ijͬѧÀûÓÃÏÂÁÐ×°ÖÃʵÏÖÍ­ÓëŨÏõËᡢϡÏõËá·´Ó¦£¬¹ý³ÌÈçÏ£º

I£® È¡Ò»¶ÎÍ­Ë¿£¬ÓÃÏ¡ÁòËá³ýȥͭÐâ[Ö÷Òª³É·ÖÊÇCu2(OH)2CO3]¡£

¢ò£®½«Ï´µÓºóµÄÍ­Ë¿×ö³ÉÔÑÊý½Ï¶àµÄÂÝÐý×´¡£

III£®°´ÈçͼËùʾװÖÃÁ¬½ÓÒÇÆ÷¡¢¼ì²éÆøÃÜÐÔ¡¢×°È뻯ѧÊÔ¼Á¡£

(1)¹ý³ÌI·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ                       ¡£

(2)д³ö¹ý³ÌIIIÖмì²éÆøÃÜÐԵķ½·¨                      ¡£

¢Ç¹ý³ÌIIIµÄºóÐø²Ù×÷ÈçÏ£º

¢Ù´ò¿ªÖ¹Ë®¼ÐaºÍb£¬ÇáÍÆ×¢ÉäÆ÷£¬Ê¹Å¨ÏõËáÓëÍ­Ë¿½Ó´¥£¬¹Û²ìµ½µÄÏÖÏóÊÇ          £¬Ò»¶Îʱ¼äºóʹ·´Ó¦Í£Ö¹µÄ²Ù×÷ÊÇ                               £¬¹Ø±Õa£¬È¡ÏÂ×¢ÉäÆ÷¡£

¢Ú´ò¿ªbºÍ·ÖҺ©¶·»îÈû£¬µ±²£Á§¹Ü³äÂúÏ¡ÏõËáºó£¬¹Ø±ÕbºÍ·ÖҺ©¶·»îÈû£¬´ò¿ªa£¬¹Û²ìµ½ÓÐÆøÅݲúÉú¡£Ï¡ÏõËá³äÂú²£Á§¹ÜµÄʵÑéÄ¿ÊÇ               £¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ                     ¡£

(4)ÁíÈ¡3֧ʢÂúNO2ÆøÌåµÄСÊԹֱܷðµ¹ÖÃÔÚÊ¢Óг£ÎÂË®¡¢ÈÈË®ºÍ±ùË®µÄ3Ö»ÉÕ±­ÖУ¬·¢ÏÖÒºÃæÉÏÉýµÄ¸ß¶ÈÃ÷ÏÔ²»Ò»Ö¡£½á¹ûÈçϱíËùʾ(ºöÂÔζȶÔÆøÌåÌå»ýµÄÓ°Ïì)£ºks5u

¢Ù¸ù¾ÝÉϱíµÃ³öµÄ½áÂÛÊÇζÈÔ½              (Ìî¡°¸ß¡±»ò¡°µÍ¡±)£¬½øÈëÊÔ¹ÜÖеÄÈÜÒºÔ½¶à¡£

¢Ú²éÔÄ×ÊÁÏ£ºa£®NO2ÓëË®·´Ó¦µÄʵ¼Ê¹ý³ÌΪ£º2NO2+H2O=HNO3+HNO2   

3HNO2 =HNO3+2NO­+H2O£»   b£®HNO2²»Îȶ¨¡£

Ôò²úÉúÉÏÊöÏÖÏóµÄÔ­ÒòÊÇ                                              ¡£

£¨1£©Cu2(OH)2CO3+4H+==2Cu2++CO2¡ü+3H2O

£¨2£©´ò¿ªbºÍa£¬¹Ø±Õ·ÖҺ©¶·µÄ»îÈû£¬½«×ó±ßµ¼¹Ü²åÈëʢˮµÄÉÕ±­ÖУ¬ÇáÇáÀ­¶¯×¢ÉäÆ÷»îÈû£¬Èôµ¼¹ÜÖÐÒºÃæÉÏÉýÔò˵Ã÷ÆøÃÜÐԺᣣ¨ÀàËÆ·½·¨¶¼ÕýÈ·£©

£¨3£©¢Ù²úÉúºì×ØÉ«ÆøÌå    ÇáÇὫעÉäÆ÷»îÈûÏòÓÒÀ­Ê¹Í­Ë¿ºÍÈÜÒº·Ö¿ª

¢Ú½«²£Á§¹ÜÖеÄNO2ºÍ¿ÕÆøÅųö  3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O

