·Ûĩ״ÑùÆ·AÊÇÓɵÈÎïÖʵÄÁ¿µÄMgOºÍAl2O3Óë³£¼û½ðÊôÑõ»¯ÎïB×é³ÉµÄ»ìºÏÎï¡£AÓÐÈçÏÂͼËùʾµÄת»¯¹Øϵ£º

ÇëÍê³ÉÏÂÁÐÎÊÌ⣺

£¨1£©µ¥ÖÊCºÍHµÄ»¯Ñ§Ê½·Ö±ðÊÇ____________¡¢____________¡£

£¨2£©Ð´³öÓÉIÉú³ÉJµÄÀë×Ó·½³Ìʽ£º___________________________________________¡£

£¨3£©Ð´³öÓÉFÉú³ÉGµÄÀë×Ó·½³Ìʽ£º___________________________________________¡£

£¨4£©Èô10.7 gÑùÆ·AÖÐMgO¡¢Al2O3ºÍBµÄÎïÖʵÄÁ¿¾ùΪ0.05 mol,ÔòBµÄ»¯Ñ§Ê½Îª____________¡£

£¨5£©ÈôBÖнðÊôÔ­×ÓÓëÑõÔ­×ÓµÄÁ£×ÓÊýÖ®±ÈΪ2¡Ã3£¬È¡7.10 gÑùÆ·A,Ç¡ºÃÓ뺬x mol HClµÄÑÎËáÍêÈ«·´Ó¦,ÔòxµÄÈ¡Öµ·¶Î§ÊÇ___________(±£ÁôСÊýµãºóÁ½Î»)¡£

£¨1£©Al  Cl2

£¨2£©Fe3++3NH3¡¤H2O====Fe£¨OH£©3¡ý+3

£¨3£©+CO2+2H2O====Al£¨OH£©3¡ý+

£¨4£©FeO

£¨5£©0.26£¼x£¼0.40

½âÎö£º´Ó¡°ºìºÖÉ«³Áµí¡±¿ÉÖªJÊÇFe£¨OH£©3£¬ÔòDÊÇFe£¬ÔòBÓ¦ÊÇFeµÄÑõ»¯Îï¡£´Ó¡°°×É«³Áµí¡±¿ÉÖªKÊÇAgCl£¬ÔòHÊÇCl2£¬´Ó·´Ó¦AE+D¿É¿´³öÕâÊÇÂÁÈÈ·´Ó¦£¬ÇÒEÓëNaOHÈÜÒº·´Ó¦£¬ÔòFÊÇNaAlO2£¬GÊÇAl£¨OH£©3¡£

£¨4£©ÓÉ10.7 g¼õÈ¥0.05 mol MgO¡¢0.05 mol Al2O3£¬¿ÉµÃÖÊÁ¿Îª3.6 g£¬Ôò¿ÉÍÆÖªBΪFeO¡£

£¨5£©2¡Ã3ÔòΪFe2O3£¬ÔÚMgO¡¢Al2O3ºÍFe2O3ÖÐÿ¸öÕý¼Ûµ¥Î»µÄÖÊÁ¿£¨¼´ÏûºÄ1 mol HClµÄÖÊÁ¿£©Al2O3×îС¡¢Fe2O3×î´ó£¬ËùÒÔxµÄȡֵΪÕâÁ½µãµÄÇø¼ä¡£


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

·Ûĩ״ÑùÆ·AÊÇÓɵÈÎïÖʵÄÁ¿µÄMgOºÍAl2O3Óë³£¼û½ðÊôÑõ»¯ÎïB×é³ÉµÄ»ìºÏÎï¡£AÓÐÈçÏÂͼËùʾµÄת»¯¹Øϵ¡£?

Çë»Ø´ðÏÂÁÐÎÊÌ⣺?

(1)µ¥ÖÊCºÍHµÄ»¯Ñ§Ê½·Ö±ðÊÇ         ¡¢         ¡£?

(2)д³öÓÉIÉú³ÉJµÄÀë×Ó·½³Ìʽ£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£?

(3)д³öÓÉFÉú³ÉGµÄÀë×Ó·½³Ìʽ£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£?

(4)Èô10.7 gÑùÆ·AÖÐMgO¡¢Al2O3ºÍBµÄÎïÖʵÄÁ¿¾ùΪ0.05 mol£¬ÔòBµÄ»¯Ñ§Ê½Îª¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£?

