ijÈÜÒºÖнöº¬Na£«¡¢H£«¡¢OH£­¡¢CH3COO£­ËÄÖÖÀë×Ó£¬ÏÂÁÐ˵·¨´íÎóµÄÊÇ
A£®ÈÜÒºÖÐËÄÖÖÁ£×ÓÖ®¼ä²»¿ÉÄÜÂú×㣺c(Na£«)£¾c(OH£­)£¾c(H£«)£¾c(CH3COO£­)
B£®ÈôÈÜÒºÖв¿·ÖÁ£×Ó¼äÂú×㣺c(CH3COO£­)£½c(Na£«)£¬Ôò¸ÃÈÜÒºÒ»¶¨³ÊÖÐÐÔ
C£®ÈôÈÜÒºÖÐÈÜÖʽöΪCH3COONa£¬ÔòÁ£×Ó¼äÒ»¶¨Âú×㣺c(Na£«)£¾c(CH3COO£­)£¾c(OH£­)£¾c(H£«)
D£®ÈôÈÜÒºÖеÄÈÜÖÊΪCH3COONaºÍCH3COOH£¬ÔòÈÜÒºÖÐÁ£×Ó¼äÒ»¶¨Âú×㣺c(CH3COO£­)£¾c(Na£«)£¾c(H£«)£¾c(OH£­)
D

ÊÔÌâ·ÖÎö£ºA¡¢ÈçÈÜÒºÖÐNaOH¹ýÁ¿£¬ÇÒ¼îÐÔ½ÏÇ¿£¬Ôò¿É´æÔÚc£¨Na+£©£¾c£¨OH-£©£¾c£¨CH3COO-£©£¾c£¨H+£©£¬Èç¹ûÈÜÒºÖÐÊÇ´×ËáÄƹýÁ¿£¬Ôò¿É´æÔÚc£¨Na+£©£¾c£¨CH3COO-£©£¾c£¨OH-£©£¾c£¨H+£©£¬Òò´ËA´íÎó£»B¡¢ÈÜÒºÖÐÀë×Ó¼äÂú×㣺c£¨CH3COO-£©=c£¨Na+£©£¬ÓɵçºÉÊغã¿ÉÖª£¬c£¨H+£©=c£¨OH-£©£¬ÈÜҺΪÖÐÐÔ£¬¹ÊBÕýÈ·£»C¡¢ÈôÈÜÒºÖÐÈÜÖʽöΪCH3COONa£¬ÔòË®½âÏÔ¼îÐÔ£¬Ó¦´æÔÚc£¨Na+£©£¾c£¨CH3COO-£©£¾c£¨OH-£©£¾c£¨H+£©£¬¹ÊCÕýÈ·£»D¡¢ÈçCH3COOH½Ï¶à£¬ÔòÈÜÒº¿ÉÄܳÊËáÐÔ£¬¿ÉÄÜÂú×㣺c£¨CH3COO-£©£¾c£¨Na+£©£¾c£¨H+£©£¾c£¨OH-£©£¬¹ÊDÕýÈ·¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁи÷ÈÜÒºÖУ¬Î¢Á£µÄÎïÖʵÄÁ¿Å¨¶È¹Øϵ±íÊöÕýÈ·µÄÊÇ(¡¡¡¡)
A£®0.1 mol¡¤L£­1 Na2CO3ÈÜÒºÖУºc(Na£«)£½c(HCO3¡ª)£«c(H2CO3)£«2c(CO32¡ª)
B£®³£ÎÂÏ£¬pH£½4µÄ´×ËáÓëpH£½10µÄNaOHÈÜÒºµÈÌå»ý»ìºÏºópH<7
C£®½«0.2 mol¡¤L£­1 NaAÈÜÒººÍ0.1 mol¡¤L£­1ÑÎËáÈÜÒºµÈÌå»ý»ìºÏËùµÃ¼îÐÔÈÜÒºÖУºc(Na£«)£«c(H£«)£½c(A£­)£«c(Cl£­)
D£®pH£½12µÄBa(OH)2ÈÜÒººÍpH£½12µÄNa2CO3ÈÜÒºÖУ¬Ë®µçÀëµÄc(H£«)ÏàµÈ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

δÀ´ÐÂÄÜÔ´µÄÌصãÊÇ×ÊÔ´·á¸»£¬ÔÚʹÓÃʱ¶Ô»·¾³ÎÞÎÛȾ»òÕßÎÛȾºÜС£¬ÇÒ¿ÉÒÔÔÙÉú£®ÏÂÁÐÊôÓÚδÀ´ÐÂÄÜÔ´±ê×¼µÄÊÇ£¨¡¡¡¡£©
¢ÙÌìÈ»Æø  ¢Ú ÉúÎïÖÊÄÜ ¢Û³±Ï«ÄÜ    ¢ÜʯÓÍ  ¢ÝÌ«ÑôÄÜ  ¢Þú ¢ß·çÄÜ ¢àÇâÄÜ
A£®¢Ù¢Ú¢Û¢ÜB£®¢Ú¢Û¢Ý¢ß¢àC£®¢Ý¢Þ¢ß¢àD£®¢Û¢Ü¢Ý¢Þ¢ß¢à

