ʵÑéÊÒÅäÖÆ500 mL 0.5 mol¡¤L-1µÄNaClÈÜÒº£¬ÓÐÈçϲÙ×÷²½Ö裺

¢Ù°Ñ³ÆÁ¿ºÃµÄNaCl¾§Ìå·ÅÈËСÉÕ±­ÖУ¬¼ÓÊÊÁ¿ÕôÁóË®Èܽ⣻

¢Ú°Ñ¢ÙËùµÃÈÜҺСÐÄתÈË500 mLÈÝÁ¿Æ¿ÖУ»

¢Û¼ÌÐøÏòÈÝÁ¿Æ¿ÖмÓÕôÁóË®ÖÁÒºÃæ¾àÀë¿Ì¶Èl¡«2 cm´¦£¬¸ÄÓýºÍ·µÎ¹ÜСÐĵμÓÕôÁóË®ÖÁÈÜÒº°¼ÒºÃæµ×²¿£¬Óë¿Ì¶ÈÏßÏàÇУ»

¢ÜÓÃÉÙÁ¿ÕôÁóˮϴµÓÉÕ±­ºÍ²£Á§°ô2¡ª3´Î£¬Ã¿´ÎÏ´µÓµÄÒºÌ嶼СÐÄתÈëÈÝÁ¿Æ¿£¬²¢ÇáÇáÒ¡ÔÈ£»

¢Ý½«ÈÝÁ¿Æ¿Èû½ô£¬³ä·ÖÒ¡ÔÈ¡£

ÇëÌîдÏÂÁпհףº

£¨1£©ÊµÑé²Ù×÷²½ÖèµÄÕýȷ˳ÐòΪ(ÌîÐòºÅ)                                     £»

£¨2£©±¾ÊµÑéÓõ½µÄ»ù±¾ÒÇÆ÷ÖгýÍÐÅÌÌìÆ½¡¢ÉÕ±­¡¢Á¿Í²Í⻹ÓР              £» 

£¨3£©ÊµÑéÖоͳÆÈ¡NaCl¾§ÌåµÄÖÊÁ¿ÊÇ      g£»

£¨4£©Èô³öÏÖÈçÏÂÇé¿ö£¬¶ÔËùÅäÈÜҺŨ¶È½«ÓкÎÓ°Ïì?£¨Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±¡¢¡°ÎÞÓ°Ï족£©

A¡¢¶¨ÈÝʱ¸©ÊÓ          £»B¡¢¼ÓÕôÁóˮʱ²»É÷³¬¹ýÁ˿̶Ƞ        £»

£¨5£©Èô¶¨ÈÝʱÕôÁóˮʱ²»É÷³¬¹ýÁ˿̶ÈÏߣ¬Ó¦ÈçºÎ´¦Àí£¿                ¡£

 

£¨1£©            ¢Ù¢Ú¢Ü¢Û¢Ý            £»£¨3·Ö£©

£¨2£©   500mLÈÝÁ¿Æ¿¡¢²£Á§°ô¡¢½ºÍ·µÎ¹Ü     £» £¨3·Ö£©

£¨3£© 14.6  g£»£¨2·Ö£©

£¨4£©

A¡¢   Æ«¸ß   £»B¡¢   Æ«µÍ  £»£¨¸÷1·Ö£©

£¨5£©   Ï´µÓÒÇÆ÷£¬ÖØÐÂÅäÖÆ     ¡££¨2·Ö£©

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

£¨1£©ÏÂͼΪ³£¼ûÒÇÆ÷µÄ²¿·Ö½á¹¹(ÓеÄÒÇÆ÷±»·Å´ó)AͼÖÐÒºÃæËùʾÈÜÒºµÄÌå»ýΪ      mL£¬ÓÃÉÏÊöËÄÖÖÒÇÆ÷ÖеÄijÖÖ²âÁ¿Ò»ÒºÌåµÄÌå»ý£¬Æ½ÊÓʱ¶ÁÊýΪN mL£¬ÑöÊÓʱ¶ÁÊýΪM mL£¬ÈôM>N£¬ÔòËùʹÓõÄÒÇÆ÷ÊÇ____        (Ìî×Öĸ±êºÅ)¡£

