(14·Ö)¸ßÃÌËá¼ØË׳ÆPP·Û£¬ÎªÇ¿Ñõ»¯¼Á£¬Óöµ½ÓлúÎï¾Í·Å³ö»îÐÔÑõ¡£ÕâÖÖÑõÓÐɱÃðϸ¾úµÄ×÷Óã¬ÇÒɱ¾úÄÜÁ¦¼«Ç¿¡£Ä³Ñ§ÉúÓûÔÚʵÑéÊÒÅäÖÆ1 L 0.06 mol/L KMnO4Ï¡ÈÜÒº£¬ÓÃÀ´ÇåÏ´ÉË¿Ú¡£
(1)ʵÑé¹ý³ÌÖÐÐèÓÃÍÐÅÌÌìƽ³ÆÈ¡KMnO4¾§ÌåµÄÖÊÁ¿Îª__________g¡£
(2)Æä²Ù×÷²½ÖèÈçÏÂͼËùʾ£¬ÔòÓÒͼËùʾ²Ù×÷Ó¦ÔÚÏÂͼÖÐ__________(ÌîÑ¡Ïî×Öĸ)Ö®¼ä¡£
A£®¢ÚÓë¢Û¡¡¡¡B£®¢ÙÓë¢Ú¡¡¡¡C£®¢ÜÓë¢Ý
(3) ÅäÖƹý³ÌÖÐÐèÒªÓõ½µÄÒÇÆ÷ÓÐ:ÍÐÅÌÌìƽ¡¢Ò©³×¡¢ÉÕ±¡¢ ¡¢ ¡¢
(4)Èô¸ÃͬѧÔÚÅäÖÆÈÜҺʱ£¬½øÐÐÁËÈçϲÙ×÷£¬ÆäÖÐʹËùÅäÈÜҺŨ¶ÈÆ«µÍµÄ²Ù×÷
ÓÐ_______________(ÌîÑ¡Ïî×Öĸ)¡£
A£®³ÆÁ¿KMnO4¾§Ìåʱ£¬Ö¸ÕëÆ«ÏòÓÒ±ß
B£®½«KMnO4¾§Ìå·ÅÔÚÉÕ±ÖÐÈܽ⣬ÀäÈ´ºó£¬×ªÒÆÖÁº¬ÓÐÉÙÁ¿ÕôÁóË®µÄÈÝÁ¿Æ¿ÖÐ
C£®¶¨ÈÝʱ£¬ÑöÊӿ̶ÈÏß
D£®Õñµ´Ò¡ÔȺ󣬷¢ÏÖÈÜÒºÒºÃæµÍÓڿ̶ÈÏߣ¬ÔٵμÓÉÙÁ¿ÕôÁóË®ÖÁ¿Ì¶ÈÏß´¦
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
(14·Ö)¸ßÃÌËá¼ØË׳ÆPP·Û£¬ÎªÇ¿Ñõ»¯¼Á£¬Óöµ½ÓлúÎï¾Í·Å³ö»îÐÔÑõ¡£ÕâÖÖÑõÓÐɱÃðϸ¾úµÄ×÷Óã¬ÇÒɱ¾úÄÜÁ¦¼«Ç¿¡£Ä³Ñ§ÉúÓûÔÚʵÑéÊÒÅäÖÆ1 L 0.06 mol/L KMnO4Ï¡ÈÜÒº£¬ÓÃÀ´ÇåÏ´ÉË¿Ú¡£
(1)ʵÑé¹ý³ÌÖÐÐèÓÃÍÐÅÌÌìƽ³ÆÈ¡KMnO4¾§ÌåµÄÖÊÁ¿Îª__________g¡£
(2)Æä²Ù×÷²½ÖèÈçÏÂͼËùʾ£¬ÔòÓÒͼËùʾ²Ù×÷Ó¦ÔÚÏÂͼÖÐ__________(ÌîÑ¡Ïî×Öĸ)Ö®¼ä¡£
A£®¢ÚÓë¢Û¡¡¡¡B£®¢ÙÓë¢Ú¡¡¡¡C£®¢ÜÓë¢Ý
(3) ÅäÖƹý³ÌÖÐÐèÒªÓõ½µÄÒÇÆ÷ÓÐ:ÍÐÅÌÌìƽ¡¢Ò©³×¡¢ÉÕ±¡¢ ¡¢ ¡¢
(4)Èô¸ÃͬѧÔÚÅäÖÆÈÜҺʱ£¬½øÐÐÁËÈçϲÙ×÷£¬ÆäÖÐʹËùÅäÈÜҺŨ¶ÈÆ«µÍµÄ²Ù×÷
ÓÐ_______________(ÌîÑ¡Ïî×Öĸ)¡£