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

δÀ´ÐÂÄÜÔ´µÄÌصãÊÇ×ÊÔ´·á¸»¡¢¶Ô»·¾³ÎÛȾС£¬ÇÒ¿ÉÒÔÔÙÉú¡£ÏÂÁÐÊôÓÚδÀ´ÐÂÄÜÔ´µÄÊÇ
¢ÙÌìÈ»Æø ¢Úú ¢ÛÇâÄÜ ¢ÜʯÓÍ ¢ÝÌ«ÑôÄÜ ¢ÞÉúÎïÖÊÄÜ ¢ß·çÄÜ
A£®¢Ù¢Ú¢Û¢ÜB£®¢Û¢Ý¢Þ¢ßC£®¢Ü¢Ý¢Þ¢ßD£®¢Ù¢Û¢Ý¢Þ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

³£ÎÂÏ£¬½«v1 mL c1 mol¡¤L£­1µÄ°±Ë®ÖðµÎµÎ¼Óµ½v2 mL c2 mol¡¤L£­1µÄÑÎËáÖУ¬ÏÂÁнáÂÛÖÐÕýÈ·µÄÊÇ£¨¡¡¡¡£©¡£
A£®Èôv1£½v2¡¡c1£½c2£¬Ôò»ìºÏÒºÖÐc(NH4+)£½c(C1£­)
B£®Èô»ìºÏÒºµÄpH£½7£¬Ôò»ìºÏÒºÖÐc(NH4+)£¾c(C1£­)
C£®Èôv1£½v2ÇÒpH£¼7£¬ÔòÒ»¶¨ÓÐc1£¼c2
D£®Èô»ìºÏÒºµÄpH£½7£¬Ôòc1v1£¾c2v2

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

½ÚÄܼõÅųÉΪÉç»á·¢Õ¹¹ý³ÌÖв»¿É»Ø±ÜµÄÎÊÌâ¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
¢ÙÍƹãÒÒ´¼ÆûÓÍ¿ÉÒÔ¼õÇá»·¾³ÎÛȾ£¬½µµÍβÆøÖÐÒ»Ñõ»¯Ì¼º¬Á¿¡£
¢ÚÒÒ´¼ÆûÓÍ×÷ΪһÖÖÐÂÐÍÇå½àȼÁÏ£¬ÊÇÄ¿Ç°ÊÀ½çÉÏ¿ÉÔÙÉúÄÜÔ´µÄ·¢Õ¹ÖصãÖ®Ò»¡£
¢ÛÒÒ´¼ÊôÓÚ¿ÉÔÙÉú×ÊÔ´£¬Ê¹ÓÃÒÒ´¼ÆûÓÍ¿ÉÒÔ»º½âĿǰʯÓͽôȱµÄì¶Ü¡£
¢ÜÌ«ÑôÄÜ¡¢·çÄÜ¡¢Ë®ÄÜ¡¢ÉúÎïÖÊÄÜ¡¢µØÈÈÄܺͺ£ÑóÄܵȶ¼ÊôÓÚ¿ÉÔÙÉúÄÜÔ´¡£
¢ÝÒÒ´¼ÊôÓÚÒ»¼¶ÄÜÔ´¡¡
A£®¢Ù¢Ú¢ÝB£®¢Ù¢Ú¢ÛC£®¢Û¢ÜD£®¢Ù¢Ú¢Û¢Ü

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÎïÖÊÈÜÓÚË®µÄ¹ý³ÌÖÐͨ³£°éËæ×ÅÄÜÁ¿µÄ±ä»¯£¬Ï±íΪËÄÖÖÎïÖʵÄÈܽâÈÈ£¨¡°£«¡±Îª·ÅÈÈ£¬¡°£­¡±ÎªÎüÈÈ£¬18¡æ£©
»¯Ñ§Ê½
NH4NO3
NaOH
Ba(NO3)2
KNO3
ÈܽâÈÈ£¨kJ/kg£©
¨C330.75
+1040.5
¨C410.62
¨C353.17
½«µÈÖÊÁ¿µÄÉÏÊöÎïÖʼÓÈëµÈÖÊÁ¿µÄË®ÖУ¬¶ÔË®µÄµçÀëƽºâÓ°Ïì×îСµÄÊÇ
A£®NH4NO3           B£®NaOH             C£®Ba( NO3)2            D£®KNO3