£¨2£©ÔÚ»¯Ñ§·ÖÎöÖУ¬³£ÐèÓÃKMnO4±ê×¼ÈÜÒº£¬ÓÉÓÚKMnO4¾§ÌåÔÚÊÒÎÂϲ»Ì«Îȶ¨£¬Òò¶øºÜÄÑÖ±½ÓÅäÖÆ×¼È·ÎïÖʵÄÁ¿Å¨¶ÈµÄKMnO4ÈÜÒº¡£ÊµÑéÊÒÒ»°ãÏȳÆÈ¡Ò»¶¨ÖÊÁ¿µÄKMnO4¾§Ì壬´ÖÅä³É´óÖÂŨ¶ÈµÄKMnO4ÈÜÒº£¬ÔÙÓÃÐÔÖÊÎȶ¨¡¢Ïà¶Ô·Ö×ÓÖÊÁ¿½Ï´óµÄ»ù×¼ÎïÖʲÝËáÄÆ[Mr(Na2C2O4)£½134£®0]¶Ô´ÖÅäµÄKMnO4ÈÜÒº½øÐб궨£¬²â³öËùÅäÖÆµÄKMnO4ÈÜÒºµÄ׼ȷŨ¶È£¬·´Ó¦Ô­ÀíΪ£º5C2O42£­£«2MnO4£­£«16H£«¡ú10CO2¡ü£«2Mn2+£«8H2O

ÒÔÏÂÊDZ궨KMnO4ÈÜÒºµÄʵÑé²½Ö裺

²½ÖèÒ»£ºÏÈ´ÖÅäŨ¶ÈԼΪ0£®15mol¡¤L-1µÄ¸ßÃÌËá¼ØÈÜÒº500 mL¡£

²½Öè¶þ£º×¼È·³ÆÈ¡Na2C2O4¹ÌÌåm g·ÅÈë×¶ÐÎÆ¿ÖУ¬ÓÃÕôÁóË®ÈܽⲢ¼ÓÏ¡ÁòËáËữ£¬¼ÓÈÈÖÁ70¡«80¡æ£¬Óò½ÖèÒ»ËùÅä¸ßÃÌËá¼ØÈÜÒº½øÐеζ¨¡£¼Ç¼Ïà¹ØÊý¾Ý¡£

