ËÄ´¨ÓзḻµÄÌìÈ»Æø×ÊÔ´¡£ÒÔÌìÈ»ÆøΪԭÁϺϳÉÄòËصÄÖ÷Òª²½ÖèÈçÏÂͼËùʾ(ͼÖÐijЩת»¯²½Öè¼°Éú³ÉÎïδÁгö)£º

ÌîдÏÂÁпհףº

(1)ÒÑÖª0.5 mol¼×ÍéÓë0.5 molË®ÕôÆûÔÚt ¡æ¡¢p kPaʱ£¬ÍêÈ«·´Ó¦Éú³ÉÒ»Ñõ»¯Ì¼ºÍÇâÆø£¨ºÏ³ÉÆø£©£¬ÎüÊÕÁËa kJÈÈÁ¿£¬¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇ£º             ¡£

(2)Ôںϳɰ±µÄʵ¼ÊÉú²ú¹ý³ÌÖУ¬³£²ÉÈ¡µÄ´ëÊ©Ö®Ò»ÊÇ£º½«Éú³ÉµÄ°±´Ó»ìºÏÆøÌåÖм°Ê±·ÖÀë³öÀ´£¬²¢½«·ÖÀë³ö°±ºóµÄµªÆøºÍÇâÆøÑ­»·ÀûÓã¬Í¬Ê±²¹³äµªÆøºÍÇâÆø¡£ÇëÔËÓû¯Ñ§·´Ó¦ËÙÂʺͻ¯Ñ§Æ½ºâµÄ¹Ûµã˵Ã÷²ÉÈ¡¸Ã´ëÊ©µÄÀíÓÉ£º             ¡£

(3)µ±¼×ÍéºÏ³É°±ÆøµÄת»¯ÂÊΪ75%ʱ£¬ÒÔ5.60¡Á107 L¼×ÍéΪԭÁÏÄܹ»ºÏ³É             L

°±Æø¡££¨¼ÙÉèÌå»ý¾ùÔÚ±ê×¼×´¿öϲⶨ£©

(4)ÒÑÖªÄòËصĽṹ¼òʽΪ£¬Çëд³öÁ½ÖÖº¬ÓÐ̼ÑõË«¼üµÄÄòËصÄͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º

¢Ù                                    ;¢Ú                                     ¡£

(1)CH4(g)+H2O(g)CO(g)+3H2 (g);¡÷H=2a kJ/mol

(2)Ôö´óµªÆøºÍÇâÆøµÄŨ¶ÈÓÐÀûÓÚÔö´ó·´Ó¦ËÙÂÊ;¼õС°±ÆøµÄŨ¶È£¬Ôö´óµªÆøºÍÇâÆøµÄŨ¶È¾ùÓÐÀûÓÚƽºâÏòÕý·´Ó¦·½ÏòÒƶ¯

(3)1.12¡Á103

£¨4£©¢Ù   ¢ÚNH4N=C=O

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ËÄ´¨ÓзḻµÄÌìÈ»Æø×ÊÔ´£®Ä³»¯¹¤³§ÒÔÌìÈ»ÆøΪԭÁϺϳɰ±µÄ¹¤ÒÕÁ÷³ÌʾÒâͼÈçÏ£º
¾«Ó¢¼Ò½ÌÍø
ÒÀ¾ÝÉÏÊöÁ÷³Ì£¬Íê³ÉÏÂÁÐÌî¿Õ£º
£¨1£©Õû¸öÁ÷³ÌÓÐÈý¸öÑ­»·£ºÒ»ÊÇK2CO3£¨aq£©Ñ­»·£¬¶þÊÇN2ºÍH2Ñ­»·£¬µÚÈý¸öÑ­»·Öб»Ñ­»·µÄÎïÖÊÊÇ
 

£¨2£©ÍÑÁò¹ý³ÌÖУ¬ÈôÓÐnmol Fe2O3?H2Oת»¯£¬ÔòÉú³ÉSµÄÎïÖʵÄÁ¿Îª
 
mol£¨Óú¬nµÄ´úÊýʽ±íʾ£©£®
£¨3£©Í¼ÖÐCH4µÄµÚ¶þ´Îת»¯¹ý³ÌÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
 
