ÖÐѧ»¯Ñ§Öг£¼ûµÄÎïÖÊÓÐÈçͼËùʾµÄת»¯¹Øϵ£¨·´Ó¦Ìõ¼þÂÔÈ¥£©£®X¡¢Y¡¢Z¡¢WÊǵ¥ÖÊ£¬ÆäÓà¾ùΪ»¯ºÏÎA¡¢W¡¢Z³£ÎÂϳÊÆø̬£¬ÇÒAÊÇÒ»ÖÖ´óÆøÎÛȾÎBÊÇÒ»ÖÖ³£ÓõÄËᣮ
£¨1£©Ð´³öÏÂÁÐÎïÖʵĻ¯Ñ§Ê½£º
Y______¡¢A______¡¢C______£®
£¨2£©DµÄµç×ÓʽΪ______£®
£¨3£©ÎÒ¹úÉú²úBµÄ¹¤ÒµÖУ¬³£²ÉÓÃÒÔÏ·½Ê½´¦ÀíβÆøA£º

¾«Ó¢¼Ò½ÌÍø

ÊÔ´Ó×ۺϾ­¼ÃЧÒæµÄ½Ç¶È·ÖÎö£¬ÕâÑù´¦ÀíµÄÄ¿µÄÊÇ£¨´ð³öÆäÖÐÁ½µã¼´¿É£©£º
a£®______£»b£®______£®
£¨4£©·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ£º______£®
·´Ó¦¢ÚµÄ»¯Ñ§·½³Ìʽ£º______£®
·´Ó¦¢ÜµÄÀë×Ó·½³Ìʽ£º______£®
¾«Ó¢¼Ò½ÌÍø
AÊÇÒ»ÖÖ´óÆøÎÛȾÎ¿ÉÄÜΪSO2»òNO2£¬ÓÉÌâÄ¿¿ÉÖª£¬X¡¢ZÖÐÖ»ÓÐZΪÆøÌ壬ÔòXӦΪS£¬ZΪO2£¬AΪSO2£¬BÊÇÒ»ÖÖ³£ÓõÄËᣬӦΪH2SO4£¬ÌâÖÐSO2ºÍK·´Ó¦Éú³ÉH2SO4£¬ÔòKӦΪÑõ»¯ÐÔÎïÖÊH2O2£¬H2SO4ºÍC·´Ó¦Éú³ÉÃ÷·¯£¬ÔòCӦΪKAlO2£¬ËùÒÔYºÍDӦΪAlºÍKOHÈÜÒºµÄ·´Ó¦£¬ÔòYΪAl£¬DΪKOH£¬WΪH2£¬EΪH2O£¬Éú³ÉÎïGΪAl£¨OH£©3£¬FΪK2SO4£¬Ôò
£¨1£©ÓÉÒÔÉÏ·ÖÎö¿ÉÖª£¬YΪAl£¬AΪSO2£¬CΪKAlO2£¬¹Ê´ð°¸Îª£ºAl¡¢SO2¡¢KAlO2£»
£¨2£©DΪKOH£¬ÎªÀë×Ó»¯ºÏÎµç×ÓʽΪ

