ijѧϰС×éÓÃÏÂͼװÖòⶨÂÁþºÏ½ðÖÐÂÁµÄÖÊÁ¿·ÖÊýºÍÂÁµÄÏà¶ÔÔ­×ÓÖÊÁ¿¡£

£¨1£©AÖÐÊÔ¼ÁΪ______________¡£

£¨2£©ÊµÑéÇ°£¬ÏȽ«ÂÁþºÏ½ðÔÚÏ¡ËáÖнþÅÝƬ¿Ì£¬ÆäÄ¿µÄÊÇ____________________________¡£

£¨3£©¼ì²éÆøÃÜÐÔ£¬½«Ò©Æ·ºÍË®×°Èë¸÷ÒÇÆ÷ÖУ¬Á¬½ÓºÃ×°Öúó£¬Ðè½øÐеIJÙ×÷»¹ÓУº¢Ù¼Ç¼CµÄÒºÃæλÖ㻢ڽ«BÖÐÊ£Óà¹ÌÌå¹ýÂË¡¢Ï´µÓ¡¢¸ÉÔ³ÆÖØ£»¢Û´ýBÖв»ÔÙÓÐÆøÌå²úÉú²¢»Ö¸´ÖÁÊÒκ󣬼ǼCµÄÒºÃæλÖ㻢ÜÓÉAÏòBÖеμÓ×ãÁ¿ÊÔ¼Á£»¢Ý¼ì²éÆøÃÜÐÔ¡£ÉÏÊö²Ù×÷µÄ˳ÐòÊÇ___________£»£¨ÌîÐòºÅ£©¼Ç¼CµÄÒºÃæλÖÃʱ£¬³ýÊÓÏßƽÊÓÍ⣬»¹Ó¦_______________¡£

£¨4£©BÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_________________________________________________¡£

£¨5£©ÈôʵÑéÓÃÂÁþºÏ½ðµÄÖÊÁ¿Îªa g£¬²âµÃÇâÆøÌå»ýΪb mL£¨ÒÑ»»ËãΪ±ê×¼×´¿ö£©£¬BÖÐÊ£Óà¹ÌÌåµÄÖÊÁ¿Îªc g£¬ÔòÂÁµÄÏà¶ÔÔ­×ÓÖÊÁ¿Îª_______________¡£

£¨6£©ÊµÑé¹ý³ÌÖУ¬ÈôδϴµÓ¹ýÂËËùµÃµÄ²»ÈÜÎÔò²âµÃÂÁµÄÖÊÁ¿·ÖÊý½«________£¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±¡¢¡°²»ÊÜÓ°Ï족£©¡£

(1)NaOHÈÜÒº

(2)³ýÈ¥ÂÁþºÏ½ð±íÃæµÄÑõ»¯Ä¤

(3)¢Ý¢Ù¢Ü¢Û¢Ú  ʹDºÍCµÄÒºÃæÏàƽ

(4)2Al+2NaOH+2H2O2NaAlO2+3H2¡ü»ò2Al+2OH-+2H2O2+3H2¡ü

(5)

(6)ƫС

½âÎö£º£¨1£©¿É¸ù¾ÝMg¡¢AlÐÔÖʵIJ»Í¬µãÑ¡ÔñÊÔ¼Á£¬Al¿ÉÓëNaOHÈÜÒº·´Ó¦£¬¶øMg²»¿ÉÒÔ£¬¹ÊÑ¡ÔñNaOHÈÜÒº¡£

£¨2£©½«Ã¾ÂÁºÏ½ðÔÚÏ¡ËáÖнþÅÝƬ¿Ì£¬Ä¿µÄÊÇΪÁ˳ýÈ¥ºÏ½ð±íÃæµÄÑõ»¯Ä¤¡£

£¨3£©ÔÚʵÑéÇ°Ó¦¼ìÑé×°ÖÃÆøÃÜÐÔ£¬²¢¼Ç¼CÖÐÒºÃæλÖã¬ÔÙÓÉAÏòB.ÖмÓÈë×ãÁ¿NaOHÈÜÒº£¬Ö±µ½·´Ó¦½áÊø£¬²¢ÇÒ»Ö¸´µ½ÊÒΣ¬ÔٴμǼCÖÐÒºÃæλÖã¬×îºó½«Ê£Óà¹ÌÌåÏ´µÓ¡¢¸ÉÔï¡¢³ÆÖØ£¬¹Ê˳ÐòΪ¢Ý¢Ù¢Ü¢Û¢Ú£»¶ÁÊýʱ³ýÁËÊÓÏßƽÊÓÍ⣬»¹Òª×¢ÒâC¡¢DÁ½¹ÜÄÚÒºÃæÏàƽ£¬²»Òª²úÉúÒºÃæ²î£¬Ó°Ïì¶ÁÊý¡£

