£¨8·Ö£©ÒÑÖªXΪÖÐѧ»¯Ñ§ÖеÄÒ»ÖÖ³£¼ûµÄÑΣ¬FΪµ»ÆÉ«¹ÌÌ壻M¡¢NΪ³£¼ûµÄ½ðÊô£¬NµÄ×é³ÉÔªËصÄÀë×Ӱ뾶ÊǵÚÈýÖÜÆÚÔªËØÖÐÀë×Ӱ뾶×îСµÄ¡£NµÄ×î¸ß¼ÛÑõ»¯ÎïÊÇÄÍ»ð²ÄÁÏ£¬ËüµÄ¾§ÌåÓ²¶ÈºÜ´ó£¬³£×öÊÖ±íµÄÖá³Ð£»HΪÆøÌåµ¥ÖÊ£¬DΪÎÞÉ«ÆøÌ壬ÔÚ¿ÕÆøÖлá³öÏÖºì×ØÉ«¡£¸÷ÎïÖʵÄת»¯¹ØϵÈçÏÂͼ£¨²¿·Ö·´Ó¦²úÎïÒÑÂÔÈ¥£©¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©XµÄ»¯Ñ§Ê½Îª £»FµÄµç×ÓʽΪ ¡£
£¨2£©·´Ó¦¢ÚµÄÀë×Ó·½³ÌʽΪ_______________________________________________¡£
·´Ó¦¢ÛµÄ»¯Ñ§·½³ÌʽΪ_______________________________________________¡£
£¨3£©ÈôÏò100 mL ÑÎXµÄÈÜÒºÖмÓÈë10 g½ðÊôµ¥ÖÊMµÄ·ÛÄ©£¬³ä·Ö½Á°èºó£¬¹ýÂË£¬ºæ¸É
µÃ10.16g¹ÌÌåC¡£ÔòÂËÒºAÖÐÈÜÖʵÄÎïÖʵÄÁ¿Å¨¶ÈΪ________________________¡£(¼ÙÉèÌå»ý²»±ä)
£¨1£©£¬£¨1·Ö/¸ö£¬¹²2·Ö£©
£¨2£©¢Ù 3Fe2+ + NO3£+ 4H+ == 3Fe3+ + NO¡ü+ 2H2O£¨2·Ö£©
¢Ú £¨2·Ö£©
£¨3£©0.2 mol/L£¨2·Ö£©
½âÎö:±¾ÌâÊôÓÚÎÞ»ú¿òͼÌ⣬˼άÈÝÁ¿´ó£¬×ÛºÏÐÔÇ¿¡£ÕâÖÖÀàÐͶñÊÔÌâ¹Ø¼üÊÇÕÒ×¼ÌâÑÛ£¬Ñ°ÇóÍ»ÆƵ㡣¸ù¾ÝÌâÒâ¿ÉÖªFÊǹýÑõ»¯ÄÆ£¬NÊÇAl£¬DÊÇNO¡£¹ýÑõ»¯ÄÆÈÜÓÚË®Éú³ÉÑõÆø£¬ÔòHÊÇÑõÆø¡£À¶É«³ÁµíÊÇÇâÑõ»¯Í£¬ÔòXÖк¬ÓÐÍÀë×Ó¡£MºÍX¿É·¢ÉúÖû»·´Ó¦Éú³É¹ÌÌåC£¬ÔòCÊÇÍ£¬Òò´ËMÊÇÌú¡£·´Ó¦ÖÐÉú³ÉNO£¬ËµÃ÷ÊÇÑõ»¯»¹Ô·´Ó¦£¬ËùÒÔAÊÇÏõËáÑÇÌú£¬BÖк¬ÓÐÌúÀë×Ó£¬ºÍ¹ýÑõ»¯ÄÆ·´Ó¦Éú³ÉÇâÑõ»¯Ìú£¬ÇâÑõ»¯Ìú·Ö½âÉú³ÉÑõ»¯Ìú£¬Ñõ»¯ÌúºÍÂÁ·¢ÉúÂÁÈÈ·´Ó¦¼´µÃµ½Ìúµ¥ÖÊ¡£ÏõËáͺÍÌú·´Ó¦µÄ·½³ÌʽΪCu(NO3)2£«Fe=Cu£«Fe(NO3)2£¬Ã¿ÏûºÄ1molÏõËáÍ£¬¹ÌÌåÖÊÁ¿Ôö¼Ó8g¡£Êµ¼ÊÔö¼ÓµÄÖÊÁ¿ÊÇ0.16g£¬ÔòÏûºÄµÄÏõËáÍΪ£¬ËùÒÔŨ¶ÈÊÇ0.2mol/L¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêºÓ±±Ê¡ºâË®ÖÐѧ¸ßÒ»ÏÂѧÆÚÈýµ÷¿¼ÊÔ»¯Ñ§ÊÔ¾í £¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ
£¨8·Ö£©ÒÑÖªXΪÖÐѧ»¯Ñ§ÖеÄÒ»ÖÖ³£¼ûµÄÑΣ¬FΪµ»ÆÉ«¹ÌÌ壻M¡¢NΪ³£¼ûµÄ½ðÊô£¬NµÄ×é³ÉÔªËصÄÀë×Ӱ뾶ÊǵÚÈýÖÜÆÚÔªËØÖÐÀë×Ӱ뾶×îСµÄ¡£NµÄ×î¸ß¼ÛÑõ»¯ÎïÊÇÄÍ»ð²ÄÁÏ£¬ËüµÄ¾§ÌåÓ²¶ÈºÜ´ó£¬³£×öÊÖ±íµÄÖá³Ð£»HΪÆøÌåµ¥ÖÊ£¬DΪÎÞÉ«ÆøÌ壬ÔÚ¿ÕÆøÖлá³öÏÖºì×ØÉ«¡£¸÷ÎïÖʵÄת»¯¹ØϵÈçÏÂͼ£¨²¿·Ö·´Ó¦²úÎïÒÑÂÔÈ¥£©¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©XµÄ»¯Ñ§Ê½Îª £»FµÄµç×ÓʽΪ ¡£