A£®³ÆÁ¿KMnO4¾§Ìåʱ£¬Ö¸ÕëÆ«ÏòÓÒ±ß
B£®½«KMnO4¾§Ìå·ÅÔÚÉÕ±ÖÐÈܽ⣬ÀäÈ´ºó£¬×ªÒÆÖÁº¬ÓÐÉÙÁ¿ÕôÁóË®µÄÈÝÁ¿Æ¿ÖÐ
C£®¶¨ÈÝʱ£¬ÑöÊӿ̶ÈÏß
D£®Õñµ´Ò¡ÔȺ󣬷¢ÏÖÈÜÒºÒºÃæµÍÓڿ̶ÈÏߣ¬ÔٵμÓÉÙÁ¿ÕôÁóË®ÖÁ¿Ì¶ÈÏß´¦
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ìɽ¶«Ê¡¼ÃÄþÊÐãôˮһÖиßÈýÉÏѧÆÚÆÚÄ©Ä£Ä⻯ѧÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ
(14·Ö)
¢ñ£®£¨1£©·ÖÎöϱíÖи÷ÏîµÄÅŲ¼¹æÂÉ£¬°´´Ë¹æÂÉÅŲ¼µÚ22ÏîӦΪ ¡£
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
C2H4 | C2H6 | C2H6O | C2H4O2 | C3H6 | C3H8 | C3H8O | C3H6O2 | C4H8 | C4H10 |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012½ìɽ¶«Ê¡»¸Ì¨µÚ¶þÖÐѧ¸ßÈý11ÔÂÄ£¿é¼ì²â»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ
(14·Ö)¸ßÃÌËá¼ØË׳ÆPP·Û£¬ÎªÇ¿Ñõ»¯¼Á£¬Óöµ½ÓлúÎï¾Í·Å³ö»îÐÔÑõ¡£ÕâÖÖÑõÓÐɱÃðϸ¾úµÄ×÷Óã¬ÇÒɱ¾úÄÜÁ¦¼«Ç¿¡£Ä³Ñ§ÉúÓûÔÚʵÑéÊÒÅäÖÆ1 L 0.06 mol/L KMnO4Ï¡ÈÜÒº£¬ÓÃÀ´ÇåÏ´ÉË¿Ú¡£
(1)ʵÑé¹ý³ÌÖÐÐèÓÃÍÐÅÌÌìƽ³ÆÈ¡KMnO4¾§ÌåµÄÖÊÁ¿Îª__________g¡£
(2)Æä²Ù×÷²½ÖèÈçÏÂͼËùʾ£¬ÔòÓÒͼËùʾ²Ù×÷Ó¦ÔÚÏÂͼÖÐ__________(ÌîÑ¡Ïî×Öĸ)Ö®¼ä¡£
A£®¢ÚÓë¢Û¡¡¡¡B£®¢ÙÓë¢Ú¡¡¡¡C£®¢ÜÓë¢Ý
(3) ÅäÖƹý³ÌÖÐÐèÒªÓõ½µÄÒÇÆ÷ÓÐ:ÍÐÅÌÌìƽ¡¢Ò©³×¡¢ÉÕ±¡¢ ¡¢ ¡¢
(4)Èô¸ÃͬѧÔÚÅäÖÆÈÜҺʱ£¬½øÐÐÁËÈçϲÙ×÷£¬ÆäÖÐʹËùÅäÈÜҺŨ¶ÈÆ«µÍµÄ²Ù×÷
ÓÐ_______________(ÌîÑ¡Ïî×Öĸ)¡£
A£®³ÆÁ¿KMnO4¾§Ìåʱ£¬Ö¸ÕëÆ«ÏòÓÒ±ß