£¨4£©AlÓëNaOHÈÜÒº·¢Éú·´Ó¦£º2Al+2NaOH+2H2O2NaAlO2+3H2¡ü

»ò2Al+2OH-+2H2O2+3H2¡ü

£¨5£©m£¨Al£©=£¨a-c£©g£¬n£¨Al£©=n£¨H2£©=¡Á

AlµÄÏà¶ÔÔ­×ÓÖÊÁ¿Îª¡£

£¨6£©ÈôδϴµÓ¹ýÂËËùµÃ²»ÈÜÎ²âµÃcֵƫ´ó£¬m£¨Al£©=£¨a-c£© gƫС£¬ÔòAlµÄÏà¶ÔÔ­×ÓÖÊÁ¿ÖµÆ«Ð¡¡£


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÎÞË®ÂÈ»¯ÂÁ£¨AlCl3£©ÊÇ°×É«¾§Ì壬ÔÚ178¡æÉý»ª£¬Ò×ÎüÊÕË®·Ö£¬×°ÓÐÎÞË®ÂÈ»¯ÂÁµÄÊÔ¼ÁÆ¿¾ÃÖó±Êª¿ÕÆøÖУ¬»á×Ô¶¯±¬Õ¨²úÉú´óÁ¿°×Îí£¬ÂÈ»¯ÂÁ³£×÷ΪÓлúºÏ³ÉºÍʯÓ͹¤ÒµµÄ´ß»¯¼Á£®Ä³Ñ§Ï°Ð¡×éÓÃÏÂͼװÖÃÔÚʵÑéÊÒÖƱ¸ÎÞË®ÂÈ»¯ÂÁ£¬ÇëÄãÒ»Æð²ÎÓë¸ÃС×éµÄ»î¶¯£®

£¨1£©Ð´³ö×°ÖÃAÖз¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º
4H++2Cl-+MnO2
 ¼ÓÈÈ 
.
 
Cl2¡ü+2H2O+Mn2+
4H++2Cl-+MnO2
 ¼ÓÈÈ 
.
 
Cl2¡ü+2H2O+Mn2+
£®
£¨2£©×°ÖÃB¡¢CÖеÄÊÔ¼Á·Ö±ðΪ£º
±¥ºÍʳÑÎË®
±¥ºÍʳÑÎË®
¡¢
ŨÁòËá
ŨÁòËá
£®
£¨3£©ÊµÑ鿪ʼʱÏȵãȼ
A
A
´¦¾Æ¾«µÆ£¬×°ÖÃEµÄ×÷ÓÃΪ£º
ÊÕ¼¯ÂÈ»¯ÂÁ
ÊÕ¼¯ÂÈ»¯ÂÁ
£®
£¨4£©×°ÖÃFµÄ×÷ÓÃΪ£º
³ýȥδ·´Ó¦µÄÂÈÆø£»·ÀÖ¹¿ÕÆøÖеÄË®ÕôÆû½øÈëEÖÐ
³ýȥδ·´Ó¦µÄÂÈÆø£»·ÀÖ¹¿ÕÆøÖеÄË®ÕôÆû½øÈëEÖÐ
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨8·Ö£©Ä³Ñ§Ï°Ð¡×éÓÃÏÂͼװÖòⶨÂÁþºÏ½ðÖÐÂÁµÄÖÊÁ¿·ÖÊýºÍÂÁµÄÏà¶ÔÔ­×ÓÖÊÁ¿.

