(9·Ö)ºìÆÏÌѾÆÃÜ·â´¢´æʱ¼äÔ½³¤£¬ÖÊÁ¿Ô½ºÃ£¬Ô­ÒòÖ®Ò»ÊÇ´¢´æ¹ý³ÌÖÐÉú³ÉÁËÓÐÏãζµÄõ¥¡£ÔÚʵÑéÊÒÒ²¿ÉÒÔÓÃÈçÓÒÏÂͼËùʾµÄ×°ÖÃÖÆÈ¡ÒÒËáÒÒõ¥£¬Çë»Ø´ðÏÂÁÐÎÊÌâ¡£
(1)ÒÒ´¼·Ö×ÓÖйÙÄÜÍŵÄÃû³ÆÊÇ___________£»ÒÒËá·Ö×ÓÖйÙÄÜÍŵÄÃû³ÆÊÇ                      

(2)ÊÔ¹ÜaÖмÓÈ뼸¿éËé´ÉƬµÄÄ¿µÄÊÇ____________¡£
(3)ÊÔ¹ÜaÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______________________________£¬·´Ó¦ÀàÐÍÊÇ________________________¡£
(4)·´Ó¦¿ªÊ¼Ç°£¬ÊÔ¹ÜbÖÐÊ¢·ÅµÄÈÜÒºÊÇ____________¡£
(5)¿ÉÓÃ____________µÄ·½·¨°ÑÖƵõÄÒÒËáÒÒõ¥·ÖÀë³öÀ´¡£
£¨1£©ôÇ»ù  ôÈ»ù£¨2£©·ÀÖ¹±©·Ð
£¨3£©õ¥»¯·´Ó¦£¨»òÈ¡´ú·´Ó¦£©
£¨4£©±¥ºÍ̼ËáÄÆÈÜÒº  £¨5£©·ÖÒº
£¨1£©¾ö¶¨ÓлúÎïÌØÊâÐÔÖʵÄÔ­×Ó»òÔ­×ÓÍÅÊǹÙÄÜÍÅ£¬ËùÒÔÒÒ´¼ºÍÒÒËáµÄ¹ÙÄÜÍÅ·Ö±ðÊÇôÇ»ùºÍôÈ»ù¡£
£¨2£©·´Ó¦ÐèÒª¼ÓÈÈ£¬ËùÒÔÐèÒª¼ÓÈëËé´ÉƬ·ÀÖ¹±©·Ð¡£
£¨3£©aÖÐÊÇÖÆÈ¡ÒÒËáÒÒõ¥µÄ£¬·½³ÌʽΪ
£¬¸Ã·´Ó¦ÊÇõ¥»¯·´Ó¦»òÈ¡´ú·´Ó¦¡£
£¨4£©ÓÉÓÚÉú³ÉÒÒËáÒÒõ¥Öк¬ÓÐÒÒËáºÍÒÒ´¼£¬ËùÒÔÒª³ýÈ¥ÔÓÖÊ£¬ÐèÒª¼ÓÈë±¥ºÍ̼ËáÄÆÈÜÒº¡£
£¨5£©ÒÒËáÒÒõ¥²»ÈÜÓÚË®£¬·ÖÒº¼´µÃµ½ÒÒËáÒÒõ¥¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÓлúÎï¾ßÓÐÏÂÁÐÐÔÖÊ£ºÄÜ·¢ÉúÒø¾µ·´Ó¦£¬µÎÈëʯÈïÊÔÒº²»±äÉ«£¬¼ÓÈëÉÙÁ¿¼îÒº²¢µÎÈë·Ó̪ÊÔÒº£¬¹²ÖóºóºìÉ«Ïûʧ¡£Ô­ÓлúÎïÊÇÏÂÁÐÎïÖÊÖеģ¨   £©
A£®¼×ËáÒÒõ¥B£®ÒÒËá¼×õ¥C£®ÒÒÈ©D£®¼×Ëá

