ij¹¤Òµ·ÏË®Öк¬ÓÐCN£ºÍCr2O72£µÈÀë×Ó£¬Ðè¾ÎÛË®´¦Àí´ï±êºó²ÅÄÜÅÅ·Å£¬ÎÛË®´¦Àí³§ÄâÓÃÏÂÁÐÁ÷³Ì½øÐд¦Àí£¬»Ø´ðÏÂÁÐÎÊÌ⣺
![]()
(1)²½Öè¢ÚÖУ¬CN£±»ClO£Ñõ»¯ÎªCNO£µÄÀë×Ó·½³ÌʽΪ£º________________________¡£
(2)²½Öè¢ÛµÄ·´Ó¦ÎªS2O32££«Cr2O72££«H£«¨D¡úSO42££«Cr3£«£«H2O(δÅ䯽)£¬ÔòÿÏûºÄ0.4 mol Cr2O72£×ªÒÆ____________mol e£¡£
(3)º¬Cr3£«·ÏË®¿ÉÒÔ¼ÓÈëÊìʯ»Ò½øÒ»²½´¦Àí£¬Ä¿µÄÊÇ_____________________¡£
(4)ÔÚ25 ¡æÏ£¬½«a mol¡¤L£1µÄNaCNÈÜÒºÓë0.01 mol¡¤L£1µÄÑÎËáµÈÌå»ý»ìºÏ£¬·´Ó¦ºó²âµÃÈÜÒºpH£½7£¬Ôòa__________0.01(Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°£½¡±)£»Óú¬aµÄ´úÊýʽ±íʾHCNµÄµçÀë³£ÊýKa£½______________¡£
(5)È¡¹¤Òµ·ÏˮˮÑùÓÚÊÔ¹ÜÖУ¬¼ÓÈëNaOHÈÜÒº¹Û²ìµ½ÓÐÀ¶É«³ÁµíÉú³É£¬¼ÌÐø¼ÓÖÁ²»ÔÙ²úÉúÀ¶É«³ÁµíΪֹ£¬ÔÙÏòÈÜÒºÖмÓÈë×ãÁ¿Na2SÈÜÒº£¬À¶É«³Áµíת»¯³ÉºÚÉ«³Áµí¡£¸Ã¹ý³ÌÖз´Ó¦µÄÀë×Ó·½³ÌÊÇ£º_________________¡£
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ì¹ã¶«Ê¡ÆÕÄþÊиßÈýÉÏѧÆÚµÚÒ»´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÏÂÁÐÓйØÎïÖÊ·ÖÀà»ò¹éÀàÕýÈ·µÄÊÇ£¨ £©
¢Ù»ìºÏÎÑÎËᡢƯ°×·Û¡¢Ë®²£Á§¡¢Ë®Òø
¢Ú»¯ºÏÎCaCl2¡¢NaOH¡¢HCl¡¢HD
¢Ûµç½âÖÊ£ºÃ÷·¯¡¢Ê¯¸à¡¢±ù´×Ëᡢʯ̿Ëá
¢ÜÍ¬ËØÒìÐÎÌ壺C60¡¢C70¡¢½ð¸Õʯ¡¢Ê¯Ä«Ï©
¢ÝͬϵÎCH2O2¡¢C2H4O2¡¢C3H6O2¡¢C4H8O2
¢Þͬ·ÖÒì¹¹Ì壺ÒÒ¶þËá¶þÒÒõ¥¡¢ÒÒ¶þËáÒÒ¶þõ¥¡¢¶þÒÒËáÒÒ¶þõ¥
A£®¢Ù¢Û¢Ü B£®¢Ú¢Û¢Ü C£®¢Û¢Ü D£®¢Ú¢Ü¢Þ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìºÓ±±Ê¡¸ßÈýÉÏѧÆÚÒ»µ÷¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÓÐÒ»ÎÞÉ«ÈÜÒº£¬¿ÉÄܺ¬ÓÐK+¡¢Al3+¡¢Mg2+¡¢NH4+¡¢Cl-¡¢SO42-¡¢HCO3-¡¢MnO4-µÄ¼¸ÖÖ¡£ÎªÈ·¶¨Æä³É·Ö£¬×öÈçÏÂʵÑ飺¢ÙÈ¡²¿·ÖÈÜÒº£¬¼ÓÈëÊÊÁ¿Na2O2¹ÌÌ壬²úÉúÎÞÉ«ÎÞζµÄÆøÌåºÍ°×É«³Áµí£¬ÔÙ¼ÓÈë×ãÁ¿µÄNaOHÈÜÒººó°×É«³Áµí²¿·ÖÈܽ⣻¢ÚÁíÈ¡²¿·ÖÈÜÒº£¬¼ÓÈëHNO3ËữµÄBa(NO3)2ÈÜÒº£¬Óа×É«³Áµí²úÉú¡£ÏÂÁÐÍÆ¶ÏÕýÈ·µÄÊÇ£¨ £©
