3.6gijÌþAµÄÕôÆøºÍCl2·¢ÉúÈ¡´ú·´Ó¦£¬¿ØÖÆÌõ¼þʹÆäÖ»Éú³ÉÒ»ÂÈ´úÎ½«·´Ó¦Éú³ÉµÄÆøÌåÓÃ0.1mol¡¤L-1NaOHÈÜÒºÖкÍ,µ±ÍêÈ«·´Ó¦Ê±ÏûºÄNaOHÈÜÒº500ml£¬ÊÔ½â´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÇóÌþAµÄÏà¶Ô·Ö×ÓÖÊÁ¿¡£
£¨2£©ÊµÑé²âµÃÌþA²»ÄÜʹËáÐÔKMnO4ÈÜÒºÍËÉ«,Ò²²»ÄÜʹäåË®ÍËÉ«£¬ÇóÌþAµÄ·Ö×Óʽ£¬ÓÃϵͳÃüÃû·¨ÃüÃû·ûºÏ¸Ã·Ö×ÓʽµÄËùÓÐͬ·ÖÒì¹¹Ìå¡£
£¨3£©ÈôÌþAµÄÒ»ÂÈ´úÎïÖ»ÓÐÒ»ÖÖ£¬ÊÔÈ·¶¨ÌþAµÄ½á¹¹¼òʽ¡£

 (1)72    (2) C5H12  CH3-CH2-CH2-CH2-CH3 ¡¢ÎìÍé         CH3-CH2-CH -CH3 ¡¢

 2-¼×»ù¶¡Íé

             CH3                                                                      CH3      

CH3- C -CH3 ¡¢ 2£¬2-¶þ¼×»ù±ûÍé   £¨3£©  CH3- C -CH3 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÒÑÖª£ºÒ»¸ö̼ԭ×ÓÉÏÁ¬ÓÐÁ½¸öôÇ»ùʱ²»Îȶ¨£¬Ò×·¢ÉúÏÂÁÐת»¯£º

ijÌþAµÄÕôÆøÃܶÈÊÇÏàͬ״¿öÏÂÇâÆøµÄ53±¶£¬ÌþA²»ÄÜʹäåµÄCCl4ÈÜÒºÍÊÉ«£¬µ«ÄÜʹËáÐÔKMnO4ÈÜÒºÍÊÉ«£®ÇâÔ­×Ӻ˴Ź²ÕñÆ×ͼ±íÃ÷AÓÐ2¸öÎüÊշ壬ǿ¶ÈÖ®±ÈΪ3£º2£®BÖ»ÓÐ1¸öÎüÊշ壬DÓÐ2¸öÎüÊշ壬GΪ»·×´½á¹¹£®A¿ÉÒÔ·¢ÉúÈçÏÂͼËùʾµÄһϵÁб仯£¨Éú³ÉµÄÆäËüÎÞ»úÎï¾ùδд³ö£©£®

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©AµÄ·Ö×ÓʽÊÇ
C8H10
C8H10
£®
£¨2£©Ö¸³öÏÂÁз´Ó¦µÄ·´Ó¦ÀàÐÍ£º¢Ù
È¡´ú·´Ó¦
È¡´ú·´Ó¦
£®
£¨3£©Ð´³öB¡¢GµÄ½á¹¹¼òʽ£ºG
£®
£¨4£©Ð´³öÏÂÁз´Ó¦µÄ»¯Ñ§·´Ó¦·½³Ìʽ£º·´Ó¦¢Ú
£»
CºÍE»¹ÄÜÉú³É¸ß·Ö×Ó»¯ºÏÎÇëд³öÆä·´Ó¦µÄ»¯Ñ§·½³Ìʽ

»ò

£¬

»ò

£¬
£®
£¨5£©Ð´³öÂú×ãÏÂÁÐÌõ¼þµÄEµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£¨E²»±ØÔÙд£©£º
£®
¢ÙÓöFeCl3ÈÜÒºÏÔ×ÏÉ«£»¢ÚÄÜ·¢ÉúÏûÈ¥·´Ó¦Éú³É̼̼˫¼ü£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÎïÀí½ÌÑÐÊÒ ÌâÐÍ£º022

