ÒÑÖªA¡¢B¡¢C¡¢D¡¢E¶¼ÊÇÖÜÆÚ±íÖÐÇ°ËÄÖÜÆÚµÄÔªËØ£¬ËüÃǵĺ˵çºÉÊýA£¼B£¼C£¼D£¼E£®ÆäÖÐA¡¢B¡¢CÊÇͬһÖÜÆڵķǽðÊôÔªËØ£®»¯ºÏÎïDCµÄ¾§ÌåΪÀë×Ó¾§Ì壬DµÄ¶þ¼ÛÑôÀë×ÓÓëCµÄÒõÀë×Ó¾ßÓÐÏàͬµÄµç×Ó²ã½á¹¹£®AC2Ϊ·Ç¼«ÐÔ·Ö×Ó£®B¡¢CµÄÇ⻯ÎïµÄ·Ðµã±ÈËüÃÇͬ×åÏàÁÚÖÜÆÚÔªËØÇ⻯ÎïµÄ·Ðµã¸ß£®EµÄÔ­×ÓÐòÊýΪ24£¬ECl3ÄÜÓëB¡¢CµÄÇ⻯ÎïÐγÉÁùÅäλµÄÅäºÏÎÇÒÁ½ÖÖÅäÌåµÄÎïÖʵÄÁ¿Ö®±ÈΪ2£º1£¬Èý¸öÂÈÀë×ÓλÓÚÍâ½ç£®Çë¸ù¾ÝÒÔÉÏÇé¿ö£¬»Ø´ðÏÂÁÐÎÊÌ⣺£¨´ðÌâʱ£¬A¡¢B¡¢C¡¢D¡¢EÓÃËù¶ÔÓ¦µÄÔªËØ·ûºÅ±íʾ£©
£¨1£©A¡¢B¡¢CµÄµÚÒ»µçÀëÄÜÓÉСµ½´óµÄ˳ÐòΪ
C£¼O£¼N
C£¼O£¼N
£®
£¨2£©BµÄÇ⻯ÎïµÄ·Ö×ӿռ乹ÐÍÊÇ
Èý½Ç׶ÐÍ
Èý½Ç׶ÐÍ
£®ÆäÖÐÐÄÔ­×Ó²ÉÈ¡
sp3
sp3
ÔÓ»¯£®
£¨3£©Ð´³ö»¯ºÏÎïAC2µÄµç×Óʽ
£»Ò»ÖÖÓÉB¡¢C×é³ÉµÄ»¯ºÏÎïÓëAC2»¥ÎªµÈµç×ÓÌ壬Æ仯ѧʽΪ
N2O
N2O
£®
£¨4£©EµÄºËÍâµç×ÓÅŲ¼Ê½ÊÇ
1s22s22p63s23p63d54s1
1s22s22p63s23p63d54s1
£¬ECl3ÐγɵÄÅäºÏÎïµÄ»¯Ñ§Ê½Îª
[Cr£¨NH3£©4£¨H2O£©2]Cl3
[Cr£¨NH3£©4£¨H2O£©2]Cl3
£®
·ÖÎö£ºA¡¢B¡¢C¡¢D¡¢E¶¼ÊÇÖÜÆÚ±íÖÐÇ°ËÄÖÜÆÚµÄÔªËØ£¬ËüÃǵĺ˵çºÉÊýA£¼B£¼C£¼D£¼E£¬»¯ºÏÎïDCµÄ¾§ÌåΪÀë×Ó¾§Ì壬DµÄ¶þ¼ÛÑôÀë×ÓÓëCµÄÒõÀë×Ó¾ßÓÐÏàͬµÄµç×Ó²ã½á¹¹£¬CÐγÉ-2¼ÛÒõÀë×Ó£¬ÇÒDλÓÚCµÄÏÂÒ»ÖÜÆÚ£¬B¡¢CµÄÇ⻯ÎïµÄ·Ðµã±ÈËüÃÇͬ×åÏàÁÚÖÜÆÚÔªËØÇ⻯ÎïµÄ·Ðµã¸ß£¬·Ö×ÓÖдæÔÚÇâ¼ü£¬CÐγÉ-2¼ÛÒõÀë×Ó£¬ÔòCΪÑõÔªËØ£¬DΪþԪËØ£¬ºËµçºÉÊýB£¼C£¬ÔòBΪµªÔªËØ£»ÆäÖÐA¡¢B¡¢CÊÇͬһÖÜÆڵķǽðÊôÔªËØ£¬AC2Ϊ·Ç¼«ÐÔ·Ö×Ó£¬ÔòAΪ̼ԪËØ£»EµÄÔ­×ÓÐòÊýΪ24£¬ÔòEΪCrÔªËØ£»CrCl3ÄÜÓëNH3¡¢H2OÐγÉÁùÅäλµÄÅäºÏÎÇÒÁ½ÖÖÅäÌåµÄÎïÖʵÄÁ¿Ö®±ÈΪ2£º1£¬ÔòÅäÌåÖÐÓÐ4¸öNH3¡¢2¸öH2O£¬Èý¸öÂÈÀë×ÓλÓÚÍâ½ç£¬¸ÃÅäºÏÎïΪ[Cr£¨NH3£©4£¨H2O£©2]Cl3£®
½â´ð£º½â£ºA¡¢B¡¢C¡¢D¡¢E¶¼ÊÇÖÜÆÚ±íÖÐÇ°ËÄÖÜÆÚµÄÔªËØ£¬ËüÃǵĺ˵çºÉÊýA£¼B£¼C£¼D£¼E»¯ºÏÎïDCµÄ¾§ÌåΪÀë×Ó¾§Ì壬DµÄ¶þ¼ÛÑôÀë×ÓÓëCµÄÒõÀë×Ó¾ßÓÐÏàͬµÄµç×Ó²ã½á¹¹£¬CÐγÉ-2¼ÛÒõÀë×Ó£¬ÇÒDλÓÚCµÄÏÂÒ»ÖÜÆÚ£¬B¡¢CµÄÇ⻯ÎïµÄ·Ðµã±ÈËüÃÇͬ×åÏàÁÚÖÜÆÚÔªËØÇ⻯ÎïµÄ·Ðµã¸ß£¬·Ö×ÓÖÐÓ¦´æÔÚÇâ¼ü£¬CÐγÉ-2¼ÛÒõÀë×Ó£¬ÔòCΪÑõÔªËØ£¬DΪþԪËØ£¬ºËµçºÉÊýB£¼C£¬ÔòBΪµªÔªËØ£»ÆäÖÐA¡¢B¡¢CÊÇͬһÖÜÆڵķǽðÊôÔªËØ£¬AC2Ϊ·Ç¼«ÐÔ·Ö×Ó£¬ÔòAΪ̼ԪËØ£»EµÄÔ­×ÓÐòÊýΪ24£¬ÔòEΪCrÔªËØ£»CrCl3ÄÜÓëNH3¡¢H2OÐγÉÁùÅäλµÄÅäºÏÎÇÒÁ½ÖÖÅäÌåµÄÎïÖʵÄÁ¿Ö®±ÈΪ2£º1£¬ÔòÅäÌåÖÐÓÐ4¸öNH3¡¢2¸öH2O£¬Èý¸öÂÈÀë×ÓλÓÚÍâ½ç£¬¸ÃÅäºÏÎïΪ[Cr£¨NH3£©4£¨H2O£©2]Cl3£¬
¹ÊAΪ̼ԪËØ£»BΪµªÔªËØ£»CΪÑõÔªËØ£¬DΪþԪËØ£¬EΪCrÔªËØ£¬
£¨1£©AΪ̼ԪËØ¡¢BΪµªÔªËØ¡¢CΪÑõÔªËØ£¬Í¬ÖÜÆÚ×Ô×ó¶øÓÒµÚÒ»µçÀëÄÜÔö´ó£¬µªÔªËØÔ­×Ó2pÄܼ¶ÓÐ3¸öµç×Ó£¬´¦ÓÚ°ëÂúÎȶ¨×´Ì¬£¬µç×ÓÄÜÁ¿µÍ£¬µªÔªËصÚÒ»µçÀëÄܸßÓÚÏàÁÚµÄÔªËصģ¬ËùÒÔµÚÒ»µçÀëÄÜÓÉСµ½´óµÄ˳ÐòΪC£¼O£¼N£¬
