ÈôÅäÖÆ500 mL 0£®2 mol/LµÄÏ¡ÁòËá
£¨1£©ÐèÒªÁ¿È¡ÖÊÁ¿·ÖÊýΪ98%µÄÁòËᣨÃܶÈΪ1£®84 g¡¤mL-1£©_____________mL¡£
£¨2£©ÏÂÃæÊÇijѧÉúµÄ²Ù×÷¹ý³Ì£º
a£®¼ì²éÈÝÁ¿Æ¿ÊÇ·ñ©ˮ£»
b£®ÓÃ100 mLµÄÁ¿Í²Á¿È¡Å¨ÁòË᣻
c£®½«Å¨ÁòËáµ¹ÈëÁíÒ»¸öÊ¢ÓÐÊÊÁ¿ÕôÁóË®µÄÁ¿Í²ÖÐÏ¡ÊÍ£¬²¢ÀäÈ´µ½ÊÒΣ»
d£®Óò£Á§°ôÒýÁ÷£¬½«Ï¡ÊͺóµÄÁòËáµ¹Èë500 mLµÄÈÝÁ¿Æ¿£»
e£®ÇáÇáÒ¡¶¯ÈÝÁ¿Æ¿£¬Ê¹Æ¿ÄÚÒºÌå»ìºÏ¾ùÔÈ£¬ÔÙÏòÈÝÁ¿Æ¿ÖмÓË®ÖÁÀë¿Ì¶ÈÏß1 cm¡«2 cm£»
f£®ÓýºÍ·µÎ¹Ü¼ÓË®ÖÁ°¼ÒºÃæµ×²¿Óë¿Ì¶ÈÏßÏàÇУ¬Ò¡ÔÈ£»
g£®ÔÚÈÝÁ¿Æ¿ÉÏÌùÉϱêÇ©´ýÓá£
°´ÕÕͨ³£µÄÅäÖÆÒªÇó£¬Ö¸³öÆäÖÐȱÉÙ»ò²Ù×÷µÄ´íÎ󣬲¢²¹³ä»ò¸ÄÕý£¨Óм¸ÏîÌÏÈô¿Õ¸ñ²»¹»¿ÉÒÔ²¹¼Ó£©¡£
¢Ù_________________________________£»
¢Ú_________________________________£»
¢Û_________________________________£»
¢Ü_________________________________£»
¢Ý_________________________________¡£
£¨3£©ÈκÎʵÑé¶¼ÓÐÎó²î£¬ÔÚÄã¸ÄÕýºóµÄ²Ù×÷ÖУ¬²úÉúÎó²îµÄÔ­Òò»¹ÓÐ_________________¡£
£¨4£©±¾ÊµÑé×îÀË·Ñʱ¼äµÄ²½ÖèÊǽ«Ï¡ÊͺóµÄÁòËáÀäÈ´µ½ÊÒΣ¬ÎªÁ˽ÚԼʱ¼ä£¬¼ò±ãÒ×ÐеļӿìÏ¡ÁòËáÀäÈ´µÄ·½·¨ÊÇ______________________________________¡£
£¨1£©5.4
£¨2£©¢ÙȱÉÙÏ´µÓÉÕ±­ºÍ²£Á§°ôµÄ²Ù×÷£»¢ÚÁ¿Í²µÄ¹æ¸ñ´í£¬Ó¦¸ÃÓÃ10mLµÄÁ¿Í²Á¿È¡Å¨H2SO4£¨»òÓÃÒÆÒº¹Ü¡¢ËáʽµÎ¶¨¹ÜÁ¿È¡Å¨H2SO4£©£»¢Û²»Ó¦¸ÃÔÚÁ¿Í²ÖÐÏ¡ÊÍŨH2SO4£¬Ó¦ÓÃÉÕ±­£»¢Ü²»Ó¦¸ÃÓÃÈÝÁ¿Æ¿±£´æÈÜÒº£¬Ó¦ÓÃϸ¿ÚÆ¿
£¨3£©Á¿Í²µÄ¾«È·¶È²»¹»¸ß£¨»ò¶ÁÊýÎó²î£¬ÈÜÖÊÈÔÓÐÉÙÁ¿²ÐÁôÔÚÉÕ±­ÄÚ¡¢ÊÒÎÂδ±ØÊÇ20¡æµÈ£©£¨´ð°¸ºÏÀí¼´¿É£©
£¨4£©³ä·Ö½Á°è£¨¸øÊ¢ÓÐÏ¡H2SO4µÄÉÕ±­·ó±ù¿éµÈ£©£¨´ð°¸ºÏÀí¼´¿É£©
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