B£®½«KMnO4¾§Ìå·ÅÔÚÉÕ±ÖÐÈܽ⣬ÀäÈ´ºó£¬×ªÒÆÖÁº¬ÓÐÉÙÁ¿ÕôÁóË®µÄÈÝÁ¿Æ¿ÖÐ
C£®¶¨ÈÝʱ£¬ÑöÊӿ̶ÈÏß
D£®Õñµ´Ò¡ÔȺ󣬷¢ÏÖÈÜÒºÒºÃæµÍÓڿ̶ÈÏߣ¬ÔٵμÓÉÙÁ¿ÕôÁóË®ÖÁ¿Ì¶ÈÏß´¦
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012½ì½ËÕÊ¡ÑïÖÝÖÐѧ¸ßÈý4ÔÂË«ÖÜÁ·Ï°»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ
(14·Ö) ²ÝËáÑÇÌúÓÃ×÷·ÖÎöÊÔ¼Á¼°ÏÔÓ°¼ÁµÈ£¬ÆäÖƱ¸Á÷³ÌÈçÏ£º
¢ÅÅäÖÆ(NH4)2Fe(SO4)26H2OÈÜҺʱ£¬Ðè¼ÓÉÙÁ¿Ï¡ÁòËᣬĿµÄÊÇ ¡£
¢Æ½«ÖƵõIJúÆ·ÔÚë²ÆøÆø·ÕÖнøÐÐÈÈÖØ·ÖÎö£¬½á¹ûÈçÓÒͼ£¨TG%±íʾ²ÐÁô¹ÌÌåÖÊÁ¿Õ¼ÔÑùÆ·×ÜÖÊÁ¿µÄ°Ù·ÖÊý£©¡£
¢ÙÔòC´¦Ê±²ÐÁôÎïµÄ»¯Ñ§Ê½Îª ¡£
¢ÚÓÐÑо¿Ñ§ÕßÔÚʵÑé¹ý³ÌÖÐÓÃÆøÏàÉ«Æ×»¹¼ì³öH2£¬×îÖÕ²úÎïÖÐÒ²ÓÐ΢Á¿µÄ´ÅÐÔÎïÖÊÉú³É£¬ÇëÄã²ÂÏëÓÃÒ»¸ö·½³Ìʽ½âÊÍÕâÖÖÊÂʵ£º ¡£
¢ÛÏÖÈ¡ÔÚÕæ¿ÕÖÐ146¡æÍÑË®ºóµÄFeC2O41.44g·ÅÔÚijÕæ¿ÕµÄÃܱÕÈÝÆ÷ÖУ¬ÔÙ³äÈë0.04molCO¡£¼ÓÈÈÖÁ1100¡æ£¬ÆäÖÐFeO(s)+CO(g)Fe(s)+CO2(g)·´Ó¦Æ½ºâ³£ÊýK=0.4£¬Ôò¸Ã·´Ó¦´ïƽºâʱ£¬FeOµÄת»¯ÂÊΪ¶àÉÙ£¿ ¡£
£¨3£©½ðÊôþÔÚ¹úÃñÉú²úÖÐÓÐÖØÒª×÷Ó㬳£ÒÔMgCl2ΪÔÁÏ»ñÈ¡£¬Î¶ȺÍѹǿP(HCl)g¶ÔMgCl2¡¤6H2O¾§ÌåÈÈ·Ö½â²úÎïµÄÓ°ÏìÈçͼËùʾ¡£½áºÏÓÒͼÇë»Ø´ðÏÂÁÐÎÊÌ⣺
¢Ùд³öP(HCl)g = 0.25MPa£¬Î¶ȴÓ300¡æÉý¸ßµ½550¡æʱ·´Ó¦µÄ»¯Ñ§·½³Ìʽ £»
¢Úʵ¼ÊÉú²úÖУ¬½«MgCl2¡¤6H2O¾§Ìå¼ÓÈȵ½600¡æµÄ¹ý³ÌÖм¸ºõµÃ²»µ½ÎÞË®MgCl2£¬ÆäÔÒòÊÇ £»ÈôÒªµÃµ½ÎÞË®MgCl2Ðë²ÉÈ¡µÄ´ëÊ©ÊÇ ¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com