£¨4£©¢ÙµÍ£»

¢Úζȵͣ¬HNO2·Ö½âÁ¿¼õÉÙ£¬·Ö½â²úÉúµÄNOÆøÌåÁ¿¼õÉÙ£¬ËùÒÔ½øÈëÊԹܵÄÈÜÒº¶à  

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

£¨2013?¼ÃÄ϶þÄ££©´¿¼î£¨Na2CO3£©ÔÚÉú²úÉú»îÖоßÓй㷺µÄÓÃ;£®Í¼1ÊÇʵÑéÊÒÄ£ÄâÖƼîÔ­ÀíÖÆÈ¡Na2CO3µÄÁ÷³Ìͼ£®
ÒÑÖª£ºÏò±¥ºÍʳÑÎË®ÖÐͨÈëNH3¡¢CO2ºó·¢ÉúºÍ·´Ó¦ÎªNaCl+NH3+CO2+H2O¡úNaHCO3¡ý+NH4Cl£¬Çë»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©´ÖÑÎÖк¬ÓеÄÔÓÖÊÀë×ÓÓÐCa2+£¬Mg2+£¬SO42-µÈ£®
¾«ÖƳýÔӵIJ½Öè˳Ðòa¡ú
c
c
¡ú
d
d
¡ú
e
e
¡úb£¨Ìî×Öĸ±àºÅ£©£®
a£®´ÖÑÎÈܽ⣬ÂËÈ¥³ÁÔü£®b£®¼ÓÈëÑÎËáµ÷pH£»c£®¼ÓÈëBa£¨OH£©2ÈÜÒº£»d£®¼ÓÈëNa2CO3ÈÜÒº£»e£®¹ýÂË
Ïò±¥ºÍʳÑÎË®ÖÐÏÈͨÈëNH3£¬ºóͨÈëCO2£¬ÀíÓÉÊÇ
NH3Ò×ÈÜÓÚË®£¬ÓÐÀûÓÚÎüÊÕÈܽâ¶È²»´óµÄCO2
NH3Ò×ÈÜÓÚË®£¬ÓÐÀûÓÚÎüÊÕÈܽâ¶È²»´óµÄCO2
£®
£¨2£©×ÆÉÕ¹ÌÌåAÖÆNa2CO3ÔÚ
a
a
£¨Ìî×ÖĸÐòºÅ£©ÖнøÐУ®
a£®ÛáÛö    b£®Õô·¢Ãó    c£®ÉÕ±­    d£®×¶ÐÎÆ¿
Ö¤Ã÷ÂËÒºAÖк¬ÓÐNH4+µÄ·½·¨ÊÇ
È¡ÉÙÁ¿ÂËÒºAÓÚÊÔ¹ÜÖУ¬¼ÓÈë×ãÁ¿NaOHÈÜÒº²¢¼ÓÈÈ£¬²úÉúÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶É«µÄÆøÌ壬֤Ã÷AÖк¬ÓÐNH4+
È¡ÉÙÁ¿ÂËÒºAÓÚÊÔ¹ÜÖУ¬¼ÓÈë×ãÁ¿NaOHÈÜÒº²¢¼ÓÈÈ£¬²úÉúÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶É«µÄÆøÌ壬֤Ã÷AÖк¬ÓÐNH4+
£®
¶ÔÂËÒºA½øÐÐÖؽᾧÄܹ»»ñµÃNH4HCO3£¬ÏòpH=13º¬Na+¡¢K+µÄÈÜÒºÖмÓÈëÉÙÁ¿NH4HCO3£®Ê¹pH½µµÍ£¬·´Ó¦µÄÀë×Ó·½³Ìʽ
NH4++HCO3-+2OH-=NH3?H2O+CO32-+H2O
NH4++HCO3-+2OH-=NH3?H2O+CO32-+H2O
£®
£¨3£©Í¼2×°ÖÃÖг£ÓÃÓÚʵÑéÊÒÖƱ¸CO2µÄÊÇ
bc
bc
£¨Ìî×Öĸ±àºÅ£©£»ÓÃbʾÒâµÄ×°ÖÃÖƱ¸NH3£¬·ÖҺ©¶·ÖÐÊ¢·ÅµÄÊÔ¼Á
Ũ°±Ë®
Ũ°±Ë®
£¨ÌîÊÔ¼ÁÃû³Æ£©£¬ÉÕÆ¿ÄڿɼÓÈëµÄ¹ÌÌåÊÔ¼Á
Éúʯ»Ò£¨»òNaOH¹ÌÌ壩
Éúʯ»Ò£¨»òNaOH¹ÌÌ壩
£¨ÌîÊÔ¼ÁÃû³Æ£©£®
£¨4£©Ò»ÖÖÌìÈ»¼î¾§Ìå³É·ÖÊÇaNa2CO3?bNa2CO3?cH2O£¬Ä³Í¬Ñ§ÀûÓÃÏÂÁÐÌṩµÄÊÔ¼Á£¬Éè¼ÆÁËÈçϼòµ¥ºÏÀí²â¶¨Na2CO3µÄÖÊÁ¿·ÖÊýµÄʵ¿¥·½°¸£®£¨ÒÇÆ÷×ÔÑ¡£©Çë°ÑʵÑé·½°¸ÌîÈ«£º¹©Ñ¡ÔñµÄÊÔ¼Á£º1mol?L-1H2SO4ÈÜÒº¡¢1.0mol?L-1BaCl2ÈÜÒº¡¢Ï¡°±Ë®¡¢¼îʯ»Ò¡¢Ca£¨OH£©2ÈÜÒº¡¢ÕôÁóË®£®
¢Ù³ÆÈ¡m1gÒ»¶¨Á¿ÌìÈ»¼î¾§ÌåÑùÆ·£¬ÈÜÓÚÊÊÁ¿ÕôÁóË®ÖУ®
¢Ú
¼ÓÈë×ãÁ¿Ï¡ÁòËᲢ΢ÈÈ£¬²úÉúµÄÆøÌåͨ¹ý×ãÁ¿µÄ³ÎÇåʯ»ÒË®
¼ÓÈë×ãÁ¿Ï¡ÁòËᲢ΢ÈÈ£¬²úÉúµÄÆøÌåͨ¹ý×ãÁ¿µÄ³ÎÇåʯ»ÒË®
£®
¢Û
¹ýÂË¡¢Ï´µÓ¡¢¸ÉÔï¡¢³ÆÁ¿³Áµí
¹ýÂË¡¢Ï´µÓ¡¢¸ÉÔï¡¢³ÆÁ¿³Áµí
£®
¢Ü¼ÆËãÌìÈ»¼î¾§ÌåÖк¬Na2CO3µÄÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011½ì¸£½¨Ê¡ÆÎÌïÊ®ÖиßÈý5ÔÂÔ¿¼£¨Àí×Û£©»¯Ñ§²¿·Ö ÌâÐÍ£ºÊµÑéÌâ

