½«Ã¾¡¢ÂÁµÄ»ìºÏÎï0.1 molÈÜÓÚ100 mL 2 mol/LµÄH2S04ÈÜÒºÖУ¬È»ºóÔٵμÓ1 mol/LµÄNaOHÈÜÒº¡£Çë»Ø´ð£º
£¨1£©ÈôÔڵμÓNaOHÈÜÒºµÄ¹ý³ÌÖУ¬³ÁµíÖÊÁ¿Ëæ¼ÓÈëNaOHÈÜÒºµÄÌå»ýV±ä»¯ÈçÏÂͼËùʾ¡£µ±V1=160 mLʱ£¬Ôò½ðÊô·ÛÄ©ÖУ¬n(Mg) =£¨ £©mol£¬V2=£¨ £©mL¡£
£¨2£©ÈôÔڵμÓNaOHÈÜÒºµÄ¹ý³ÌÖУ¬ÓûʹMg2+¡¢A13 +¸ÕºÃ³ÁµíÍêÈ«£¬ÔòµÎÈëNaOHÈÜÒºµÄÌå»ýΪ¶àÉÙ
| Äê¼¶ | ¸ßÖÐ¿Î³Ì | Äê¼¶ | ³õÖÐ¿Î³Ì |
| ¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
| ¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍÆ¼ö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
½«Ã¾¡¢ÂÁµÄ»ìºÏÎï0.1mol ÈÜÓÚ100mL 2mol/LH2SO4ÈÜÒºÖУ¬È»ºóÔڵõ½µÄÈÜÒºÖеμÓ1mol/LNaOH ÈÜÒº£¬Çë»Ø´ð£º
£¨1£©ÈôÔڵμÓNaOHÈÜÒºµÄ¹ý³ÌÖУ¬ÓûʹMg2+¡¢Al3+¸ÕºÃÍêÈ«³Áµí£¬Ôò¼ÓÈëNaOHÈÜÒºµÄÌå»ýÊÇV(NaOH)=________mL¡£
£¨2£©ÈôÔڵμÓNaOHÈÜÒº¹ý³ÌÖУ¬³ÁµíµÄÖÊÁ¿Ëæ¼ÓÈëNaOHÈÜÒºµÄÌå»ý±ä»¯ÈçÏÂͼËùʾ¡£µ±V1=160mLʱ£¬Çó½ðÊô·ÛÄ©ÖÐþµÄÎïÖʵÄÁ¿ºÍV2µÄÌå»ý£¿£¨ÒªÇóд³ö½âÌâ¹ý³Ì£©
![]()
(3)Èô»ìºÏÎïÈÔΪ0.1mol £¬ÆäÖÐMgµÄÎïÖʵÄÁ¿·ÖÊýΪa£¬ÓÃ100mL 2mol/LµÄH2SO4Èܽâ´Ë»ìºÏÎïºó£¬ÔÙ¼ÓÈë450mL 1mol/LµÄNaOHÈÜÒº£¬ËùµÃ³ÁµíÖÐÎÞAl(OH)3£¬ÔòÂú×ã´ËÌõ¼þµÄaµÄȡֵ·¶Î§Îª ¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
½«Ã¾¡¢ÂÁµÄ»ìºÏÎï0.1mol ÈÜÓÚ100mL 2mol/LH2SO4ÈÜÒºÖУ¬È»ºóÔڵõ½µÄÈÜÒºÖеμÓ1mol/LNaOH ÈÜÒº£¬Çë»Ø´ð£º
£¨1£©ÈôÔڵμÓNaOHÈÜÒºµÄ¹ý³ÌÖУ¬ÓûʹMg2+¡¢Al3+¸ÕºÃÍêÈ«³Áµí£¬Ôò¼ÓÈëNaOHÈÜÒºµÄÌå»ýÊÇV(NaOH)=________mL¡£
£¨2£©ÈôÔڵμÓNaOHÈÜÒº¹ý³ÌÖУ¬³ÁµíµÄÖÊÁ¿Ëæ¼ÓÈëNaOHÈÜÒºµÄÌå»ý±ä»¯ÈçÏÂͼËùʾ¡£µ±V1=160mLʱ£¬Çó½ðÊô·ÛÄ©ÖÐþµÄÎïÖʵÄÁ¿ºÍV2µÄÌå»ý£¿£¨ÒªÇóд³ö½âÌâ¹ý³Ì£©