A£®¿Ï¶¨ÓÐAl3+¡¢Mg2+¡¢NH4+¡¢Cl- B£®¿Ï¶¨ÓÐAl3+¡¢Mg2+¡¢HCO3-
C£®¿Ï¶¨ÓÐK+¡¢HCO3-¡¢MnO4- D£®¿Ï¶¨ÓÐAl3+¡¢Mg2+¡¢SO42-
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìºÓ±±Ê¡¸ßÈýÉÏѧÆÚÒ»µ÷¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÏÂÁйØÓÚÂÁ¼°Æä»¯ºÏÎïµÄ˵·¨Öв»ÕýÈ·µÄÊÇ£¨ £©
A£®ÂÁ¼È¿ÉÓÃÓÚʳƷ°ü×°£¬Ò²¿ÉÓÃÓÚ½¨Öþ²ÄÁÏ
B£®Ñõ»¯ÂÁ¼È¿ÉÒÔÓÃÀ´Ò±Á¶ÂÁ£¬Ò²¿ÉÓÃ×÷ÄÍ»ð²ÄÁÏ
C£®ÇâÑõ»¯ÂÁ¼È¿ÉÒÔÓÃÓÚÖÎÁÆÎ¸Ëá¹ý¶àµÄÒ©ÎҲ¿ÉÓÃÀ´ÖƱ¸Ò»Ð©ÂÁÑÎ
D£®Ã÷·¯¼ÈÄÜÓÃÀ´¾»Ë®£¬Ò²¿ÉÓÃ×÷Ïû¶¾¼Á
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìºÓ±±Ê¡¸ßÈýÉÏѧÆÚÒ»µ÷¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÈôÓÃX´ú±íF¡¢C1¡¢Br¡¢IËÄÖÖ±×åÔªËØ£¬ÏÂÁÐÄܹ»±í´ïËüÃǵĹ²ÐÔ·´Ó¦µÄÊÇ£¨ £©
A. X2+H2=2HX B. X2+H2O=HX+HXO
C. 2Fe£«3X2=2FeX3 D. X2+2NaOH=NaX+NaXO+H2O
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìºþÄÏʦ´ó¸½ÖиßÈýÉÏѧÆÚÈëѧÃþµ×¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ijϡÁòËáºÍÏ¡ÏõËáµÄ»ìºÏÈÜÒº200 mL£¬Æ½¾ù·Ö³ÉÁ½·Ý¡£ÏòÆäÖÐÒ»·ÝÖÐÖð½¥¼ÓÈëÍ·Û£¬×î¶àÄÜÈܽâ6 g¡£ÏòÁíÒ»·ÝÖÐÖð½¥¼ÓÈëÌú·Û£¬²úÉúÆøÌåµÄÁ¿ËæÌú·ÛÖÊÁ¿Ôö¼ÓµÄ±ä»¯ÈçͼËùʾ(ÒÑÖªÏõËáÖ»±»»¹ÔΪNOÆøÌå)¡£ÏÂÁзÖÎö»ò½á¹û´íÎóµÄÊÇ
![]()
A£®H2SO4Ũ¶ÈΪ2.5 mol¡¤L£1
B£®OA¶Î²úÉúµÄÊÇNO£¬AB¶ÎµÄ·´Ó¦ÎªFe£«2Fe3£«===3Fe2£«£¬BC¶Î²úÉúÇâÆø
C£®µÚ¶þ·ÝÈÜÒºÖÐ×îÖÕÈÜÖÊΪFeSO4
D£®Ô»ìºÏËáÖÐNO3£ÎïÖʵÄÁ¿Îª0.1 mol