£¨15·Ö£©ÏÖÓÐÑõ»¯Í­ºÍÍ­·Û×é³ÉµÄ»ìºÏÎijͬѧÀûÓÃÏÂͼËùʾװÖã¬Í¨¹ý²â¶¨»ìºÏÎïÖÊÁ¿¡¢ÊµÑéÇ°ºóUÐ͹ÜÖÊÁ¿±ä»¯À´È·¶¨»ìºÏÎïÖÐÑõ»¯Í­µÄÖÊÁ¿·ÖÊý¡£

»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©UÐιÜÖпÉÒÔ¼ÓÈëµÄÎïÖÊÊÇ_________£¨ÌîÐòºÅ£©£»
A¡¢Å¨              B¡¢ÎÞË®ÁòËáÍ­·ÛÄ©                           C¡¢ÎÞË®ÂÈ»¯¸Æ¿ÅÁ£
£¨2£©ÏÂÁв½Ö谴ʵÑé²Ù×÷˳ÐòӦΪ_________£¨Ìî×Öĸ£©£»
A£®Í£Ö¹Í¨ÇâÆø£»        B£®µçÈÈ˿ͨµç£»        C£®Í¨ÈËÇâÆø£»
D£®×°ÖÃÆøÃÜÐÔ¼ì²é£»    E£®µçÈÈ˿ֹͣͨµç¡£
£¨3£©Îª×¼È·²â¶¨Êý¾Ý£¬ÄãÈÏΪ±¾×°ÖÃÊÇ·ñÍêÕû?ÈôÐèÒª¸Ä½ø£¬ÇëÔÚͼÖÐÐéÏßÏÂÃæµÄ·½¿òÄÚ»­³öËùÐèÌí¼ÓµÄ×°ÖÃʾÒâͼ²¢×¢Ã÷±ØÒªµÄÎïÖÊÃû³Æ¡£ÈôÎÞÐè¸Ä½ø£¬Ôò½«×°ÖÃͼÖÐÐéÏß²¿·Ö¸ÄΪʵÏߣ»

£¨4£©ÊµÑé½áÊøºó£¬¸Ãͬѧ½»¸øÀÏʦµÄʵÑ鱨¸æÖ÷ÒªÏîÄ¿Èçͼ£¨¾ßÌåÄÚÈÝÒÑÂÔ£©¡£ÇëÄã¸ù¾ÝʵÑ鱨¸æµÄ׫дҪÇ󣬶Դ˷ݱ¨¸æ×÷³öÆÀ¼Û£¬ÈôÒÑÍêÕû£¬ÔòÎÞÐèÌîд£¬Èô²»ÍêÕû£¬ÇëÔÚÏÂÃæµÄ¿Õ¸ñÖÐд³öËùȱÏîÄ¿______     _  
£¨5£©ÀÏʦ¿´ÍêʵÑ鱨¸æºóÖ¸³ö£¬¸Ä±äʵÑéÔ­Àí¿ÉÒÔÉè¼Æ³ö¸ü¼Ó¼ò±ãµÄʵÑé·½°¸¡£ÇëÓû¯Ñ§·½³Ìʽ±íʾÄãÉè¼ÆµÄз½°¸µÄ·´Ó¦Ô­Àí____    ______£¬¸Ã·½°¸Ðè²â¶¨µÄÊý¾Ý______________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011½ìɽÎ÷Ê¡¿µ½ÜÖÐѧÁÙ·ÚÒ»ÖÐÐÃÖÝÒ»Öг¤ÖζþÖиßÈýµÚÈý´ÎËÄУÁª¿¼£¨Àí×Û£©»¯Ñ§²¿ ÌâÐÍ£ºÌî¿ÕÌâ

ÏÖÓÐÑõ»¯Í­ºÍÍ­·Û×é³ÉµÄ»ìºÏÎijͬѧÀûÓÃÏÂͼËùʾװÖã¬Í¨¹ý²â¶¨»ìºÏÎïÖÊÁ¿¡¢ÊµÑéÇ°ºóUÐ͹ÜÖÊÁ¿±ä»¯À´È·¶¨»ìºÏÎïÖÐÑõ»¯Í­µÄÖÊÁ¿·ÖÊý¡£

»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©UÐιÜÖпÉÒÔ¼ÓÈëµÄÎïÖÊÊÇ_________£¨ÌîÐòºÅ£©£»
A£®Å¨         B£®ÎÞË®ÁòËáÍ­·Û        C£®ÎÞË®ÂÈ»¯¸Æ¿ÅÁ£
£¨2£©ÏÂÁв½Ö谴ʵÑé²Ù×÷˳ÐòӦΪ_________£¨Ìî×Öĸ£©£»
A£®Í£Ö¹Í¨ÇâÆø£»            B£®µçÈÈ˿ͨµç£»        C£®Í¨ÈËÇâÆø£»        
D£®×°ÖÃÆøÃÜÐÔ¼ì²é£»       E£®µçÈÈ˿ֹͣͨµç¡£
£¨3£©Îª×¼È·²â¶¨Êý¾Ý£¬ÄãÈÏΪ±¾×°ÖÃÊÇ·ñÍêÕû?ÈôÐèÒª¸Ä½ø£¬ÇëÔÚͼÖÐÐéÏßÏÂÃæµÄ·½¿òÄÚ»­³öËùÐèÌí¼ÓµÄ×°ÖÃʾÒâͼ²¢×¢Ã÷±ØÒªµÄÎïÖÊÃû³Æ¡£ÈôÎÞÐè¸Ä½ø£¬Ôò½«×°ÖÃͼÖÐÐéÏß²¿·Ö¸ÄΪʵÏߣ»
£¨4£©ÊµÑé½áÊøºó£¬¸Ãͬѧ½»¸øÀÏʦµÄʵÑ鱨¸æÖ÷ÒªÏîÄ¿Èçͼ£¨¾ßÌåÄÚÈÝÒÑÂÔ£©¡£ÇëÄã¸ù¾ÝʵÑ鱨¸æµÄ׫дҪÇ󣬶Դ˷ݱ¨¸æ×÷³öÆÀ¼Û£¬ÈôÒÑÍêÕû£¬ÔòÎÞÐèÌîд£¬Èô²»ÍêÕû£¬ÇëÔÚÏÂÃæµÄ¿Õ¸ñÖÐд³öËùȱÏîÄ¿______     _______            __£»