£®
£¨4£©Ôںϳɰ±µÄʵ¼ÊÉú²ú¹ý³ÌÖУ¬³£²ÉÈ¡µÄ´ëÊ©Ö®Ò»ÊÇ£º½«Éú³ÉµÄ°±´Ó»ìºÏÆøÌåÖм°Ê±·ÖÀë³öÀ´£¬²¢½«·ÖÀë³ö°±ºóµÄµªÆøºÍÇâÆøÑ­»·ÀûÓã¬Í¬Ê±²¹³äµªÆøºÍÇâÆø£®ÇëÔËÓû¯Ñ§·´Ó¦ËÙÂʺͻ¯Ñ§Æ½ºâµÄ¹Ûµã˵Ã÷²ÉÈ¡ÕâЩ´ëÊ©µÄÀíÓÉ£º
 

£¨5£©¸ÄÓùýÁ¿NaOHÈÜÒºÎüÊÕÌìÈ»ÆøÖеÄÁò»¯Ç⣬ÒÔʯī×÷µç¼«µç½âÎüÊÕºóËùµÃÈÜÒº¿É»ØÊÕÁò£¬Æäµç½â×Ü·´Ó¦·½³Ìʽ£¨ºöÂÔÑõÆøµÄÑõ»¯»¹Ô­£©Îª
 

£¨6£©Èô¹¤ÒµÉú²úÖÐÒÔa g°±ÆøºÍ×ãÁ¿µÄ¿ÕÆøΪԭÁÏ£¨²»¿¼ÂÇ¿ÕÆøÖÐN2µÄ·´Ó¦£©×î´óÏ޶ȵÄÖÆÈ¡NH4NO3£¬¾­¹ýһϵÁÐת»¯ºó£¬ÔÙÏò·´Ó¦ºóµÄ»ìºÏÎïÖмÓÈëbgË®£¬µÃµ½ÃܶÈΪd g/mLµÄNH4NO3ÈÜÒº£¬ÀíÂÛÉϸÃÈÜÒºÖÐÈÜÖʵÄÎïÖʵÄÁ¿Å¨¶È¿ÉÄܵÄ×î´óֵΪ
 
mol/L£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

29.

    ËÄ´¨ÓзḻµÄÌìÈ»Æø×ÊÔ´¡£ÒÔÌìÈ»ÆøΪԭÁϺϳÉÄòËصÄÖ÷Òª²½ÖèÈçÏÂͼËùʾ£¨Í¼ÖÐijЩת»¯²½Öè¼°Éú³ÉÎïδÁгö£©£º

ÇëÌîдÏÂÁпհףº

£¨1£©ÒÑÖª0.5 mol¼×ÍéÓë0.5 molË®ÕôÆûÔÚt ¡æ¡¢p kPaʱ£¬ÍêÈ«·´Ó¦Éú³ÉÒ»Ñõ»¯Ì¼ºÍÇâÆø£¨ºÏ³ÉÆø£©£¬ÎüÊÕÁËa kJÈÈÁ¿£¬¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇ£º                ¡£

£¨2£©Ôںϳɰ±µÄʵ¼ÊÉú²ú¹ý³ÌÖУ¬³£²ÉÈ¡µÄ´ëÊ©Ö®Ò»ÊÇ£º½«Éú³ÉµÄ°±´Ó»ìºÏÆøÌåÖм°Ê±·ÖÀë³öÀ´£¬²¢½«·ÖÀë³ö°±ºóµÄµªÆøºÍÇâÆøÑ­»·ÀûÓã¬Í¬Ê±²¹³äµªÆøºÍÇâÆø£¬ÇëÔËÓû¯Ñ§·´Ó¦ËÙÂʺͻ¯Ñ§Æ½ºâµÄ¹Ûµã˵Ã÷²ÉÈ¡¸Ã´ëÊ©µÄÀíÓÉ£º                ¡£