¾«Ó¢¼Ò½ÌÍø

£¬¹Ê´ð°¸Îª£º

¾«Ó¢¼Ò½ÌÍø

£»
£¨3£©¶þÑõ»¯ÁòºÍ°±Ë®·´Ó¦Éú³ÉÑÇÁòËá泥¬½ø¶øÓë¹ýÑõ»¯Çâ·´Ó¦Éú³ÉÁòËá泥¬¿É¼õÉÙSO2¶Ô»·¾³ÎÛȾ¡¢Ê¹Ô­ÁÏÀûÓÃÂʵõ½Ìá¸ß¡¢¸±²úÆ·¿É×÷»¯·Ê£¬
¹Ê´ð°¸Îª£ºa£®¼õÉÙSO2¶Ô»·¾³ÎÛȾ£»b£®¿ÉÒÔʹԭÁÏÀûÓÃÂʵõ½Ìá¸ß£»c£®¸±²úÆ·¿É×÷»¯·Ê£¬Éç»áÐèÇóÁ¿´ó£¨ÈÎÒâÌîÁ½ÖÖ£©
£¨4£©·´Ó¦¢ÙAlºÍKOHÈÜÒºµÄ·´Ó¦£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2Al+2KOH+2H2O=2KAlO2+3H2¡ü£¬·´Ó¦¢ÚΪH2O2ºÍSO2µÄ·´Ó¦£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪH2O2+SO2=H2SO4£¬·´Ó¦¢ÜKAlO2ÓëËáµÄ·´Ó¦£¬Éú³ÉAl£¨OH£©3³Áµí£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪAlO2-+H++H2O=Al£¨OH£©3£¬
¹Ê´ð°¸Îª£º2Al+2KOH+2H2O=2KAlO2+3H2¡ü£»H2O2+SO2=H2SO4£»AlO2-+H++H2O=Al£¨OH£©3¡ý£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÈçͼÖÐA¡«H¾ùΪÖÐѧ»¯Ñ§Öг£¼ûµÄÎïÖÊ£¬ËüÃÇÖ®¼äÓÐÈçÏÂת»¯¹Øϵ£®ÆäÖÐA¡¢C¾ùΪ½ðÊôµ¥ÖÊ£¬CÓëË®·´Ó¦Éú³ÉDºÍ×îÇáµÄÆøÌ壬D¡¢HµÄÑæÉ«·´Ó¦¾ù³Ê»ÆÉ«£¬ÔÚͨ³£×´¿öÏÂE£¨ÇâÑõ»¯Î¸úNaOH»òÑÎËá¾ù¿É·¢Éú¸´·Ö½â·´Ó¦£¨·´Ó¦¹ý³ÌÖÐÉú³ÉµÄË®¼°ÆäËû²úÎïÒÑÂÔÈ¥£©£®
Çë»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©BÊÇ
AlCl3
AlCl3
£¬HÊÇ
NaHCO3
NaHCO3
£®£¨Ìѧʽ£©
£¨2£©Ð´³öEת»¯ÎªGµÄÀë×Ó·½³Ìʽ
Al£¨OH£©3+OH-¨TAlO2-+2H2O
Al£¨OH£©3+OH-¨TAlO2-+2H2O
£®
£¨3£©AÔÚ³£ÎÂÏÂÒ²¿ÉÓëDÈÜÒº·´Ó¦Éú³ÉG£¬Ð´³ö´Ë·´Ó¦µÄ»¯Ñ§·½³Ìʽ
2Al+2NaOH+2H2O¨T2NaAlO2+3H2¡ü
2Al+2NaOH+2H2O¨T2NaAlO2+3H2¡ü
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÎïÖÊA¡«E¾ùº¬Í¬ÖÖÔªËØ£¬¶¼ÊÇÖÐѧ»¯Ñ§Öг£¼ûµÄÎïÖÊ£¬ËüÃÇ¿É·¢ÉúÈçͼËù±íʾµÄ·´Ó¦£¨³ýA¡«EÍâµÄÆäËüÎïÖÊÒÑÂÔÈ¥£©£º
£¨1£©Ð´³öÏàÓ¦ÎïÖʵÄÀà±ð£º
B C D
Àà±ð
£¨2£©ÔÚÒÔÉÏ·´Ó¦ÖУ¨ÓÃÐòºÅÌî¿Õ£©£º
ÊôÓÚÑõ»¯»¹Ô­·´Ó¦µÄÊÇ
¢Ù¢Ú¢ß
¢Ù¢Ú¢ß
£»ÊôÓÚ¸´·Ö½â·´Ó¦µÄÊÇ
¢Û¢Ü¢Ý
¢Û¢Ü¢Ý
£®
£¨3£©Ð´³ö·´Ó¦¢ÛºÍ¢ßµÄÀë×Ó·½³Ìʽ£º
CuO+2H+=Cu2++H2O
CuO+2H+=Cu2++H2O
£º
Fe+Cu2+=Cu+Fe2+
Fe+Cu2+=Cu+Fe2+
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ͼÖÐA¡«H¾ùΪÖÐѧ»¯Ñ§Öг£¼ûµÄÎïÖÊ£¬A¡¢B¡¢HÊÇÆøÌ壬ËüÃÇÖ®¼äÓÐÈçÏÂת»¯¹Øϵ£®£¨·´Ó¦ÖÐÉú³ÉµÄË®ÒÑÂÔÈ¥£©


