£¨12·Ö£©X¡¢Y¡¢Z¡¢WΪµç×ÓÊýÏàͬµÄ·Ö×Ó»òÀë×Ó¡£XÓÐ5¸öÔ­×Ӻˡ£Í¨³£×´¿öÏ£¬WΪÎÞÉ«ÒºÌå¡£ËüÃÇÖ®¼äת»¯¹ØϵÈçͼËùʾ£¬Çë»Ø´ð£º

£¨1£©¹¤ÒµÉÏÿÖÆÈ¡1molZÒª·Å³ö46.2 kJµÄÈÈÁ¿£¬Ð´³ö¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º      ¡£
£¨2£©ÊµÑéÊÒÖÆÈ¡ZµÄ·½·¨²»Ö¹Ò»ÖÖ£¬Ð´³öÆäÖÐÒ»ÖÖ·½·¨µÄ»¯Ñ§·½³Ìʽ£º      ¡£
£¨3£©Ä³»¯Ñ§Ð¡×éͬѧģÄ⹤ҵÉú²úÖÆÈ¡HNO3£¬Éè¼ÆÏÂͼËùʾװÖã¬ÆäÖÐaΪһ¸ö¿É³ÖÐø¹ÄÈë¿ÕÆøµÄÏðƤÇò¡£

¢ÙAÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ                                ¡£
¢ÚBÖÐŨH2SO4µÄ×÷ÓÃÊÇ      ¡£
£¨4£©Ð´³öD×°ÖÃÖз´Ó¦µÄ»¯Ñ§·½³Ìʽ                          ¡£
£¨5£©Ïòº¬ÓÐag HNO3µÄÏ¡ÈÜÒºÖУ¬¼ÓÈëbgÌú·Û³ä·Ö·´Ó¦£¬Ìú·ÛÈ«²¿Èܽ⡣ÒÑÖª£¬Ôò±»»¹Ô­µÄHNO3µÄÖÊÁ¿Îª      g¡£

£¨1£©N2(g)+3H2(g)2NH3(g) ¡÷H="-92.4" kJ£¯mol
£¨2£©2NH4Cl+Ca(OH)22NH3¡ü+2H2O+CaCl2»òNH3¡¤H2ONH3¡ü+H2O
£¨3£©¢Ù4NH3+5O24NO+6H2O ¢ÚÎüÊÕH2O£¨g£©ºÍδ·´Ó¦µÄNH3
£¨4£©3NO2+H2O=2HNO3+NO   £¨5£©