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÊµÑéÌâ

ij»¯Ñ§Ð¡×é²ÉÓÃÀàËÆÖÆÒÒËáÒÒõ¥µÄ×°ÖÃ(ÈçÏÂͼ)£¬ÒÔ»·¼º´¼ÖƱ¸»·¼ºÏ©£º

ÒÑÖª£º
 
ÃܶÈ(g/cm3)
ÈÛµã(¡æ)
·Ðµã(¡æ)
ÈܽâÐÔ
»·¼º´¼
0.96
25
161
ÄÜÈÜÓÚË®
»·¼ºÏ©
0.81
£­103
83
ÄÑÈÜÓÚË®
(1)ÖƱ¸´ÖÆ·
½«12.5 mL»·¼º´¼¼ÓÈëÊÔ¹ÜAÖУ¬ÔÙ¼ÓÈë1 mLŨÁòËᣬҡ      
ÔȺó·ÅÈëËé´ÉƬ£¬»ºÂý¼ÓÈÈÖÁ·´Ó¦ÍêÈ«£¬ÔÚÊÔ¹ÜCÄڵõ½»·¼ºÏ©´ÖÆ·¡£
¢ÙAÖÐËé´ÉƬµÄ×÷ÓÃÊÇ________£¬µ¼¹ÜB³ýÁ˵¼ÆøÍ⻹¾ßÓеÄ×÷ÓÃÊÇ________¡£
¢ÚÊÔ¹ÜCÖÃÓÚ±ùˮԡÖеÄÄ¿µÄÊÇ________________________________________¡£
(2)ÖƱ¸¾«Æ·
¢Ù»·¼ºÏ©´ÖÆ·Öк¬Óл·¼º´¼ºÍÉÙÁ¿ËáÐÔÔÓÖʵȡ£ÏȼÓÈëNa2CO3ÈÜÒº£¬Õñµ´¡¢¾²Öᢷֲ㣬»·¼ºÏ©ÔÚ________²ã(Ìî¡°ÉÏ¡±»ò¡°Ï¡±)£¬·ÖÒººóÓÃˮϴµÓ¡£
¢ÚÔÙ½«»·¼ºÏ©°´ÏÂͼװÖÃÕôÁó£¬ÀäÈ´Ë®´Ó________¿Ú½øÈë(Ìî¡°g¡±»ò¡°f¡±)¡£ÕôÁóʱҪ¼ÓÈëÉúʯ»Ò£¬Ä¿µÄÊÇ________________________________________¡£

¢ÛʵÑéÖƵõĻ·¼ºÏ©¾«Æ·ÖÊÁ¿µÍÓÚÀíÂÛ²úÁ¿£¬¿ÉÄܵÄÔ­ÒòÊÇ________¡£
A£®ÕôÁóʱ´Ó70 ¡æ¿ªÊ¼ÊÕ¼¯²úÆ·
B£®»·¼º´¼Êµ¼ÊÓÃÁ¿¶àÁË
C£®ÖƱ¸´ÖƷʱ»·¼º´¼Ëæ²úÆ·Ò»ÆðÕô³ö

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÊµÑéÌâ

(12·Ö)õ¥ÊÇÖØÒªµÄÓлúºÏ³ÉÖмäÌ壬¹ã·ºÓ¦ÓÃÓÚÈܼÁ¡¢ÔöËܼÁ¡¢ÏãÁÏ¡¢Õ³ºÏ¼Á¼°Ó¡Ë¢¡¢·ÄÖ¯µÈ¹¤Òµ¡£ÒÒËáÒÒõ¥µÄʵÑéÊҺ͹¤ÒµÖÆ·¨³£Óñù´×Ëá¡¢ÎÞË®ÒÒ´¼ºÍŨÁòËá»ìºÏ£¬ÔÚ¼ÓÈÈÌõ¼þÏ·´Ó¦ÖƵãº

Çë¸ù¾ÝÒªÇó»Ø´ðÏÂÁÐÎÊÌ⣺
(1) д³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ                 
£¨2£©´Ë·´Ó¦ÖÐŨÁòËáµÄ×÷ÓÃÊÇ                    
±¥ºÍ̼ËáÄƵÄ×÷ÓÃÊÇ                           
£¨3£©Èô²ÉÓÃͬλËØʾ×Ù·¨Ñо¿¸Ã»¯Ñ§·´Ó¦£¬·´Ó¦ÎïÎÞË®ÒÒ´¼Öк¬ÓÐ18O£¬±ù´×ËáÖоùΪ16O£¬·´Ó¦ºóµÄ»ìºÏÎïÖУ¬º¬ÓÐ18OµÄÎïÖÊÓР                 
£¨4£©ÈôÓÃÈçͼËùʾװÖÃÀ´ÖƱ¸ÉÙÁ¿µÄÒÒËáÒÒõ¥£¬×¶ÐÎÆ¿ÖеÄÏÖÏóΪ               £¬²»¹ýÍùÍù²úÂÊÆ«µÍ£¬ÆäÔ­Òò¿ÉÄÜΪ            (ÈÎÌî2ÖÖ£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÊµÑéÌâ

(11·Ö) ¡°¾ÆÊdzµÄÏ㡱£¬¾ÍÊÇÒòΪ¾ÆÔÚ´¢´æ¹ý³ÌÖÐÉú³ÉÁËÓÐÏãζµÄÒÒËáÒÒõ¥£¬ÔÚʵÑéÊÒÎÒÃÇÒ²¿ÉÒÔÓÃÈçͼËùʾµÄ×°ÖÃÖÆÈ¡ÒÒËáÒÒõ¥¡£»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Ð´³öÖÆÈ¡ÒÒËáÒÒõ¥µÄ»¯Ñ§·´Ó¦·½³Ìʽ£º
                  ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡    
£¨2£©ÊÔ¹ÜBÖÐÊ¢·ÅµÄÈÜÒºÊÇ                £¬ÆäÖ÷Òª×÷ÓÃÊÇ                  
                                                                                                        ¡£
£¨3£©×°ÖÃÖÐͨÕôÆøµÄµ¼¹Ü²»ÄܲåÈëÊÔ¹ÜBµÄÈÜÒºÖУ¬Ä¿µÄÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
£¨4£©ÈôÒª°ÑÖƵõÄÒÒËáÒÒõ¥·ÖÀë³öÀ´£¬Ó¦²ÉÓõÄʵÑé²Ù×÷ÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
£¨5£©×ö´ËʵÑéʱ£¬ÍùÍù»¹Ïò´óÊÔ¹ÜAÖмÓÈ뼸¿éËé´ÉƬ£¬ÆäÄ¿µÄÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡£
£¨6£©ÓÃ30gÒÒËáÓë46gÒÒ´¼·´Ó¦£¬Èç¹ûʵ¼Ê²úÁ¿ÊÇÀíÂÛ²úÁ¿µÄ67%£¬Ôòʵ¼ÊµÃµ½ÒÒËáÒÒõ¥µÄÖÊÁ¿ÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡£
A£®44gB£®29.5gC£®74.8gD£®88g

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÊµÑéÌâ

£¨8·Ö£©ÒÒËáÒÒõ¥ÊÇÖØÒªµÄÓлúºÏ³ÉÖмäÌ壬¹ã·ºÓ¦ÓÃÓÚ»¯Ñ§¹¤Òµ¡£ÊµÑéÊÒÀûÓÃÓÒͼµÄ×°ÖÃÖƱ¸ÒÒËáÒÒõ¥¡£

£¨1£©Óë½Ì²Ä²ÉÓõÄʵÑé×°Öò»Í¬£¬´Ë×°ÖÃÖвÉÓÃÁËÇòÐθÉÔï¹Ü£¬Æä×÷ÓÃÊÇ£º     ¡£
£¨2£©ÎªÁËÖ¤Ã÷ŨÁòËáÔڸ÷´Ó¦ÖÐÆðµ½ÁË´ß»¯¼ÁºÍÎüË®¼ÁµÄ×÷Óã¬Ä³Í¬Ñ§ÀûÓÃÉÏͼËùʾװÖýøÐÐÁËÒÔÏÂ4¸öʵÑ顣ʵÑ鿪ʼÏÈÓþƾ«µÆ΢ÈÈ3min£¬ÔÙ¼ÓÈÈʹ֮΢΢·ÐÌÚ3min¡£ÊµÑé½áÊøºó³ä·ÖÕñµ´Ð¡ÊԹܢòÔÙ²âÓлú²ãµÄºñ¶È£¬ÊµÑé¼Ç¼ÈçÏ£º
ʵÑé±àºÅ
ÊԹܢñÖÐÊÔ¼Á
ÊԹܢòÖÐ
ÊÔ¼Á
Óлú²ãµÄ
ºñ¶È/cm
A
2 mLÒÒ´¼¡¢1 mLÒÒËá¡¢
1mL18mol¡¤L£­1ŨÁòËá
 ±¥ºÍNa2CO3
ÈÜÒº
3.0
B
2 mLÒÒ´¼¡¢1 mLÒÒËá
0.1
C
2 mLÒÒ´¼¡¢1 mLÒÒËá¡¢
3 mL 2mol¡¤L£­1 H2SO4
   0.6
D
2 mLÒÒ´¼¡¢1 mLÒÒËá¡¢ÑÎËá
0.6
¢ÙʵÑéDµÄÄ¿µÄÊÇÓëʵÑéCÏà¶ÔÕÕ£¬Ö¤Ã÷H+¶Ôõ¥»¯·´Ó¦¾ßÓд߻¯×÷Óá£ÊµÑéDÖÐÓ¦¼ÓÈëÑÎËáµÄÌå»ýºÍŨ¶È·Ö±ðÊÇ______mLºÍ_____mol¡¤L£­1¡£
¢Ú·ÖÎöʵÑé                £¨ÌîʵÑé±àºÅ£©µÄÊý¾Ý£¬¿ÉÒÔÍƲâ³öŨH2SO4µÄÎüË®ÐÔÌá¸ßÁËÒÒËáÒÒõ¥µÄ²úÂÊ¡£
£¨3£©ÈôÏÖÓÐÒÒËá90g£¬ÒÒ´¼138g·¢Éúõ¥»¯·´Ó¦µÃµ½80gÒÒËáÒÒõ¥£¬ÊÔ¼ÆËã¸Ã·´Ó¦µÄ²úÂÊΪ______________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