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÊµÑéÌâ

ʵÑéÌâ
£¨1£©ÉÕ¼îÔÚ±£´æ¹ý³Ì»á²¿·Ö±äÖÊ£¨ÔÓÖÊÖ÷ҪΪNa2CO3£©¡£
׼ȷ³ÆÈ¡5.0gÑùÆ·ÅäÖƳÉ250mLÈÜÒº£¬¸÷È¡ÅäÖƺõÄÉÕ¼îÈÜÒº10.00mLÓÚ׶ÐÎÆ¿ÖУ¬·Ö±ðÏò׶ÐÎÆ¿Öи÷¼ÓÈë1¡«2µÎ·Óָ̪ʾ¼Á£¬£¨ÒÑÖª£º·Ó̪±äɫʱ£¬´ËʱֻÓÐNaOHÓëHCl·´Ó¦£¬Na2CO3»¹Ã»ÓÐÓëHCl·´Ó¦£©ÓÃŨ¶ÈΪ0.20mol¡¤L-1µÄÑÎËá±ê×¼Òº½øÐеζ¨¡£Ïà¹ØÊý¾Ý¼Ç¼ÈçÏ£º
ʵÑé±àºÅ
V£¨ÉÕ¼îÈÜÒº£©/mL
V£¨ÑÎËᣩ/mL
³õʼ¶ÁÊý
ĩβ¶ÁÊý
1
10.00
0.50
21.52
2
10.00
1.00
21.98
3
10.00
0.20
24.80
 
ÊԻشð£º
¢ÙµÎ¶¨Ê±ÓÒÊÖµÄÕýÈ·²Ù×÷ÊÇ______________________________________¡£
¢ÚÅжϵ½´ïµÎ¶¨ÖÕµãµÄʵÑéÏÖÏóÊÇ__________________________________________£¬ÒÀ¾Ý±íÖÐÊý¾Ý£¬¼ÆËã³öÉÕ¼îÑùÆ·Öк¬NaOHµÄÖÊÁ¿·ÖÊýΪ______    _£¥¡£
¢ÛÏÂÁвÙ×÷»áµ¼ÖÂÉÕ¼îÑùÆ·ÖÐNaOHº¬Á¿²â¶¨ÖµÆ«¸ßµÄÊÇ__________¡£
A£®×¶ÐÎÆ¿ÓÃÕôÁóˮϴºóδÓôý²âÒºÈóÏ´
B£®ËáʽµÎ¶¨¹ÜÓÃÕôÁóˮϴºóδÓñê×¼ÒºÈóÏ´
C£®µÎ¶¨¹ý³ÌÖÐÕñµ´×¶ÐÎƿʱ£¬ÓÐÉÙÁ¿´ý²âÈÜÒº½¦³ö
D£®µÎ¶¨Ç°Æ½ÊÓ¶ÁÊý£¬µÎ¶¨½áÊøÑöÊÓ¶ÁÊý
£¨2£©Ñõ»¯»¹Ô­µÎ¶¨ÊµÑéͬÖк͵ζ¨ÀàËÆ¡£¹ýÑõ»¯ÇâÊÇÖØÒªµÄÑõ»¯¼Á£¬ËüµÄË®ÈÜÒºÓÖ³ÆΪ˫ÑõË®£¬³£ÓÃ×÷Ïû¶¾¡¢É±¾ú¡¢Æ¯°×µÈ¡£Ä³»¯Ñ§ÐËȤС×éÈ¡Ò»¶¨Á¿µÄ¹ýÑõ»¯ÇâÈÜÒº£¬×¼È·²â¶¨Á˹ýÑõ»¯ÇâµÄŨ¶È¡£ÒÑÖª£º2KMnO4£«5H2O2£«6H2SO4===2MnSO4£«8H2O£«5O2¡ü£¬ÇëÌîдÏÂÁпհףº
¢ÙÓà        (Ìî¡°Ëáʽ¡±»ò¡°¼îʽ¡±)µÎ¶¨¹ÜÒÆÈ¡¹ýÑõ»¯ÇâÈÜÒº25.00 mLÖÁ׶ÐÎÆ¿ÖУ¬×÷±»²âÊÔÑù¡£
¢ÚµÎ¶¨Ê±£¬½«¸ßÃÌËá¼Ø±ê×¼ÈÜҺעÈëËáʽµÎ¶¨¹ÜÖУ¬¸ßÃÌËá¼Ø±ê×¼ÈÜÒºÓÃËáʽµÎ¶¨¹ÜÔ­ÒòΪ       ¡£¢ÛÖظ´µÎ¶¨Èý´Î£¬Æ½¾ùºÄÓÃc mol/L KMnO4±ê×¼ÈÜÒºV mL£¬ÔòÔ­¹ýÑõ»¯ÇâÈÜÒºÖйýÑõ»¯ÇâµÄÎïÖʵÄÁ¿Å¨¶ÈΪ                    ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£º¼ÆËãÌâ

ÁÐʽ²¢¼ÆËãÏÂÁи÷СÌ⣺
£¨1£©Ä³Î¶Èʱ£¬²âµÃ0.01 mol/LµÄNaOHÈÜÒºpHΪ11£¬Çó¸ÃζÈÏÂË®µÄÀë×Ó»ý³£ÊýKw
£¨2£©ÔÚ´ËζÈÏ£¬½«pH£½aµÄNaOHÈÜÒºVa LÓëpH£½bµÄÁòËáVb L»ìºÏ¡£
¢ÙÈôËùµÃ»ìºÏÈÜҺΪÖÐÐÔ£¬ÇÒa£½12£¬b£½2£¬ÇóVa¡ÃVb¡£
¢ÚÈôËùµÃ»ìºÏÈÜÒºµÄpH£½10£¬ÇÒa£½12£¬b£½2£¬ÇóVa¡ÃVb¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