½âÎöÊÔÌâ·ÖÎö£ºWΪÎÞÉ«ÒºÌ壬һ°ãÊÇH2O£¬¼´ÓÐ10¸öµç×Ó£¬XÓÐ5¸öÔ­×ÓºËÇÒÓÐ10¸öµç×Ó£¬¿ÉÍƶϳöÊÇNH4£«£¬ÔòYΪOH£­£¬ZΪNH3¡£
£¨1£©¹¤ÒµÉϺϳɰ±£¬ÊÇÓÃÇâÆøºÍµªÆøÖ±½ÓºÏ³É£¬·´Ó¦·½³ÌʽΪN2(g)+3H2(g)2NH3(g) ¡÷H="-92.4" kJ£¯mol
£¨2£©°±µÄʵÑéÊÒÖÆ·¨£¬Ò»°ãÊǼÓÈÈï§ÑκͼîµÄ»ìºÏÎï¡£
£¨3£©£¨4£©°±¾­¹ýһϵÁз´Ó¦¿ÉÒԵõ½ÏõËᣬÆä¹ý³Ì¿É±íʾΪN2 ¡ªNH3¡ªNO¡ªNO2¡ªHNO3¡£
£¨5£©µ±Ìú²»×ãʱ£¬´Ë·´Ó¦µÄ·½³ÌʽΪ
4HNO3£«FeFe(NO3)3£«NO£«2H2O
4      1
b/14   b/56
Ôò£¨b/14£©=(a/63) µÃa/b=4.5
µ±Ìú¹ýÁ¿Ê±£¬Ê£ÓàµÄÌúÄܼÌÐøºÍFe(NO3)3·´Ó¦£¬¸Ã·´Ó¦·½³ÌʽΪ
8HNO3£«3Fe3Fe(NO3)2£«2NO£«4H2O
8      3
b/56   b/21
Ôò b/21=(a/63) µÃa/b=3
ÓÖÒòΪ£¨a/b£©´óÓÚµÈÓÚ3£¬Ð¡ÓÚµÈÓÚ4.5£¬ËµÃ÷¸Ã·´Ó¦½éÓÚ¸Õ²ÅËùÁоٵÄÁ½ÕßÖ®¼ä£¬¼´·´Ó¦·½³ÌʽΪ
4Fe£«12HNO33Fe(NO3)2£«Fe(NO3)3£«3NO£«6H2O
12                       3
a                        a/4
¼´±»»¹Ô­µÄÏõËáµÄÖÊÁ¿Îª(a/4)g¡£
¿¼µã£º°±µÄÐÔÖʼ°ÖÆ·¨¡£
µãÆÀ£º±¾Ìâͨ¹ýÍƶϣ¬ÅжϳöNÔªËصÄÏà¹ØÎïÖÊ£¬Ö÷Òª¿¼²ìÊéÉϹØÓÚNH3¼°HNO3µÄÖÆ·¨µÄ»¯Ñ§·½³Ìʽ£¬Ñ§Éú¿ÉÒÔ¸ù¾ÝËùѧ֪ʶ½øÐнâ´ð£¬ÄѶȲ»´ó¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍøX¡¢Y¡¢Z¡¢WΪËÄÖÖ¶ÌÖÜÆÚÔªËØ£¬ËüÃÇÔÚÖÜÆÚ±íÖеÄλÖÃÈçͼËùʾ£®ZÔªËØÔ­×ÓºËÍâµÚÒ»²ãÓëµÚÈý²ãµç×ÓÊýÏàµÈ£®ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A¡¢ÓëÏàͬŨ¶ÈµÄÑÎËá·´Ó¦£¬Zµ¥ÖʱÈWµ¥Öʸü¾çÁÒB¡¢YÔªËØ¿ÉÒÔÐγɶàÖÖ¾ßÓÐƯ°×ÐԵĻ¯ºÏÎïC¡¢YÓëZ¡¢YÓëWÐγɵĻ¯ºÏÎﺬÓеĻ¯Ñ§¼üÀàÐÍÏàͬD¡¢ËÄÖÖÔªËصÄÀë×Ӱ뾶´óСΪZ£¾W£¾X£¾Y

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ìÕã½­Ê¡ºþÖÝÊÐÁâºþÖÐѧ¸ßÈýÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÊµÑéÌâ

£¨12·Ö£©X¡¢Y¡¢Z¡¢WΪµç×ÓÊýÏàͬµÄ·Ö×Ó»òÀë×Ó¡£XÓÐ5¸öÔ­×Ӻˡ£Í¨³£×´¿öÏ£¬WΪÎÞÉ«ÒºÌå¡£ËüÃÇÖ®¼äת»¯¹ØϵÈçͼËùʾ£¬Çë»Ø´ð£º

£¨1£©¹¤ÒµÉÏÿÖÆÈ¡1molZÒª·Å³ö46.2 kJµÄÈÈÁ¿£¬Ð´³ö¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º      ¡£
£¨2£©ÊµÑéÊÒÖÆÈ¡ZµÄ·½·¨²»Ö¹Ò»ÖÖ£¬Ð´³öÆäÖÐÒ»ÖÖ·½·¨µÄ»¯Ñ§·½³Ìʽ£º      ¡£
£¨3£©Ä³»¯Ñ§Ð¡×éͬѧģÄ⹤ҵÉú²úÖÆÈ¡HNO3£¬Éè¼ÆÏÂͼËùʾװÖã¬ÆäÖÐaΪһ¸ö¿É³ÖÐø¹ÄÈë¿ÕÆøµÄÏðƤÇò¡£

