Question

¡¾ÌâÄ¿¡¿»¯Ñ§¼ÆÁ¿ÔÚ»¯Ñ§ÖÐÕ¼ÓÐÖØÒªµØ룬Çë»Ø´ðÏÂÁÐÎÊÌâ¡£

£¨1£© 0.3molNH3·Ö×ÓÖÐËùº¬Ô­×ÓÊýÓë ¸öH2O·Ö×ÓÖÐËùº¬Ô­×ÓÊýÏàµÈ¡£

£¨2£©º¬0.4mol Al3+µÄAl2£¨SO4£© 3ÖÐËùº¬µÄSO42-µÄÎïÖʵÄÁ¿ÊÇ ¡£

£¨3£©ÒÑÖª16gAºÍ20gBÇ¡ºÃÍêÈ«·´Ó¦Éú³É0.04molCºÍ31.76gD£¬ÔòCµÄĦ¶ûÖÊÁ¿Îª ¡£

£¨4£©ÔÚÒ»¶¨µÄζȺÍѹǿÏ£¬1Ìå»ýÆøÌåX2¸ú3Ìå»ýÆøÌåY2»¯ºÏÉú³É2Ìå»ý»¯ºÏÎÔò¸Ã»¯ºÏÎïµÄ»¯Ñ§Ê½ÊÇ ¡£

£¨5£©Ä³ÑλìºÏÈÜÒºÖк¬ÓÐÀë×Ó£ºNa+¡¢Mg2+¡¢Cl-¡¢SO42-£¬²âµÃNa+¡¢Mg2+ºÍCI-µÄÎïÖʵÄÁ¿Å¨¶ÈÒÀ´ÎΪ£º0.2moI¡¤L-l¡¢0.25mol¡¤L-l¡¢0.4mol¡¤L-l£¬Ôòc £¨S O42-£©= ¡£

Answer 1

¡¾´ð°¸¡¿£¨1£©0.4NA»ò2.408¡Á1023£»£¨2£©0.6 mol£»

£¨3£©106 mol¡¤L£­1£»£¨4£©XY3»òY3X£»£¨5£©0.15 mol¡¤L£­1¡£

¡¾½âÎö¡¿

ÊÔÌâ·ÖÎö£º£¨1£©0.3molNH3Öк¬ÓÐÔ­×ÓÎïÖʵÄÁ¿Îª0.3¡Á4mol=1.2mol£¬Òò´ËË®µÄÎïÖʵÄÁ¿Îª1.2/3mol=0.4mol£¬¼´Ë®·Ö×ӵĸöÊýΪ0.4NA»ò2.408¡Á1023£»£¨2£©n£¨Al3£«£©£ºn£¨SO42£­£©=2£º3£¬Ôòn£¨SO42£­£©=0.4¡Á3/2mol=0.6mol£»£¨3£©¸ù¾ÝÖÊÁ¿Êغ㣬CµÄÖÊÁ¿Îª£¨16£«20£­31.76£©g=4.24g£¬Òò´ËCµÄĦ¶ûÖÊÁ¿Îª4.241/0.04g¡¤mol£­1=106g¡¤mol£­1£»£¨4£©·´Ó¦·½³ÌʽΪX2£«3Y2=2Z£¬¸ù¾ÝÔ­×ÓÊغãºÍÔªËØÊغ㣬Òò´ËZµÄ»¯Ñ§Ê½ÎªXY3»òY3X£»£¨5£©¸ù¾ÝµçºÉÊغ㣬c£¨Na£«£©£«2c£¨Mg2£«£©=c£¨Cl£­£©£«2c£¨SO42£­£©£¬c£¨SO42£­£©=[c£¨Na£«£©£«2c£¨Mg2£«£©£­c£¨Cl£­£©]/2=£¨0.2£«2¡Á0.25£­0.4£©/2mol¡¤L£­1=0.15mol¡¤L£­1¡£