Ä£ÐÍÈçÏÂͼ3Ëùʾ¡£Ôòm£½          £¨ÌîÊý×Ö£©¡£
£¨5£©ÒÔËÄÂÈ»¯îÑ¡¢Ì¼»¯¸Æ¡¢µþµªËáÑΣ¨ÈçNaN₃£©×÷Ô­ÁÏ£¬¿ÉÒÔÉú³É̼µª»¯îÑ»¯ºÏÎÆä½á¹¹ÊÇÓÃ̼ԭ×ÓÈ¡´úµª»¯îѾ§°û£¨½á¹¹ÈçÏÂͼ4£©ËùÓж¥µãµÄµªÔ­×Ó£¬ÕâÖÖ̼µª»¯îÑ»¯ºÏÎïµÄ»¯Ñ§Ê½Îª      ¡£
          
ͼ3                            Í¼4
£¨6£©²¿·Ö»¯Ñ§¼üµÄ¼üÄܼûÏÂ±í£º

»¯Ñ§¼ü	Si¡ªO	Si¡ªCl	H¡ªH	H¡ªCl	Si¡ªSi	Si¡ªC
¼üÄÜ/ kJ¡¤mol¡ª1	460	360	436	431	176	347

¢Ù±È½ÏÏÂÁÐÁ½×éÎïÖʵÄÈÛµã¸ßµÍ £¨Ìî¡°£¾¡±»ò¡°£¼¡±£© SiC______ Si£»  SiCl₄ ______ SiO₂
¢Ú¹¤ÒµÉϸߴ¿¹è¿Éͨ¹ýÏÂÁз´Ó¦ÖÆÈ¡£ºSiCl₄ (g) + 2H₂(g) ¸ßÎÂSi(s) + 4HCl(g)
¼ÆËã¸Ã·´Ó¦µÄ·´Ó¦ÈÈ¡÷H £½___________ kJ/mol¡£

Answer 1

£¨1£©Be¡¢C¡¢O   £¨2£© +3 £»Cl^¡ª¡¢H₂O £¨3£©B£»Èý½Ç׶ÐÍ £¨4£©2 £¨5£© Ti₄CN₃
 £¨6£©£¾£»£¼£» 360¡Á4+436¡Á2¡ª(176¡Á2+431¡Á4)£½+236

ÊÔÌâ·ÖÎö£º£¨1£©Í¬ÖÜÆÚ×Ô×óÏòÓÒµçÀëÄÜÖð½¥Ôö´ó£¬µ«ÓÉÓÚBeÔªËصÄ2s¹ìµÀµç×Ó´¦ÓÚÈ«³äÂú״̬£¬Îȶ¨ÐÔÇ¿£¬Òò´ËBeÔªËصĵÚÒ»µçÀëÄÜ´óÓÚBÔªËصĵÚÒ»µçÀëÄÜ¡£µªÔªËصÄ2p¹ìµÀµç×Ó´¦ÓÚ°ë³äÂú״̬£¬Îȶ¨ÐÔÇ¿£¬Òò´ËÑõÔªËصÚÒ»µçÀëÄÜСÓÚµªÔªËصĵÚÒ»µçÀëÄÜ£¬Òò´ËµÚÒ»µçÀëÄܽéÓÚB¡¢NÖ®¼äµÄµÚ¶þÖÜÆÚÔªËØÓÐBe¡¢C¡¢O¡£
£¨2£©Ë®·Ö×ÓÕûÌåÊÇ0¼ÛµÄ£¬ÂÈÔªËØÊÇ£­1¼Û£¬ÔòÅäÀë×Ó[TiCl(H₂O)₅]^2£«µÄÖÐÐÄÀë×Ó»¯ºÏ¼ÛΪ£«3¼Û£¬Äܹ»Ìṩ¹Â¶Ôµç×ÓµÄÊÇÅäÌ壬Òò´Ë¸ÃÅäÁ´×ÓÖÐÅäÌåµÄ»¯Ñ§Ê½ÎªCl^¡ª¡¢H₂O¡£
£¨3£©¢Ù¸ù¾Ý¾§ÌåQµÄ½á¹¹¿ÉÖª£¬·Ö×ÓÖдæÔÚÇâ¼ü¡¢¹²¼Û¼ü¡¢·¶µÂ»ªÁ¦£¬ÁíÍâBÓëOÖ®¼ä»¹ÓÐÅäλ¼ü£¬²»´æÔÚÒõÑôÀë×Ó£¬Òò´ËûÓÐÀë×Ó¼ü£¬´ð°¸Ñ¡B¡£
¢ÚRÖÐÑôÀë×ÓÊÇË®ºÏÇâÀë×Ó£¬ÆäÖÐÑõÔ­×ӵļ۲ãµç×Ó¶ÔÊýÊÇ4¸ö£¬µ«º¬ÓÐ1¸ö¹Â¶Ôµç×Ó£¬Òò´ËÆä¿Õ¼ä¹¹ÐÍΪÈý½Ç׶ÐΡ£
£¨4£©¸ù¾ÝÇò¹÷Ä£ÐÍ¿ÉÖª1£¬3£¬5£¬6´ú±íÑõÔ­×Ó£¬2£¬4´ú±íBÔ­×Ó£¬¹Û²ìÄ£ÐÍ£¬¿ÉÖªX^m-ÊÇ£¨H₄B₄O₉£©^m-£¬ÒÀ¾Ý»¯ºÏ¼ÛHΪ+1£¬BΪ+3£¬OΪ-2£¬¿ÉµÃm£½2¡£
£¨5£©¸ù¾Ý¾§°û½á¹¹¿ÉÖª¾§°ûÖÐ̼ԭ×ӵĸöÊý£½8¡Á£½1£¬µªÔ­×Ó¸öÊý£½6¡Á£½3£¬TiÔ­×Ó¸öÊý£½12¡Á+1£½4£¬ËùÒÔ¾§°ûµÄ»¯Ñ§Ê½ÎªTi₄CN₃¡£
£¨6£©¢Ù̼»¯¹èºÍ¹èµ¥ÖÊÐγɵľ§ÌåÀàÐÍÊÇÔ­×Ó¾§Ì壬ÓÉÓÚ̼ԭ×Ӱ뾶СÓÚ¹èÔ­×Ó£¬Òò´Ë̼»¯¹èµÄ·Ðµã¸ßÓÚµ¥ÖʹèµÄ·Ðµã¡£ËÄÂÈ»¯Ì¼Ðγɵľ§ÌåÊÇ·Ö×Ó¾§Ì壬¶þÑõ»¯¹èÐγɵľ§ÌåÊÇÔ­×Ó¾§Ì壬Òò´ËËÄÂÈ»¯¹èµÄ·ÐµãµÍÓÚ¶þÑõ»¯¹èµÄ·Ðµã¡£
¢Ú»¯Ñ§·´Ó¦·½³ÌʽÖеķ´Ó¦ÈÈ=·´Ó¦ÎïµÄ¼üÄÜÖ®ºÍ£­Éú³ÉÎïµÄ¼üÄÜÖ®ºÍ£©£¬¾§Ìå¹èÖÐ1¸ö¹èÔ­×ÓÐγÉ2¸ö¹²¼Û¼ü£¬ËùÒÔ¸ù¾Ý·½³Ìʽ¿ÉÖª¡÷H£½360kJ/mol¡Á4£«436kJ/mol¡Á2£­176kJ/mol¡Á2£­431kJ/mol¡Á4£½£«236 kJ/mol¡£