5£®¾ßÓÐË®¹ûÏãζµÄÖÐÐÔÎïÖÊA¿ÉÒÔ·¢ÉúÏÂÁб仯£º
£¨1£©ÆäÖеÄÈõËáÊÇCH3COOH£¬GµÄ½á¹¹¼òʽΪCH2=CH2
£¨2£©Ð´³öÏÂÁб仯µÄ·½³Ìʽ£º
A+NaOH¡úB+CµÄ»¯Ñ§·½³Ìʽ£ºCH3COOCH2CH3+NaOH$\stackrel{¡÷}{¡ú}$CH3COONa+CH3CH2OH
C¡úDµÄ»¯Ñ§·½³Ìʽ£º2C2H5OH+O2$¡ú_{¡÷}^{Í­»òÒø}$2CH3CHO+2H2O
DµÄÒø¾µ·´Ó¦µÄÀë×Ó·½³Ìʽ£ºCH3CHO+2Ag£¨NH3£©2++2OH-$\stackrel{ˮԡ}{¡ú}$CH3COO-+NH4++2Ag¡ý+3NH3+H2O£®

·ÖÎö ¾ßÓÐË®¹ûÏãζµÄÖÐÐÔÎïÖÊAÄÜ·¢ÉúË®½â·´Ó¦Éú³ÉB¡¢C£¬BºÍÁòËá·´Ó¦Éú³ÉÒ»ÖÖÈõËᣬÔòBÊÇôÈËáÄÆ£¬CÊÇ´¼£¬C±»Ñõ»¯Éú³ÉD£¬DÄÜ·¢ÉúÒø¾µ·´Ó¦£¬ÔòDΪȩ£¬D±»Ñõ»¯Éú³ÉôÈËáE£¬EºÍÇâÑõ»¯ÄÆ·´Ó¦Éú³ÉôÈËáÄÆB£¬ÔòôÈËáºÍ´¼·Ö×ÓÖÐCÔ­×ÓÏàµÈ£¬C·¢ÉúÏûÈ¥·´Ó¦Éú³ÉG£¬GºÍäå·¢Éú¼Ó³É·´Ó¦Éú³É1£¬2-¶þäåÒÒÍ飬ÔòG½á¹¹¼òʽΪCH2=CH2¡¢C½á¹¹¼òʽΪCH3CH2OH¡¢DΪCH3CHO¡¢EΪCH3COOH¡¢BΪCH3COONa¡¢AΪCH3COOCH2CH3£¬¾Ý´Ë·ÖÎö½â´ð£®

½â´ð ½â£º¾ßÓÐË®¹ûÏãζµÄÖÐÐÔÎïÖÊAÄÜ·¢ÉúË®½â·´Ó¦Éú³ÉB¡¢C£¬BºÍÁòËá·´Ó¦Éú³ÉÒ»ÖÖÈõËᣬÔòBÊÇôÈËáÄÆ£¬CÊÇ´¼£¬C±»Ñõ»¯Éú³ÉD£¬DÄÜ·¢ÉúÒø¾µ·´Ó¦£¬ÔòDΪȩ£¬D±»Ñõ»¯Éú³ÉôÈËáE£¬EºÍÇâÑõ»¯ÄÆ·´Ó¦Éú³ÉôÈËáÄÆB£¬ÔòôÈËáºÍ´¼·Ö×ÓÖÐCÔ­×ÓÏàµÈ£¬C·¢ÉúÏûÈ¥·´Ó¦Éú³ÉG£¬GºÍäå·¢Éú¼Ó³É·´Ó¦Éú³É1£¬2-¶þäåÒÒÍ飬ÔòG½á¹¹¼òʽΪCH2=CH2¡¢C½á¹¹¼òʽΪCH3CH2OH¡¢DΪCH3CHO¡¢EΪCH3COOH¡¢BΪCH3COONa¡¢AΪCH3COOCH2CH3£¬
£¨1£©Í¨¹ýÒÔÉÏ·ÖÎöÖª£¬ÆäÖеÄÈõËáÊÇCH3COOH£¬GµÄ½á¹¹¼òʽΪCH2=CH2£¬
¹Ê´ð°¸Îª£ºCH3COOH£»CH2=CH2£»
£¨2£©AÊÇÒÒËáÒÒõ¥£¬AºÍÇâÑõ»¯ÄƵķ´Ó¦·½³ÌʽΪCH3COOCH2CH3+NaOH$\stackrel{¡÷}{¡ú}$CH3COONa+CH3CH2OH£¬C¡úDµÄ»¯Ñ§·½³ÌʽΪ2C2H5OH+O2$¡ú_{¡÷}^{Í­»òÒø}$2CH3CHO+2H2O£¬DΪCH3CHO£¬DµÄÒø¾µ·´Ó¦µÄÀë×Ó·½³ÌʽΪCH3CHO+2Ag£¨NH3£©2++2OH- $\stackrel{ˮԡ}{¡ú}$ CH3COO-+NH4++2Ag¡ý+3NH3+H2O£¬
¹Ê´ð°¸Îª£ºCH3COOCH2CH3+NaOH$\stackrel{¡÷}{¡ú}$CH3COONa+CH3CH2OH£»2C2H5OH+O2$¡ú_{¡÷}^{Í­»òÒø}$2CH3CHO+2H2O£»CH3CHO+2Ag£¨NH3£©2++2OH- $\stackrel{ˮԡ}{¡ú}$ CH3COO-+NH4++2Ag¡ý+3NH3+H2O£®