£¨5£©ÀÏʦ¿´ÍêʵÑ鱨¸æºóÖ¸³ö£¬¸Ä±äʵÑéÔ­Àí¿ÉÒÔÉè¼Æ³ö¸ü¼Ó¼ò±ãµÄʵÑé·½°¸¡£ÇëÓû¯Ñ§·½³Ìʽ±íʾÄãÉè¼ÆµÄз½°¸µÄ·´Ó¦Ô­Àí____    ________£¬
¸Ã·½°¸Ðè²â¶¨µÄÊý¾Ý____________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêɽ¶«Ê¡¼ÃÄÏÊиßÈý4Ô¹®¹ÌÐÔѵÁ·Àí×Û»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

´¿¼î(Na2CO3)ÔÚÉú²úÉú»îÖоßÓй㷺µÄÓÃ;¡£ÒÔÏÂÊÇʵÑéÊÒÄ£ÄâÖƼîÔ­ÀíÖÆÈ¡Na2CO3µÄÁ÷³Ìͼ

ÒÑÖª:Ïò±¥ºÍʳÑÎË®ÖÐͨÈëNH3£¬CO2ºó·¢ÉúºÍ·´Ó¦ÎªNaCl£«NH3£«CO2£«H2ONaHCO3¡ý£«NH4Cl,Çë»Ø´ðÒÔÏÂÎÊÌ⣺

£¨1£©´ÖÑÎÖк¬ÓеÄÔÓÖÊÀë×ÓÓÐCa2+£¬Mg2+£¬SO42-µÈ¡£

¾«ÖƳýÔӵIJ½Öè˳Ðòa¡ú_______¡ú________¡ú________¡úb(Ìî×Öĸ±àºÅ£©¡£

a£®´ÖÑÎÈܽ⣬ÂËÈ¥³ÁÔü£®b£®¼ÓÈëÑÎËáµ÷pH£»c£®¼ÓÈëBa(OH)2ÈÜÒº£»d£®¼ÓÈëNa2CO3ÈÜÒº£»e£®¹ýÂË

Ïò±¥ºÍʳÑÎË®ÖÐÏÈͨÈëNH3£¬ºóͨÈËCO2£¬ÀíÓÉÊÇ_____________________¡£

£¨2£©×ÆÉÕ¹ÌÌåAÖÆNa2CO3ÔÚ_____Ìî×ÖĸÐòºÅ£©ÖнøÐС£

a£®ÛáÛö    b£®Õô·¢Ãó    c£®ÉÕ±­    d£®×¶ÐÎÆ¿

Ö¤Ã÷ÂËÒºAÖк¬ÓÐNH4+µÄ·½·¨ÊÇ__________________________________________________________¡£

¶ÔÂËÒºA½øÐÐÖؽᾧÄܹ»»ñµÃNH4HCO3£¬ÏòpH=13º¬Na+£¬K+µÄÈÜÒºÖмÓÈëÉÙÁ¿NH4HCO3¡£Ê¹pH½µµÍ£¬·´Ó¦µÄÀë×Ó·½³Ìʽ____________________________________¡£

£¨3£©ÏÂͼװÖÃÖг£ÓÃÓÚʵÑéÊÒÖƱ¸CO2µÄÊÇ_____(Ìî×Öĸ±àºÅ£©£»ÓÃbʾÒâµÄ×°ÖÃÖƱ¸NH3£¬·ÖҺ©¶·ÖÐÊ¢·ÅµÄÊÔ¼Á______(ÌîÊÔ¼ÁÃû³Æ£©£¬ÉÕÆ¿ÄڿɼÓÈëµÄ¹ÌÌåÊÔ¼Á__________£¨ÌîÊÔ¼ÁÃû³Æ£©¡£

£¨4£©Ò»ÖÖÌìÈ»¼î¾§Ìå³É·ÖÊÇaNa2CO3¡¤bNa2CO3¡¤cH2O£¬Ä³Í¬Ñ§ÀûÓÃÏÂÁÐÌṩµÄÊÔ¼Á£¬Éè¼ÆÁËÈçϼòµ¥ºÏÀí²â¶¨Na2CO3µÄÖÊÁ¿·ÖÊýµÄʵ¿¥·½°¸¡££¨ÒÇÆ÷×ÔÑ¡£©Çë°ÑʵÑé·½°¸ÌîÈ«£º¹©Ñ¡ÔñµÄÊÔ¼Á£º1.0mol/LH2SO4ÈÜÒº¡¢1.0mol/L BaCl2ÈÜÒº¡¢Ï¡°±Ë®¡¢¼îʯ»Ò¡¢Ca(OH)2ÈÜÒº¡¢ÕôÁóË®

