µª¿ÉÒÔÐγɶàÖÖÀë×Ó£¬ÈçN3-£¬NH2-£¬N3-£¬NH4+£¬N2H5+£¬N2H62+µÈ£¬ÒÑÖªN2H5+ÓëN2H62+ÊÇÓÉÖÐÐÔ·Ö×Ó½áºÏÖÊ×ÓÐγɵģ¬ÀàËÆ
ÓÚNH4+£¬Òò´ËÓÐÀàËÆÓÚ NH4+µÄÐÔÖÊ£®
£¨1£©Ð´³öN2H62+ÔÚ¼îÐÔÈÜÒºÖз´Ó¦µÄÀë×Ó·½³Ìʽ
N2H62++2OH-=N2H4+2H2O
N2H62++2OH-=N2H4+2H2O
£®
£¨2£©NH2-µÄµç×ÓʽΪ
£® 
£¨3£©N3-ÓÐ
22
22
¸öµç×Ó£®
£¨4£©Ð´³ö¶þÖÖÓɶà¸öÔ­×Ó×é³ÉµÄº¬ÓÐÓëN3-µç×ÓÊýÏàͬµÄÎïÖʵĻ¯Ñ§Ê½
N2O¡¢CO2
N2O¡¢CO2
£®
£¨5£©µÈµç×ÓÊýµÄ΢Á£ÍùÍù¾ßÓÐÏàËƵĽṹ£¬ÊÔÔ¤²âN3-µÄ¹¹ÐÍ
Ö±ÏßÐÍ
Ö±ÏßÐÍ
£®
£¨6£©¾Ý±¨µÀ£¬ÃÀ¹ú¿Æѧ¼Ò¿¨¶û?¿ËÀï˹ÌØÓÚ1998Äê11ÔºϳÉÁËÒ»ÖÖÃûΪ¡°N5¡±µÄÎïÖÊ£¬ÓÉÓÚÆä¾ßÓм«Ç¿µÄ±¬Õ¨ÐÔ£¬ÓÖ³ÆΪ¡°ÑÎÁ£Õ¨µ¯¡±£®Æù½ñΪֹ£¬ÈËÃǶÔËüµÄ½á¹¹Éв»Çå³þ£¬Ö»ÖªµÀ¡°N5¡±Êµ¼ÊÉÏÊÇ´øÕýµçºÉµÄ·Ö×ÓËéƬ£¬Æä½á¹¹ÊǶԳƵģ¬5¸öNÅųÉVÐΣ®Èç¹û5¸öN½áºÏºó¶¼´ïµ½8µç×ӽṹ£¬ÇÒº¬ÓÐ2¸öN¡ÔN¼ü£®Ôò¡°N5¡±·Ö×ÓËéƬËù´øµçºÉÊÇ
Ò»¸öµ¥Î»ÕýµçºÉ
Ò»¸öµ¥Î»ÕýµçºÉ
£®
·ÖÎö£º£¨1£©ÖÐN2H62+ÖÐNµÄ»¯ºÏ¼ÛΪ+4¼Û£¬N2H62+ÊÇÓÉÖÐÐÔ·Ö×Ó N2H4 ½áºÏ2¸öÖÊ×ÓÐγɵģ¬Ï൱ÓÚ¹ÊN2H62+Ï൱ÓÚ¶þÔªËᣬ¼îÐÔÈÜÒºÖз´Ó¦µÄÀë×Ó·½³ÌʽΪN2H62++2OH-=N2H4+2H2O£»
£¨2£©NH2-µÄµç×ÓʽΪ£º£»
£¨3£©1¸öNº¬ÓÐ7¸öµç×Ó£¬¹ÊN3-ÓÐ22¸öµç×Ó£»
