£¨±¾Ð¡ÌâÂú·Ö9·Ö£© ÈçͼËùʾ£¬½«¼×¡¢ÒÒÁ½¸ö×°Óв»Í¬ÎïÖʵÄÕëͲÓõ¼¹ÜÁ¬½ÓÆðÀ´£¬½«ÒÒÕëͲÄÚµÄÎïÖÊѹµ½¼×ÕëͲÄÚ£¬½øÐÐϱíËùÁеIJ»Í¬ÊµÑ飨ÆøÌåÔÚͬÎÂͬѹϲⶨ£©¡£ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©ÊµÑé1¼×ÕëͲÄÚµÄÏÖÏóÊÇ£ºÓÐ___________Éú³É£¬ÕëͲ»îÈû________Òƶ¯£¨ÌîÏòÍâ¡¢ÏòÄÚ¡¢²»£©¡£·´Ó¦ºó¼×ÕëͲÄÚÓÐÉÙÁ¿µÄ²ÐÁôÆøÌ壬ÕýÈ·µÄ´¦Àí·½·¨Êǽ«ÆäͨÈë___________ÈÜÒºÖС£
£¨2£©ÊµÑé2ÖУ¬¼×ÖеÄ3mLÆøÌåÊÇNO2ºÍN2O4µÄ»ìºÏÆøÌ壬ÄÇô¼×ÖÐ×îºóÊ£ÓàµÄÎÞÉ«ÆøÌåÊÇ_______£¬Ð´³öNO2ÓëH2O·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____________________¡£
£¨3£©ÊµÑé3ÖУ¬ÒÑÖª£º3Cl2£«2NH3===N2£«6HCl¡£¼×ÕëͲ´¦»îÈûÓÐÒƶ¯£¬ÕëͲÄÚÓа×Ñ̲úÉúÍ⣬ÆøÌåµÄÑÕÉ«±äΪ____________¡£×îºóÕëͲÄÚÊ£ÓàÆøÌåµÄÌå»ýԼΪ________mL¡£
£¨1£©»ÆÉ«¹ÌÌ壻ÏòÄÚ£»NaOH¡££¨Ã¿¿Õ1·Ö£©
£¨2£©NO £¨1·Ö£©£» 3NO2+H2O=2HNO3£«NO£¨2·Ö£©¡£
£¨3£©ÎÞÉ«£¨1·Ö£©£» 5£¨2·Ö£©
½âÎö:£¨1£©SO2ºÍH2SÖÐÁòÔªËصĻ¯ºÏ¼Û·Ö±ðÊÇ£«4¼ÛºÍ£2¼Û£¬ËùÒÔ¶þÕß¿ÉÒÔ·¢ÉúÑõ»¯»¹Ô·´Ó¦Éú³Éµ¥ÖÊÁòºÍË®£¬·½³ÌʽΪSO2£«2H2S=3S£«2H2O¡£ËùÒÔ·´Ó¦ºóѹǿ½µµÍ£¬ÕëͲ»îÈûÏòÄÚÒƶ¯¡£SO2ºÍH2S¾ùÊôÓÚ´óÆøÎÛȾÎÐèҪβÆø´¦Àí£¬¿ÉÓüîÒºÀ´ÎüÊÕ¡£
£¨2£©NO2ÈÜÓÚË®µÄ·½³ÌʽΪ3NO2+H2O=2HNO3£«NO£¬ËùÒÔ×îÖÕµÄÆøÌåÊÇÎÞÉ«µÄNO¡£
£¨3£©ÂÈÆø¿ÉÒÔ½«°±ÆøÑõ»¯Éú³ÉµªÆø£¬¶øÂÈÆø±»»¹ÔÉú³ÉÂÈ»¯Çâ¡£¸ù¾Ý·½³ÌʽºÍÓйط´Ó¦ÎïµÄÌå»ý¿ÉÖª£¬15mlÂÈÆø¿ÉÒÔÏûºÄ10ml°±Æø£¬Éú³É5mlµªÆøºÍ30mlÂÈ»¯Çâ¡£ËùÒÔ°±ÆøÊ£Óà30ml£¬¹ýÁ¿µÄ°±ÆøºÍÂÈ»¯ÇâÇ¡ºÃ·´Ó¦Éú³ÉÂÈ»¯ï§£¬´Ó¶ø³öÏÖ°×ÑÌÏÖÏó¡£Òò´Ë×îÖÕµÄÆøÌåÊÇ5mlµªÆø¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄ긣½¨Ê¡ÄÏ°²Ò»ÖиßÒ»ÏÂѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÊµÑéÌâ