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìºþÄÏʦ´ó¸½ÖиßÈýÉÏѧÆÚÈëѧÃþµ×¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ
A£®½öÓÃËáÐÔ¸ßÃÌËá¼ØÈÜÒº¿ÉÇø·Ö±½ºÍ¼×±½
B£®½öÓÃÂÈ»¯ÌúÈÜÒº¿ÉÇø·Ö±½·ÓÏ¡ÈÜÒººÍ¸ÊÓÍ
C£®½öÓÃÏõËáºÍÏõËáÒøÈÜÒº¿ÉÑé֤±´úÌþÖбÔ×ÓµÄÖÖÀà
D£®½öÓÃäåµÄËÄÂÈ»¯Ì¼ÈÜÒº¿ÉÇø±ðҺ̬µÄÖ²ÎïÓͺͶ¯ÎïÓÍ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìºþ±±Ê¡ËÉ×ÌÊиßÈýÉÏѧÆÚ9ÔÂÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÏÂÁÐÀë×Ó·½³ÌʽÊéдÕýÈ·µÄÊÇ
A£®ÈÛÈÚ״̬ÏÂÁòËáÇâ¼ØµÄµçÀë·½³Ìʽ£ºKHSO4 = K++HSO4-
B£®NaHSË®½â£ºHS£+H2O
H3O++S2£
C£®Fe(OH)3ÈÜÓÚÇâµâË᣺Fe(OH)3+3H+ =Fe3++3H2O
D£®Ì¼ËáµçÀ룺H2CO3
2H++CO32£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìÎ÷²ØÈÕ¿¦ÔòÇøµÚÒ»¸ß¼¶ÖÐѧ¸ßÈýÉϵÚÒ»´ÎÔ¿¼»¯Ñ§¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ
ijÂÈ»¯ÌúÑùÆ·º¬ÓÐÉÙÁ¿FeCl2ÔÓÖÊ¡£ÏÖÒª²â¶¨ÆäÖÐÌúÔªËØµÄÖÊÁ¿·ÖÊý£¬ÊµÑé°´ÒÔϲ½Öè½øÐУºÇë¸ù¾ÝÏÂÃæÁ÷³Ì£¬»Ø´ðÒÔÏÂÎÊÌ⣺
![]()
(1)²Ù×÷¢ñËùÓõ½µÄ²£Á§ÒÇÆ÷³ýÉÕ±¡¢²£Á§°ôÍ⣬»¹±ØÐëÓÐ___________¡¢___________(ÌîÒÇÆ÷Ãû³Æ)£¬²Ù×÷¢ò±ØÐëÓõ½µÄÒÇÆ÷ÊÇ___________(Ìî±àºÅ)¡£
A£®50 mLÉÕ± B£®50 mLÁ¿Í² C£®100 mLÁ¿Í² D£®25 mLµÎ¶¨¹Ü
(2)Çëд³ö¼ÓÈëäåË®·¢ÉúµÄÀë×Ó·´Ó¦·½³Ìʽ_________________£¬¼ÓÈ백ˮҪ¹ýÁ¿µÄÔÒòÊÇ________________¡£
(3)¼ìÑé³ÁµíÊÇ·ñÒѾϴµÓ¸É¾»µÄ²Ù×÷ÊÇ____________________¡£
(4)ÈôÕô·¢ÃóÖÊÁ¿ÊÇW1 g£¬Õô·¢ÃóÓë¼ÓÈȺó¹ÌÌå×ÜÖÊÁ¿ÊÇW2 g£¬ÔòÑùÆ·ÖÐÌúÔªËØµÄÖÊÁ¿·ÖÊýÊÇ_________ (ÁгöÔʼ¼ÆËãʽ£¬²»Ð軯¼ò)£»Èô³ÆÁ¿×¼È·£¬×îÖÕ²âÁ¿µÄ½á¹ûÆ«´ó£¬ÔòÔì³ÉÎó²îµÄÔÒò¿ÉÄÜÊÇ_________________________¡£(д³öÒ»ÖÖÔÒò¼´¿É)¡£
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com