²½ÖèÈý£º                                                       ¡£

²½ÖèËÄ£º¼ÆËãµÃ¸ßÃÌËá¼ØµÄÎïÖʵÄÁ¿Å¨¶È¡£ÊԻشðÏÂÁÐÎÊÌ⣺

¢Ù¸ÃµÎ¶¨ÊµÑé             £¨¡°ÐèÒª¡±»ò¡°²»ÐèÒª¡±£©¼Óָʾ¼Á¡£

¢Ú²½Öè¶þÖе樲Ù×÷ͼʾÕýÈ·µÄÊÇ__________£¨Ìî±àºÅ£©¡£

¢Û²½Öè¶þµÄµÎ¶¨¹ý³Ìζȱ仯²¢²»Ã÷ÏÔ£¬µ«²Ù×÷¹ý³ÌÖз¢ÏÖǰһ½×¶ÎÈÜÒºÍÊÉ«½ÏÂý£¬Öмä½×¶ÎÍÊÉ«Ã÷ÏÔ±ä¿ì£¬×îºó½×¶ÎÍÊÉ«ÓÖ±äÂý¡£ÊÔ¸ù¾ÝÓ°Ï컯ѧ·´Ó¦ËÙÂʵÄÌõ¼þ·ÖÎö£¬ÈÜÒºÍÊÉ«Ã÷ÏÔ±ä¿ìµÄÔ­Òò¿ÉÄÜÊÇ_______             £¬×îºóÓÖ±äÂýµÄÔ­ÒòÊÇ         ¡£¢ÜÇëд³ö²½ÖèÈýµÄ²Ù×÷ÄÚÈÝ                           ¡£¢ÝÈômµÄƽ¾ùÊýֵΪ1.340g£¬µÎ¶¨µÄKMnO4ÈÜҺƽ¾ùÓÃÁ¿Îª25.00mL£¬ÔòKMnO4ÈÜÒºµÄŨ¶ÈΪ                 mol¡¤L-1¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012ѧÄêɽ¶«Ê¡Î«·»Êи߶þº®¼Ù×÷Òµ»¯Ñ§ÊÔ¾í£¨ËÄ£© ÌâÐÍ£ºÊµÑéÌâ

£¨1£©ÏÂͼΪ³£¼ûÒÇÆ÷µÄ²¿·Ö½á¹¹(ÓеÄÒÇÆ÷±»·Å´ó)AͼÖÐÒºÃæËùʾÈÜÒºµÄÌå»ýΪ     mL£¬ÓÃÉÏÊöËÄÖÖÒÇÆ÷ÖеÄijÖÖ²âÁ¿Ò»ÒºÌåµÄÌå»ý£¬Æ½ÊÓʱ¶ÁÊýΪN mL£¬ÑöÊÓʱ¶ÁÊýΪM mL£¬ÈôM>N£¬ÔòËùʹÓõÄÒÇÆ÷ÊÇ____        (Ìî×Öĸ±êºÅ)¡£
£¨2£©ÔÚ»¯Ñ§·ÖÎöÖУ¬³£ÐèÓÃKMnO4±ê×¼ÈÜÒº£¬ÓÉÓÚKMnO4¾§ÌåÔÚÊÒÎÂϲ»Ì«Îȶ¨£¬Òò¶øºÜÄÑÖ±½ÓÅäÖÆ×¼È·ÎïÖʵÄÁ¿Å¨¶ÈµÄKMnO4ÈÜÒº¡£ÊµÑéÊÒÒ»°ãÏȳÆÈ¡Ò»¶¨ÖÊÁ¿µÄKMnO4¾§Ì壬´ÖÅä³É´óÖÂŨ¶ÈµÄKMnO4ÈÜÒº£¬ÔÙÓÃÐÔÖÊÎȶ¨¡¢Ïà¶Ô·Ö×ÓÖÊÁ¿½Ï´óµÄ»ù×¼ÎïÖʲÝËáÄÆ[Mr(Na2C2O4)£½134£®0]¶Ô´ÖÅäµÄKMnO4ÈÜÒº½øÐб궨£¬²â³öËùÅäÖÆµÄKMnO4ÈÜÒºµÄ׼ȷŨ¶È£¬·´Ó¦Ô­ÀíΪ£º5C2O42£­£«2MnO4£­£«16H£«¡ú10CO2¡ü£«2Mn2+£«8H2O

ÒÔÏÂÊDZ궨KMnO4ÈÜÒºµÄʵÑé²½Ö裺
²½ÖèÒ»£ºÏÈ´ÖÅäŨ¶ÈԼΪ0£®15mol¡¤L-1µÄ¸ßÃÌËá¼ØÈÜÒº500 mL¡£
²½Öè¶þ£º×¼È·³ÆÈ¡Na2C2O4¹ÌÌåm g·ÅÈë×¶ÐÎÆ¿ÖУ¬ÓÃÕôÁóË®ÈܽⲢ¼ÓÏ¡ÁòËáËữ£¬¼ÓÈÈÖÁ70¡«80¡æ£¬Óò½ÖèÒ»ËùÅä¸ßÃÌËá¼ØÈÜÒº½øÐеζ¨¡£¼Ç¼Ïà¹ØÊý¾Ý¡£
²½ÖèÈý£º                                                       ¡£
²½ÖèËÄ£º¼ÆËãµÃ¸ßÃÌËá¼ØµÄÎïÖʵÄÁ¿Å¨¶È¡£ÊԻشðÏÂÁÐÎÊÌ⣺
¢Ù¸ÃµÎ¶¨ÊµÑé             £¨¡°ÐèÒª¡±»ò¡°²»ÐèÒª¡±£©¼Óָʾ¼Á¡£
¢Ú²½Öè¶þÖе樲Ù×÷ͼʾÕýÈ·µÄÊÇ__________£¨Ìî±àºÅ£©¡£