¹Ê´ð°¸Îª£ºC£¼O£¼N£»
£¨2£©BΪµªÔªËØ£¬ÆäÇ⻯ÎïΪNH3£¬·Ö×ÓÖк¬ÓÐ3¸öN-H¼ü£¬NÔ­×ÓÓÐ1¶Ô¹Â¶Ôµç×Ó¶Ô£¬ÔÓ»¯¹ìµÀÊýΪ4£¬NÔ­×Ó²ÉÈ¡sp3ÔÓ»¯£¬¿Õ¼ä¹¹ÐÍΪÈý½Ç׶ÐÍ£¬
¹Ê´ð°¸Îª£ºÈý½Ç׶ÐÍ£»sp3£»
£¨3£©»¯ºÏÎïAC2ÊÇCO2£¬·Ö×ÓÖÐ̼ԭ×ÓÓëÑõÔ­×ÓÖ®¼äÐγÉ2¶Ô¹²Óõç×Ó¶Ô£¬µç×ÓʽΪ£»Ò»ÖÖÓÉNÔªËØ¡¢OÔªËØ»¯ºÏÎïÓëCO2»¥ÎªµÈµç×ÓÌ壬Æ仯ѧʽΪN2O£¬
¹Ê´ð°¸Îª£º£»N2O£»
£¨4£©EΪCrÔªËØ£¬Ô­×ÓÐòÊýΪ24£¬Ô­×ÓºËÍâÓÐ24¸öµç×Ó£¬ºËÍâµç×ÓÅŲ¼Ê½ÊÇ 1s22s22p63s23p63d54s1£»CrCl3ÄÜÓëNH3¡¢H2OÐγÉÁùÅäλµÄÅäºÏÎÇÒÁ½ÖÖÅäÌåµÄÎïÖʵÄÁ¿Ö®±ÈΪ2£º1£¬ÔòÅäÌåÖÐÓÐ4¸öNH3¡¢2¸öH2O£¬Èý¸öÂÈÀë×ÓλÓÚÍâ½ç£¬¸ÃÅäºÏÎïΪ[Cr£¨NH3£©4£¨H2O£©2]Cl3£¬
¹Ê´ð°¸Îª£º1s22s22p63s23p63d54s1£»[Cr£¨NH3£©4£¨H2O£©2]Cl3£®
µãÆÀ£ºÌâÄ¿×ÛºÏÐԽϴó£¬Éæ¼°½á¹¹ÐÔÖÊԽλÖùØϵ¡¢ÔªËØÖÜÆÚÂÉ¡¢µç×ÓʽÓëºËÍâµç×ÓÅŲ¼¡¢ÅäºÏÎïÓëÔÓ»¯ÀíÂÛ¡¢·Ö×ӽṹ£¬Ñõ»¯»¹Ô­·´Ó¦µÈ£¬ÄѶÈÖеȣ¬ÊÇÎïÖʽṹµÄ×ÛºÏÐÔÌâÄ¿£¬ÊǶÔѧÉú×ÛºÏÄÜÁ¦µÄ¿¼²é£¬Ç⻯ÎïµÄ·Ðµã±ÈËüÃÇͬ×åÏàÁÚÖÜÆÚÔªËØÇ⻯ÎïµÄ·Ðµã¸ßÊÇÍƶϵÄÍ»ÆÆ¿Ú£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2011?