£¨Ìáʾ£ºÃ¾¡¢ÂÁ¾ùÓëËá·´Ó¦£¬ÂÁ»¹ÄܺͼӦ£º2Al+2NaOH+2H2O=2NaAlO2+3H2¡ü£©

ʵÑéÇ°£¬ÏȽ«ÂÁþºÏ½ðÔÚÏ¡ËáÖнþÅÝƬ¿Ì£¬ÆäÄ¿µÄÊdzýÈ¥ÂÁþºÏ½ð±íÃæµÄÑõ»¯Ä¤¡£

£¨1£©AÖÐÊÔ¼ÁΪ       .

£¨Ìî¡°NaOHÈÜÒº¡±»ò¡°Ï¡ÑÎËᡱ£©

£¨2£©¼ì²éÆøÃÜÐÔ£¬½«Ò©Æ·ºÍË®×°Èë¸÷ÒÇÆ÷ÖУ¬Á¬½ÓºÃ×°Öúó£¬Ðè½øÐеIJÙ×÷»¹ÓУº¢Ù¼Ç¼

CµÄÒºÃæλÖ㻢ڽ«BÖÐÊ£Óà¹ÌÌå¹ýÂË£¬Ï´µÓ£¬¸ÉÔ³ÆÖØ£»¢Û´ýBÖв»ÔÙÓÐÆøÌå²úÉú²¢»Ö¸´ÖÁÊÒΣ»¢ÜÓÉAÏòBÖеμÓ×ãÁ¿ÊÔ¼Á£»¢Ý¼ì²éÆøÃÜÐÔ£»¢Þµ÷ÕûÏð½ºÈí¹ÜʹDºÍCµÄÒºÃæÏàƽ¡£

ÉÏÊö²Ù×÷µÄ˳ÐòÊÇ          £»£¨ÌîÐòºÅ£©

£¨3£©BÖз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ                .

£¨4£©ÊµÑé¹ý³ÌÖУ¬ÈôδϴµÓ¹ýÂËËùµÃµÄ²»ÈÜÎÔò²âµÃÂÁµÄÖÊÁ¿·ÖÊý½«           .

£¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±¡¢¡°²»ÊÜÓ°Ï족£©

£¨5£©ÈôʵÑéÓÃÂÁþºÏ½ðµÄÖÊÁ¿Îªa g,²âµÃÇâÆøÌå»ýΪb ml£¨ÒÑ»»ËãΪ±ê×¼×´¿ö£©£¬BÖÐÊ£Óà¹ÌÌåµÄÖÊÁ¿Îªc g£¬ÔòÂÁµÄÏà¶ÔÔ­×ÓÖÊÁ¿Îª           .£¨Óú¬a¡¢b¡¢cµÄ´úÊýʽ±íʾ£©

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012½ìÉÂÎ÷Ê¡³¤°²Ò»ÖиßÈýÉÏѧÆÚµÚ¶þ´ÎÖÊÁ¿¼ì²â»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

£¨12·Ö£©Ä³Ñ§Ï°Ð¡×éÓÃÏÂͼװÖòⶨÂÁþºÏ½ðÖÐÂÁµÄÖÊÁ¿·ÖÊýºÍÂÁµÄÏà¶ÔÔ­×ÓÖÊÁ¿¡£

£¨1£©AÖÐÊÔ¼ÁΪ______________¡£
£¨2£©ÊµÑéÇ°£¬ÏȽ«ÂÁþºÏ½ðÔÚÏ¡ËáÖнþÅÝƬ¿Ì£¬ÆäÄ¿µÄÊÇ_________________________¡£
£¨3£©¼ì²éÆøÃÜÐÔ£¬½«Ò©Æ·ºÍË®×°Èë¸÷ÒÇÆ÷ÖУ¬Á¬½ÓºÃ×°Öúó£¬Ðè½øÐеIJÙ×÷»¹ÓУº¢Ù¼Ç¼CµÄÒºÃæλÖ㻢ڽ«BÖÐÊ£Óà¹ÌÌå¹ýÂË¡¢Ï´µÓ¡¢¸ÉÔ³ÆÖØ£»¢Û´ýBÖв»ÔÙÓÐÆøÌå²úÉú²¢»Ö¸´ÖÁÊÒκ󣬼ǼCµÄÒºÃæλÖ㻢ÜÓÉAÏòBÖеμÓ×ãÁ¿ÊÔ¼Á£»¢Ý¼ì²éÆøÃÜÐÔ¡£ÉÏÊö²Ù×÷µÄ˳ÐòÊÇ___________£»£¨ÌîÐòºÅ£©¼Ç¼CµÄÒºÃæλÖÃʱ£¬³ýÊÓÏßƽÊÓÍ⣬»¹Ó¦_______________¡£
£¨4£©BÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____________________________________________¡£
£¨5£©ÈôʵÑéÓÃÂÁþºÏ½ðµÄÖÊÁ¿Îªa g£¬²âµÃÇâÆøÌå»ýΪb mL£¨ÒÑ»»ËãΪ±ê×¼×´¿ö£©£¬BÖÐÊ£Óà¹ÌÌåµÄÖÊÁ¿Îªc g£¬ÔòÂÁµÄÏà¶ÔÔ­×ÓÖÊÁ¿Îª_______________¡£
£¨6£©ÊµÑé¹ý³ÌÖУ¬ÈôδϴµÓ¹ýÂËËùµÃµÄ²»ÈÜÎÔò²âµÃÂÁµÄÖÊÁ¿·ÖÊý½«________£¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±¡¢¡°²»ÊÜÓ°Ï족£©¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ÄêÁÉÄþÊ¡¿ªÔ­¸ßÖиßÒ»ÉÏѧÆÚµÚÒ»´Î¿¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