¢Û²½Öè¶þµÄµÎ¶¨¹ý³Ìζȱ仯²¢²»Ã÷ÏÔ£¬µ«²Ù×÷¹ý³ÌÖз¢ÏÖǰһ½×¶ÎÈÜÒºÍÊÉ«½ÏÂý£¬Öмä½×¶ÎÍÊÉ«Ã÷ÏÔ±ä¿ì£¬×îºó½×¶ÎÍÊÉ«ÓÖ±äÂý¡£ÊÔ¸ù¾ÝÓ°Ï컯ѧ·´Ó¦ËÙÂʵÄÌõ¼þ·ÖÎö£¬ÈÜÒºÍÊÉ«Ã÷ÏÔ±ä¿ìµÄÔ­Òò¿ÉÄÜÊÇ_______             £¬×îºóÓÖ±äÂýµÄÔ­ÒòÊÇ         ¡£¢ÜÇëд³ö²½ÖèÈýµÄ²Ù×÷ÄÚÈÝ                           ¡£¢ÝÈômµÄƽ¾ùÊýֵΪ1.340g£¬µÎ¶¨µÄKMnO4ÈÜҺƽ¾ùÓÃÁ¿Îª25.00mL£¬ÔòKMnO4ÈÜÒºµÄŨ¶ÈΪ                 mol¡¤L-1¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012ѧÄêɽ¶«Ê¡Î«·»Êи߶þº®¼Ù×÷Òµ»¯Ñ§ÊÔ¾í£¨ËÄ£© ÌâÐÍ£ºÊµÑéÌâ

£¨1£©ÏÂͼΪ³£¼ûÒÇÆ÷µÄ²¿·Ö½á¹¹(ÓеÄÒÇÆ÷±»·Å´ó)AͼÖÐÒºÃæËùʾÈÜÒºµÄÌå»ýΪ       mL£¬ÓÃÉÏÊöËÄÖÖÒÇÆ÷ÖеÄijÖÖ²âÁ¿Ò»ÒºÌåµÄÌå»ý£¬Æ½ÊÓʱ¶ÁÊýΪN mL£¬ÑöÊÓʱ¶ÁÊýΪM mL£¬ÈôM>N£¬ÔòËùʹÓõÄÒÇÆ÷ÊÇ____         (Ìî×Öĸ±êºÅ)¡£

£¨2£©ÔÚ»¯Ñ§·ÖÎöÖУ¬³£ÐèÓÃKMnO4±ê×¼ÈÜÒº£¬ÓÉÓÚKMnO4¾§ÌåÔÚÊÒÎÂϲ»Ì«Îȶ¨£¬Òò¶øºÜÄÑÖ±½ÓÅäÖÆ×¼È·ÎïÖʵÄÁ¿Å¨¶ÈµÄKMnO4ÈÜÒº¡£ÊµÑéÊÒÒ»°ãÏȳÆÈ¡Ò»¶¨ÖÊÁ¿µÄKMnO4¾§Ì壬´ÖÅä³É´óÖÂŨ¶ÈµÄKMnO4ÈÜÒº£¬ÔÙÓÃÐÔÖÊÎȶ¨¡¢Ïà¶Ô·Ö×ÓÖÊÁ¿½Ï´óµÄ»ù×¼ÎïÖʲÝËáÄÆ[Mr(Na2C2O4)£½134£®0]¶Ô´ÖÅäµÄKMnO4ÈÜÒº½øÐб궨£¬²â³öËùÅäÖÆµÄKMnO4ÈÜÒºµÄ׼ȷŨ¶È£¬·´Ó¦Ô­ÀíΪ£º5C2O42£­£«2MnO4£­£«16H£«¡ú10CO2¡ü£«2Mn2+£«8H2O