ÉϺ£Ä£Ä⣩ÒÑÖªA¡¢B¡¢C¡¢D¡¢E¶¼ÊÇÖÜÆÚ±íÖÐÇ°ËÄÖÜÆÚµÄÔªËØ£¬ËüÃǵĺ˵çºÉÊýA£¼B£¼C£¼D£¼E£®ÆäÖÐA¡¢B¡¢CÊÇͬһÖÜÆڵķǽðÊôÔªËØ£®»¯ºÏÎïDCµÄ¾§ÌåΪÀë×Ó¾§Ì壬DµÄ¶þ¼ÛÑôÀë×ÓÓëCµÄÒõÀë×Ó¾ßÓÐÏàͬµÄµç×Ó²ã½á¹¹£®AC2Ϊ·Ç¼«ÐÔ·Ö×Ó£®B¡¢CµÄÇ⻯ÎïµÄ·Ðµã±ÈËüÃÇͬ×åÏàÁÚÖÜÆÚÔªËØÇ⻯ÎïµÄ·Ðµã¸ß£®EÊÇÈËÌåÄÚº¬Á¿×î¸ßµÄ½ðÊôÔªËØ£®Çë¸ù¾ÝÒÔÉÏÇé¿ö£¬»Ø´ðÏÂÁÐÎÊÌ⣺£¨´ðÌâʱ£¬A¡¢B¡¢C¡¢D¡¢EÓÃËù¶ÔÓ¦µÄÔªËØ·ûºÅ±íʾ£©
£¨1£©A¡¢B¡¢CµÄ·Ç½ðÊôÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòΪ
O£¾N£¾C
O£¾N£¾C
£®
£¨2£©BµÄÇ⻯ÎïµÄ·Ö×ӿռ乹ÐÍÊÇ
Èý½Ç׶ÐÍ
Èý½Ç׶ÐÍ
£®ËüÊÇ
¼«ÐÔ·Ö×Ó
¼«ÐÔ·Ö×Ó
£¨ÌÐԺͷǼ«ÐÔ£©·Ö×Ó£®
£¨3£©Ð´³ö»¯ºÏÎïAC2µÄµç×Óʽ
£»Ò»ÖÖÓÉB¡¢C×é³ÉµÄ»¯ºÏÎïÓëAC2µç×ÓÊýÏàµÈ£¬Æ仯ѧʽΪ
N2O
N2O
£®
£¨4£©EµÄºËÍâµç×ÓÅŲ¼Ê½ÊÇ
1s22s22p63s23p64s2
1s22s22p63s23p64s2
£¬
£¨5£©10molBµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïµÄÏ¡ÈÜÒºÓë4molDµÄµ¥ÖÊ·´Ó¦Ê±£¬B±»»¹Ô­µ½×îµÍ¼Û£¬B±»»¹Ô­ºóµÄ²úÎﻯѧʽΪ
NH4NO3
NH4NO3
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÒÑÖªA¡¢B¡¢C¡¢D¡¢EÎåÖÖÎïÖÊÓÐÈçͼËùʾµÄת»¯¹Øϵ£¨²¿·Ö·´Ó¦Îï¼°·´Ó¦Ìõ¼þδÁгö£¬Èô½âÌâʱÐèÒª£¬¿É×÷ºÏÀí¼ÙÉ裩£¬ÇÒÎåÖÖÎïÖÊÖоùº¬ÓÐAÔªËØ£®
£¨1£©ÈôAΪ¹ÌÌåµ¥ÖÊ
¢ÙDµÄ»¯Ñ§Ê½Îª
SO3
SO3
£¬
¢ÚE¡úCµÄ»¯Ñ§·½³ÌʽΪ
2H2SO4£¨Å¨£©+Cu
  ¡÷  
.
 