µãÆÀ ±¾Ì⿼²éÓлúÎïÍÆ¶Ï£¬²àÖØ¿¼²é·ÖÎöÍÆ¶ÏÄÜÁ¦£¬Éæ¼°´¼¡¢È©¡¢ôÈËá¡¢õ¥Ö®¼äµÄת»¯£¬¸ù¾Ý·´Ó¦Ìõ¼þÈ·¶¨ÎïÖʾßÓеĹÙÄÜÍż°Æä½á¹¹£¬ÊìÁ·ÕÆÎÕ³£¼ûÓлú·´Ó¦ÀàÐÍ£¬ÌâÄ¿ÄѶȲ»´ó£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

15£®ÅÝÄ­Ãð»ðÆ÷ÄÚº¬ÓÐNaHCO3ŨÈÜÒººÍŨµÄAl2£¨SO4£©3ÈÜÒº£¬Ê¹ÓÃʱ°ÑÃð»ðÆ÷µ¹Öü´ÓÐÅÝÄ­Åç³öÃð»ð£¬¸Ã¹ý³ÌÖз¢ÉúµÄ·´Ó¦ÎªAl3++3HCO3-=Al£¨OH£©3¡ý+3CO2¡ü£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

16£®ÔÚÒ»¶¨Î¶ÈÏ£¬ÏòÒ»¸ö2LµÄÕæ¿ÕÃܱÕÈÝÆ÷ÖУ¨Ô¤ÏÈ×°Èë´ß»¯¼Á£©Í¨Èë1mol N2ºÍ3mol H2£¬¾­¹ýÒ»¶Îʱ¼äºó£¬²âµÃÈÝÆ÷ÄÚѹǿÓëÆðʼʱµÄѹǿ֮±ÈΪ9£º10£®ÔÚ´Ëʱ¼äÄÚH2µÄƽ¾ù·´Ó¦ËÙÂÊΪ0.1mol•£¨L•min£©-1£¬Ôò¾­¹ýʱ¼äΪ£¨¡¡¡¡£©
A£®2 minB£®3 minC£®4 minD£®5 min

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

13£®µª»¯ÂÁ£¨AlN£©¾ßÓÐÄ͸ßΡ¢¿¹³å»÷¡¢µ¼ÈÈÐԺõÈÓÅÁ¼ÐÔÖÊ£¬±»¹ã·ºÓÃÓÚµç×Ó¹¤Òµ¡¢Ìմɹ¤ÒµµÈÁìÓò£®ÔÚÒ»¶¨Ìõ¼þÏ£¬µª»¯ÂÁ¿Éͨ¹ý·´Ó¦ Al2O3+N2+3C¨T2AlN+3COºÏ³É£¬ÏÂÁÐÐðÊöÕýÈ·ÊÇ£¨¡¡¡¡£©
A£®·´Ó¦ÖУ¬N2ÊÇ»¹Ô­¼Á£¬Al2O3ÊÇÑõ»¯¼Á
B£®·´Ó¦ÖУ¬Ã¿Éú³É2 mol AlN£¬N2µÃµ½3 molµç×Ó
C£®µª»¯ÂÁÖеªÔªËصϝºÏ¼ÛΪ-3
D£®AlNµÄĦ¶ûÖÊÁ¿Îª41g