£¨4£©º¬ÓÐ22¸öµç×ӵĶàÔ­×ÓÎïÖÊÓÐN2O¡¢CO2¡¢CNO-¡¢BeF2¡¢CaH2¡¢C3H4µÈ£»
£¨5£©CO2ΪֱÏßÐÍ·Ö×Ó£¬¹Ê¿ÉÈÏΪN3-µÄ¹¹ÐÍΪֱÏßÐÍ£»
£¨6£©N5½á¹¹ÊǶԳƵģ¬5¸öNÅųÉVÐΣ¬5¸öN½áºÏºó¶¼´ïµ½8µç×ӽṹ£¬ÇÒº¬ÓÐ2¸öN¡ÔN¼ü£¬Âú×ãÌõ¼þµÄ½á¹¹Îª£º£¬¹Ê¡°N5¡±´øÒ»¸öµ¥Î»ÕýµçºÉ£®
½â´ð£º½â£º£¨1£©ÖÐN2H62+ÖÐNµÄ»¯ºÏ¼ÛΪ+4¼Û£¬N2H62+ÊÇÓÉÖÐÐÔ·Ö×ÓN2H4½áºÏ2¸öÖÊ×ÓÐγɵģ¬¹ÊN2H62+Ï൱ÓÚ¶þÔªËᣬ¹ÊÔÚ¼îÐÔÈÜÒºÖз´Ó¦µÄÀë×Ó·½³ÌʽΪN2H62++2OH-=N2H4+2H2O£¬¹Ê´ð°¸Îª£ºN2H62++2OH-=N2H4+2H2O£»
£¨2£©NH2-µÄµç×ÓʽΪ£º£¬¹Ê´ð°¸Îª£º£»
£¨3£©1¸öNº¬ÓÐ7¸öµç×Ó£¬¹ÊN3-ÓÐ22¸öµç×Ó£¬¹Ê´ð°¸Îª£º22£»
£¨4£©º¬ÓÐ22¸öµç×ӵĶàÔ­×ÓÎïÖÊÓÐN2O¡¢CO2¡¢CNO-¡¢BeF2¡¢CaH2¡¢C3H4µÈ£¬¹Ê´ð°¸Îª£ºN2O¡¢CO2£»
£¨5£©CO2ΪֱÏßÐÍ·Ö×Ó£¬¹Ê¿ÉÈÏΪN3-µÄ¹¹ÐÍΪֱÏßÐÍ£¬¹Ê´ð°¸Îª£ºÖ±ÏßÐÍ£»
£¨6£©N5½á¹¹ÊǶԳƵģ¬5¸öNÅųÉVÐΣ¬5¸öN½áºÏºó¶¼´ïµ½8µç×ӽṹ£¬ÇÒº¬ÓÐ2¸öN¡ÔN¼ü£¬Âú×ãÌõ¼þµÄ½á¹¹Îª£º£¬¹Ê¡°N5¡±´øÒ»¸öµ¥Î»ÕýµçºÉ£¬¹Ê´ð°¸Îª£ºÒ»¸öµ¥Î»ÕýµçºÉ£®
µãÆÀ£º±¾ÌâÖص㿼²éÁ˵ç×ÓʽµÄÊéдÒÔ¼°µÈµç×Ó΢Á£µÄÐÔÖÊ£¬²àÖØÔ­×ӽṹÓë·Ö×Ó¹¹Ð͵ķÖÎö£¬×¢Òâ°ÑÎÕÔ­×ӵĵç×ÓÅŲ¼£¬ÌâÄ¿ÄѶȲ»´ó£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