£¨±¾Ð¡ÌâÂú·Ö9·Ö£©ÈçͼËùʾ£¬½«¼×¡¢ÒÒÁ½¸ö×°Óв»Í¬ÎïÖʵÄÕëͲÓõ¼¹ÜÁ¬½ÓÆðÀ´£¬½«ÒÒÕëͲÄÚµÄÎïÖÊѹµ½¼×ÕëͲÄÚ£¬½øÐÐϱíËùÁеIJ»Í¬ÊµÑ飨ÆøÌåÔÚͬÎÂͬѹϲⶨ£©¡£ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©ÊµÑé1¼×ÕëͲÄÚµÄÏÖÏóÊÇ£ºÓÐ___________Éú³É£¬ÕëͲ»îÈû________Òƶ¯£¨ÌîÏòÍâ¡¢ÏòÄÚ¡¢²»£©¡£·´Ó¦ºó¼×ÕëͲÄÚÓÐÉÙÁ¿µÄ²ÐÁôÆøÌ壬ÕýÈ·µÄ´¦Àí·½·¨Êǽ«ÆäͨÈë___________ÈÜÒºÖС£
£¨2£©ÊµÑé2ÖУ¬¼×ÖеÄ3mLÆøÌåÊÇNO2ºÍN2O4µÄ»ìºÏÆøÌ壬ÄÇô¼×ÖÐ×îºóÊ£ÓàµÄÎÞÉ«ÆøÌåÊÇ_______£¬Ð´³öNO2ÓëH2O·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____________________¡£
£¨3£©ÊµÑé3ÖУ¬ÒÑÖª£º3Cl2£«2NH3===N2£«6HCl¡£¼×ÕëͲ´¦»îÈûÓÐÒƶ¯£¬ÕëͲÄÚÓа×Ñ̲úÉúÍ⣬ÆøÌåµÄÑÕÉ«±äΪ____________¡£×îºóÕëͲÄÚÊ£ÓàÆøÌåµÄÌå»ýԼΪ________mL¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄ긣½¨Ê¡ÄÏ°²Ò»ÖиßÒ»ÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ
£¨±¾Ð¡ÌâÂú·Ö9·Ö£©
£¨1£©°Ñ6 mol AÆøÌåºÍ5 mol BÆøÌå»ìºÏ·ÅÈë4 LÃܱÕÈÝÆ÷ÖУ¬ÔÚÒ»¶¨Ìõ¼þÏ·¢Éú·´Ó¦£º3A(g)+B(g)2C(g)+xD(g)£¬¾5min´ïµ½Æ½ºâ£¬´ËʱÉú³É2 mol C£¬²âµÃDµÄƽ¾ù·´Ó¦ËÙÂÊΪ0.15 mol/(L¡¤min)£¬ÔòƽºâʱAµÄÎïÖʵÄÁ¿Å¨¶ÈÊÇ____________£»BµÄת»¯ÂÊÊÇ__________£»xµÄÖµÊÇ___________¡£
£¨2£©·´Ó¦2H2£¨g£© + O2£¨g£©£½ 2H2O£¨g£©µÄÄÜÁ¿±ä»¯ÈçͼËùʾ¡£ÒÑÖª²ð¿ª1molH2¡¢1molO2ºÍ1molH-OÖеĻ¯Ñ§¼ü·Ö±ðÐèÒªÏûºÄ436KJ¡¢496KJºÍ463KJÄÜÁ¿£¬Ôò¸Ã·´Ó¦ £¨Ìî¡°ÎüÊÕ¡± »ò¡°·Å³ö¡±£© KJÈÈÁ¿¡£
£¨3£©ÃÀ¹ú°¢²¨ÂÞÓîÖæ·É´¬ÉÏʹÓÃÁËÒ»ÖÖÐÂÐÍ×°Öã¬Æä¹¹ÔìÈçÓÒͼËùʾ£º
a¡¢bÁ½¸öµç¼«¾ùÓɶà¿×µÄ̼¿é×é³É¡£Ð´³öa¼«µÄµç¼«·´Ó¦Ê½£º ¡£
£¨4£©¹¤ÒµÉÏÓõç½â±¥ºÍʳÑÎË®µÄ·½·¨ÖÆÈ¡½ðÊôÂÈÆø£¬·´Ó¦ÖÐÄÜÁ¿µÄת»¯ÐÎʽÊÇ £»ÂÈÆøÔÚ ¼«ÉϲúÉú£¬·´Ó¦ºóÈÜÒºµÄpH ¡££¨Ìî¡°Ôö´ó¡±»ò¡°¼õС¡±£©¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ì¸£½¨Ê¡¸ßÒ»ÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ
£¨±¾Ð¡ÌâÂú·Ö9·Ö£©