¢ÙAÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ                                ¡£
¢ÚBÖÐŨH2SO4µÄ×÷ÓÃÊÇ      ¡£
£¨4£©Ð´³öD×°ÖÃÖз´Ó¦µÄ»¯Ñ§·½³Ìʽ                          ¡£
£¨5£©Ïòº¬ÓÐag HNO3µÄÏ¡ÈÜÒºÖУ¬¼ÓÈëbgÌú·Û³ä·Ö·´Ó¦£¬Ìú·ÛÈ«²¿Èܽ⡣ÒÑÖª£¬Ôò±»»¹Ô­µÄHNO3µÄÖÊÁ¿Îª      g¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêɽ¶«Ê¡ÁijÇÊиßÈýÉÏѧÆÚ1Ô·ÝÄ£¿é¼ì²â»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨12·Ö£©X¡¢Y¡¢Z¡¢WΪµç×ÓÊýÏàͬµÄ·Ö×Ó»òÀë×Ó¡£XÓÐ5¸öÔ­×Ӻˡ£Í¨³£×´¿öÏ£¬WΪÎÞÉ«ÒºÌå¡£ËüÃÇÖ®¼äת»¯¹ØϵÈçͼËùʾ£¬Çë»Ø´ð£º

£¨1£©¹¤ÒµÉÏÿÖÆÈ¡1molZÒª·Å³ö46.2 kJµÄÈÈÁ¿£¬Ð´³ö¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º      ¡£

£¨2£©ÊµÑéÊÒÖÆÈ¡ZµÄ·½·¨²»Ö¹Ò»ÖÖ£¬Ð´³öÆäÖÐÒ»ÖÖ·½·¨µÄ»¯Ñ§·½³Ìʽ£º      ¡£

£¨3£©Ä³»¯Ñ§Ð¡×éͬѧģÄ⹤ҵÉú²úÖÆÈ¡HNO3£¬Éè¼ÆÏÂͼËùʾװÖã¬ÆäÖÐaΪһ¸ö¿É³ÖÐø¹ÄÈë¿ÕÆøµÄÏðƤÇò¡£

¢ÙAÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ                                ¡£

¢ÚBÖÐŨH2SO4µÄ×÷ÓÃÊÇ      ¡£

£¨4£©Ð´³öD×°ÖÃÖз´Ó¦µÄ»¯Ñ§·½³Ìʽ                          ¡£

£¨5£©Ïòº¬ÓÐag HNO3µÄÏ¡ÈÜÒºÖУ¬¼ÓÈëbgÌú·Û³ä·Ö·´Ó¦£¬Ìú·ÛÈ«²¿Èܽ⡣ÒÑÖª£¬Ôò±»»¹Ô­µÄHNO3µÄÖÊÁ¿Îª      g¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêÕã½­Ê¡ºþÖÝÊиßÈýÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

£¨12·Ö£©X¡¢Y¡¢Z¡¢WΪµç×ÓÊýÏàͬµÄ·Ö×Ó»òÀë×Ó¡£XÓÐ5¸öÔ­×Ӻˡ£Í¨³£×´¿öÏ£¬WΪÎÞÉ«ÒºÌå¡£ËüÃÇÖ®¼äת»¯¹ØϵÈçͼËùʾ£¬Çë»Ø´ð£º

£¨1£©¹¤ÒµÉÏÿÖÆÈ¡1molZÒª·Å³ö46.2 kJµÄÈÈÁ¿£¬Ð´³ö¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º       ¡£

£¨2£©ÊµÑéÊÒÖÆÈ¡ZµÄ·½·¨²»Ö¹Ò»ÖÖ£¬Ð´³öÆäÖÐÒ»ÖÖ·½·¨µÄ»¯Ñ§·½³Ìʽ£º       ¡£

£¨3£©Ä³»¯Ñ§Ð¡×éͬѧģÄ⹤ҵÉú²úÖÆÈ¡HNO3£¬Éè¼ÆÏÂͼËùʾװÖã¬ÆäÖÐaΪһ¸ö¿É³ÖÐø¹ÄÈë¿ÕÆøµÄÏðƤÇò¡£

¢ÙAÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ                                 ¡£

¢ÚBÖÐŨH2SO4µÄ×÷ÓÃÊÇ       ¡£

£¨4£©Ð´³öD×°ÖÃÖз´Ó¦µÄ»¯Ñ§·½³Ìʽ                           ¡£

£¨5£©Ïòº¬ÓÐag HNO3µÄÏ¡ÈÜÒºÖУ¬¼ÓÈëbgÌú·Û³ä·Ö·´Ó¦£¬Ìú·ÛÈ«²¿Èܽ⡣ÒÑÖª£¬Ôò±»»¹Ô­µÄHNO3µÄÖÊÁ¿Îª       g¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