I¡¢Â±ËØ»¯Ñ§·á¸»¶à²Ê£¬ÄÜÐγɱ»¯Î±ËØ»¥»¯Îï¡¢¶à±»¯ÎïµÈ¶àÖÖÀàÐ͵Ļ¯ºÏÎ
£¨1£©¢ÙHClO4¡¢¢ÚHIO4¡¢¢ÛH5IO6  µÄËáÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòΪ
¢Ù¢Ú¢Û
¢Ù¢Ú¢Û
£¨ÌîÐòºÅ£©£®
£¨2£©Â±ËØ»¥»¯ÎïÈçBrI¡¢IClµÈÓë±Ëص¥ÖʽṹÏàËÆ¡¢ÐÔÖÊÏà½ü£®Cl2¡¢BrI¡¢ICl·ÐµãÓɸߵ½µÍµÄ˳ÐòΪ
BrI£¾ICl£¾Cl2
BrI£¾ICl£¾Cl2
£®
£¨3£©Æø̬·ú»¯ÇâÖдæÔÚ¶þ¾Û·Ö×Ó£¨HF£©2£¬ÕâÊÇÓÉÓÚ
HF·Ö×Ó¼äÐγÉÇâ¼ü
HF·Ö×Ó¼äÐγÉÇâ¼ü
£®
£¨4£©I3+£¨¿É¿´³ÉII2+£©ÊôÓÚ¶à±ËØÑôÀë×Ó£¬¸ù¾ÝVSEPRÄ£ÐÍÍƲâI3+µÄ¿Õ¼ä¹¹ÐÍΪ
VÐÎ
VÐÎ
£®
£¨5£©Â±»¯ÎïRbICl2¼ÓÈÈʱ»á·Ö½âΪ¾§¸ñÄÜÏà¶Ô½Ï´óµÄ±»¯ÎïAºÍ±ËØ»¥»¯Îï»ò±Ëص¥ÖÊ£¬AµÄ»¯Ñ§Ê½Îª
RbCl
RbCl
£®
II£®µª¿ÉÒÔÐγɶàÖÖÀë×Ó£¬ÈçN3-£¬NH2-£¬N3-£¬NH4+£¬N2H5+£¬N2H62+µÈ£¬ÒÑÖªN2H5+ÓëN2H62+ÊÇÓÉÖÐÐÔ·Ö×Ó½áºÏÖÊ×ÓÐγɵģ¬ÀàËÆÓÚNH4+£¬Òò´ËÓÐÀàËÆÓÚ NH4+µÄÐÔÖÊ£®
£¨1£©³öN2H62+ÔÚ×ãÁ¿¼îÐÔÈÜÒºÖз´Ó¦µÄÀë×Ó·½³Ìʽ
N2H62++2OH-=N2H4+2H2O
N2H62++2OH-=N2H4+2H2O
£®
£¨2£©NH2-µÄµç×ÓʽΪ
£®
£¨3£©Ð´³öÁ½ÖÖÓɶà¸öÔ­×Ó×é³ÉµÄº¬ÓÐÓëN3-µç×ÓÊýÏàͬµÄÎïÖʵĻ¯Ñ§Ê½
N2O¡¢CO2
N2O¡¢CO2
£®
£¨4£©µÈµç×ÓÊýµÄ΢Á£ÍùÍù¾ßÓÐÏàËƵĽṹ£¬ÊÔÔ¤²âN3-µÄ¹¹ÐÍ
Ö±ÏßÐÍ
Ö±ÏßÐÍ
£®
£¨5£©¾Ý±¨µÀ£¬ÃÀ¹ú¿Æѧ¼Ò1998Äê11ÔºϳÉÁËÒ»ÖÖÃûΪ¡°N5¡±µÄÎïÖÊ£¬ÓÉÓÚÆä¾ßÓм«Ç¿µÄ±¬Õ¨ÐÔ£¬ÓÖ³ÆΪ¡°ÑÎÁ£Õ¨µ¯¡±£®Æù½ñΪֹ£¬ÈËÃǶÔËüµÄ½á¹¹Éв»Çå³þ£¬Ö»ÖªµÀ¡°N5¡±Êµ¼ÊÉÏÊÇ´øÕýµçºÉµÄ·Ö×ÓËéƬ£¬Æä½á¹¹ÊǶԳƵģ¬5¸öNÅųÉVÐΣ®Èç¹û5¸öN½áºÏºó¶¼´ïµ½8µç×ӽṹ£¬ÇÒº¬ÓÐ2¸öN¡ÔN¼ü£®Ôò¡°N5¡±·Ö×ÓËéƬ Ëù´øµçºÉÊÇ
Ò»¸öµ¥Î»ÕýµçºÉ
Ò»¸öµ¥Î»ÕýµçºÉ
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