һС¿éÄÆÂ¶ÖÃÔÚ¿ÕÆøÖУ¬¿É¹Û²ìµ½ÈçÏÂÏÖÏó(a¡«f´ú±í¶ÔÓ¦µÄÎïÖÊ)£º

     

ÊԻشðÒÔÏÂÎÊÌ⣺

(1)ÒÔÉϱ仯ÊôÓÚÎïÀí±ä»¯µÄÊÇ______(´Ó¢Ù¢Ú¢Û¢Ü¢ÝÖÐÑ¡ÔñÌîд)£¬ÕâÒ»ÏÖÏóÔÚ»¯Ñ§ÉϳÆÖ®Îª______¡£

(2)Á½ÖÖ»òÁ½ÖÖÒÔÉϵķ´Ó¦ÎïÉú³ÉÒ»ÖÖÉú³ÉÎïµÄ·´Ó¦½Ð»¯ºÏ·´Ó¦¡£ÒÔÉÏ»¯Ñ§±ä»¯ÊôÓÚ»¯ºÏ·´Ó¦µÄÊÇ______¡£(´Ó¢Ù¢Ú¢Û¢Ü¢ÝÖÐÑ¡ÔñÌîд)

(3)Ϊ֤Ã÷µÚ¢Ü²½ÒÑ·¢Éú£¬ÈçºÎÓÃʵÑé·½·¨Ö¤Ã÷¡£¼òÒªÐðÊöʵÑé·½·¨ºÍÏÖÏó

__________________________________£¬ÓйصĻ¯Ñ§·½³ÌʽÊÇ

__________________________¡£

(4)ÈôÅäÖÆ500 mL 1 mol¡¤L£­1µÄfÈÜÒº£¬³ÆÈ¡53.0 gÎïÖÊe£¬ÔòµÃµ½µÄÈÜҺŨ¶È______(´óÓÚ¡¢Ð¡ÓÚ»òµÈÓÚ)1 mol¡¤L£­1¡£ËùÓõIJ£Á§ÒÇÆ÷ÓÐÉÕ±­¡¢______¡¢______ºÍ______¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(12·Ö)һС¿éÄÆÂ¶ÖÃÔÚ¿ÕÆøÖУ¬¿É¹Û²ìµ½ÈçÏÂÏÖÏó(a¡«f´ú±í¶ÔÓ¦µÄÎïÖÊ)£º

     

ÊԻشðÒÔÏÂÎÊÌ⣺

(1)ÒÔÉϱ仯ÊôÓÚÎïÀí±ä»¯µÄÊÇ______(´Ó¢Ù¢Ú¢Û¢Ü¢ÝÖÐÑ¡ÔñÌîд)£¬ÕâÒ»ÏÖÏóÔÚ»¯Ñ§ÉϳÆÖ®Îª______¡£

(2)Á½ÖÖ»òÁ½ÖÖÒÔÉϵķ´Ó¦ÎïÉú³ÉÒ»ÖÖÉú³ÉÎïµÄ·´Ó¦½Ð»¯ºÏ·´Ó¦¡£ÒÔÉÏ»¯Ñ§±ä»¯ÊôÓÚ»¯ºÏ·´Ó¦µÄÊÇ______¡£(´Ó¢Ù¢Ú¢Û¢Ü¢ÝÖÐÑ¡ÔñÌîд)