µ¨¹Ì´¼ÊÇÈËÌå±ØÐèµÄÉúÎï»îÐÔÎïÖÊ£¬·Ö×ÓʽΪC25H45OH¡£ÒÑ֪ijÖÖµ¨¹Ì´¼õ¥ÊÇÒº¾§²ÄÁÏ£¬·Ö×ÓʽΪC32H50O2¡£ÔòÉú³ÉÕâÖÖµ¨¹Ì´¼õ¥µÄËáÊÇ£¨ £©
A£®C6H13COOHB£®C6H5COOHC£®C7H15COOHD£®C6H5CH2COOH

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ijÖÖõ¥µÄ×é³É¿É±íʾΪCmH2m+1COOCnH2n+1£¬ÆäÖÐm+n=5¡£¸Ãõ¥µÄÒ»ÖÖË®½â²úÎï¾­´ß»¯Ñõ»¯¿Éת»¯³ÉÁíÒ»ÖÖË®½â²úÎÔòÔ­À´µÄõ¥ÊÇ£¨   £©
A£®±ûËá±ûõ¥B£®ÒÒËáÒÒõ¥C£®¼×ËáÒÒËáD£®±ûËáÒÒõ¥

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÊµÑéÌâ

(16·Ö£©Ë«°²Í×Ã÷ÊÇÒ»ÖÖ½µÑªÖ¬Ò©ÎÖ÷ÒªÓÃÓÚ½µµÍѪҺÖе¨¹Ì´¼Å¨¶È£¬°²È«£¬¸±×÷ÓÃС£¬Æä½á¹¹¼òʽΪ£º
ÒÑÖª£º

Ë«°²Í×Ã÷µÄºÏ³É·ÏßÈçÏ£º

ÒÑÖª£ºCµÄĦ¶ûÖÊÁ¿ÊÇͬÎÂͬѹÏÂÇâÆøÖÊÁ¿µÄ28±¶£»IÄÜ·¢ÉúÒø¾µ·´Ó¦ÇÒ1mol IÄÜÓë2molH2SÉú¼Ó³É·´Ó¦£»KµÄ½á¹¹¾ßÓжԳÆÐÔ¡£ÊԻشðÏÂÁÐÎÊÌ⣺
(1)Ë«°²Í×Ã÷µÄ·Ö×ÓʽΪ£º_____________¡£
(2)EµÄ½á¹¹¼òʽΪ£º________________________
(3)·´Ó¦¢ÚµÄÌõ¼þÊÇ__________________
(4)JÓëÐÂÖÆÇâÑõ»¯Í­·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º__________________
(5)·´Ó¦¢ÜµÄ»¯Ñ§·½³ÌʽΪ£º______________________________
(6)·ûºÏÏÂÁÐ3¸ö±¸¼þµÄHµÄͬ·ÖÒì¹¹ÌåÓÐ____________ÖÖ,¢ÙÄÜÓëFeCl3ÈÜÒºÏÔÉ«£»¢ÚÆ»»·ÉÏÖ»ÓÐ2¸öÈ¡´ú»ù£º¢Û1mol¸ÃÎïÖÊ×î¶à¿ÉÏûºÄ3mol NaOH,ÆäÖÐÇâÔ­×Ó¹²ÓÐÎåÖÖ²»Í¬»·¾³µÄÊÇ£¨Ð´½á¹¹Í²Ê½£©____________

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