£¨2£©·´Ó¦¢ÚµÄÀë×Ó·½³ÌʽΪ_______________________________________________¡£
·´Ó¦¢ÛµÄ»¯Ñ§·½³ÌʽΪ_______________________________________________¡£
£¨3£©ÈôÏò100 mL ÑÎXµÄÈÜÒºÖмÓÈë10 g½ðÊôµ¥ÖÊMµÄ·ÛÄ©£¬³ä·Ö½Á°èºó£¬¹ýÂË£¬ºæ¸É
µÃ10.16g¹ÌÌåC¡£ÔòÂËÒºAÖÐÈÜÖʵÄÎïÖʵÄÁ¿Å¨¶ÈΪ________________________¡£(¼ÙÉèÌå»ý²»±ä)
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013-2014ѧÄê½Î÷Ê¡¸ßÈýÉÏѧÆÚµÚËÄ´ÎÔ¿¼Àí×Û»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÒÑÖªXΪÖÐѧ»¯Ñ§ÖеÄÒ»ÖÖ³£¼ûµÄÑΣ¬FΪµ»ÆÉ«¹ÌÌ壻M¡¢NΪ³£¼ûµÄ½ðÊô£¬NµÄ×î¸ß¼ÛÑõ»¯ÎïÊÇÄÍ»ð²ÄÁÏ£»HΪÆøÌåµ¥ÖÊ£¬DΪÎÞÉ«ÆøÌ壬ÔÚ¿ÕÆøÖлá³öÏÖºì×ØÉ«¡£¸÷ÎïÖʵÄת»¯¹ØϵÈçÏÂͼ£¨²¿·Ö·´Ó¦²úÎïÒÑÂÔÈ¥£©¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©XµÄ»¯Ñ§Ê½Îª ¡£
£¨2£©ÔÚ·´Ó¦¢Ù¢Ú¢Û¢ÜÖÐÊôÓÚÖû»·´Ó¦µÄÊÇ £¨ÌîÐòºÅ£©¡£
£¨3£©·´Ó¦¢ÛµÄ»¯Ñ§·½³ÌʽΪ_________________________________¡£
£¨4£©XÈÜÒºÓëF·´Ó¦µÄ×Ü»¯Ñ§·½³ÌʽΪ ¡£
£¨5£©¼ìÑéÂËÒºAÖнðÊôÀë×ӵķ½·¨ÊÇ ¡£
£¨6£©ÈôÏò100 mLÑÎXµÄÈÜÒºÖмÓÈë10 g¹ýÁ¿½ðÊôµ¥ÖÊMµÄ·ÛÄ©£¬³ä·Ö½Á°èºó£¬¹ýÂË£¬ºæ¸ÉµÃ10.16g¹ÌÌå¡£ÔòÂËÒºAÖÐÈÜÖʵÄÎïÖʵÄÁ¿Å¨¶ÈΪ_________¡££¨¼ÙÉèÈÜÒºÌå»ý²»±ä£©
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ìºÓ±±Ê¡¸ßÒ»ÏÂѧÆÚÈýµ÷¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ
£¨8·Ö£©ÒÑÖªXΪÖÐѧ»¯Ñ§ÖеÄÒ»ÖÖ³£¼ûµÄÑΣ¬FΪµ»ÆÉ«¹ÌÌ壻M¡¢NΪ³£¼ûµÄ½ðÊô£¬NµÄ×é³ÉÔªËصÄÀë×Ӱ뾶ÊǵÚÈýÖÜÆÚÔªËØÖÐÀë×Ӱ뾶×îСµÄ¡£NµÄ×î¸ß¼ÛÑõ»¯ÎïÊÇÄÍ»ð²ÄÁÏ£¬ËüµÄ¾§ÌåÓ²¶ÈºÜ´ó£¬³£×öÊÖ±íµÄÖá³Ð£»HΪÆøÌåµ¥ÖÊ£¬DΪÎÞÉ«ÆøÌ壬ÔÚ¿ÕÆøÖлá³öÏÖºì×ØÉ«¡£¸÷ÎïÖʵÄת»¯¹ØϵÈçÏÂͼ£¨²¿·Ö·´Ó¦²úÎïÒÑÂÔÈ¥£©¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©XµÄ»¯Ñ§Ê½Îª £»FµÄµç×ÓʽΪ ¡£
£¨2£©·´Ó¦¢ÚµÄÀë×Ó·½³ÌʽΪ_______________________________________________¡£
·´Ó¦¢ÛµÄ»¯Ñ§·½³ÌʽΪ_______________________________________________¡£
£¨3£©ÈôÏò100 mL ÑÎXµÄÈÜÒºÖмÓÈë10 g½ðÊôµ¥ÖÊMµÄ·ÛÄ©£¬³ä·Ö½Á°èºó£¬¹ýÂË£¬ºæ¸É
µÃ10.16g¹ÌÌåC¡£ÔòÂËÒºAÖÐÈÜÖʵÄÎïÖʵÄÁ¿Å¨¶ÈΪ________________________¡£(¼ÙÉèÌå»ý²»±ä)
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com