£¨3£©µ±¼×ÍéºÏ³É°±ÆøµÄת»¯ÂÊΪ75%ʱ£¬ÒÔ5.60¡Á107 L¼×ÍéΪԭÁÏÄܹ»ºÏ³É£º      L°±Æø¡££¨¼ÙÉèÌå»ý¾ùÔÚ±ê×¼×´¿öϲⶨ£©

£¨4£©ÒÑÖªÄòËصĽṹ¼òʽΪÇëд³öÁ½ÖÖº¬ÓÐ̼ÑõË«¼üµÄÄòËصÄͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º

     ¢Ù                       £»¢Ú                       ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012ÄêÈ˽̰æ¸ßÖл¯Ñ§Ñ¡ÐÞ2 1.2È˹¤¹Ìµª¼¼Êõ-ºÏ³É°±Á·Ï°¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

ËÄ´¨ÓзḻµÄÌìÈ»Æø×ÊÔ´¡£ÒÔÌìÈ»ÆøΪԭÁϺϳÉÄòËصÄÖ÷Òª²½ÖèÈçÏÂͼËùʾ£¨Í¼ÖÐijЩת»¯²½Öè¼°Éú³ÉÎïδÁгö£©£º

ÇëÌîдÏÂÁпհףº

£¨1£©ÒÑÖª0.5 mol¼×ÍéºÍ0.5 molË®ÕôÆøÔÚt ¡æ£¬p k Paʱ£¬ÍêÈ«·´Ó¦Éú³ÉÒ»Ñõ»¯Ì¼ºÍÇâÆø£¨ºÏ³ÉÆø£©£¬ÎüÊÕÁËa kJÈÈÁ¿¡£¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇ£º       _____________    

£¨2£©Ôںϳɰ±µÄʵ¼ÊÉú²ú¹ý³ÌÖУ¬³£²ÉÈ¡µÄ´ëÊ©Ö®Ò»ÊÇ£º½«Éú³ÉµÄ°±´Ó»ìºÏÆøÌåÖм´Ê¹·ÖÀë³öÀ´£¬²¢½«·ÖÀë³ö°±ºóµÄµªÆøºÍÇâÆøÑ­»·ÀûÓã¬Í¬Ê±²¹³äµªÆøºÍÇâÆø¡£ÇëÓ¦Óû¯Ñ§·´Ó¦ËÙÂʺͻ¯Ñ§Æ½ºâµÄ¹Ûµã˵Ã÷²ÉÈ¡¸Ã´ëÊ©µÄÀíÓÉ£º            _____________________ 

£¨3£©µ±¼×ÍéºÏ³É°±ÆøµÄת»¯ÂÊΪ75£¥Ê±£¬ÒÔ5.60¡Á107 L¼×ÍéΪԭÁÏÄܹ»ºÏ³É                       L °±Æø¡££¨¼ÙÉèÌå»ý¾ùÔÚ±ê×¼×´¿öϲⶨ£©

£¨4£©ÒÑÖªÄòËصĽṹ¼òʽΪ£¬Çëд³öÁ½ÖÖº¬ÓÐ̼ÑõË«¼üµÄÄòËصÄͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º¢Ù                      £¬¢Ú                        ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÉÂÎ÷Ê¡Ä£ÄâÌâ ÌâÐÍ£ºÌî¿ÕÌâ