£¨1£©°Ñ6 mol AÆøÌåºÍ5 mol BÆøÌå»ìºÏ·ÅÈë4 LÃܱÕÈÝÆ÷ÖУ¬ÔÚÒ»¶¨Ìõ¼þÏ·¢Éú·´Ó¦£º3A(g)+B(g)2C(g)+xD(g)£¬¾5min´ïµ½Æ½ºâ£¬´ËʱÉú³É2 mol C£¬²âµÃDµÄƽ¾ù·´Ó¦ËÙÂÊΪ0.15 mol/(L¡¤min)£¬ÔòƽºâʱAµÄÎïÖʵÄÁ¿Å¨¶ÈÊÇ____________£»BµÄת»¯ÂÊÊÇ__________£»xµÄÖµÊÇ___________¡£
£¨2£©·´Ó¦2H2£¨g£© + O2 £¨g£©£½ 2H2O£¨g£© µÄÄÜÁ¿±ä»¯ÈçͼËùʾ¡£ÒÑÖª²ð¿ª1molH2¡¢1molO2ºÍ1molH-OÖеĻ¯Ñ§¼ü·Ö±ðÐèÒªÏûºÄ436KJ¡¢496KJºÍ463KJÄÜÁ¿£¬Ôò¸Ã·´Ó¦ £¨Ìî¡°ÎüÊÕ¡± »ò¡°·Å³ö¡±£© KJÈÈÁ¿¡£
£¨3£©ÃÀ¹ú°¢²¨ÂÞÓîÖæ·É´¬ÉÏʹÓÃÁËÒ»ÖÖÐÂÐÍ×°Öã¬Æä¹¹ÔìÈçÓÒͼËùʾ£º
a¡¢bÁ½¸öµç¼«¾ùÓɶà¿×µÄ̼¿é×é³É¡£Ð´³öa¼«µÄµç¼«·´Ó¦Ê½£º ¡£
£¨4£©¹¤ÒµÉÏÓõç½â±¥ºÍʳÑÎË®µÄ·½·¨ÖÆÈ¡½ðÊôÂÈÆø£¬·´Ó¦ÖÐÄÜÁ¿µÄת»¯ÐÎʽÊÇ £»ÂÈÆøÔÚ ¼«ÉϲúÉú£¬·´Ó¦ºóÈÜÒºµÄpH ¡£ £¨Ìî¡°Ôö´ó¡±»ò¡°¼õС¡±£©¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ì½ËÕÊ¡¸ßÒ»µÚһѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ
£¨±¾Ð¡ÌâÂú·Ö9·Ö£© ÈçͼËùʾ£¬½«¼×¡¢ÒÒÁ½¸ö×°Óв»Í¬ÎïÖʵÄÕëͲÓõ¼¹ÜÁ¬½ÓÆðÀ´£¬½«ÒÒÕëͲÄÚµÄÎïÖÊѹµ½¼×ÕëͲÄÚ£¬½øÐÐϱíËùÁеIJ»Í¬ÊµÑ飨ÆøÌåÔÚͬÎÂͬѹϲⶨ£©¡£ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©ÊµÑé1¼×ÕëͲÄÚµÄÏÖÏóÊÇ£ºÓÐ___________Éú³É£¬ÕëͲ»îÈû________Òƶ¯£¨ÌîÏòÍâ¡¢ÏòÄÚ¡¢²»£©¡£·´Ó¦ºó¼×ÕëͲÄÚÓÐÉÙÁ¿µÄ²ÐÁôÆøÌ壬ÕýÈ·µÄ´¦Àí·½·¨Êǽ«ÆäͨÈë___________ÈÜÒºÖС£
£¨2£©ÊµÑé2ÖУ¬¼×ÖеÄ3mLÆøÌåÊÇNO2ºÍN2O4µÄ»ìºÏÆøÌ壬ÄÇô¼×ÖÐ×îºóÊ£ÓàµÄÎÞÉ«ÆøÌåÊÇ_______£¬Ð´³öNO2ÓëH2O·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____________________¡£
£¨3£©ÊµÑé3ÖУ¬ÒÑÖª£º3Cl2£«2NH3===N2£«6HCl¡£¼×ÕëͲ´¦»îÈûÓÐÒƶ¯£¬ÕëͲÄÚÓа×Ñ̲úÉúÍ⣬ÆøÌåµÄÑÕÉ«±äΪ____________¡£×îºóÕëͲÄÚÊ£ÓàÆøÌåµÄÌå»ýԼΪ________mL¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com