Question

19£®ÏÂͼÊÇA¡¢B¡¢C¡¢D¡¢E¡¢FµÈ¼¸ÖÖ³£¼ûÓлúÎïÖ®¼äµÄת»¯¹Øϵͼ£®ÆäÖÐAÊÇÃæ·ÛµÄÖ÷Òª³É·Ö£»CºÍE·´Ó¦ÄÜÉú³ÉF£¬F¾ßÓÐÏãζ£®

ÔÚÓлúÎïÖУ¬·²ÊǾßÓÐ-CHO½á¹¹µÄÎïÖÊ£¬¾ßÓÐÈçÏÂÐÔÖÊ£º
£¨1£©ÓëÐÂÖƵÄÇâÑõ»¯Í­Ðü×ÇÒº·´Ó¦£¬²úÉúשºìÉ«µÄ³Áµí£»
£¨2£©ÔÚ´ß»¯¼Á×÷ÓÃÏ£¬-CHO±»ÑõÆøÑõ»¯Îª-COOH£¬¼´£º2R-CHO+O₂$¡ú_{¡÷}^{´ß»¯¼Á}$2R-COOH
¸ù¾ÝÒÔÉÏÐÅÏ¢¼°¸÷ÎïÖʵÄת»¯¹ØϵÍê³ÉÏÂÁи÷Ì⣺
£¨1£©AµÄ·Ö×ÓʽΪ£¨C₆H₁₀O₅£©_n£¬BÖк¬ÓеĹÙÄÜÍÅÓÐ-OH¡¢-CHO£¬ÓëB»¥ÎªÍ¬·ÖÒì¹¹ÌåµÄÒ»ÖÖÎïÖʵÄÃû³Æ¹ûÌÇ£®
£¨2£©A--FÖУ¬ÄÜÓëÐÂÖÆÇâÑõ»¯Í­Ðü×ÇÒº²úÉúשºìÉ«µÄ³ÁµíµÄÎïÖÊÓÐÆÏÌÑÌǺÍÒÒÈ©£¨ÌîÃû³Æ£©
£¨3£©EÓëСËÕ´òÈÜÒº·´Ó¦µÄÀë×Ó·½³ÌʽΪCH₃COOH+HCO₃^-=CH₃COO^-+H₂O+CO₂¡ü£®
£¨4£©C¡úDµÄ»¯Ñ§·½³ÌʽΪ2CH₃CH₂OH+O₂$¡ú_{¡÷}^{´ß»¯¼Á}$2CH₃CHO+2H₂O·´Ó¦ÀàÐÍΪÑõ»¯·´Ó¦£®
£¨5£©C+E¡úFµÄ»¯Ñ§·½³ÌʽΪCH₃COOH+CH₃CH₂OH$?_{¡÷}^{ŨH_{2}SO_{4}}$CH₃COOCH₂CH₃+H₂O£®

Answer 1

·ÖÎö AÊÇÃæ·ÛÖеÄÖ÷Òª³É·Ö£¬ÔòAΪµí·Û£¬·Ö×ÓʽΪ£¨C₆H₁₀O₅£©_n£»A³ä·ÖË®½âµÃB£¬B·¢½ÍµÃC¡¢CÑõ»¯Éú³ÉD£¬DÄÜÓëÐÂÖƵÄCu£¨OH£©₂·´Ó¦²úÉúשºìÉ«³Áµí£¬ÔòDÖк¬ÓÐÈ©»ù£¬¿ÉÖªBΪÆÏÌÑÌÇ£¬Æä½á¹¹¼òʽΪCH₂OH£¨CHOH£©₄CHO£¬ÆÏÌÑÌÇ·¢½ÍÉú³ÉÒÒ´¼£¬ÔòCΪCH₃CH₂OH£¬ÒÒ´¼Ñõ»¯Éú³ÉÒÒÈ©£¬ÔòDΪCH₃CHO£¬ÒÒÈ©Ñõ»¯Éú³ÉÒÒËᣬÔòEΪCH₃COOH£¬CÓëE·¢Éúõ¥»¯·´Ó¦Éú³ÉF£¬ÔòFΪCH₃COOCH₂CH₃£¬ÒÔ´ËÀ´½â´ð£®

½â´ð ½â£º£¨1£©AΪµí·Û£¬·Ö×ÓʽΪ£¨C₆H₁₀O₅£©_n£»BΪÆÏÌÑÌÇ£¬½á¹¹¼òʽΪCH₂OH£¨CHOH£©₄CHO£¬¹ÙÄÜÍÅΪ-OH¡¢-CHO£¬ÓëÆÏÌÑÌÇ»¥ÎªÍ¬·ÖÒì¹¹ÌåµÄÒ»ÖÖÎïÖÊΪ¹ûÌÇ£¬
¹Ê´ð°¸Îª£º£¨C₆H₁₀O₅£©_n£»-OH¡¢-CHO£»¹ûÌÇ£»
£¨2£©Äܹ»ÓëÐÂÖÆCu£¨OH£©₂·´Ó¦²úÉúשºìÉ«³ÁµíµÄÎïÖÊÖÐÒ»¶¨º¬ÓÐÈ©»ù£¬Aµ½FÖк¬ÓÐÈ©»ùµÄΪÆÏÌÑÌǺÍÒÒÈ©£¬
¹Ê´ð°¸Îª£ºÆÏÌÑÌǺÍÒÒÈ©£»
£¨3£©ÒÒËáÓë̼ËáÇâÄÆ·´Ó¦Éú³ÉÒÒËáÄÆ¡¢¶þÑõ»¯Ì¼ÆøÌåºÍË®£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪCH₃COOH+NaHCO₃=CH₃COONa+H₂O+CO₂¡ü£¬Àë×Ó·´Ó¦ÎªCH₃COOH+HCO₃^-=CH₃COO^-+H₂O+CO₂¡ü£¬
¹Ê´ð°¸Îª£ºCH₃COOH+HCO₃^-=CH₃COO^-+H₂O+CO₂¡ü£»
£¨4£©C¡úDµÄ·´Ó¦·½³ÌʽΪ2CH₃CH₂OH+O₂$¡ú_{¡÷}^{´ß»¯¼Á}$2CH₃CHO+2H₂O£¬ÊôÓÚÑõ»¯·´Ó¦£¬
¹Ê´ð°¸Îª£º2CH₃CH₂OH+O₂$¡ú_{¡÷}^{´ß»¯¼Á}$2CH₃CHO+2H₂O£»Ñõ»¯£»
£¨5£©C+E¡úFµÄ»¯Ñ§·½³ÌʽΪCH₃COOH+CH₃CH₂OH$?_{¡÷}^{ŨH_{2}SO_{4}}$CH₃COOCH₂CH₃+H₂O£¬
¹Ê´ð°¸Îª£ºCH₃COOH+CH₃CH₂OH$?_{¡÷}^{ŨH_{2}SO_{4}}$CH₃COOCH₂CH₃+H₂O£®

µãÆÀ ±¾Ì⿼²éÓлúÎïµÄÍƶϣ¬Îª¸ßƵ¿¼µã£¬°ÑÎÕÁ÷³ÌÖйÙÄÜÍŵı仯¡¢Óлú·´Ó¦Îª½â´ðµÄ¹Ø¼ü£¬²àÖØ·ÖÎöÓëÓ¦ÓÃÄÜÁ¦µÄ¿¼²é£¬×¢ÒâÓлúÎïÐÔÖʵÄÓ¦Óã¬ÌâÄ¿ÄѶȲ»´ó£®