(5)ÈôBÖнðÊôÔ­×ÓÓëÑõÔ­×ÓµÄÁ£×ÓÊýÖ®±ÈΪ2¡Ã3£¬È¡7.10 gÑùÆ·A£¬Ç¡ºÃÓ뺬x mol HClµÄÑÎËáÍêÈ«·´Ó¦£¬ÔòxµÄÈ¡Öµ·¶Î§ÊÇ¡¡¡¡¡¡¡¡(±£ÁôСÊýµãºóÁ½Î»)¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

·Ûĩ״ÑùÆ·AÊÇÓɵÈÎïÖʵÄÁ¿µÄMgOºÍAl2O3Óë³£¼û½ðÊôÑõ»¯ÎïB×é³ÉµÄ»ìºÏÎï¡£AÓÐÈçÏÂͼËùʾµÄת»¯¹Øϵ¡£

 

ÇëÍê³ÉÏÂÁÐÎÊÌ⣺

(1)µ¥ÖÊCºÍHµÄ»¯Ñ§Ê½·Ö±ðÊÇ__________¡¢__________¡£

(2)д³öÓÉIÉú³ÉJµÄÀë×Ó·½³Ìʽ£º_____________¡£

(3)д³öÓÉFÉú³ÉGµÄÀë×Ó·½³Ìʽ£º________¡£

(4)Èô10.7 gÑùÆ·AÖÐMgO¡¢Al2O3ºÍBµÄÎïÖʵÄÁ¿¾ùΪ0.05  mol£¬ÔòBµÄ»¯Ñ§Ê½Îª_________¡£

(5)ÈôBÖнðÊôÔ­×ÓÓëÑõÔ­×ÓµÄÁ£×ÓÊýÖ®±ÈΪ2¡Ã3£¬È¡7.10 g ÑùÆ·A£¬Ç¡ºÃÓ뺬mol HClµÄÑÎËáÍêÈ«·´Ó¦£¬ÔòµÄÈ¡Öµ·¶Î§ÊÇ___________(±£ÁôСÊýµãºóÁ½Î»)¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ìÁÉÄþ³¯ÑôÁø³Ç¸ß¼¶ÖÐѧ¸ßÈýÉÏѧÆÚµÚ¶þ´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨10·Ö£©·Ûĩ״ÑùÆ·AÊÇÓɵÈÎïÖʵÄÁ¿µÄMgOºÍAl2O3Óë³£¼û½ðÊôÑõ»¯ÎïB×é³ÉµÄ»ìºÏÎï¡£AÓÐÈçÏÂͼËùʾµÄת»¯¹Øϵ¡£
 
ÇëÍê³ÉÏÂÁÐÎÊÌ⣺?
(1)µ¥ÖÊCºÍHµÄ»¯Ñ§Ê½·Ö±ðÊÇ__________¡¢__________¡£
(2)д³öÓÉIÉú³ÉJµÄÀë×Ó·½³Ìʽ£º_____________________________________
(3)д³öÓÉFÉú³ÉGµÄÀë×Ó·½³Ìʽ________________________________________
(4)Èô10.7 gÑùÆ·AÖÐMgO¡¢Al2O3ºÍBµÄÎïÖʵÄÁ¿¾ùΪ0.05  mol£¬ÔòBµÄ»¯Ñ§Ê½Îª_________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêÁÉÄþ³¯ÑôÁø³Ç¸ß¼¶ÖÐѧ¸ßÈýÉÏѧÆÚµÚ¶þ´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨10·Ö£©·Ûĩ״ÑùÆ·AÊÇÓɵÈÎïÖʵÄÁ¿µÄMgOºÍAl2O3Óë³£¼û½ðÊôÑõ»¯ÎïB×é³ÉµÄ»ìºÏÎï¡£AÓÐÈçÏÂͼËùʾµÄת»¯¹Øϵ¡£?

  ?

ÇëÍê³ÉÏÂÁÐÎÊÌ⣺?

(1)µ¥ÖÊCºÍHµÄ»¯Ñ§Ê½·Ö±ðÊÇ__________¡¢__________¡£?

(2)д³öÓÉIÉú³ÉJµÄÀë×Ó·½³Ìʽ£º_____________________________________?

(3)д³öÓÉFÉú³ÉGµÄÀë×Ó·½³Ìʽ________________________________________

(4)Èô10.7 gÑùÆ·AÖÐMgO¡¢Al2O3ºÍBµÄÎïÖʵÄÁ¿¾ùΪ0.05  mol£¬ÔòBµÄ»¯Ñ§Ê½Îª_________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