ÒÔÏÂÊDZ궨KMnO4ÈÜÒºµÄʵÑé²½Ö裺

²½ÖèÒ»£ºÏÈ´ÖÅäŨ¶ÈԼΪ0£®15mol¡¤L-1µÄ¸ßÃÌËá¼ØÈÜÒº500 mL¡£

²½Öè¶þ£º×¼È·³ÆÈ¡Na2C2O4¹ÌÌåm g·ÅÈë×¶ÐÎÆ¿ÖУ¬ÓÃÕôÁóË®ÈܽⲢ¼ÓÏ¡ÁòËáËữ£¬¼ÓÈÈÖÁ70¡«80¡æ£¬Óò½ÖèÒ»ËùÅä¸ßÃÌËá¼ØÈÜÒº½øÐеζ¨¡£¼Ç¼Ïà¹ØÊý¾Ý¡£

²½ÖèÈý£º                                                        ¡£

²½ÖèËÄ£º¼ÆËãµÃ¸ßÃÌËá¼ØµÄÎïÖʵÄÁ¿Å¨¶È¡£ÊԻشðÏÂÁÐÎÊÌ⣺

¢Ù¸ÃµÎ¶¨ÊµÑé              £¨¡°ÐèÒª¡±»ò¡°²»ÐèÒª¡±£©¼Óָʾ¼Á¡£

¢Ú²½Öè¶þÖе樲Ù×÷ͼʾÕýÈ·µÄÊÇ__________£¨Ìî±àºÅ£©¡£

¢Û²½Öè¶þµÄµÎ¶¨¹ý³Ìζȱ仯²¢²»Ã÷ÏÔ£¬µ«²Ù×÷¹ý³ÌÖз¢ÏÖǰһ½×¶ÎÈÜÒºÍÊÉ«½ÏÂý£¬Öмä½×¶ÎÍÊÉ«Ã÷ÏÔ±ä¿ì£¬×îºó½×¶ÎÍÊÉ«ÓÖ±äÂý¡£ÊÔ¸ù¾ÝÓ°Ï컯ѧ·´Ó¦ËÙÂʵÄÌõ¼þ·ÖÎö£¬ÈÜÒºÍÊÉ«Ã÷ÏÔ±ä¿ìµÄÔ­Òò¿ÉÄÜÊÇ_______              £¬×îºóÓÖ±äÂýµÄÔ­ÒòÊÇ          ¡£¢ÜÇëд³ö²½ÖèÈýµÄ²Ù×÷ÄÚÈÝ                            ¡£¢ÝÈômµÄƽ¾ùÊýֵΪ1.340g£¬µÎ¶¨µÄKMnO4ÈÜҺƽ¾ùÓÃÁ¿Îª25.00mL£¬ÔòKMnO4ÈÜÒºµÄŨ¶ÈΪ                  mol¡¤L-1¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

