£¨8·Ö£©AΪÌþ£¬BΪÌþµÄº¬ÑõÑÜÉúÎÓɵÈÎïÖʵÄÁ¿µÄAºÍB×é³ÉµÄ»ìºÏÎï0.05molÔÚ0.125molµÄÑõÆøÖÐÍêȫȼÉÕ£¬Éú³É0.1mol CO2ºÍ0.1mol H2O¡£ÊÔͨ¹ý¼ÆËã»Ø´ð£º

(1)ÓÉA¡¢B×é³É»ìºÏÎïµÄƽ¾ù·Ö×ÓʽΪ___________

(2) ÁíÈ¡Ò»¶¨Á¿µÄAºÍBÍêȫȼÉÕ£¬½«ÆäÒÔÈÎÒâÎïÖʵÄÁ¿±È»ìºÏ£¬ÇÒÎïÖʵÄÁ¿Ö®ºÍÒ»¶¨¡£¢ÙÈôºÄÑõÁ¿Ò»¶¨£¬ÔòA¡¢BµÄ·Ö×Óʽ·Ö±ðÊÇ___________¡¢ ____________

¢ÚÈôÉú³ÉµÄ¶þÑõ»¯Ì¼ºÍË®µÄÎïÖʵÄÁ¿Ò»¶¨£¬ÔòA¡¢BµÄ·Ö×Óʽ·Ö±ðÊÇ        ¡¢       (3) ÁíÈ¡a mol µÄÒÔÈÎÒâ±È»ìºÏµÄAºÍBµÄ»ìºÏÎÔÚ¹ýÁ¿µÄÑõÆøÖÐÍêȫȼÉÕ¡£

¢ÙÈôºÄÑõÁ¿Îª¶¨Öµ£¬ÔòºÄÑõÁ¿Îª_____________mol(Óú¬aµÄ´úÊýʽ±íʾ£¬ÏÂͬ)

¢ÚÈôÉú³ÉµÄCO2µÄÁ¿Îª¶¨Öµ£¬ÔòÉú³ÉÎïË®µÄÖÊÁ¿·¶Î§Îª__________________________¡£

 

¡¾´ð°¸¡¿

 

¡¾½âÎö¡¿ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

AΪÌþ£¬BΪÌþµÄº¬ÑõÑÜÉúÎÓɵÈÎïÖʵÄÁ¿µÄAºÍB×é³ÉµÄ»ìºÏÎï0.05molÔÚ0.125molµÄÑõÆøÖÐÍêȫȼÉÕ£¬Éú³É0.1mol CO2ºÍ0.1mol H2O£®ÊÔͨ¹ý¼ÆËã»Ø´ð£º
£¨1£©ÓÉA¡¢B×é³É»ìºÏÎïµÄƽ¾ù·Ö×ÓʽΪ
C2H4O
C2H4O

£¨2£©ÁíÈ¡Ò»¶¨Á¿µÄAºÍBÍêȫȼÉÕ£¬½«ÆäÒÔÈÎÒâÎïÖʵÄÁ¿±È»ìºÏ£¬ÇÒÎïÖʵÄÁ¿Ö®ºÍÒ»¶¨£®
¢ÙÈôºÄÑõÁ¿Ò»¶¨£¬ÔòA¡¢BµÄ·Ö×Óʽ·Ö±ðÊÇ
C2H2
C2H2
¡¢
C2H6O2
C2H6O2

¢ÚÈôÉú³ÉµÄ¶þÑõ»¯Ì¼ºÍË®µÄÎïÖʵÄÁ¿Ò»¶¨£¬ÔòA¡¢BµÄ·Ö×Óʽ·Ö±ðÊÇ
C2H4
C2H4
¡¢
C2H4O2
C2H4O2