(3)Èô»ìºÏÎïÈÔΪ0.1mol £¬ÆäÖÐMgµÄÎïÖʵÄÁ¿·ÖÊýΪa£¬ÓÃ100mL 2mol/LµÄH2SO4Èܽâ´Ë»ìºÏÎïºó£¬ÔÙ¼ÓÈë450mL 1mol/LµÄNaOHÈÜÒº£¬ËùµÃ³ÁµíÖÐÎÞAl(OH)3£¬ÔòÂú×ã´ËÌõ¼þµÄaµÄȡֵ·¶Î§Îª ¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011½ìÕã½½ð»ªÒ»ÖиßÈýÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ
½«Ã¾¡¢ÂÁµÄ»ìºÏÎï0.1mol ÈÜÓÚ100mL 2mol/LH2SO4ÈÜÒºÖУ¬È»ºóÔڵõ½µÄÈÜÒºÖеμÓ1mol/LNaOH ÈÜÒº£¬Çë»Ø´ð£º
£¨1£©ÈôÔڵμÓNaOHÈÜÒºµÄ¹ý³ÌÖУ¬ÓûʹMg2+¡¢Al3+¸ÕºÃÍêÈ«³Áµí£¬Ôò¼ÓÈëNaOHÈÜÒºµÄÌå»ýÊÇV(NaOH)=________mL¡£
£¨2£©ÈôÔڵμÓNaOHÈÜÒº¹ý³ÌÖУ¬³ÁµíµÄÖÊÁ¿Ëæ¼ÓÈëNaOHÈÜÒºµÄÌå»ý±ä»¯ÈçÏÂͼËùʾ¡£µ±V1=160mLʱ£¬Çó½ðÊô·ÛÄ©ÖÐþµÄÎïÖʵÄÁ¿ºÍV2µÄÌå»ý£¿£¨ÒªÇóд³ö½âÌâ¹ý³Ì£©![]()
(3)Èô»ìºÏÎïÈÔΪ0.1mol £¬ÆäÖÐMgµÄÎïÖʵÄÁ¿·ÖÊýΪa£¬ÓÃ100mL 2mol/LµÄH2SO4Èܽâ´Ë»ìºÏÎïºó£¬ÔÙ¼ÓÈë450mL 1mol/LµÄNaOHÈÜÒº£¬ËùµÃ³ÁµíÖÐÎÞAl(OH)3£¬ÔòÂú×ã´ËÌõ¼þµÄaµÄȡֵ·¶Î§Îª ¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ì½Î÷Ê¡¸ßÒ»ÉÏѧÆÚµÚ¶þ´ÎÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£º¼ÆËãÌâ
£¨7·Ö£©½«Ã¾ºÍÂÁµÄ»ìºÏÎï0.1 molÈÜÓÚ100 mL 2 mol/LµÄH2SO4ÈÜÒºÖУ¬È»ºóµÎ¼Ó1 mol/LµÄNaOHÈÜÒº¡£ÔڵμÓNaOHÈÜÒºµÄ¹ý³ÌÖУ¬³ÁµíÖÊÁ¿£¨m£©Ëæ¼ÓÈëNaOHÈÜÒºµÄÌå»ý£¨V£©±ä»¯ÈçͼËùʾ¡£Çë»Ø´ð£º
![]()
£¨1£©Èôµ±V1=160ʱ£¬Ôò½ðÊô·ÛÄ©ÖÐ
n(Mg)= mol£¬V2= mL£»
£¨2£©ÈôÔڵμÓNaOHÈÜÒºµÄ¹ý³ÌÖУ¬ÓûʹMg2+¡¢Al3+¸ÕºÃ³ÁµíÍêÈ«£¬ÔòµÎÈëNaOHÈÜÒºµÄÌå»ýӦΪ mL¡£
²é¿´´ð°¸ºÍ½âÎö>>
¹ú¼ÊѧУÓÅÑ¡ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com