¢Ù³ÆÈ¡m1gÒ»¶¨Á¿ÌìÈ»¼î¾§ÌåÑùÆ·£¬ÈÜÓÚÊÊÁ¿ÕôÁóË®ÖС£

¢Ú_________________________________________________________________¡£

¢Û_________________________________________________________________¡£

¢Ü¼ÆËãÌìÈ»¼î¾§ÌåÖк¬Na2CO3µÄÖÊÁ¿·ÖÊý¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010-2011ѧÄ긣½¨Ê¡¸ßÈý5ÔÂÔ¿¼£¨Àí×Û£©»¯Ñ§²¿·Ö ÌâÐÍ£ºÊµÑéÌâ

£¨15·Ö£©ÏÖÓÐÑõ»¯Í­ºÍÍ­·Û×é³ÉµÄ»ìºÏÎijͬѧÀûÓÃÏÂͼËùʾװÖã¬Í¨¹ý²â¶¨»ìºÏÎïÖÊÁ¿¡¢ÊµÑéÇ°ºóUÐ͹ÜÖÊÁ¿±ä»¯À´È·¶¨»ìºÏÎïÖÐÑõ»¯Í­µÄÖÊÁ¿·ÖÊý¡£

»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©UÐιÜÖпÉÒÔ¼ÓÈëµÄÎïÖÊÊÇ_________£¨ÌîÐòºÅ£©£»

     A¡¢Å¨               B¡¢ÎÞË®ÁòËáÍ­·ÛÄ©                           C¡¢ÎÞË®ÂÈ»¯¸Æ¿ÅÁ£

£¨2£©ÏÂÁв½Ö谴ʵÑé²Ù×÷˳ÐòӦΪ_________£¨Ìî×Öĸ£©£»

           A£®Í£Ö¹Í¨ÇâÆø£»        B£®µçÈÈ˿ͨµç£»        C£®Í¨ÈËÇâÆø£»

D£®×°ÖÃÆøÃÜÐÔ¼ì²é£»    E£®µçÈÈ˿ֹͣͨµç¡£

£¨3£©Îª×¼È·²â¶¨Êý¾Ý£¬ÄãÈÏΪ±¾×°ÖÃÊÇ·ñÍêÕû?ÈôÐèÒª¸Ä½ø£¬ÇëÔÚͼÖÐÐéÏßÏÂÃæµÄ·½¿òÄÚ»­³öËùÐèÌí¼ÓµÄ×°ÖÃʾÒâͼ²¢×¢Ã÷±ØÒªµÄÎïÖÊÃû³Æ¡£ÈôÎÞÐè¸Ä½ø£¬Ôò½«×°ÖÃͼÖÐÐéÏß²¿·Ö¸ÄΪʵÏߣ»

£¨4£©ÊµÑé½áÊøºó£¬¸Ãͬѧ½»¸øÀÏʦµÄʵÑ鱨¸æÖ÷ÒªÏîÄ¿Èçͼ£¨¾ßÌåÄÚÈÝÒÑÂÔ£©¡£ÇëÄã¸ù¾ÝʵÑ鱨¸æµÄ׫дҪÇ󣬶Դ˷ݱ¨¸æ×÷³öÆÀ¼Û£¬ÈôÒÑÍêÕû£¬ÔòÎÞÐèÌîд£¬Èô²»ÍêÕû£¬ÇëÔÚÏÂÃæµÄ¿Õ¸ñÖÐд³öËùȱÏîÄ¿______     _  

£¨5£©ÀÏʦ¿´ÍêʵÑ鱨¸æºóÖ¸³ö£¬¸Ä±äʵÑéÔ­Àí¿ÉÒÔÉè¼Æ³ö¸ü¼Ó¼ò±ãµÄʵÑé·½°¸¡£ÇëÓû¯Ñ§·½³Ìʽ±íʾÄãÉè¼ÆµÄз½°¸µÄ·´Ó¦Ô­Àí____    ______£¬¸Ã·½°¸Ðè²â¶¨µÄÊý¾Ý______________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