£¨3£©ÁíÈ¡a mol µÄÒÔÈÎÒâ±È»ìºÏµÄAºÍBµÄ»ìºÏÎÔÚ¹ýÁ¿µÄÑõÆøÖÐÍêȫȼÉÕ£®
¢ÙÈôºÄÑõÁ¿Îª¶¨Öµ£¬ÔòºÄÑõÁ¿Îª
2.5a
2.5a
mol£¨Óú¬aµÄ´úÊýʽ±íʾ£¬ÏÂͬ£©
¢ÚÈôÉú³ÉµÄCO2µÄÁ¿Îª¶¨Öµ£¬ÔòÉú³ÉÎïË®µÄÖÊÁ¿·¶Î§Îª
18ag£¼m£¨H2O£©£¼54ag
18ag£¼m£¨H2O£©£¼54ag
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÒÑÖªAΪÌþ£¬BΪÌþµÄº¬ÑõÑÜÉúÎÓɵÈÎïÖʵÄÁ¿µÄ A ºÍ B ×é³ÉµÄ»ìºÏÎï 0.05mol ÔÚ0.125mol µÄÑõÆøÖÐÇ¡ºÃÍêȫȼÉÕ£¬Éú³É 0.1mol µÄ CO2 ºÍ 0.1mol H2O£¬ÊÔͨ¹ý¼ÆËã»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©´Ó·Ö×ÓʽµÄ½Ç¶È¿´£¬µÈÎïÖʵÄÁ¿A ºÍ B ×é³ÉµÄ»ìºÏÎïƽ¾ù×é³É¿ÉÓû¯Ñ§Ê½±íʾΪ
C2H4O
C2H4O
£¬
£¨2£©ÁíÈ¡Ò»¶¨Á¿µÄAºÍBÍêȫȼÉÕ£¬½«ÆäÒÔÈÎÒâÎïÖʵÄÁ¿±È»ìºÏ£¬ÇÒÎïÖʵÄÁ¿Ö®ºÍÒ»¶¨£¬Ôò£º
¢ÙÈôºÄÑõÁ¿Ò»¶¨£¬ÔòAºÍBµÄ½á¹¹¼òʽ·Ö±ðΪ£ºA
CH¡ÔCH
CH¡ÔCH
 B

¢ÚÈôÉú³ÉµÄCO2 ºÍ H2O µÄÎïÖʵÄÁ¿Ò»¶¨£¬ÔòAºÍBµÄ½á¹¹¼òʽΪ£ºA
CH2=CH2
CH2=CH2
   B
CH3COOH
CH3COOH
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(4·Ö) AΪÌþ£¬BΪÌþµÄº¬ÑõÑÜÉúÎȡµÈÎïÖʵÄÁ¿µÄAºÍB»ìºÏÎï¹²0.5molÔÚ1.5molµÄÑõÆøÖÐÍêȫȼÉÕ£¬Éú³É1molCO2ºÍ1.5molH2O¡£ÁíÈ¡Ò»¶¨Á¿µÄAºÍBÍêȫȼÉÕ£¬½«ÆäÒÔÈÎÒâÎïÖʵÄÁ¿±È»ìºÏ£¬ÇÒÎïÖʵÄÁ¿Ö®ºÍÒ»¶¨ÊÔͨ¹ý¼ÆËã»Ø´ð£º

£¨1£©ÈôÉú³ÉCO2ºÍË®µÄÎïÖʵÄÁ¿Ò»¶¨£¬ÔòAºÍBµÄ·Ö×Óʽ·Ö±ðÊÇ         £¨ÈÎдһ×飩

£¨2£©ÈôºÄÑõÁ¿Ò»¶¨£¬ÔòAºÍBµÄ·Ö×Óʽ·Ö±ðÊÇ                   £¨ÈÎдһ×飩

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010¡ª2011ѧÄêºÓ±±Ê¡ºâË®ÖÐѧ¸ß¶þÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

(4·Ö) AΪÌþ£¬BΪÌþµÄº¬ÑõÑÜÉúÎȡµÈÎïÖʵÄÁ¿µÄAºÍB»ìºÏÎï¹²0.5molÔÚ1.5molµÄÑõÆøÖÐÍêȫȼÉÕ£¬Éú³É1molCO2ºÍ1.5molH2O¡£ÁíÈ¡Ò»¶¨Á¿µÄAºÍBÍêȫȼÉÕ£¬½«ÆäÒÔÈÎÒâÎïÖʵÄÁ¿±È»ìºÏ£¬ÇÒÎïÖʵÄÁ¿Ö®ºÍÒ»¶¨ÊÔͨ¹ý¼ÆËã»Ø´ð£º
£¨1£©ÈôÉú³ÉCO2ºÍË®µÄÎïÖʵÄÁ¿Ò»¶¨£¬ÔòAºÍBµÄ·Ö×Óʽ·Ö±ðÊÇ         £¨ÈÎдһ×飩
£¨2£©ÈôºÄÑõÁ¿Ò»¶¨£¬ÔòAºÍBµÄ·Ö×Óʽ·Ö±ðÊÇ                   £¨ÈÎдһ×飩

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