Question

A¡¢B¡¢C¡¢DÊÇËÄÖÖ³£¼ûµ¥ÖÊ£¬B¡¢DΪ³£¼û½ðÊô£¬A¡¢CΪÆøÌ壬Æä¶ÔÓ¦ÔªËصÄÔ­×ÓÐòÊýÒÀ´ÎÔö´ó£¬¼×¡¢ÒÒ¡¢±ûΪ³£¼û»¯ºÏÎËüÃÇÖ®¼äÓÐÈçͼËùʾת»¯¹Øϵ£º

»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©AµÄµç×Óʽ

 

£®
£¨2£©DÓë¼×ÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ

 

£®
£¨3£©±ûµÄË®ÈÜÒºÏÔ

 

ÐÔ£¨ÌîËá»ò¼î£©£¬Óë¹ýÁ¿CO₂·´Ó¦Àë×Ó·½³Ìʽ

 

£®
£¨4£©Ò»¶¨Ìõ¼þÏ£¬2mol BÓë3mol DµÄÑõ»¯ÎïWÇ¡ºÃ·´Ó¦£¬ÔòWµÄ»¯Ñ§Ê½

 

£®

Answer 1

¿¼µã£ºÎÞ»úÎïµÄÍƶÏ

רÌ⣺ÍƶÏÌâ

·ÖÎö£ºA¡¢B¡¢C¡¢DÊÇËÄÖÖ³£¼ûµ¥ÖÊ£¬Æä¶ÔÓ¦ÔªËصÄÔ­×ÓÐòÊýÒÀ´ÎÔö´ó£¬¼×¡¢ÒÒ¡¢±ûΪ³£¼û»¯ºÏÎB¡¢DΪ³£¼û½ðÊô£¬A¡¢CΪÆøÌ壬BÄÜÓëNaOHÈÜÒº·´Ó¦£¬ÔòBӦΪAl£¬AΪH₂£¬±ûΪNaAlO₂£¬DÔÚ¸ßÎÂÏÂÓëË®ÕôÆø·´Ó¦£¬DӦΪFe£¬ÔòÒÒΪFe₃O₄£¬DÔÚCÖÐȼÉÕÉú³É¼×£¬CΪCl₂£¬¼×ΪFeCl₃£¬ÒԴ˽â´ð¸ÃÌ⣮

½â´ð£º ½â£ºA¡¢B¡¢C¡¢DÊÇËÄÖÖ³£¼ûµ¥ÖÊ£¬Æä¶ÔÓ¦ÔªËصÄÔ­×ÓÐòÊýÒÀ´ÎÔö´ó£¬¼×¡¢ÒÒ¡¢±ûΪ³£¼û»¯ºÏÎB¡¢DΪ³£¼û½ðÊô£¬A¡¢CΪÆøÌ壬BÄÜÓëNaOHÈÜÒº·´Ó¦£¬ÔòBӦΪAl£¬AΪH₂£¬±ûΪNaAlO₂£¬DÔÚ¸ßÎÂÏÂÓëË®ÕôÆø·´Ó¦£¬DӦΪFe£¬ÔòÒÒΪFe₃O₄£¬DÔÚCÖÐȼÉÕÉú³É¼×£¬CΪCl₂£¬¼×ΪFeCl₃£¬
£¨1£©ÓÉÒÔÉÏ·ÖÎö¿ÉÖªAΪH₂£¬Æäµç×ÓʽΪ£º£¬¹Ê´ð°¸Îª£º£»
£¨2£©DÓë¼×ÈÜÒº·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºFe+2FeCl₃=3FeCl₂£¬¹Ê´ð°¸Îª£ºFe+2FeCl₃=3FeCl₂£»
£¨3£©±ûΪNaAlO₂£¬ÎªÇ¿¼îÈõËáÑΣ¬ÔÚÈÜÒºÖз¢ÉúAlO₂^-+2H₂O?Al£¨OH£©₃+OH^-£¬ÈÜÒº³Ê¼îÐÔ£¬NaAlO₂ÈÜÒºÓë¹ýÁ¿CO₂·´Ó¦Àë×Ó·½³ÌʽΪ£ºAlO₂^-+CO₂+2H₂O=Al£¨OH£©₃¡ý+HCO₃^-£¬
¹Ê´ð°¸Îª£º¼î£»AlO₂^-+CO₂+2H₂O=Al£¨OH£©₃¡ý+HCO₃^-£»
£¨4£©Ò»¶¨Ìõ¼þÏ£¬2molAlÓë3molFeµÄÒ»ÖÖÑõ»¯ÎïWÇ¡ºÃ·´Ó¦£¬ÉèWÖÐFeµÄ»¯ºÏ¼ÛΪx£¬¸ù¾ÝתÒƵç×ÓÊýÄ¿ÏàµÈ¿ÉÖª2¡Á3=3£¨x-0£©£¬x=2£¬¹ÊWΪFeO£¬
¹Ê´ð°¸Îª£ºFeO£®

µãÆÀ£º±¾Ì⿼²éÎÞ»úÎïµÄÍƶϣ¬ÄѶÈÖеȣ¬·´Ó¦ÖÐÌØÊâת»¯¹ØϵΪ½â´ð¸ÃÌâµÄÍ»ÆÆ¿Ú£¬ÕÆÎÕÏà¹ØÎïÖʵÄÐÔÖÊ£¬Ñ§Ï°ÖÐ×¢ÒâÏȹػù´¡ÖªÊ¶µÄ»ýÀÛ£®