£¨1£©1Ìå»ýijÌþAµÄÕôÆøÍêȫȼÉÕÉú³ÉµÄCO2±ÈH2O(g)ÉÙ1Ìå»ý(ÔÚÏàͬÌõ¼þϲⶨ)¡£0.1mol¸ÃÌþȼÉÕ£¬Æä²úÎïÈ«²¿±»¼îʯ»ÒÎüÊÕ£¬¼îʯ»ÒÔöÖØ20.4g£¬Ôò¸ÃÌþµÄ·Ö×ÓʽΪ____________£¬ÓÖÖª1g¸ÃÌþÍêȫȼÉÕÉú³ÉCO2ºÍH2O£¨1£©£¬·Å³ö50.46kJÈÈÁ¿£¬Ôò¸ÃÌþȼÉÕµÄÈÈ»¯Ñ§·½³ÌʽΪ_______________¡£

£¨2£©Á´ÌþBÊÇÉÏÊöAµÄͬϵÎËüÃǵÄÏà¶Ô·Ö×ÓÖÊÁ¿²îΪ42£¬BµÄ·Ö×ÓʽΪ______________£¬ÈôBµÄÒ»ÂÈÈ¡´úÎïÓÐ3ÖÖÔòB¿ÉÄܵĽṹ¼òʽΪ_________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÎïÀí½ÌÑÐÊÒ ÌâÐÍ£º038

3.6 gijÌþAµÄÕôÆøºÍCl2·¢ÉúÈ¡´ú·´Ó¦£¬¿ØÖÆÌõ¼þʹÆäÉú³ÉÒ»ÂÈ´úÎ½«·´Ó¦Éú³ÉµÄÆøÌåÓÃ0.10 mol¡¤L£­1 NaOHÈÜÒºÖкͣ¬µ±ÍêÈ«·´Ó¦Ê±ºÄNaOHÈÜÒº500 mL£¬ÊÔ½â´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÇóÌþAµÄÏà¶Ô·Ö×ÓÖÊÁ¿£®

£¨2£©ÊµÑé²âµÃÌþA²»ÄÜʹËáÐÔKMnO4ÈÜÒºÍÊÉ«Ò²²»ÄÜʹäåË®ÍÊÉ«£¬ÇóÌþAµÄ·Ö×Óʽ£¬Ð´³ö·ûºÏ·Ö×ÓʽµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£®²¢ÓÃϵͳÃüÃû·¨ÃüÃû£®

£¨3£©ÈôÌþAµÄÒ»ÂÈ´úÎïÖ»ÓÐÒ»ÖÖ£¬ÊÔÈ·¶¨ÌþAµÄ½á¹¹¼òʽ£®

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÎïÀí½ÌÑÐÊÒ ÌâÐÍ£º038

¡¡¡¡3.6 gijÌþAµÄÕôÆøºÍCl2·¢ÉúÈ¡´ú·´Ó¦£¬¿ØÖÆÌõ¼þʹÆäÉú³ÉÒ»ÂÈ´úÎ½«·´Ó¦Éú³ÉµÄÆøÌåÓÃ0.10 mol¡¤L£­1 NaOHÈÜÒºÖкͣ¬µ±ÍêÈ«·´Ó¦Ê±ÏûºÄNaOHÈÜÒº500 mL£¬ÊÔ½â´ðÏÂÁÐÎÊÌ⣺

¡¡¡¡£¨1£©ÇóÌþAµÄÏà¶Ô·Ö×ÓÖÊÁ¿£®

¡¡¡¡£¨2£©ÊµÑé²âµÃÌþA²»ÄÜʹËáÐÔKMnO4ÈÜÒºÍÊÉ«Ò²²»ÄÜʹäåË®ÍÊÉ«£¬ÇóÌþAµÄ·Ö×Óʽ£¬Ð´³ö·ûºÏ·Ö×ÓʽµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£®²¢ÓÃϵͳÃüÃû·¨ÃüÃû£®

¡¡¡¡£¨3£©ÈôÌþAµÄÒ»ÂÈ´úÎïÖ»ÓÐÒ»ÖÖ£¬ÊÔÈ·¶¨ÌþAµÄ½á¹¹¼òʽ£®

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