£¨9·Ö£©ÔÚ»¯Ñ§·ÖÎöÖУ¬³£ÐèÓÃKMnO4±ê×¼ÈÜÒº£¬ÓÉÓÚKMnO4¾§ÌåÔÚÊÒÎÂϲ»Ì«Îȶ¨£¬Òò¶øºÜÄÑÖ±½ÓÅäÖÆ×¼È·ÎïÖʵÄÁ¿Å¨¶ÈµÄKMnO4ÈÜÒº¡£ÊµÑéÊÒÒ»°ãÏȳÆÈ¡Ò»¶¨ÖÊÁ¿µÄKMnO4¾§Ì壬´ÖÅä³É´óÖÂŨ¶ÈµÄKMnO4ÈÜÒº£¬ÔÙÓÃÐÔÖÊÎȶ¨¡¢Ïà¶Ô·Ö×ÓÖÊÁ¿½Ï´óµÄ»ù×¼ÎïÖʲÝËáÄÆ[Mr(Na2C2O4)£½134.0]¶Ô´ÖÅäµÄKMnO4ÈÜÒº½øÐб궨£¬²â³öËùÅäÖÆµÄKMnO4ÈÜÒºµÄ׼ȷŨ¶È£¬·´Ó¦Ô­ÀíΪ£º   C2O42£­£«MnO4£­£«H£«¡úCO2¡ü£«Mn2+£«H2O

ÒÔÏÂÊDZ궨KMnO4ÈÜÒºµÄʵÑé²½Ö裺

²½ÖèÒ»£ºÏÈ´ÖÅäŨ¶ÈԼΪ0.15mol?L-1µÄ¸ßÃÌËá¼ØÈÜÒº500 mL¡£

²½Öè¶þ£º×¼È·³ÆÈ¡Na2C2O4¹ÌÌåm g·ÅÈë×¶ÐÎÆ¿ÖУ¬ÓÃÕôÁóË®ÈܽⲢ¼ÓÏ¡ÁòËáËữ£¬¼ÓÈÈÖÁ70~80¡æ£¬Óò½ÖèÒ»ËùÅä¸ßÃÌËá¼ØÈÜÒº½øÐеζ¨¡£¼Ç¼Ïà¹ØÊý¾Ý¡£

²½ÖèÈý£º                                                        ¡£

²½ÖèËÄ£º¼ÆË㣬µÃ¸ßÃÌËá¼ØµÄÎïÖʵÄÁ¿Å¨¶È¡£ÊԻشðÏÂÁÐÎÊÌ⣺

£¨1£©Å䯽·´Ó¦·½³Ìʽ£º   C2O42£­£«   MnO4£­£«   H£«¡ú   CO2¡ü£«   Mn2+£«   H2O

£¨2£©¸ÃµÎ¶¨ÊµÑé              £¨¡°ÐèÒª¡±»ò¡°²»ÐèÒª¡±£©¼Óָʾ¼Á¡£

£¨3£©²½Öè¶þÖе樲Ù×÷ͼʾÕýÈ·µÄÊÇ__________£¨Ìî±àºÅ£©¡£

 

£¨4£©²½Öè¶þµÄµÎ¶¨¹ý³Ìζȱ仯²¢²»Ã÷ÏÔ£¬µ«²Ù×÷¹ý³ÌÖз¢ÏÖǰһ½×¶ÎÈÜÒºÍÊÉ«½ÏÂý£¬Öмä½×¶ÎÍÊÉ«Ã÷ÏÔ±ä¿ì£¬×îºó½×¶ÎÍÊÉ«ÓÖ±äÂý¡£ÊÔ¸ù¾ÝÓ°Ï컯ѧ·´Ó¦ËÙÂʵÄÌõ¼þ·ÖÎö£¬ÈÜÒºÍÊÉ«Ã÷ÏÔ±ä¿ìµÄÔ­Òò¿ÉÄÜÊÇ_________                 £¬×îºóÓÖ±äÂýµÄÔ­ÒòÊÇ           ¡£

£¨5£©Çëд³ö²½ÖèÈýµÄ²Ù×÷ÄÚÈÝ                                             ¡£

£¨6£©ÈômµÄƽ¾ùÊýֵΪ1.340g£¬µÎ¶¨µÄKMnO4ÈÜҺƽ¾ùÓÃÁ¿Îª25.00mL£¬ÔòKMnO4ÈÜÒºµÄŨ¶ÈΪ           mol?L-1¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