ijÓÅÖÊÌðÓ£ÌÒÖк¬ÓÐÒ»ÖÖôÇ»ùËᣨÓÃM±íʾ£©£¬MµÄ̼Á´½á¹¹ÎÞÖ§Á´£¬·Ö×ÓʽΪC4H6O5£»1.34g MÓë×ãÁ¿µÄ̼ËáÇâÄÆÈÜÒº·´Ó¦£¬Éú³É±ê×¼×´¿öϵÄÆøÌå0.448L£®MÔÚÒ»¶¨Ìõ¼þÏ¿ɷ¢ÉúÈçÏÂת»¯£ºM  
 Å¨ÁòËá 
.
¡÷
A
Br2
B
×ãÁ¿NaOHÈÜÒº
  C £¨M¡¢A¡¢B¡¢C·Ö×ÓÖÐ̼ԭ×ÓÊýÄ¿Ïàͬ£©£®ÏÂÁÐÓйØ˵·¨Öв»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
·ÖÎö£ºMµÄ̼Á´½á¹¹ÎÞÖ§Á´£¬·Ö×ÓʽΪC4H6O5£»1.34gMÓë×ãÁ¿µÄ̼ËáÇâÄÆÈÜÒº·´Ó¦£¬Éú³É±ê×¼×´¿öϵÄÆøÌå0.448L£¬Ôòn£¨M£©=
1.34g
134g/mol
=0.01mol£¬n£¨CO2£©=
0.448L
22.4L/mol
=0.02mol£¬ÔòMÖк¬2¸ö-COOH£¬ËùÒÔMΪHOOC-CHOH-CH2-COOH£¬È»ºó½áºÏÓлúÎïµÄ½á¹¹ÓëÐÔÖÊÀ´½â´ð£®
½â´ð£º½â£ºMµÄ̼Á´½á¹¹ÎÞÖ§Á´£¬·Ö×ÓʽΪC4H6O5£»1.34gMÓë×ãÁ¿µÄ̼ËáÇâÄÆÈÜÒº·´Ó¦£¬Éú³É±ê×¼×´¿öϵÄÆøÌå0.448L£¬Ôòn£¨M£©=
1.34g
134g/mol
=0.01mol£¬n£¨CO2£©=
0.448L
22.4L/mol
=0.02mol£¬ÔòMÖк¬2¸ö-COOH£¬ËùÒÔMΪHOOC-CHOH-CH2-COOH£¬
A£®ÓÉÉÏÊö·ÖÎö¿ÉÖª£¬MµÄ½á¹¹¼òʽΪHOOC-CHOH-CH2-COOH£¬¹ÊAÕýÈ·£»
B£®M·¢ÉúÏûÈ¥¡¢¼Ó³É·´Ó¦Éú³ÉB£¬ÔòBµÄ·Ö×ÓʽΪC4H4O4Br2£¬¹ÊBÕýÈ·£»
C£®ÓëMµÄ¹ÙÄÜÍÅÖÖÀà¡¢ÊýÁ¿ÍêÈ«ÏàͬµÄͬ·ÖÒì¹¹Ì廹ÓУ¨HOOC£©2-CH-CH2OH¡¢£¨HOOC£©2-CHOH-CH3£¬¹ÊCÕýÈ·£»
D£®BË®½âÉú³ÉCÖк¬2¸ö-OHºÍ2¸ö-COOH£¬ÔòCÄÜÈÜÓÚË®£¬¹ÊD´íÎó£»
¹ÊÑ¡D£®
µãÆÀ£º±¾Ì⿼²éÓлúÎïµÄºÏ³É¼°½á¹¹ÓëÐÔÖÊ£¬×¢Òâ°ÑÎÕÓлúÎïÖеĹÙÄÜÍÅ£¬ÊìϤ·Ö×Óʽ¼°½á¹¹µÄÈ·¶¨¼°´¼µÄÐÔÖʼ´¿É½â´ð£¬×¢ÖØ»ù´¡ÖªÊ¶µÄ¿¼²é£¬ÌâÄ¿ÄѶȲ»´ó£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijÓÅÖÊÌðÓ£ÌÒÖк¬ÓÐÒ»ÖÖôÇ»ùËᣨÓÃM±íʾ£©£¬MµÄ̼Á´½á¹¹ÎÞÖ§Á´£¬·Ö×ÓʽΪC4H6O5£»1.34gMÓë×ãÁ¿µÄ̼ËáÇâÄÆÈÜÒº·´Ó¦£¬Éú³É±ê×¼×´¿öϵÄÆøÌå0.448L£®MÔÚÒ»¶¨Ìõ¼þÏ¿ɷ¢ÉúÈçÏÂת»¯M
ŨÁòËá
¡÷
A
Br2
B
×ãÁ¿NaOHÈÜÒº
C£¨M¡¢A¡¢B¡¢C·Ö×ÓÖÐ̼ԭ×ÓÊýÄ¿Ïàͬ£©£®ÏÂÁÐÓйØ˵·¨Öв»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêºþÄÏÊ¡ä¯ÑôÒ»Öи߶þ4Ô¶ο¼»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºµ¥Ñ¡Ìâ