(3)Ϊ֤Ã÷µÚ¢Ü²½ÒÑ·¢Éú£¬ÈçºÎÓÃʵÑé·½·¨Ö¤Ã÷¡£¼òÒªÐðÊöʵÑé·½·¨ºÍÏÖÏó

__________________________________£¬ÓйصĻ¯Ñ§·½³ÌʽÊÇ

__________________________¡£

(4)ÈôÅäÖÆ500 mL 1 mol¡¤L£­1µÄfÈÜÒº£¬³ÆÈ¡53.0 gÎïÖÊe£¬ÔòµÃµ½µÄÈÜҺŨ¶È______(´óÓÚ¡¢Ð¡ÓÚ»òµÈÓÚ)1 mol¡¤L£­1¡£ËùÓõIJ£Á§ÒÇÆ÷ÓÐÉÕ±­¡¢______¡¢______ºÍ______¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010Äê½­ËÕÊ¡º£°²ÏØÄÏĪÖÐѧ¸ßÒ»ÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

ÈôÅäÖÆ500 mL 0.2 mol/LµÄÏ¡ÁòË᣺
£¨1£©ÐèÒªÁ¿È¡ÖÊÁ¿·ÖÊýΪ98%µÄÁòËᣨÃܶÈΪ1.84 g¡¤mL-1£©_____________mL¡£
£¨2£©ÏÂÃæÊÇijѧÉúµÄ²Ù×÷¹ý³Ì£º
a.¼ì²éÈÝÁ¿Æ¿ÊÇ·ñ©ˮ£»b.ÓÃ100 mLµÄÁ¿Í²Á¿È¡Å¨ÁòË᣻
c.½«Å¨ÁòËáµ¹ÈëÁíÒ»¸öÊ¢ÓÐÊÊÁ¿ÕôÁóË®µÄÁ¿Í²ÖÐÏ¡ÊÍ£¬²¢ÀäÈ´µ½ÊÒΣ»
d.Óò£Á§°ôÒýÁ÷£¬½«Ï¡ÊͺóµÄÁòËáµ¹Èë500 mLµÄÈÝÁ¿Æ¿£»
e.ÇáÇáÒ¡¶¯ÈÝÁ¿Æ¿£¬Ê¹Æ¿ÄÚÒºÌå»ìºÏ¾ùÔÈ£¬ÔÙÏòÈÝÁ¿Æ¿ÖмÓË®ÖÁÀë¿Ì¶ÈÏß1 cm¡«2 cm;
f.ÓýºÍ·µÎ¹Ü¼ÓË®ÖÁ°¼ÒºÃæµ×²¿Óë¿Ì¶ÈÏßÏàÇУ¬Ò¡ÔÈ£»
g.ÔÚÈÝÁ¿Æ¿ÉÏÌùÉϱêÇ©´ýÓá£
°´ÕÕͨ³£µÄÅäÖÆÒªÇó£¬Ö¸³öÆäÖÐȱÉÙ»ò²Ù×÷µÄ´íÎ󣬲¢²¹³ä»ò¸ÄÕý£¨Óм¸ÏîÌÏÈô¿Õ¸ñ²»¹»¿ÉÒÔ²¹¼Ó£©¡£
¢Ù________________________________________________________£»
¢Ú________________________________________________________£»
¢Û________________________________________________________£»
¢Ü________________________________________________________£»
¢Ý________________________________________________________¡£
£¨3£©ÈκÎʵÑé¶¼ÓÐÎó²î£¬ÔÚÄã¸ÄÕýºóµÄ²Ù×÷ÖУ¬²úÉúÎó²îµÄÔ­Òò»¹ÓÐ_________________¡££¨4£©±¾ÊµÑé×îÀË·Ñʱ¼äµÄ²½ÖèÊǽ«Ï¡ÊͺóµÄÁòËáÀäÈ´µ½ÊÒΣ¬ÎªÁ˽ÚԼʱ¼ä£¬¼ò±ãÒ×ÐеļӿìÏ¡ÁòËáÀäÈ´µÄ·½·¨ÊÇ_______________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÂ³µÚ1ÕÂÈÏʶ»¯Ñ§¿ÆÑ§Á·Ï° ÌâÐÍ£ºÊµÑéÌâ