CuSO4+SO2¡ü+2H2O
2H2SO4£¨Å¨£©+Cu
  ¡÷  
.
 
CuSO4+SO2¡ü+2H2O

¢Û½«CͨÈëij·Ç½ðÊôµ¥ÖʵÄÈÜÒºÖУ¬¿É·¢ÉúÑõ»¯»¹Ô­·´Ó¦Éú³ÉÁ½ÖÖÇ¿ËᣬÊÔ¾ÙÒ»Àýд³ö»¯Ñ§·½³Ìʽ
Cl2+SO2+2H2O=2HCl+H2SO4
Cl2+SO2+2H2O=2HCl+H2SO4
£®
£¨2£©ÈôAΪÆøÌåµ¥ÖÊ
¢ÙC¡úDµÄ»¯Ñ§·½³Ìʽ
2NO+O2=2NO2
2NO+O2=2NO2

¢ÚE¡úCµÄÀë×Ó·½³ÌʽΪ
3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O
3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨¢ñ£©Í¨³£Çé¿öÏ£¬Î¢Á£AºÍBΪ·Ö×Ó£¬CºÍEΪÑôÀë×Ó£¬DΪÒõÀë×Ó£¬ËüÃǶ¼º¬ÓÐ10¸öµç×Ó£»BÈÜÓÚAºóËùµÃµÄÎïÖʿɵçÀë³öCºÍD£»A¡¢B¡¢EÈýÖÖ΢Á£·´Ó¦ºó¿ÉµÃCºÍÒ»ÖÖ°×É«³Áµí£®Çë»Ø´ð£º
£¨1£©Óû¯Ñ§·ûºÅ±íʾÏÂÁÐ4ÖÖ΢Á££º
A
H2O
H2O
£»B
NH3
NH3
£»C
NH4+
NH4+
£»D
OH-
OH-
£®
£¨2£©Ð´³öA¡¢B¡¢EÈýÖÖ΢Á£·´Ó¦µÄÀë×Ó·½³Ìʽ£º
Al3++3NH3+3H2O¨TAl£¨OH£©3¡ý+3NH4+£»»òMg2++2NH3+2H2O¨TMg£¨OH£©2¡ý+2NH4+
Al3++3NH3+3H2O¨TAl£¨OH£©3¡ý+3NH4+£»»òMg2++2NH3+2H2O¨TMg£¨OH£©2¡ý+2NH4+
£®
£¨¢ò£©ÒÑÖªA¡¢B¡¢C¡¢DΪÆøÌ壬E¡¢FΪ¹ÌÌ壬GÊÇÂÈ»¯¸Æ£¬ËüÃÇÖ®¼äµÄת»»¹ØϵÈçͼËùʾ£º
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©DµÄ»¯Ñ§Ê½ÊÇ
NH3
NH3
£¬EµÄ»¯Ñ§Ê½ÊÇ
NH4Cl
NH4Cl
£®
£¨2£©AºÍB·´Ó¦Éú³ÉCµÄ»¯Ñ§·½³ÌʽÊÇ£º
H2+Cl2
 µãȼ 
.
 
2HCl
H2+Cl2
 µãȼ 
.
 
2HCl
£®
£¨3£©EºÍF·´Ó¦Éú³ÉD¡¢HºÍGµÄ»¯Ñ§·½³ÌʽÊÇ£º
2NH4Cl+Ca£¨OH£©2
  ¡÷  
.
 
2NH3¡ü+2H2O+CaCl2
2NH4Cl+Ca£¨OH£©2
  ¡÷  
.
 
2NH3¡ü+2H2O+CaCl2
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÒÑÖªA¡¢B¡¢C¡¢D¡¢E¡¢F¶¼ÊÇÖÜÆÚ±íÖÐÇ°ËÄÖÜÆÚµÄÔªËØ£¬ËüÃǵĺ˵çºÉÊýÒÀ´ÎÔö´ó£¬ÆäÖÐA¡¢B¡¢CÊÇͬһÖÜÆÚÏàÁÚµÄÈýÖÖÔªËØ£¬B¡¢D¡¢FÔªËØÔ­×Ó×îÍâµç×Ó²ãµÄpÄܼ¶£¨¹ìµÀ£©Éϵĵç×Ó¾ù´¦ÓÚ°ëÂú״̬£¬ÔªËØEµÄ×î¸ßÕý¼ÛÑõ»¯ÎïµÄË®»¯ÎïÔÚͬÖÜÆÚÔªËصÄ×î¸ßÕý¼ÛÑõ»¯ÎïµÄË®»¯ÎïÖÐËáÐÔ×îÇ¿£®
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©A¡¢B¡¢CÈýÔªËصĵÚÒ»µçÀëÄÜÓÉ´óµ½Ð¡µÄ˳ÐòΪ
 