ijÓÅÖÊÌðÓ£ÌÒÖк¬ÓÐÒ»ÖÖôÇ»ùËᣨÓÃM±íʾ£©£¬MµÄ̼Á´½á¹¹ÎÞÖ§Á´£¬·Ö×ÓʽΪ
C4H6O5£»1.34gMÓë×ãÁ¿µÄ̼ËáÇâÄÆÈÜÒº·´Ó¦£¬Éú³É±ê×¼×´¿öϵÄÆøÌå0.448L¡£MÔÚÒ»¶¨Ìõ¼þÏ¿ɷ¢ÉúÈçÏÂת»¯£ºMABC£¨M¡¢A¡¢B¡¢C·Ö×ÓÖÐ̼ԭ×ÓÊýÄ¿Ïàͬ£©¡£ÏÂÁÐÓйØ˵·¨Öв»ÕýÈ·µÄÊÇ              £¨    £©
A£®MµÄ½á¹¹¼òʽΪHOOC¡ªCHOH¡ªCH2¡ªCOOH
B£®BµÄ·Ö×ÓʽΪC4H4O4Br2
C£®ÓëMµÄ¹ÙÄÜÍÅÖÖÀà¡¢ÊýÁ¿ÍêÈ«ÏàͬµÄͬ·ÖÒì¹¹Ì廹ÓÐ2ÖÖ
D£®CÎïÖʲ»¿ÉÄÜÈÜÓÚË®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ìºþÄÏÊ¡¸ß¶þ4Ô¶ο¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ijÓÅÖÊÌðÓ£ÌÒÖк¬ÓÐÒ»ÖÖôÇ»ùËᣨÓÃM±íʾ£©£¬MµÄ̼Á´½á¹¹ÎÞÖ§Á´£¬·Ö×ÓʽΪ

C4H6O5£»1.34gMÓë×ãÁ¿µÄ̼ËáÇâÄÆÈÜÒº·´Ó¦£¬Éú³É±ê×¼×´¿öϵÄÆøÌå0.448L¡£MÔÚÒ»¶¨Ìõ¼þÏ¿ɷ¢ÉúÈçÏÂת»¯£ºMABC£¨M¡¢A¡¢B¡¢C·Ö×ÓÖÐ̼ԭ×ÓÊýÄ¿Ïàͬ£©¡£ÏÂÁÐÓйØ˵·¨Öв»ÕýÈ·µÄÊÇ              £¨    £©

A£®MµÄ½á¹¹¼òʽΪHOOC¡ªCHOH¡ªCH2¡ªCOOH

B£®BµÄ·Ö×ÓʽΪC4H4O4Br2

C£®ÓëMµÄ¹ÙÄÜÍÅÖÖÀà¡¢ÊýÁ¿ÍêÈ«ÏàͬµÄͬ·ÖÒì¹¹Ì廹ÓÐ2ÖÖ

D£®CÎïÖʲ»¿ÉÄÜÈÜÓÚË®

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ì½­Î÷Ê¡¸ß¶þÏÂѧÆÚµÚÒ»´ÎÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÑ¡ÔñÌâ

ijÓÅÖÊÌðÓ£ÌÒÖк¬ÓÐÒ»ÖÖôÇ»ùËᣨÓÃM±íʾ£©£¬MµÄ̼Á´½á¹¹ÎÞÖ§Á´£¬·Ö×ÓʽΪC4H6O5£»

1.34gMÓë×ãÁ¿µÄ̼ËáÇâÄÆÈÜÒº·´Ó¦£¬Éú³É±ê×¼×´¿öϵÄÆøÌå0.448L¡£MÔÚÒ»¶¨Ìõ¼þÏ¿ɷ¢ÉúÈçÏÂת»¯£º£¨M¡¢A¡¢B¡¢C·Ö×ÓÖÐ̼ԭ×ÓÊýÄ¿Ïàͬ£©¡£ÏÂÁÐÓйØ˵·¨Öв»ÕýÈ·µÄÊÇ               £¨     £©

A£®MµÄ½á¹¹¼òʽΪHOOC¡ªCHOH¡ªCH2¡ªCOOH

B£®BµÄ·Ö×ÓʽΪC4H4O4Br2

C£®ÓëMµÄ¹ÙÄÜÍÅÖÖÀà¡¢ÊýÁ¿ÍêÈ«ÏàͬµÄͬ·ÖÒì¹¹Ì廹ÓÐ1ÖÖ

D£®CÎïÖÊ¿ÉÄÜÈÜÓÚË®

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