Çë»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©ÎïÖÊFµÄ»¯Ñ§Ê½ÊÇ
HCl
HCl
£®
£¨2£©CÎïÖÊÔÚÈÕ³£Éú»îÖпÉ×÷
Ïû¶¾£¨»òƯ°×£©
Ïû¶¾£¨»òƯ°×£©
¼Á£®
£¨3£©Ð´³ö·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ£º
2Cl2+2Ca£¨OH£©2¨TCaCl2+Ca£¨ClO£©2+2H2O
2Cl2+2Ca£¨OH£©2¨TCaCl2+Ca£¨ClO£©2+2H2O
£®
£¨4£©Ð´³ö·´Ó¦¢ÚµÄÀë×Ó·½³Ìʽ£º
CO2+Ca2++2OH-¨TCaCO3¡ý+H2O
CO2+Ca2++2OH-¨TCaCO3¡ý+H2O
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÈçͼÖÐA¡«H¾ùΪÖÐѧ»¯Ñ§Öг£¼ûµÄÎïÖÊ£¬A¡¢B¡¢HÊÇÆøÌ壬ÆäÖÐAΪ»ÆÂÌÉ«ÆøÌ壬ËüÃÇÖ®¼äÓÐÈçÏÂת»¯¹Øϵ£®£¨·´Ó¦ÖÐÉú³ÉµÄË®ÒÑÂÔÈ¥£©

Çë»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©EÊÇ
CaCO3
CaCO3
£¬HÊÇ
O2
O2
£»£¨Ìѧʽ£©
£¨2£©Ð´³ö·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ£º
2Cl2+2Ca£¨OH£©2¨TCaCl2+Ca£¨ClO£©2+2H2O
2Cl2+2Ca£¨OH£©2¨TCaCl2+Ca£¨ClO£©2+2H2O
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍøA¡¢B¡¢C¡¢XÊÇÖÐѧ»¯Ñ§Öг£¼ûµÄÎïÖÊ£¬ËüÃÇÖ®¼äµÄת»¯¹ØϵÈçͼËùʾ£¨²¿·Ö²úÎïÒÑÂÔÈ¥£©£®Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÈôXÊÇÇ¿Ñõ»¯ÐÔµ¥ÖÊ£¬ÔòA²»¿ÉÄÜÊÇ
 
£¨ÌîÐòºÅ£©£®
a£®C     b£®N2     c£®S       d£®Mg    e£®Al
£¨2£©ÈôAÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶£¬CΪºì×ØÉ«µÄÆøÌ壮Aת»¯ÎªBµÄ»¯Ñ§·½³ÌʽΪ
 
£®
£¨3£©ÈôXÊǽðÊôµ¥ÖÊ£¬ÏòB¡¢CÈÜÒºÖзֱðµÎ¼ÓAgNO3ÈÜÒº£¬¾ù²úÉú²»ÈÜÓÚÏ¡ÏõËáµÄ°×É«³Áµí£¬ÔòBµÄ»¯Ñ§Ê½Îª
 
£®±£´æCÈÜÒº³£¼ÓÈëÉÙÁ¿X£¬ÆäÄ¿µÄÊÇ
 
£®
£¨4£©ÈôA¡¢B¡¢CÈýÖÖ»¯ºÏÎïµÄË®ÈÜÒº¾ù³ÊËáÐÔ£¬Ð´³öAÓëB·´Ó¦µÄ»¯Ñ§·½³Ìʽ
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