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

20£®¸ù¾ÝʵÑéÄ¿µÄÅжÏÏÂÁÐʵÑé²Ù×÷»ò×°ÖÃÕýÈ·µÄÊÇ£¨¡¡¡¡£©
Ñ¡ÏîABCD
Ä¿µÄʵÑéÊÒÖÆO2ÅäÖÃÏ¡ÁòËáÈÜÒºÔÚÌúÖÆÆ·É϶ÆÍ­¼ì²é×°ÖÃÆøÃÜÐÔ
×°Öûò²Ù×÷
A£®AB£®BC£®CD£®D

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

10£®ÏÂÁвÙ×÷´ï²»µ½Ô¤ÆÚÄ¿µÄÊÇ£¨¡¡¡¡£©
¢ÙʯÓÍ·ÖÁóʱ°ÑζȼƲåÈëÊÜÈȵÄÒºÌåÖР 
¢ÚÓñ¥ºÍ̼ËáÄÆÈÜÒº³ýÈ¥ÒÒËáÒÒõ¥ÖлìÓеÄÒÒ´¼¡¢ÒÒËᣮ
¢ÛÓÃËáÐÔ¸ßÃÌËá¼ØÈÜÒº³ýÈ¥ÒÒȲÖеÄÒÒÏ©
¢Ü½«±½ºÍäåË®»ìºÏºó¼ÓÈëÌú·ÛÖÆÈ¡äå±½£®
A£®Ö»ÓТÙB£®Ö»ÓТ٢ۢÜC£®Ö»ÓТ٢ڢÛD£®¢Ù¢Ú¢Û¢Ü

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

5£®Ìú¶¤ÈÜÓÚÏ¡ÑÎËáºó£¬¼ÓÈë¹ýÁ¿ÇâÑõ»¯ÄÆÈÜÒº£¬È»ºó·ÅÖÃÓÚ¿ÕÆøÖÐÒ»¶Îʱ¼ä£¬´ËʱÌúµÄ´æÔÚÐÎʽΪ£¨¡¡¡¡£©
A£®Fe£¨OH£©3B£®Fe£¨OH£©2C£®FeCl2D£®FeCl3

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

2£®¸ù¾ÝÏÂÁм¸ÖÖÎïÖʵÄÈÛµãºÍ·ÐµãÊý¾Ý£¬ÅжÏÏÂÁÐÓйØËµ·¨ÖУ¬´íÎóµÄÊÇ£¨¡¡¡¡£©£¨×¢£ºAlCl3ÈÛµãÔÚ2.02¡Á105PaÌõ¼þϲⶨ£©
NaClMgCl2AlCl3SiCl4µ¥ÖÊB
ÈÛµã/¡æ810710190-682300
·Ðµã/¡æ14651418182.7572500
A£®SiCl4ÊÇ·Ö×Ó¾§ÌåB£®MgCl2Ëùº¬Àë×Ó¼üµÄÇ¿¶È±ÈNaCl´ó
C£®AlCl3¼ÓÈÈÄÜÉý»ªD£®µ¥ÖÊBÊÇÔ­×Ó¾§Ìå

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

3£®ÈçͼÊDz¿·Ö¶ÌÖÜÆÚÔªËØÔ­×Ó°ë¾¶ÓëÔ­×ÓÐòÊýµÄ¹ØÏµÍ¼£¬ÏÂÁÐ˵·¨´íÎóµÄÊÇ£¨¡¡¡¡£©
A£®QX2¡¢RX2¶¼ÓÐɱ¾úÏû¶¾µÄ×÷Ó㬶þÕß³£ÓÃÓÚ×ÔÀ´Ë®Ïû¶¾
B£®¼òµ¥Àë×ӵİ뾶£ºX£¾Y£¾Z
C£®Y¡¢Z¡¢R¶ÔÓ¦µÄ×î¸ßÑõ»¯ÎïÏ໥֮¼ä¿ÉÒÔ·¢Éú·´Ó¦
D£®µç½âÈÛÈÚµÄXÓëZ¹¹³ÉµÄ»¯ºÏÎï¿ÉÒԵõ½µ¥ÖÊZ

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