µª¿ÉÒÔÐγɶàÖÖÀë×Ó£¬È磺µÈ¡£ÒÑÖªµÄÐγɹý³ÌÀàËÆÓÚµÄÐγɹý³Ì£¬ÔÚ¼îÐÔÈÜÒºÖÐÉú³ÉµçÖÐÐԵķÖ×ÓºÍH2O£¬ÊÔÌîдÏÂÁпհףº?

£¨1£©¸ÃµçÖÐÐÔ·Ö×ӵĻ¯Ñ§Ê½Îª                       ¡£?

£¨2£©Àë×ӵĵç×ÓʽΪ                           ¡£?

£¨3£©Ò»¸öÀë×Ó¹²ÓР                          ¸öµç×Ó¡£?

£¨4£©Ð´³öÁ½ÖÖÓɶàÔ­×Ó×é³ÉµÄº¬ÓÐÓëµç×ÓÊýÏàͬµÄÁ£×ӵĻ¯Ñ§Ê½£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

µª¿ÉÒÔÐγɶàÖÖÀë×Ó£¬ÈçN3£­¡¢¡¢¡¢¡¢¡¢µÈ£¬ÒÑÖªÓëÊÇÓÉÖÐÐÔ·Ö×Ó½áºÏÖÊ×ÓÐγɵģ¬ÀàËÆÓÚ£¬Òò´ËÓÐÀàËÆÓÚµÄÐÔÖÊ¡£

£¨1£©µÄµç×ÓʽΪ__________¡£?

£¨2£©ÓÐ__________¸öµç×Ó¡£?

£¨3£©Ð´³öÁ½ÖÖÓɶà¸öÔ­×Ó×é³ÉµÄº¬ÓÐÓëNµç×ÓÊýÏàͬµÄÎïÖʵĻ¯Ñ§Ê½__________¡£

£¨4£©µÈµç×ÓÊýµÄÁ£×ÓÍùÍù¾ßÓÐÏàËƵĽṹ£¬ÊÔÔ¤²âµÄ¹¹ÐÍ____________________¡£

£¨5£©¾Ý±¨µÀ£¬ÃÀ¹ú¿Æѧ¼Ò¿¨¶û¡¤¿ËÀï˹ÌØÓÚ1998Äê11ÔºϳÉÁËÒ»ÖÖÃûΪ¡°N5¡±µÄÎïÖÊ£¬ÓÉÓÚÆä¾ßÓм«Ç¿µÄ±¬Õ¨ÐÔ£¬ÓÖ³ÆΪ¡°ÑÎÁ£Õ¨µ¯¡±¡£Æù½ñΪֹ£¬ÈËÃǶÔËüµÄ½á¹¹Éв»Çå³þ£¬Ö»ÖªµÀ¡°N5¡±Êµ¼ÊÉÏÊÇ´øÕýµçºÉµÄ·Ö×ÓËéƬ£¬Æä½á¹¹ÊǶԳƵģ¬5¸öNÅųÉVÐΡ£Èç¹û5¸öN½áºÏºó¶¼´ïµ½8µç×ӽṹ£¬ÇÒº¬ÓÐ2¸öN¡ÔN¼ü¡£Ôò¡°N5¡±·Ö×ÓËéƬËù´øµçºÉÊÇ__________¡£ ?

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ìÕã½­Ê¡Õ㶫±±ÈýУ¸ßÒ»ÏÂѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

µª¿ÉÒÔÐγɶàÖÖÀë×Ó£¬ÈçN3£­¡¢NH2£­¡¢N3£­¡¢NH4£«¡¢N2H5£«¡¢N2H6£«µÈ¡£ÒÑÖªN2H5£«µÄÐγɹý³ÌÀàËÆÓÚNH4£«µÄÐγɹý³Ì£¬N2H5£«ÔÚ¼îÐÔÈÜÒºÖн«Éú³ÉµçÖÐÐԵķÖ×ÓºÍË®¡£ÊÔд³ö£º

£¨1£©¸ÃµçÖÐÐÔ·Ö×ӵĻ¯Ñ§Ê½£º          £»

£¨2£©N2H5£«µÄµç×Óʽ£º              £»

£¨3£©1 mol N3£­¹²ÓР    mol µç×Ó£»

£¨4£©Ð´³öÁ½ÖַǽðÊôÑõ»¯Îï¸úN3£­µç×ÓÊýÏàͬµÄÎïÖʵĻ¯Ñ§Ê½        ¡¢         ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