(12·Ö)һС¿éÄÆÂ¶ÖÃÔÚ¿ÕÆøÖУ¬¿É¹Û²ìµ½ÈçÏÂÏÖÏó(a¡«f´ú±í¶ÔÓ¦µÄÎïÖÊ)£º
ÊԻشðÒÔÏÂÎÊÌ⣺
(1)ÒÔÉϱ仯ÊôÓÚÎïÀí±ä»¯µÄÊÇ______(´Ó¢Ù¢Ú¢Û¢Ü¢ÝÖÐÑ¡ÔñÌîд)£¬ÕâÒ»ÏÖÏóÔÚ»¯Ñ§ÉϳÆÖ®Îª______¡£
(2)Á½ÖÖ»òÁ½ÖÖÒÔÉϵķ´Ó¦ÎïÉú³ÉÒ»ÖÖÉú³ÉÎïµÄ·´Ó¦½Ð»¯ºÏ·´Ó¦¡£ÒÔÉÏ»¯Ñ§±ä»¯ÊôÓÚ»¯ºÏ·´Ó¦µÄÊÇ______¡£(´Ó¢Ù¢Ú¢Û¢Ü¢ÝÖÐÑ¡ÔñÌîд)
(3)Ϊ֤Ã÷µÚ¢Ü²½ÒÑ·¢Éú£¬ÈçºÎÓÃʵÑé·½·¨Ö¤Ã÷¡£¼òÒªÐðÊöʵÑé·½·¨ºÍÏÖÏó
__________________________________£¬ÓйصĻ¯Ñ§·½³ÌʽÊÇ
__________________________¡£
(4)ÈôÅäÖÆ500 mL 1 mol¡¤L£­1µÄfÈÜÒº£¬³ÆÈ¡53.0 gÎïÖÊe£¬ÔòµÃµ½µÄÈÜҺŨ¶È______(´óÓÚ¡¢Ð¡ÓÚ»òµÈÓÚ)1 mol¡¤L£­1¡£ËùÓõIJ£Á§ÒÇÆ÷ÓÐÉÕ±­¡¢______¡¢______ºÍ______¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÂ³µÚ1ÕÂÈÏʶ»¯Ñ§¿ÆÑ§Á·Ï° ÌâÐÍ£ºÆäËü

(12·Ö)һС¿éÄÆÂ¶ÖÃÔÚ¿ÕÆøÖУ¬¿É¹Û²ìµ½ÈçÏÂÏÖÏó(a¡«f´ú±í¶ÔÓ¦µÄÎïÖÊ)£º

     

ÊԻشðÒÔÏÂÎÊÌ⣺

(1)ÒÔÉϱ仯ÊôÓÚÎïÀí±ä»¯µÄÊÇ______(´Ó¢Ù¢Ú¢Û¢Ü¢ÝÖÐÑ¡ÔñÌîд)£¬ÕâÒ»ÏÖÏóÔÚ»¯Ñ§ÉϳÆÖ®Îª______¡£

(2)Á½ÖÖ»òÁ½ÖÖÒÔÉϵķ´Ó¦ÎïÉú³ÉÒ»ÖÖÉú³ÉÎïµÄ·´Ó¦½Ð»¯ºÏ·´Ó¦¡£ÒÔÉÏ»¯Ñ§±ä»¯ÊôÓÚ»¯ºÏ·´Ó¦µÄÊÇ______¡£(´Ó¢Ù¢Ú¢Û¢Ü¢ÝÖÐÑ¡ÔñÌîд)

(3)Ϊ֤Ã÷µÚ¢Ü²½ÒÑ·¢Éú£¬ÈçºÎÓÃʵÑé·½·¨Ö¤Ã÷¡£¼òÒªÐðÊöʵÑé·½·¨ºÍÏÖÏó

__________________________________£¬ÓйصĻ¯Ñ§·½³ÌʽÊÇ

__________________________¡£

(4)ÈôÅäÖÆ500 mL 1 mol¡¤L£­1µÄfÈÜÒº£¬³ÆÈ¡53.0 gÎïÖÊe£¬ÔòµÃµ½µÄÈÜҺŨ¶È______(´óÓÚ¡¢Ð¡ÓÚ»òµÈÓÚ)1 mol¡¤L£­1¡£ËùÓõIJ£Á§ÒÇÆ÷ÓÐÉÕ±­¡¢______¡¢______ºÍ______¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