ËÄ´¨ÓзḻµÄÌìÈ»Æø×ÊÔ´¡£ÒÔÌìÈ»ÆøΪԭÁϺϳÉÄòËصÄÖ÷Òª²½ÖèÈçÏÂͼËùʾ£¨Í¼ÖÐijЩת»¯²½Öè¼°Éú³ÉÎïδÁгö£©£º ÇëÌîдÏÂÁпհףº
£¨1£©ÒÑÖª0.5 mol¼×ÍéºÍ0.5 molË®ÕôÆøÔÚt ¡æ£¬p k Paʱ£¬ÍêÈ«·´Ó¦Éú³ÉÒ»Ñõ»¯Ì¼ºÍÇâÆø£¨ºÏ³ÉÆø£©£¬ÎüÊÕÁËa kJÈÈÁ¿¡£¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇ£º____________¡£
£¨2£©Ôںϳɰ±µÄʵ¼ÊÉú²ú¹ý³ÌÖУ¬³£²ÉÈ¡µÄ´ëÊ©Ö®Ò»ÊÇ£º½«Éú³ÉµÄ°±´Ó»ìºÏÆøÌåÖм´Ê±·ÖÀë³öÀ´£¬²¢½«·ÖÀë³ö°±ºóµÄµªÆøºÍÇâÆøÑ­»·ÀûÓã¬Í¬Ê±²¹³äµªÆøºÍÇâÆø¡£ÇëÓ¦Óû¯Ñ§·´Ó¦ËÙÂʺͻ¯Ñ§Æ½ºâµÄ¹Ûµã˵Ã÷²ÉÈ¡¸Ã´ëÊ©µÄÀíÓÉ£º_______________¡£
£¨3£©µ±¼×ÍéºÏ³É°±ÆøµÄת»¯ÂÊΪ75£¥Ê±£¬ÒÔ5.60¡Á107 L¼×ÍéΪԭÁÏÄܹ»ºÏ³É______________L °±Æø¡££¨¼ÙÉèÌå»ý¾ùÔÚ±ê×¼×´¿öϲⶨ£©
£¨4£©ÒÑÖªÄòËصĽṹ¼òʽΪ£ºÇëд³öÁ½ÖÖº¬ÓÐ̼ÑõË«¼ü µÄÄòËصÄͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º¢Ù________________ £¬¢Ú_____________ ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÍ¬²½Ìâ ÌâÐÍ£ºÌî¿ÕÌâ

ËÄ´¨ÓзḻµÄÌìÈ»Æø×ÊÔ´¡£ÒÔÌìÈ»ÆøΪԭÁϺϳÉÄòËصÄÖ÷Òª²½ÖèÈçÏÂͼËùʾ£¨Í¼ÖÐijЩת»¯²½Öè¼°Éú³ÉÎïδÁгö£©£º
ÇëÌîдÏÂÁпհףº
£¨1£©ÒÑÖª0£®5 mol¼×ÍéºÍ0£®5 molË®ÕôÆøÔÚt ¡æ£¬p k Paʱ£¬ÍêÈ«·´Ó¦Éú³ÉÒ»Ñõ»¯Ì¼ºÍÇâÆø£¨ºÏ³ÉÆø£©£¬ÎüÊÕÁËa kJÈÈÁ¿¡£¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇ£º______________________________ ¡£
£¨2£©Ôںϳɰ±µÄʵ¼ÊÉú²ú¹ý³ÌÖУ¬³£²ÉÈ¡µÄ´ëÊ©Ö®Ò»ÊÇ£º½«Éú³ÉµÄ°±´Ó»ìºÏÆøÌåÖм´Ê¹·ÖÀë³öÀ´£¬²¢½«·ÖÀë³ö°±ºóµÄµªÆøºÍÇâÆøÑ­»·ÀûÓã¬Í¬Ê±²¹³äµªÆøºÍÇâÆø¡£ÇëÓ¦Óû¯Ñ§·´Ó¦ËÙÂʺͻ¯Ñ§Æ½ºâµÄ¹Ûµã˵Ã÷²ÉÈ¡¸Ã´ëÊ©µÄÀíÓÉ£º___________________________________ ¡£
£¨3£©µ±¼×ÍéºÏ³É°±ÆøµÄת»¯ÂÊΪ75£¥Ê±£¬ÒÔ5£®60¡Á107 L¼×ÍéΪԭÁÏÄܹ»ºÏ³É____________ L °±Æø¡££¨¼ÙÉèÌå»ý¾ùÔÚ±ê×¼×´¿öϲⶨ£©
£¨4£©ÒÑÖªÄòËصĽṹ¼òʽΪ£¬Çëд³öÁ½ÖÖº¬ÓÐ̼ÑõË«¼üµÄÄòËصÄͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º¢Ù__________________ £¬¢Ú_______________________ ¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