£¨ÓöÔÓ¦µÄÔªËØ·ûºÅÌî¿Õ£¬Ï¿Õͬ£©£¬ÈýÕߵĵ縺ÐÔÓÉ´óµ½Ð¡µÄ˳ÐòΪ
 

£¨2£©A¡¢B¡¢CÈýÔªËصÄÇ⻯Îï·Ö×ӵĿռä½á¹¹·Ö±ðÊÇ
 

£¨3£©B¡¢D¡¢FÈýÔªËصÄÇ⻯ÎïµÄ·Ðµã´Ó¸ßµ½µÍÅÅÁдÎÐòÊÇ£¨Ìѧʽ£©
 
£¬ÆäÔ­ÒòÊÇ
 
£®
£¨4£©FÔªËØÔ­×Ó»ù̬ʱµÄºËÍâµç×ÓÅŲ¼Ê½Îª
 
£®
£¨5£©ÓÉB¡¢EÁ½ÖÖÔªËØ×é³ÉµÄ»¯ºÏÎïX£¬³£ÎÂÏÂΪÒ×»Ó·¢µÄµ­»ÆÉ«ÒºÌ壬x·Ö×ÓΪÈý½Ç׶ÐηÖ×Ó£¬ÇÒ·Ö×ÓÀïB¡¢EÁ½ÖÖÔ­×Ó×îÍâ²ã¾ù´ïµ½8¸öµç×ÓµÄÎȶ¨½á¹¹£®XÓöË®ÕôÆø¿ÉÐγÉÒ»ÖÖ³£¼ûµÄƯ°×ÐÔÎïÖÊ£¬ÔòX·Ö×ӵĵç×ÓʽΪ
 
£¬X·Ö×ÓµÄÖÐÐÄÔ­×ÓµÄÔÓ»¯¹ìµÀÀàÐÍΪ
 
£¬XÓëË®·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ
 
£®¾«Ó¢¼Ò½ÌÍø
£¨6£©ÁíÓÐÒ»ÖÖλÓÚÖÜÆÚ±íÖÐdsÇøµÄÔªËØG£¬¸ÃÔªËص¥ÖÊÐγɵľ§Ì徧°ûÈçͼËùʾ£¬Èô¼ÙÉè¸ÃÔ­×Ӱ뾶Ϊr£¬Ïà¶ÔÔ­×ÓÖÊÁ¿ÎªMr£¬Ôò¸ÃÔªËص¥ÖʵÄÃܶȿɱíʾΪ
 
£®£¨ÓÃNA±íʾ°¢·ü¼ÓµÂÂÞ³£Êý£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÒÑÖªA¡¢B¡¢C¡¢D·Ö±ðÊÇCu¡¢Ag¡¢Fe¡¢AlËÄÖÖ½ðÊôÖеÄÒ»ÖÖ£®ÒÑÖª¢ÙA¡¢C¾ùÄÜÓëÏ¡ÁòËá·´Ó¦·Å³öÆøÌ壻¢ÚBÓëDµÄÏõËáÑη´Ó¦£¬Öû»³öµ¥ÖÊD£»¢ÛCÓëÇ¿¼î·´Ó¦·Å³öÆøÌ壬ÓÉ´Ë¿ÉÒÔÍƶÏA¡¢B¡¢C¡¢DÒÀ´ÎÊÇ£¨¡¡¡¡£©
A¡¢Fe¡¢Cu¡¢Al¡¢AgB¡¢Al¡¢Cu¡¢Fe¡¢AgC¡¢Cu¡¢Ag¡¢Al¡¢FeD¡¢Ag¡¢Al¡¢Cu¡¢Fe

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