£¨8·Ö£©Ä³Ñ§Ï°Ð¡×éÓÃÏÂͼװÖòⶨÂÁþºÏ½ðÖÐÂÁµÄÖÊÁ¿·ÖÊýºÍÂÁµÄÏà¶ÔÔ­×ÓÖÊÁ¿.

£¨Ìáʾ£ºÃ¾¡¢ÂÁ¾ùÓëËá·´Ó¦£¬ÂÁ»¹ÄܺͼӦ£º2Al+2NaOH+2H2O=2NaAlO2+3H2¡ü£©
ʵÑéÇ°£¬ÏȽ«ÂÁþºÏ½ðÔÚÏ¡ËáÖнþÅÝƬ¿Ì£¬ÆäÄ¿µÄÊdzýÈ¥ÂÁþºÏ½ð±íÃæµÄÑõ»¯Ä¤¡£
£¨1£©AÖÐÊÔ¼ÁΪ      .
£¨Ìî¡°NaOHÈÜÒº¡±»ò¡°Ï¡ÑÎËᡱ£©
£¨2£©¼ì²éÆøÃÜÐÔ£¬½«Ò©Æ·ºÍË®×°Èë¸÷ÒÇÆ÷ÖУ¬Á¬½ÓºÃ×°Öúó£¬Ðè½øÐеIJÙ×÷»¹ÓУº¢Ù¼Ç¼
CµÄÒºÃæλÖ㻢ڽ«BÖÐÊ£Óà¹ÌÌå¹ýÂË£¬Ï´µÓ£¬¸ÉÔ³ÆÖØ£»¢Û´ýBÖв»ÔÙÓÐÆøÌå²úÉú²¢»Ö¸´ÖÁÊÒΣ»¢ÜÓÉAÏòBÖеμÓ×ãÁ¿ÊÔ¼Á£»¢Ý¼ì²éÆøÃÜÐÔ£»¢Þµ÷ÕûÏð½ºÈí¹ÜʹDºÍCµÄÒºÃæÏàƽ¡£
ÉÏÊö²Ù×÷µÄ˳ÐòÊÇ          £»£¨ÌîÐòºÅ£©
£¨3£©BÖз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ                 .
£¨4£©ÊµÑé¹ý³ÌÖУ¬ÈôδϴµÓ¹ýÂËËùµÃµÄ²»ÈÜÎÔò²âµÃÂÁµÄÖÊÁ¿·ÖÊý½«           .
£¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±¡¢¡°²»ÊÜÓ°Ï족£©
£¨5£©ÈôʵÑéÓÃÂÁþºÏ½ðµÄÖÊÁ¿Îªa g,²âµÃÇâÆøÌå»ýΪb ml£¨ÒÑ»»ËãΪ±ê×¼×´¿ö£©£¬BÖÐÊ£Óà¹ÌÌåµÄÖÊÁ¿Îªc g£¬ÔòÂÁµÄÏà¶ÔÔ­×ÓÖÊÁ¿Îª          .£¨Óú¬a¡¢b¡¢cµÄ´úÊýʽ±íʾ£©

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